[experiment 4] design of experiment with formula
DESCRIPTION
Heat Transfer LabTRANSCRIPT
DESIGN OF EXPERIMENT
MEHB 321 : HEAT TRANSFER AND APPLIED
THERMODYNAMICS LABORATORY
“THERMAL CONDUCTIVITY OF LIQUID AND GAS”
PREPARED FOR:
MOHD EQWAN BIN MOHD ROSLAN, MR
NAME ID
1. AMAN BIN ZAINAL RASID ME092809
2. MUHAMMAD LUQMAN HAKIM BIN ROZMAN ME092830
3. LUQMAN HAKIM BIN ALIAS ME092812
4. AHMAD HAMZI BIN AZHAR ME092805
5. MUHAMMAD AIMAN BIN YUNUS ME092817
GROUP : 04
SECTION : 01
SUBMIT DATE : 23 NOVEMBER 2015
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CONTENTS
1.0 Objectives 2
2.0 Test Preparations 2
3.0 Methods 2
4.0 Materials 3
5.0 Test Procedures 5
6.0 Test Datasheet 5
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OBJECTIVES
The purposes of conducting this experiment is to investigate the temperature profile and thermal
conductivity of fluid
TEST PREPARATION
1. Place the equipment on a level surface.
2. Connect the water inlet manifold at the front of the unit to a cold water supply.
3. Connect the water outlet manifold at the rear of the unit to a drain.
4. Connect the power cable to a single phase, 220 - 240 VAC / 13 A / 50 Hz power supply and switch on
the power supply.
5. Switch on the mains power on the control panel.
6. Check to ensure that all the temperature sensors are working properly by comparing the readings for
each point. The readings should be approximately equal, with deviations of no more than 0.5°C. Note any
differences for zero error correction later.
7. Switch on heaters and set their input power to 75 W. Observe the temperature inside the test modules to
ensure that they are working properly.
8. If all components are in good working order, the system is ready for use.
METHODS
The purpose of conducting this experiment is to investigate the temperature profile and thermal
conductivity of fluid.
Basically, the govern equation, Fourier’s Law is used to identify the thermal conductivity is;
q=−kA dTdx
A - Area perpendicular to the direction of the heat flow
k - Thermal conductivity of the material
From the equation above, to find value for K, the equation will be:
k=−qAdxdT
From the equation, we know that the parameters that can be manipulated are area, A that perpendicular
with heat flow, q ,the amount of power is supplied, and dx, distance of heat flow.
The value for q is controlled by heaters and set to input power to 75W (in this experiment).
Then, after one minute, the temperature of TC 101 (temperature controller) and TI 101 (temperature of
water surface) is taken from control panel.
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Using the area given, A ,the value of k is determined.
MATERIALS
A - Control Panel
B - Pressure Gauge
C - Charging Gas Valve / Drain Valve
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A
B
C
D
E
F
G
H
I
Figure 1: Full diagram of the experiment apparatus
D - Liquid Charging Valve
E - Water Cooling Inlet
F - Water Cooling Outlet
G - Main Power switch
H - Power meter
I - Temperature indicator
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Figure 2: Cylinder cross section
PROCEDURE
1. Open fully the main pipe.
2. Open fully the inlet valve at the left side and the outlet valve at the right side.
3. Switch on the main power on the control panel.
4. Check to ensure that all the temperature sensors are working properly by comparing the readings
for each point. The readings should be approximately equal, with deviations of no more than 0.5°C. Note
any differences for zero error correction later.
5. Switch on heaters.
6. Set the input power to 0 W.
7. Observe the temperature inside the test modules to ensure that they are working properly.
8. Record the temperature of the TC 101 (setting) and TI 101 (middle of the cylinder).
9. Repeat the step 6 to 8 using 75 W and 100 W.
10. Calculate the k, thermal conductivity using Fourier’s Law and Newton’s Law of cooling.
11. Close the inlet valve and outlet valve.
12. Switch off the control panel.
TEST DATASHEET
READING FROM EXPERIMENT
POWER (W) TC 101 (°C) TI 101 (°C) k (W/m.k)
0 25.8 25.0 0
75.2 31.6 28.3 0.112
102.0 32.7 28.5 0.119
SAMPLE CALCULATION:
Original equation: q=−kA dTdx
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Sample calculation for power 75.2 W,
q=−kA dTdx
75.2=−k (2π (0.0414 )(0.235))( 28.3−31.60.0003
)
k=0.112Wm.k
From equipment,
H=−kA(TI 101−TC 101)
dr
H: power reading from power meter
A: surface cylinder: 2πrL (m2)
dr: 0.0003 m
Information given,
r: 0.0414 m
L: 0.235 m
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