energy balance and systems
DESCRIPTION
ENERGY BALANCE AND SYSTEMS. References. Blaxter, K. L. 1989. Energy Metabolism in Animals and Man. Cambidge University Press Kleiber, M. 1975. The Fire of Life. Krieger Publishing, New York Also Beef, Dairy, and Sheep NRC. Basics of Energy Use in Mammals. Simple Practical - PowerPoint PPT PresentationTRANSCRIPT
ENERGY BALANCE AND SYSTEMS
References
• Blaxter, K. L. 1989. Energy Metabolism in Animals and Man. Cambidge University Press
• Kleiber, M. 1975. The Fire of Life. Krieger Publishing, New York
Also Beef, Dairy, and Sheep NRC
Basics of Energy Use in Mammals
• Simple
• Practical– Energy systems to predict and monitor livestock
production– The common thread among human weight loss
systems
ENERGY CONCEPTS
• Energy - “ability to do work”
• Feedstuffs– protein– carbohydrates– lipids
• Physics of energy– Priestly 1700’s - the flame and the mouse
Priestly and the discovery of oxygen
A candle or an animal can make good air bad.
Plants restore to the air whatever breathing animals and burning candles remove.
Early discoveries of relevance
• Theory of combustion - Both fire and animals produce the same amount of heat per unit of CO2
• Heat production /unit of O2 produced is a more uniform measurement
• 1st law of thermodynamics - energy cannot be created or destroyed
Hess’ Law of Heat Summation
FEED ANIMALFECES
URINE
GAS
HEAT
MAINTENANCE
PRODUCTION
100% OF
ENERGY
INTAKE
1. Not concerned with mechanisms or rates of energy change
2. True for living as well as non-living systems
3. Forms basis for bioenergetic investigation even if mechanisms of action is unknown
ATP-ADP CYCLE
CATABOLISM
MECHANICALWORK
TRANSPORTWORK
BIOSYNTHETICWORK
CO2
H2O
FUELS
O2
Pi
Pi
Pi
ADP ATP
Units of Measure
• Calorie - energy required to raise the temperature of 1 g of water 1 degree C (from 16.5 to 17.5)– 1 kilocalorie (kcal) = 1,000 calories– 1megacalorie (Mcal) = 1,000,000 calories– 1kcal/g = 1 Mcal/kg– 1 calorie = 4.184 joules
Bomb Calorimeter
PARTITIONING OF ENERGY
Gross Energy (GE)
Digestible Energy (DE)
Metabolizable Energy (ME)
Net Energy (NE)
Digestion loss (fecal)
Urine lossCombustible gases (CH4)
Heat increment (HI)-heat of fermentation-heat of nutrient metabolism
NEm-basal metabolism-activity at maintenance-sustaining body temp
NEg-retained energy
HEAT LOSS
•BASAL METABOLISM
•VOLUNTARY ACTIVITY
•PRODUCT FORMATION
•THERMAL REGULATION
•WORK OF DIGESTION
•HEAT OF FERMENTATION
•WASTE FORMATION AND EXCRETION
BASAL METABOLISM
•VITAL CELLULAR ACTIVITY
•RESPIRATION
•BLOOD CIRCULATION
•IONIC BALANCE
•TURNOVER OF PROTEINS
RETAINED ENERGY
•TISSUE GROWTH
•LACTATION
•WOOL GROWTH
•HAIR GROWTH
•PREGNANCY
SYNTHESIS OF BODY TISSUES
•FAT contains 9.4 Mcal/kg and 3.8 Mcal/kg is lost as heat
•13.2 Mcal are required to deposit 1 kg fat
•PROTEIN contains 5.6 Mcal/kg (muscle=1.1 Mcal/kg)
•7.4 Mcal are lost as heat (1.5 Mcal for muscle)
•13 Mcal are required to deposit 1 kg of protein
•2.6 Mcal are required to deposit 1 kg of muscle
GROSS ENERGY
•FEED GE (kcal/g)
•Corn meal 4.4
•Oats 4.6
•Wheat bran 4.5
•Timothy hay 4.5
•Clover hay 4.5
•Corn stover 4.3
•Oat straw 4.4
GROSS ENERGY OF FEEDSTUFF
COMPONENTS
•CARBOHYDRATE 4.2 kcal/g
•FAT 9.4 kcal/g
•PROTEIN 5.6 kcal/g
•ASH 0.0 kcal/g
BACON TORCH
Calorimetry
• DIRECT - direct measurement of heat production
• INDIRECT - calculation of heat production from O2 intake, CO2 release and methane and nitrogen losses– HE = 3.886 02 +1.2 CO2 -.518 CH4-1.231N
Nitrogen Carbon Balance (Indirect)
• Required data: dry matter, nitrogen, carbon and energy of feed, feces, urine, methane and carbon dioxide.
• Assumed: – 6 g protein/g N– .5254 g carbon/g. protein– 5.6 kcal/g protein
N-C balance cont’
• Carbon gained as fat = Foodc – (Fecesc + Urinec + CO2c + Methanec + Proteinc)
• Fat assumptions:– 1.307 g fat/ g carbon– 9.4 kcal/g fat
• Heat productionkcal = Intakekcal - (Feceskcal + Urinekcal + Methanekcal +Protein gainedkcal + Fat gainedkcal)
Body Size and Metabolism
Kleiber
Armsby Calorimeter
Determination of Nem of timothy hay by a difference trial
Feedinglevel
Feedeaten(lb)
ME intake(kcal)
Heat prod.(kcal)
Energygain(kcal)
1 6.2 5788 8062 -2296
2 10.2 9544 9812 -268
Diff. 4.0 3766 1748 2028
Armsby (1922) NEm = 2028/4 = 51 Mcal/cwt
Of historical importance:
1. H = ME - P
2. Development of comparitive slaughter technique
Lofgreen and Garrett (1968)
NEm DETERMINATION
Alfalfa High Item Hay Concentrate
Intake at Equilibrium 35 23Heat Prod. an No Feed 43 43NEm of the Feed (kcal/g) 1.23 1.87
NEp BY THE "DIFFERENCE TRIAL"
+
0
ENERGYGAIN
NEp
FEED INCREASE
ACTUAL "DIFFERENCE TRIAL" ON
HIGH CONC. RATION
Level of FeedingItem Equilibrium Free ChoiceFeed Intake 23 59Energy Gain 0 40
Differences:Feed Intake, g -- 36Energy Gain, kcal -- 40
NEp of Feed:kcal per gram -- 1.11
Comparison of Fed and Fasted Steers by Indirect calorimetry (“head box”)
Fed Fasted
Weight (kg) 339 333
Gas exchange (1/2 h):
Oxygen 197.2 131.0
Carbon dioxide 198.8 96.1
Methane 8.2 1.0
RQ 1.01 0.73
Heat Production
kJ/d per kg BW 147.3 93.7
jJ/d per kg BW0.75 632.6 400.8
Eisemann and Nienaber (Brit. J. of Nutr. 64:399, 1990)
DIGESTIBLE ENERGY (DE)
•TOTAL DIGESTIBLE NUTRIENTS (TDN)
•1 lb TDN = 2,000 kcal DE
•TDN = DCP + DNFE + DCF + 2.25(DEE)
•Estimated from ADF
•from truly digestible NFC, NDF, CP and FA
•Dairy NRC
• (http://www.nap.edu/books/0309069971/html/)
•pp. 13-27
CONVERSION BETWEEN DE, ME & NE
•ME = .82DE
•NEm = 1.37 ME - 0.138 ME2 + 0.0105 ME3 -1.12
•NEg = 1.42 ME - 0.174 ME2 + 0.0122 ME3 -1.65
EFFECT OF ENVIRONMENT ON
ENERGY REQUIREMENTS
EFFECTIVE AMBIENT TEMPERATURE
THERMONEUTRALZONE
Low High
Heat StressCold stress
OptimumforPerformanceand Health
LowerCriticalTemperature
UpperCriticalTemperature
Lower Critical Temperature
•Coat Description LCT
•Summer or wet 59
•Fall 45
•Winter 32
•Heavy winter 18
Effective Temperature
TemperatureWind Speed -10 0 10 20 30Calm -10 0 10 20 305 -16 -6 3 13 2315 -25 -15 -5 4 1430 -46 -36 -26 -16 -6
*Maintenance Requirements increase .7% for each degreeof cold stress.
NEp (production)
•NEg (gain)
•NEc (conceptus)
•NEl (lactation)
Beef NRC Gain equations
•NEm (Mcal) = .077 WTkg.75 *(environmental adjustment)
•EBW = .891 SBW
•EBG = .956 SWG
•SRW = 478 kg for animals finishing at small marbling
•EQSBW = SBW * (SRW)/(FSBW)
•EQEBW = .891 EQSBW
•RE = 0.0635 EQEBW0.75 EBG1.097
•SWG = 13.91 RE 0.9116 EQSBW-.6837
Using Net Energy for Gain Projection
Step 1. Determine dry matter intake of each ingredient
Lb. as fed DM fraction Lb DM
Corn silage 15 .4 6.0Corn 7 .85 5.95SBM 1.5 .9 1.35
Total 23.5 13.3
X =
Step 2. Determine NEm intake
Lb. DM NEm/lb NEm(Mcal)
Corn silage 6 .4 4.44Corn 5.95 1.02 6.07SBM 1.35 .93 1.26
Total 13.3 11.77
Ration NEm (DM Basis) = 11.77Mcal/13.3 lb DM = .89 Mcal/lb
X =
Using Net Energy for Gain Projection
Using Net Energy for Gain Projection
Step 3. Determine NEg intake
Lb. DM NEg/lb NEg(Mcal)
Corn silage 6 ..47 2.82Corn 5.95 .70 4.17SBM 1.35 .63 .85
Total 13.3 7.84
Ration NEg (DM Basis) = 7.84Mcal/13.3 lb DM = .59 Mcal/lb
X =
Using Net Energy for Gain Projection
Step 4. Determine Lb of DM for maintenance
1. NEm requirement 500 lb. steer = 4.5 Mcal4.5 Mcal * environmental adjustment (1.3) =
5.85 Mcal required / .89 Mcal NEm per lb of DM =
6.6 lb. of feed dry matter needed for maintenance
Environmental adjustment (maintenance ratio) for calf fed inopen lot conditions in November in Iowa.
Using Net Energy for Gain Projection
Step 5. Determine energy available for gain
1. 13.3 lb DM intake - 6.6 lb (needed for maintenance) =6.7 lb. of feed DM available for gain.
2. 6.7 lbs of DM X .59 Mcal/lb (NEg) = 3.95 Mcal available for gain.
Using Net Energy for Gain Projection
• Step 6 - Determine weight gain– 227 kg steer (low choice at 500 kg)– EQSBW = 227 * (478/500) = 217 kg– SWG = 13.91 * 3.95 0.9116 * 217 -.6837 = 1.23 kg/d– ADG = 1.23*2.205 = 2.71 lb/day
Energy Calculations for Dairy Cattle
•NEm = .08 LW.75 - increased for activity
•Growing bulls & heifers have 12% higher req than beef
•NEm = .086 LW.75
•or use beef equations and increase Maint 7-10%
•NEl~NEm because of similar efficiency
•Lactation requirement (Mcal/kg) milk
•= .0969(percent fat in milk)+.36•Feed Energy Values discounted for level of feeding
•For a comparison of Dairy Energy Systems see:
J Dairy Sci 81:830, 840, 846 (1998) Energy Symposium
Dairy NRC Feed Energy Discounts
00.5
11.5
22.5
33.5
44.5
60 65 70 75 80
Maintenance TDN
Uni
t d
eclin
e p
er m
ulti
ple
of
Mai
nt
= .18 X -10.3
Energy calculations for Sheep
•Maintenance requirement is lower than beef
•.056 W.75
•Wool has great insulative value
•Fetal number is important (Nep, Mcal/day)
Stage of gestation (days)#fetuses 100 120 1401 .070 .145 .2602 .125 .265 .4403 .170 .345 .570
1996/2001 Beef NRC Model Objectives:• Predict net energy requirements across a continuum of
cattle types
• Adjust requirements for physiological state
• Adjust requirements for environmental conditions
• Predict variable lactation requirements
• Predict energy reserves fluxes
• Describe feeds by fermentation characteristics
• Describe rumen and animal tissue N requirements
• Compute variable ME and MP from feed analysis
• Two levels of solution
Maintenance Requirements
Factors affecting Maintenance
• Weight
• Physiological State
• Acclimatization
• Sex
• Breed
• Activity
• Heat or Cold stress– External Insulation
• Coat Condition
• Wind speed
• Hide Thickness
– Internal Insulation
• Condition Score
• Age
Base NEm Requirement
• 77 kcal / (BWkg)0.75
• Adjusted for:– Acclimatization– Sex– Breed– Physiological state
• Lactation
• Condition Score
Effect of Condition Score on Maintenance Requirement
80%
85%
90%
95%
100%
105%
110%
115%
120%
1 2 3 4 5 6 7 8 9
Condition Score (1-9 scale)
Mai
nte
nan
ce M
ult
ipli
er
Energy Requirements vs. Body Weight
0.00
2.00
4.00
6.00
8.00
10.00
12.00
0 200 400 600 800
Body Weight
NE
m R
equ
ired
, Mca
l/d
Energy Requirements vs. Previous Temp.
50
60
70
80
90
100
110
-20 -10 0 10 20 30 40
Previous Temperature, OC
NE
m R
equ
ired
, M
cal/
BW
0.75
Effect of Breed on Energy Requirements
90%100%
120%
0%
20%
40%
60%
80%
100%
120%
Bosindicus
Bos taurus Dairybreeds
Rel
ativ
e N
Em
Req
uir
ed
Effect of Lactation on Energy Requirements
100%
120%
0%
20%
40%
60%
80%
100%
120%
Non-lactating
Lactating
Rel
ativ
e N
Em
Req
uir
ed,
% o
f B
asal
Maintenance Adjustment for Grazing(based on a 600 kg cow)
100%
110%
120%
130%
140%
150%
160%
0.25 0.75 1.25 1.75
Forage Availability (T/ha)
Mai
nen
ance
Ad
just
men
t
Level
Hilly
Estimation of Heat Production and Calculation of Lower Critical Temp (LCT)
• Calculate Feed for Maintenance (FFM)– NEm Req./ NEm Diet = FFM
• Calculate Feed for Production (FFP)– DMI - FFM = FFP
• Calculate Net Energy of Production (NEP Tot)
– NEP Diet x FFP = NEP Tot
– For growing & finishing; NEP Diet = NEg Diet
– For other animals; NEP Diet = NEm Diet
• Calculate Heat Production (HP)– MEIntake - NEP Tot = HP, Mcal
Body Surface Area vs. Body Weight
0.00
1.00
2.00
3.00
4.00
5.00
6.00
7.00
8.00
0 200 400 600 800
Body Weight
Su
rfac
e A
rea,
M2
Effect of Condition Score on Internal Insulation
0
2
4
6
8
10
12
14
1 2 3 4 5 6 7 8 9
Condition Score (1-9 scale)
Inte
rnal
Insu
lati
on
,
Mca
l/M2 /O
C/d
<30
30-183
184-364
>365
Age, d
Effect of Wind Speed and Coat Condition on External Insulation
0
5
10
15
20
25
0 5 10 15 20 25 30
Wind Speed, kph
Ext
ern
al In
sula
tio
n,
Mca
l/M2 /O
C/d
Clean & Dry some mud on lower body
mud on lower body and sides heavily covered with mud
Effect of Wind Speed and Hide Thickness on External Insulation
0
5
10
15
20
25
30
35
0 5 10 15 20 25 30
Wind Speed, kph
Ext
ern
al In
sula
tio
n,
Mca
l/M2 /O
C/d
Thin Hide Medium Hide Thick Hide
Effect of Wind Speed and Hair Depth on External Insulation
05
101520253035404550
0 5 10 15 20 25 30
Wind Speed, kph
Ext
ern
al In
sula
tio
n,
Mca
l/M2 /O
C/d
1 cm 2 cm 3 cm
Estimation of Heat Production and Calculation of Lower Critical Temp (LCT)
Calculate Heat Loss (HL)– HL = HP / SA, Mcal/M2
Calculate Total Insulation (TI)– TI = EI + II, Mcal/M2/OC/d
Calculate Lower Critical Temp (LCT)– LCT = 39 - (HL x TI), OC
Calculate Heat Production– MEIntake - NEP Tot = Heat Production
Energy Requirements vs. Current Temp.
0
1
2
3
4
5
6
7
-30 -20 -10 0 10 20 30 40
Current Temperature, OC
Ad
dit
ion
al M
E
Req
uir
ed,
Mca
l/d
LCT = 5
LCT = -5
Assumed SA = 6 M2
and TI = 28 Mcal/M2/OC/d
Environmental Effects on Maintenance RequirementsBeef Cow Wintering Ration (hay @ .90 mcal ME/lb DM)
Hair Coat Code at30oF
Hair Coat Code at10oF
1 3 1 3
HideCode
Wind @ 1 mph
1 1.19 1.19 1.29 1.682 1.19 1.19 1.29 1.553 1.19 1.19 1.29 1.45
Wind @ 10 mph
1 1.22 1.48 1.60 1.942 1.19 1.41 1.47 1.843 1.19 1.34 1.36 1.75
Environmental Effects on Maintenance RequirementsTypical Calf Wintering Ration ( .35 mcal NEg/lb DM)
Hair Coat Code at30oF
Hair Coat Code at10oF
1 3 1 3
HideCode
Wind @ 1 mph
1 1.19 1.47 1.50 2.932 1.19 1.37 1.36 1.803 1.19 1.28 1.29 1.69
Wind @ 10 mph
1 1.41 1.69 1.85 2.202 1.30 1.61 1.71 2.103 1.21 1.54 1.60 2.01
Environmental Effects on Maintenance RequirementsTypical Finishing Ration ( .62 mcal NEg/lb DM)
Hair Coat Code at30oF
Hair Coat Code at10oF
1 3 1 3
HideCode
Wind @ 1 mph
1 1.19 1.19 1.33 1.762 1.19 1.19 1.29 1.633 1.19 1.19 1.29 1.51
Wind @ 10 mph
1 1.24 1.52 1.67 2.032 1.19 1.44 1.54 1.933 1.19 1.36 1.42 1.83
Growth Requirements
Factors we must account for to predict NEg required in North America
• Genotype - over 80 types have been identified• Sex
– Feedlot steers, heifers & bulls
– Replacement heifers
– Bulls
– Cows
• Implant combinations• Feeding systems
Relationship between Body Fat & Grade
Marbling % Body USDA CanadianScore Fat Grade Grade
Trace 25.2% Standard A1Slight 26.8% Select A2Small 27.8% Choice A3
NEg Required for Growth
0
1
2
3
4
5
6
7
8
200 250 300 350 400 450 500
Shrunk Body Weight, kg
NE
g M
cal/
d
0.6 kg/d
1.0 kg/d
1.3 kg/d
% Protein in Gain vs. Rate of Gain
0
5
10
15
20
25
200 250 300 350 400 450 500
Shrunk Body Weight, kg
% P
rote
in i
n G
ain
0.6 kg/d
1.0 kg/d
1.3 kg/d
% Fat in Gain vs. Rate of Gain
0
10
20
30
40
50
60
70
80
90
200 250 300 350 400 450 500
Shrunk Body Weight, kg
% F
at i
n G
ain
0.6 kg/d
1.0 kg/d
1.3 kg/d
Shrunk Body Fat
10
12
14
16
18
20
22
24
26
28
30
200 250 300 350 400 450 500
Shrunk Body Weight, kg
% S
hru
nk
Bo
dy
Fat
Body Fat vs. Shrunk Body Weight
10
12
14
16
18
20
22
24
26
28
30
200 250 300 350 400 450 500
Shrunk Body Weight
% B
od
y F
at
Traces
SmallSlight
Birth to Maturity - Protein Composition
0
2
4
6
8
10
12
14
16
18
20
0 200 400 600 800 1000
Shrunk Body Weight, kg
% P
rote
in i
n G
ain
0
20
40
60
80
100
120
Em
pty
Bo
dy
Pro
tein
, kg
%PIG
EBP,kg
Birth to Maturity - Fat Composition
0
10
20
30
40
50
60
70
80
90
100
0 200 400 600 800 1000
Shrunk Body Weight, kg
% F
at i
n G
ain
0
100
200
300
400
500
600
700
Em
pty
Bo
dy
Fat
, kg
%FIG
EBF,kg
5%
15%
25%
100 300 500 700 900
Empty body weight, kg
Em
pty
bo
dy
fat,
%
1 = Angus heifer2 = Holstein heifer3 = Angus steers4 = Holstein steers5 = Angus bulls6 = Holstein bulls
1 2 3 4 5 6
Non-implanted cattle of Fortin et. al., 1980 Non-implanted cattle of Fortin et. al., 1980 (50 heifers, 37 steers and 54 bulls)(50 heifers, 37 steers and 54 bulls)
Calculation of Equivalent Weight
Actual BW x (SRW / FW) = EQSW
Calculation of Retained Energy
RE = 0.0635 x EBW0.75 x EBG1.097
RE = 0.0635 x EQEBW0.75 x EBG1.097
Calculation of Daily Gain
SWG = 13.91 x RE0.9116 x SBW-0.6837
SWG = 13.91 x RE0.9116 x EQSBW-0.6837