engineering physics
DESCRIPTION
waveTRANSCRIPT
Topic 1
Interference and Diffraction
Spring 2013 1 ENGG 2520 Engineering Physics II
(Halliday/Resnick/Walker Ch.35, 36)
Spring 2013 ENGG 2520 Engineering Physics II 2
Interference and Diffraction
• Introduction to Interference
• Young’s Interference Experiment
• Intensity of Interference Pattern
• Thin Film Interference
• Optical Interferometers
• Introduction to Diffraction
• Single Slit and Double Slit Diffractions
• Diffraction Grating
• Diffraction Resolution Limit
Spring 2013 ENGG 2520 Engineering Physics II 3
Interference in Nature
butterfly
peacock
soap film and bubble beetle
CD/DVD
Spring 2013 ENGG 2520 Engineering Physics II 4
What is Interference? Interference: a physical phenomenon in which two or more waves superimpose
to form a resultant wave. It usually refers to the interaction of waves that are
coherent/correlated with each other. Optical interference is the interference
between light waves and is applied in many branches of science and engineering.
The resultant wave is obtained by the superposition principle. Its amplitude
depends on the phase difference between the interacting waves,
In-phase interference → amplitude doubling
Out-of-phase interference → amplitude cancelling
The blue colour on the top surface of a
Morpho butterfly wing is due to optical
interference. It shifts in color as you
change your viewing angle.
Spring 2013 ENGG 2520 Engineering Physics II 5
Young’s Interference Experiment
Thomas Young
(1773-1829)
Young’s interference experiment (Young’s double slit interference expt): ~1801
Significance: proved that light is a wave, contradicted Isaac Newton’s view
Formation of wave interference pattern
Optical interference
fringes
Spring 2013 ENGG 2520 Engineering Physics II 6
Optical Path Difference
(1.1) sindL
parallel and rays
,For
21
rr
dD
Spring 2013 ENGG 2520 Engineering Physics II 7
Constructive and Destructive
Interferences
Bright fringes (constructive interference, maxima): L must be either zero or an
integer number of wavelengths. Appear at angles satisfying
Dark fringes (destructive interference, minima): L must be an odd multiple of
half a wavelength. Appear at angles satisfying
(1.2) 2,... 1, 0,,sin mmd
(1.3) 2,... 1, 0,,2
1sin
mmd
Spring 2013 ENGG 2520 Engineering Physics II 8
Fringe Spacing
Consider near pattern center, i.e. small
(1.4) tansinD
y
Spacing between 2 bright fringes:
(1.5)
1
sinsin 1
1
d
D
d
mD
d
mD
DD
yy
mm
mm
Conclusion: The spacing between
neighboring bright fringes remains
unchanged when and d are small.
Spring 2013 ENGG 2520 Engineering Physics II 9
Example: Measuring Plastic Thickness
Plastic block inserted → 1 (first order) bright fringe
moves to center for = 600nm
Given that a plastic
block of refractive
index 1.5 is placed on
the upper slit,
determine the plastic
thickness.
Let L be the plastic block thickness, the path difference at
the center bright fringe is and is equal to L x (1.5-1)
m102.1
m106005.0
6
9
L
L
Spring 2013 ENGG 2520 Engineering Physics II 10
Wave Coherence For the interference pattern to
appear on the screen, the light
waves reaching any point on the
screen must have a phase
difference that does not vary in
time. When the phase difference
remains constant, the light from
slits S1 and S2 are said to be
completely coherent.
If the phase difference constantly
changes in time, the light is said
to be incoherent.
Incandescent light – incoherent light source
Laser – highly coherent light source
Sunlight – partially coherent, i.e., phase difference is constant only if the
points under consideration are very close
Spring 2013 ENGG 2520 Engineering Physics II 11
Intensity of Interference Pattern
)71(sin
)61(sin
0
0
.tωEE
.t ωEE
2
1
Consider electric field components of the light waves at point P on the screen:
It can be shown (proof to follow) that the intensity (power/area) at P is
Constant phase difference → coherent
(1.9) sin2
where(1.8) 2
cos4 2
0
dII
Total energy is
conserved
Spring 2013 ENGG 2520 Engineering Physics II 12
Proof:
Recall
2sin
2cos2sinsin
BABABA
Hence, the electric field at point P is
(1.10) 2
sin2
cos2sinsin 00021
tEtEtEEEE
Constant amplitude
Thus, the electric field amplitude is changed by a factor of .2
cos2
Intensity (field amplitude)2 → changed by (1.8) 2
cos4 2
0
II.
2cos4 2
sin
2d Phase difference
Path difference (1.1)
(1.9) sin2
d
Intensity of Interference Pattern
Spring 2013 ENGG 2520 Engineering Physics II 13
Thin Film Interference
Ray representation of incident, transmitted, and reflected light waves.
Phase difference of the reflected waves is determined by:
• phase shift by reflection
• different physical path lengths
• different RI different optical path lengths
Spring 2013 ENGG 2520 Engineering Physics II 14
Phase shift on normal reflection (RI = refractive index):
Incident from high RI to low RI (e.g from water/glass to air) → no phase shift
Incident from low RI to high RI (e.g from air to water/glass) → phase shift
Phase Shift by Reflection
http://www.schoolphysics.co.uk
i.e., /2
Spring 2013 ENGG 2520 Engineering Physics II 15
Maxima and Minima Air Water Air
/2 reflection shift no phase shift
Assume normal incidence,
(1.11) 2,... 1, 0,,2
12 2
mmnL
Destructive interference (Minima): (1.12) 2,... 1, 0,,2 2 mmnL
Constructive interference (Maxima):
Spring 2013 ENGG 2520 Engineering Physics II 16
Different soap film thicknesses → maxima at different wavelengths
Soap Film and Bubble
Dark region: L<< (about to burst)
Path difference: negligible
Phase difference dominated by
phase shift in reflection =
m =1
m =2
m =3
Spring 2013 ENGG 2520 Engineering Physics II 17
Thin Film Coating Thin film coatings are widely used in glasses, camera lens, optical
instruments, semiconductor optical devices, fiber devices, etc. to
improve their performances through reduction or enhancement of
optical reflections/transmission of specific wavelengths.
CUHK Photonic Packaging Lab
Coating Machine
Spring 2013 ENGG 2520 Engineering Physics II 18
Example: Antireflection Coating A glass lens (RI=1.50) is coated with MgF2 (RI=1.38) to reduce optical
reflections. Determine the minimum coating thickness required to eliminate
reflections at the center of the visible spectrum, i.e. =550 nm. Assume
incident light is perpendicular to the lens surface.
Reflection is minimized if we
choose coating thickness L s.t.
waves reflected from the interfaces
are exactly out of phase.
2,... 1, 0,,2
12 2
mmnL
For minimum thickness, m = 0
nm 6.9938.14
nm 550
4 2
n
L
Spring 2013 ENGG 2520 Engineering Physics II 19
Optical Interferometer Interferometer: an optical instrument/device that measures lengths or
changes in length (or RI) with great accuracy by means of interference fringes.
Common types of Interferometer:
mirror Beam splitter
Mach-Zehnder Interferometer
Sagnac Interferometer
Michelson Interferometer
Fabry-Perot Interferometer
Spring 2013 ENGG 2520 Engineering Physics II 20
The Nobel Prize in Physics 1907 was awarded to Albert A. Michelson
"for his optical precision instruments and the spectroscopic and
metrological investigations carried out with their aid". He was the first
American to receive the Nobel Prize in Sciences.
Michelson Interferometer
http://en.bj-force.net/
MIPAS Interferometer Assembly (Michelson
Interferometer for Passive Atmospheric Sounding) https://earth.esa.int/web/guest/missions/esa-operational-eo-
missions/envisat/instruments/mipas
Spring 2013 ENGG 2520 Engineering Physics II 21
)13.1( 12
nL
For each path change of (phase change = 2), the pattern is shifted by one
fringe. Thus, by counting the number of fringes through which the material causes
the pattern to shift, the thickness L can be determined in terms of .
Animation on shifting of interference fringes http://skullsinthestars.com/2008/10/16/fabry-perot-and-their-wonderful-
interferometer-1897-1899/
Michelson Interferometer Path difference of the interfering branches is 2d2-2d1.
When one of the mirrors is moved by /2, the path
difference is changed by and the interference pattern
will be shifted by one fringe.
Similarly, insertion of a transparent material of
thickness L and RI n on one of the paths will cause a
phase change equal to
Spring 2013 ENGG 2520 Engineering Physics II 22
Diffraction
vertical slit
razor blade
sunlight diffraction
diffraction photography
circular disk square aperature
Spring 2013 ENGG 2520 Engineering Physics II 23
Basics of Diffraction Light diffraction: light passes through a narrow slit (dimension ~
wavelength) or an edge interferes with itself and produces an interference
pattern called the diffraction pattern. It is a wave nature of light.
Interference pattern from two-
slit diffraction http://en.wikipedia.org/wiki/Diffraction
Water wave encounters a barrier with an
opening of dimensions similar to the
wavelength, the part of the wave that passes
through the opening will flare (spread) out—will
diffract—into the region beyond the barrier. The
flaring is consistent with the spreading of
wavelets according to Huygens principle.
Spring 2013 ENGG 2520 Engineering Physics II 24
Dependence on Slit Width
The narrower the slit, the stronger the diffraction.
Diffraction limits geometrical optics (ray optics) since a narrow slit will
cause the light to spread. Geometrical optics holds only when slits or
apertures have dimensions much greater than the wavelength of light.
In projecting an image of tiny features on a photo film, the image will
become blurred through optical diffraction.
Spring 2013 ENGG 2520 Engineering Physics II 25
Single Slit Diffraction: Locating Minima
First, if we divide the slit into two zones of equal widths a/2, and then
consider a light ray r1 from the top point of the top zone and a light ray r2
from the top point of the bottom zone. For destructive interference at P1,
.2/sin2/ a
)14.1( sin aHence, the first minimum is located at
For D>>a, rays r1 and r2
can be treated as parallel
and inclined at angle to
the central axis.
This pair of rays r1 and
r2 cancel each other at
P1. Similarly, we can
pair up other rays in
the two zones. This path length
difference shifts one
wave from the other,
which determines the
interference.
Spring 2013 ENGG 2520 Engineering Physics II 26
Single Slit Diffraction: Locating Minima After locating the first dark fringes, one can find the second dark fringes above and
below the central axis. The slit is now divided into four zones of equal widths a/4.
2sin i.e. ,2/sin4/ aaThe second minimum is located at
In general, the minima (dark fringes) are located at
)15.1( ,...3,2,1for ,sin mma
Spring 2013 ENGG 2520 Engineering Physics II
The slit is divided into 18
zones. Resultant
amplitudes E are shown for
the central maximum and
for different points on the
screen.
(b) Light waves have a small
phase difference and add to give
a smaller amplitude
(c) With a sufficiently large phase
difference, the waves can add
together to give zero amplitude.
(a) Light waves from the zones are
in phase and add constructively to
give the maximum amplitude.
(d) With even larger phase
difference, the waves add to
give a small net amplitude.
Single Slit Diffraction: Intensity Pattern
27
Spring 2013 ENGG 2520 Engineering Physics II 28
Double Slit Diffraction For slit width a << → central
maximum of the diffraction
pattern of each slit covers the
entire screen. Interference leads
to fringes of same intensities.
If a << is NOT satisfied → each slit
produces its own diffraction pattern
described on p.27 with the first
minima close to the center.
Hence, interference of light from the
2 slits produces fringes of different
intensities. The diffraction pattern in
(b) sets an envelope for the intensity
plot in (a) to produce plot (c).
Double slit
Single slit
Spring 2013 ENGG 2520 Engineering Physics II
29
Diffraction Gratings Diffraction gratings contain a large number of slits, often called rulings. They
can be made on a opaque surface with narrow parallel grooves arranged like
the slits, forming a reflection grating instead of a transmission grating.
The fine rulings of ~0.5 micron width
on a CD function as a reflection grating
Interference fringe width is inversely proportional to the number
N of rulings for a given ruling separation d and wavelength.
Hence, a diffraction grating with large N can be used to
determine the wavelength of a monochromatic light. In contrast,
the bright fringes from double slit interference are broad and
different wavelengths will overlap too much to be distinguished.
)16.1( ... 2, 1, 0,for ,sin mmd
Constructive interference (maxima) occurs at
Visible emission lines of Cadmium
resolved with a grating spectroscope
Spring 2013 ENGG 2520 Engineering Physics II 30
Diffraction by Circular Aperture A tiny circular aperture such as a circular lens can result in an optical
diffraction pattern.
Diffraction pattern of a circular
aperture showing the central
maximum and the interference
fringes. For an aperture of diameter
d, the first minimum is located at an
angle given by
)17.1( 22.1sind
Compared to (1.14), the factor 1.22
here is caused by the circular shape
of the aperture.
In photography, a larger aperture (smaller f-number) gives a better resolved
image due to weaker diffraction effect. You may take a look on photos
taken with different apertures in the following link: http://www.luminous-landscape.com/tutorials/understanding-series/u-diffraction.shtml
Spring 2013 ENGG 2520 Engineering Physics II 31
Resolvability Consider the lens image of two distant point objects (e.g. stars) with a small
angular separation. They cannot be resolved (distinguished) if their diffraction
patterns overlap. Two objects are barely resolvable when their angular separation
is given by That is, the central maximum of one source
coincides with the first minimum of the other source in the diffraction pattern.
This is called the Rayleigh’s criterion.
.22.1sind
RR
Indistinguishable marginally distinguishable clearly distinguishable
Spring 2013 ENGG 2520 Engineering Physics II 32
Diffraction Limit in Optical Imaging
Diffraction Limit: a fundamental limit to the
resolution of an imaging system, such as
camera, telescope, and microscope. The
resolution is proportional to the size of the
objective lens, and inversely proportional to the
wavelength. The resolution limit is roughly
equal to half the wavelength in modern optics.
E.g, for green light at 0.5 mm, the resolution limit
is ~0.25 mm. To increase the resolution, shorter
wavelength such as ultraviolet or X-ray can be
used for the imaging. Alternatively, instead of
using optical imaging, one can use electronic
imaging. Electron exhibits wave-particle duality
with a wavelength (de Broglie wavelength)
inversely proportional to its momentum, and
can reach ~0.01 nm at 10 keV energy.
Scanning electron microscope
(SEM), CUHK
10 mm
Photo taken with a SEM showing
nano-features fabricated on silicon at
CUHK (Courtesy of Prof. H. K. Tsang)