engineering test sample questions

8/8/2019 Engineering Test Sample Questions

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Vietnamese German University Sample Questions for the Enginneering Test -1-

________________________________________________________________________________________________ ITB Consulting GmbH and Gesellschaft fr Akademische Studienvorbereitung und Testentwicklung e.V. (g.a.s.t. =Society for Academic Study Preparation and Test Development, a Registered Association).VGU is responsible for this translation into Vietnamese.

The TestAS, a scholastic aptitude test developed and executed by ITB Consulting GmbH andTestDaF Institute in Germany, is being used as VGU Entrance Exam. VGU is responsible for thefollowing translation of sample questions into Vietnamese. This translation is meant for internal useby VGU applicants.

Bi ki m tra TestAS, mt bi kim tra kh nng hc tp c pht trin v thc hin bi Cng tyTNHH C Vn ITB v Vin TestDaF, CHLB c, c s dng lm Bi Thi Tuyn Sinh ca VGU.VGU ch u trch nhim i vi bn dch kim tra mu di y sang t ing Vit. Bn dch ny chc s dng ni b cho th sinh d tuyn vo VGU.

Sample Questions for the Engineering ModuleCu h i mu cho kh i K thu t

Subtest Formalising Technical InterrelationshipsPh n ki m tra Thi t lp cc m i quan h k thu t

In the subtest "Formalising Technical Interrelationships," you are to transfer technical or scientificfacts described verbally into a formulaic presentation and to interrelate the arising parameters toeach other.This test measures your ability to formalise, your deductive and combinatory powers and yourability to use basic mathematical tools of the trade. Deeper knowledge of mathematics and physicsis not required to solve the problems formulae and laws are given but must be used andinterrelated correctly.Trong phn Thit lp cc mi quan hk thut, th sinh phi chuyn cc d liu k thut haykhoa hc c m tbng li sang dng cc tham s, cng thc v cc h thc lin hgia cctham shay cng thc vi nhau.Phn ny kim tra kh nng thit lp cng thc, kh nng suy lun v tng hp cng nh kh

nng s dng cc cng c ton hc c bn trong gii quyt vn . gii cc cu hi ny thsinh khng cn cc kin thc vTon hc v Vt l nhiu hn cc cng thc v cc nh lutc cho trong phn hng dn, tuy nhin th sinh cn bit cch vn dng ng cc cng thc vnh lut ny.

InstructionsWorking time: 60 minutes


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Hng dn:

Thi gian lm bi: 60 pht

Trong cc mc sau y, Cc mi lin hgia cc i lng k thut khc nhau s c din t bng cu vn hay h nh v. Th sinh cn phi xc nh cc cng thc lin hgia cc i lngc cho.

H tr: - Chu vi ca mt ng trn: U = 2 r = D- Din tch ca mt hnh trn: A= r 2 = D2 /4

- Hnh trn: 360o hay 2 - Vn tc trung bnh: Qungng chia cho thi gian- Tn squay: Svng quay trnn v thi gian (chng hn 10

vng quay trn giy hay n = 10s-1)- p sut: Lc chia n vdin tch- M-men lc: Vector lc nhn hu hng vi vector chiu di

cnh tay n- Mt cnh tay n scn bng nu m-men lc xon tri v m-men lc xon phi tc

ng ln n bng nhau.- Tnh t l:

- Cc i lng x v y (chng hn khi lng v th tch) ca mt vt c gi l t lvi nhau (x ~ y) nu thng sca chng l mt hng s.

- Cc i lng u v w (chng hn th tch v p sut ca mt kh l tng nhit khng i) c gi l t lnghch vi nhau (u ~ 1/w) nu tch s ca chng lmt hng s.


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Lng gic:

Cc hnh ch mang tnh minh ha khng nht thit ng t l.

ExampleV d

A gear mechanism consists of the gears A and B. Gear A hasZ A cogs; Gear B has Z B cogs. In thetime it takes Gear A to completen A number of rotations, Gear B completesn B number of rotations.Which of the following equations is correct?


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Mt h thng truyn ng c hc gm hai bnh rng A v B. Bnh rng A c ZA rng; Bnh rng Bc ZB rng. Trong thi gian bnh rng A quay trn vn nA vng, bnh rng B quay c nB vng.Phng tr nh no trong cc phng tr nh sau y cho mi quan h ng?

Solutionsp n

Subtest Formalising Technical InterrelationshipsPh n ki m tra Thi t lp cc m i quan h k thu t

Example

To solve this problem, an equation is to be derived from the introductory text and then transformed.As described in the text, the time required by Gear A to rotate exactly nA timesis equal to the time it takes Gear B to rotate nB number of times. The following products cantherefore be equated: ZA nA = ZB nB.To solve this equation for nB, both sides must be divided by ZB. Therefore the solution is theequation shown under (B).

V d

gii bi ny, th sinh cn s dng mt phng tr nh cho trong phn ch dn. Nh c mtbng cu vn, thi gian bnh rng A quay ng nA vng bng thi gian bnh rng B quay nB vng. Do ta c mi quan h sau: ZA nA = ZB nB.

tm nB, chia hai vcho ZB. V th p n l cu (B).


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Subtest Visualising SolidsPh n ki m tra Hnh dung v t th khi

In the subtest "Visualising Solids"; you have to infer perspectives of a solid from one given view ofthe solid. The test measures your spatial sense.Trong phn kim tra Hnh dung vt thkhi, th sinh phi hnh dung ra phi cnh ca mt vt rntmt gc nhn cho trc. Phn ny kim tra cm nhn khng gian ca th sinh.

InstructionsHng dn:

Two parts, Working time: 30 minutesHai phn, Thi gian lm bi: 30 pht

Question type 1

To solve the following items, you are to visualize the bodies three-dimensionally. In eachexercise, the body is shown from two perspectives. You are to identify the view of the samebody from a third perspective. Please mark the correct solution (A, B, C or D) on your answersheet.The views/perspectives are referred to as follows:

Further pointers:

- In the illustrations, all visible edges are depicted as continuous (uninterrupted) lines.- If the illustration of a view from the side is not accompanied by an arrow indicating

which of the two side views is intended, part of the task is to find that out.- If, for example, a side view is illustrated to the right of the view from the front or the

view from above, it does not necessarily mean that it is a view from the right side.


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Cu h i lo i 1

gii cc cu hi trong phn ny, th sinh phi hnh dungc cc vt thba chiu. Trongmi cu hi, vt th c v theo hai gc nhn. Th sinh phi xc nh gc nhn theo hng th 3 ca cng mt vt. Hynh du vo p n ng (A, B, C hay D) trn phiu bi lm.

Cc gc nhnc quy c nh sau

Hnh chiu mt camt khi lp phng

Cc ch dn thm:

- Trong cc hnh v, tt ccc cnh nhn thy c c vbng cc ng lin nt- Nu trong hnh vm tgc nhn t pha bn cnh m khng c mi tn ch r pha tri

hay phi, nhim vs l tm cnh tri hay phi.- Nu, chng hn trong mt hnh v, hnh nhn t bn cnh c vbn phi ca mt hnhnhn t trn hay t trc, iu khng c ngh a rng y l h nh vi gc nhn t bn cnhphi.

ExampleV d

Given: The view of a solid from above and one side view of the same solidCho: gc nhn ca mt vt th rn t bn trn v tmt cnh bn ca n

(khng nhnthy)

Nhn t trn

Nhn t bn cnh

Nhn t trc

Nhn t trn (VA) Nhn t bn cnh (VS)


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Wanted: View from the front (VF) of the solidHy tm: Hnh vgc nhn t pha trc (VF) ca vt thny.

Question type 2 Cu h i lo i 2

The following items also test your ability to visualise three-dimensional figures. Each itemconsists of two illustrations showing a transparent cube with one or two cables in its interior.The first illustration (left) always shows the view from the front. In the picture on the right, the

same cube is illustrated again. Your task is to determine whether the picture on the right showsthat cube from the right (r), left (l), from below (w), above (a) or behind (d).Cc cu hi sau cng kim tra kh nng h nh dung hnhnh ca vt thba chiu. Mi cu hic hainh ca mt khi hp trong sut vi 1 hay 2 si dy bn trong.nh u tin (bn tri)lun lnh chp t pha trc. Trongnh bn tay phi, cng mt khi hp nhng c nhn t pha khc. Nhim vca th sinh l xc nh xemnh bn phi lnh chp t pha no cakhi hp, bn phi (r), tri (l), t pha di (w), t bn trn (a) hay t ng sau (d)

Here you see the cube from the front!

y l khi hp nhn t pha trc!

Here you see the cube from.....?..... y l khi hp nhn t .....?.....


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In the picture on the right, you see the cube from above. On your answer sheet, youwould mark the (D).Trong hnh bn phi, ta thy khi hp t bn trn. Th sinh s nh du chn (D) vo phiu tr li.

These items can be solved in one of the following two ways:Cu hi ny c thgii bng mt trong hai cch sau:

- Imagine that the cube had been placed on a glass table and that you could walk all the wayaround it. Standing to the right or left of the table, you look at the cube from the right or fromthe left. If you go behind the table, you look at the cube from behind. If you come back to thefront of the table and bend over it, to look at the cube from above, and if you imagine yourselflying down underneath the table, feet first, you see the view from below.

- Hy tng tng rng khi hp c t trn mt ci bn knh v ta c th i vng quanhbn. ng bn tri hay phi ca bn, ta snhn thy pha tri hay phi ca khi hp. Nu ta ira sau, ta s thy khi hp t ng sau. Nu i ra pha trc bn v nhn khi hp t bndi ta snhn thy khi hp nh h nh bn phi.

- Or you imagine that you could pick up the cube and turn it around in your hands. If you lookedat the cube from the front, i.e. from the position shown in the left-hand illustration, and thentipped it towards you by 90 degrees, not changing your own position at all, then you would seethe view from above. If you looked at the cube from the front and then turned it 90 degrees tothe right you would see the view from the left. If you turned it from the starting position 90degrees to the left, you would see it from the right. And if you turned it 180 degrees to the rightor left from the starting position you would see it from behind. Finally, if you tipped it backward,you would see it from below

- Ta c thhnh dung rng ta cm khi hp ln v xoay n trn tay. Nu ta lt khi hp ln mt

gc 90 ta s thy hnh bn trn.

ExampleV d

Here you see the cubefrom the front! y l khi hp nhn t pha trc!

Here you see the cubefrom .....?..... y l khi hp nhn t pha .....?.....


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Solutionsp n

Subtest Visualising Solids

Ph n ki m tra Hnh dung v t th khiQuestion type 1Cu h i lo i 1

ExampleV d

Visualise this solid as a tree stump which has been cut off diagonally. When you look at it fromabove (view from above), you see that a fairly large piece has been cut out of its left half. Behindthe cut-out section, however, a relatively large section of the stump has remained standing.You can therefore rule out Option (A) immediately, because this option shows nothing remainingbehind the cut-out section except for the outer bark. Option (B) can likewise not be the correctsolution, since here only a section of bark has been removed from the front. The piece cut out ofOption (D) has only one straight side. According to the view from above, however, the cut-outsection has to have three straight sides. This is the case only with the section cut out of Option (C).Therefore, (C) is the correct answer.

Hy hnh dung vt th ny nh 1 gc cy b ct cho. Khi ra nhn t trn (AV), ta thy rng mtmnh kh ln b ct b pha na tri. Pha sau mng b ct b, mt mng tng i ln cnli.V th ta c th loi tr ngay kh nng (A), do la chn ny khng cho thy phn cn li phasau phn b ct bngoi tr phn vngoi. Kh nng (B) cng khng thl la chn ng, v

trong hnh ny, ch mt phn ca vb ct i t pha trc. Mu b ct i trong h nh (D) ch c mtpha l phng. Tuy nhin, theo hnh nhn t pha trn (AV) phn b ct i c 3 mt phng. Duy nhtla chn (C) l li gii ng.

Question type 2 Cu h i lo i 2

ExampleV d

Here the only view you can rule out immediately is the one from "behind" (Option E): If the viewfrom the front shows one end of the cable leading toward the back of the cube at the top right, the

view from behind would show this cable end "coming at you" at the top left. This is not the case inthe right-hand picture. If you tip the cube forward in your imagination, you immediately see that thecorrect answer cannot be the view from "above;" and turning the cube 180 degrees or 90 degreesto the right also does not lead to the desired perspective. But if you imagine yourself standing onthe right side of the cube, you see that the end of the cable which is concealed in the left-handillustration comes toward you on the right side of the cube in the right-hand illustration: Therefore"right" (A) is the correct answer.

Trong cu hi ny, gc nhn t pha sau (E) c th loi bngay: do hnh nhn t pha trc c mtu dy hng vpha sau ca hp gc trn bn phi, v vy gc nhn t pha sau phi chothy u dy hng v pha ngi quan st gc cao bn tri. y r rng khng phi l hnhpha bn phi. Nu ta lt ci hp hay xoay n sang phi 90 ta cng khng thu c nh bn phi.


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Nhng nu tng tng l ta ng bn tay phi ca khi hp, ta thy rng u dy b khut tronghnh bn tri s hng ti ta pha phi. Do p n l nh n t pha phi (A).


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Subtest Analysing Technical InterrelationshipsPh n ki m tra Phn tch cc quan h k thu t

In the subtest "Analysing Technical Interrelationships," you have to analyse and interpretdiagrams, charts or tables depicting technical laws or formulae.The test measures the ability to abstract from scientific and technical facts and to put abstract factsin concrete terms. Knowledge of mathematics, physics or technology is not needed, backgroundinformation will be provided if necessary.

Trong phn kim tra Phn tch cc quan hkthut, th sinh phi phn tch v din gii cc s, biu hay cc bng m tcc quy lut hay cng thc.Phn ny kim tra kh nng khi qut ha cc d kin khoa hc hay k thut v pht biu cc vn tru tng mt cch c th. Kin thc Ton hc, Vt l, K thut l khng cn thit, cc kinthc c bn s c cung cp khi cn thit.

Instructions

Hng dn:Working time: 60 minutesThi gian lm bi: 60 pht

These items contain questions from various technical areas. Your task is to visualize simpletechnical procedures and recognize technical interrelationships. Unless otherwise indicated, theaxes (scales) of all diagrams are linearly subdivided. In some of the items, you must identify thequalitatively correct diagram. In other words, your task is to decide which graph bestrepresents the relationship between the variables shown. Even the correct diagram will notnecessarily drawn to scale.

Phn ny bao gm cc cu hi t cc l nh vc khc nhau. Th sinh phi hnh dung ra cc qutrnh k thut n gin v tm ra cc mi quan hk thut trong .Ngoi tr khi c ni r, cc trc (t l) ca tt c cc s c chia theo t l tuyn tnh.Trong mt vi cu hi, th sinh phi xc nh mt cch nh tnh cc s ng. Ni cch khc,th sinh phi quyt nh s no m t tt nht cc mi quan h c cho. Cc s khngnht thit phi v ng t l.


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ExampleV d

Arrangements I and II each include a beam which is pivot-mounted (like a swing or see-saw). Ahook has been mounted on the right end of the beam. The ends of the beam are connected by arope which is threaded through rolls. A weight is hung on the hook.

Hai h thng I v II gm mt thanh ngang gn c nh 1 im (nh cu bp bnh). Mt ci mcc gn pha phi ca thanh ngang. Hai u ca thanh ngang gn vi 1 si dy chy vngqua cc rng rc. Mt vt nng c treo vo mc.

Which of the following statements is/are then correct? (The masses of the beam, rope and hookcan be neglected.)Pht biu no trong cc pht biu sau y l ng? (Khi lng ca thanh ngang, si dy v cimc l khng ng k)

I. In the case of Arrangement I, the right end of the beam moves downward.II. In the case of Arrangement II, the right end of the beam moves downward.

I. Trong trng hp h thng I, u pha phi ca thanh ngang sb ko xung.II. Trong trng hp h thng II, u pha phi ca thanh ngang sb ko xung.

(A) Only statement I is correct.(B) Only statement II is correct.(C) Both statements are correct.(D) Neither of the two statements is correct

(A) Duy nht pht biu I l ng (B) Duy nht pht biu II l ng (C) Chai pht biu u ng (D) Chai pht biu u sai

Thanh ngang Thanh ngang

Mc Mc Gi Gi

Dy Dy


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Solutionsp n

Subtest Analysing Technical Interrelationships

Ph n ki m tra Phn tch cc quan h k thu tExampleV d

If there is no rope, the right end of the beam moves downward in both cases when a weight issuspended from the hook. So the question is whether this movement is prevented by the rope.When a weight is suspended from the hook in Arrangement I, the rope slackens at the right endand at the left end. The right end of the beam moves downward, and Statement I is accordinglycorrect. When a weight is suspended from the hook in Arrangement II, traction (pulling power) isapplied to the right end of the rope. By way of the rope, this traction is transferred to the left end ofthe beam. Since both ends of the beam are pulled downward with the same force, the beam doesnot move. Statement II is false.The solution to this item is therefore A.

Nu khng c si dy, u pha phi ca thanh ngang sb ko xung trong c 2 trng hp khita treo vt nng vo mc. V thcu hi l khi no si dy scn tr s di chuyn i xung ny.Trong trng hp h thng I, khi vt nng c treo vo mc, si dy s th lng c hai u cathanh ngang. u pha phi ca thanh ngang sb ko xung v pht biu (I) l ng. Khi vtnng c treo vo h II, lc cng s c t vo u phi ca si dy. Lc cng ny s kou tri ca thanh ngang i xung. V thc hai u ca thanh ngang sb ko vi cng mt lc,thanh ngang skhng di chuyn. Pht biu (II) l sai. p n ng l (A).

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