electrophile (lewis acid) nucleophile (lewis base) free …psbeauchamp/pdf/315_arrow_pushing… ·...
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
Electrophile (Lewis Acid) = electron loving = any general electron pair acceptor (can also be an acidic proton = Bronsted acid)
Nucleophile (Lewis Base) = nucleus/positive loving = any general electron pair donor (can also be donated to an acidic proton = Bronsted base) Free Radicals = one electron transfers, only limited examples are emphasized in our course (free radical substitution at sp3 C-H, anti-Markovnikov free radical addition reactions to pi bonds and some reactions with metals),
Problems - Supply the lone pairs, formal charge and the curved arrows to show how the electrons move for each step of a reaction mechanism. Be able to identify nucleophiles and electrophiles in each step of the reactions below. Our two free radical mechanisms (substitution at sp3 C-H and anti-Markovnikov addition to pi bonds) are at the end. Check your mechanisms against the examples provided.
SN2 and E2 Mechanisms (strong base/nucleophile competition reacting at a carbon or reacting at a proton)
1. Hydroxide (available as NaOH, KOH or LiOH)
CC
BrNa
H3C H
S
OHH
H CH3
Problem
H2CC
BrNa
H3C H
H3C
OC
CH2
H3C H
CH3
SR
OH
H
CC
BrNa
H3C H
S
OH H
H CH3
CC
H
H3C
CH3
H
CC
H3C
H
CH3
H CC
H
CH2
H
H
H3C
methyl RBr = only SN2primary RBr = SN2 > E2secondary RBr = E2 > SN2tertiary RBr = only E2
E2
SN2alcohols
2. Alkoxide (make with ROH + NaH or make ROH + Na )
CC
Br Na
H3C H
S
OH3CH
H CH3
Problem
H2CC
BrNa
H3C H
H3C
OC
CH2
H3C H
CH3
SR
OH3C
H3C
CC
BrNa
H3C H
S
OH3C H
H CH3
CC
H
H3C
CH3
H
CC
H3C
H
CH3
H CC
H
CH2
H
H
H3C
methyl RBr = only SN2primary RBr = SN2 > E2secondary RBr = E2 > SN2tertiary RBr = only E2SN2
E2
ethers
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3. Carboxylates (make with RCO2H + NaOH)
4. Potassium t-butoxide (make with (CH3)3COH + KH)
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5. Sodium azide (available as NaN3)
Problem
H2CC
BrNa
H3C H
H3C
NC
CH2
H3C H
CH3
S RN
Follow up reaction = SN2 reaction at nitrogen, followed by workup (protonates nitrogen)
NN
N N
methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2
NR
NN
Al H
H
H
HLi
NR
NNH
LiO H
H
H
2. workup
NR
H
H
azido compounds
Na
NN
NH2C
CBr
H3C H
H3C
1o amines
Can also usethe Gabrielamine synthesis(next).
2. LiAlH4
3. workup
SN2
SN2
resonance
1.
azido compounds 1o amines
6. Phthalimidate (make from phthalimide + NaOH or KOH), Also called the Gabriel amine synthesis.
Problem
Na
H2CC
Br
H3C H
H3C
H2CC
Br
Na
H3C H
H3C
CCH2
H3C H
CH3SR
methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2
N
O
O
N
O
O
Follow up reaction = acyl substitution (twice) to make primary amines
alkyl imide
Na
O H N
O
R
O O
N
O
R
O
OH
N
O
R
O
O
H
OH
N
O
R
O
O
H
O
H
N R
O
OH
O
OH
O
O
O
ON R
H
H
primary amine(also made by1. NaN3
2. LiAlH4
3. workup)
throw away
N
O
O
R
Hacylsubstitution
(twice)
alkyl imide
SN2
N
O
O
acidbase
acidbase
acylsubstitution
T.I.
T.I.
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7. Sodium hydrogensulfide (available as NaSH)
ProblemH2C
CBr
H3C H
H3C
Na
SH
H2CC
BrNa
H3C H
H3C
SC
CH2
H3C H
CH3
SR
SH
H
methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2
SN2thiol
8. Sodium alkylsulfide (make from RSH + NaOH)
ProblemH2C
CBr
H3C H
H3C
Na
SH3C
9. Cyanide (available as NaCN)
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10. Terminal acetylides (make from terminal alkynes, RCCH + NaNR2)
zipper reaction – moves an internal triple bond (CC) to the end position in unbranched chains where the negative charge is the most stable (in sp orbital).
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11. Enolates (make from carbonyl compounds or nitriles + LDA, -78oC to prevent side reactions)
ProblemH2C
CBr
H3C H
H3C
H2CC
O
H3C
H2CC
Br
H3C H
H3C
S
CCH2
H3C H
CH3H2C
C
O
H3C methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2
H2CC
O
O
H2CC
Br
H3C H
H3C
S
CCH2
H3C H
CH3H2C
C
O
OR R
H2CC
H2CC
Br
H3C H
H3C
S
CCH2
H3C H
CH3H2CN
CN
ketone enolate
ester enolate
nitrile enolate
Li
Li
Li
H2CC
O
H3C
Li
There are many variations ofthis reaction on the enolatecomponent and on theelectrophilic component.
SN2
SN2
SN2
-78oC
-78oC
-78oC
-78oC
S
R
R
R
12. Dithiane anion (made from dithiane + n-butyl lithium)
Problem H2CC
Br
H3C H
H3C
Li
H2CC
Br
Li
H3C H
H3C
CCH2
H3C H
CH3S
R
methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2
C
S
S
Follow up reaction = hydrolysis to carbonyl compound to make aldehydes or ketones.
R
O
H
aldehydeor
ketone
SC
S
H R
3. workup
Hg+2S
CS
H R
Hg SC
H R
S
HgO
H H
SC
R
S
Hg
OH
H
HH2O
SC
R
S
Hg
OH
H
SHg
S
CH
OR
H
SHg
S
CH
O
HO
H H
H2O
S
C
S
H
S
C
S
HH
hydrolysis
discard
RThink of Hg+2
as a giant proton
for sulfur.
SN2
Can repeatone moretime.
resonance
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13. Cuprates (made from RBr/Li RLi + CuBr R2Cu-- + R’Br R-R’)
ProblemH2C
CBr
H3C H
H3C
Li
H2CC
BrLi
H3C H
H3C
CCH2
H3C H
CH3
S R methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2Cu
R
R
R
CuR
R
SN2(for us)
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SN1 / E1 possibilities –extra complications at Cβ positions of 2o RX, rearrangement to more stable 3o R+ considered
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E1 product from left C carbon atom (without rearrangement)
HC
CC
H2C
CH3
H H
H
CH3
Br
H
HC
CC
H2C
CH3
H H CH3H
H
Redrawn
(3S)
(achiral)
CCH
C
H
HH
H2O
CCH
CH
HH
H2O
same first stepfor SN1/E1
add nuclephile (top/bottom) = SN1
lose -H (top/bottom) = E1
"H" parallel toempty 2p orbitalon top
"H" parallel toempty 2p orbitalon bottom
C C
H H
H C
H2C
CH3
H2O
CH3CH
C
H
CH2H3C
CH3
CH3CH
C
"H" parallel toempty 2p orbitalon top
"H" parallel toempty 2p orbitalon bottom
3Z-alkene
3E-alkene
OH2
H
CH3
OH2
C
C CH2
H3C
H3C
H
CH3
C
C CH3
H3C
H2C
H
CH3
OH2
CH3CH
C
OH2
H2O
a
b
SN1 product (a. add from top and b. add from bottom), (without rearrangement), usually SN1 > E1 (in our course)
CH3C
C
H
O
HH
H2C
CH3
CH3C
H
C
O
HH
a
b
OH2
OH2
CH3C
C
H
O
H
H2C
CH3
CH3C
H
C
O
H (2S,3S)
diastereomers
acid/baseproton transfer
acid/baseproton transfer
E1 product from right C carbon atom (without rearrangement)
H2C
H3C
(2R,3S)
(2R,3S)
H2C
CH3
CH3H CH3H
H2C
CH3
CH3H
H2C
CH3
H CH3 CH3H2C
CH3
CH3H
H H
H
H2C
CH3
CH3
CH3
(3S)
(3S)
(3S)
(3S)
(3S)
diastereomers
same alkene
3R stereochemistry is lost
(2R,3S)
(2S,3S)
rearrangement to similar or
more stable carbocation (R+)
(start all over)carbocation
choices
rotate bond
rotate bond
rotate bond
(rearrangement on next page)
E1
E1
E1
E1
SN1
Both chiralcenters aredestroyed.
(3S)
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After rearrangement to 3o carbocation (R+)
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1. Water as a weak nucleophile/base with R-Br (or RX), makes alcohols by SN1 (No reaction at methyl and 1o RBr)
Br H
HO
H
HH
HH rearrangement
H2O
OH2
a = back
b = frontc
H O
O HH
H
H H
SN1
SN1
E1
H
H
OH2
OH2
H2O
OH H
OH2
OH
SN1E1
H O H
O H
H
2S
2R
2S
H
de
f
a
b
c = f
a
b
c
c' = not shownd
d
ef = c
Problem
Br H
HO
H2S
(2o to 3o)
achiral (top attack = bottom attack)
2. Alcohols as weak nucleophile/bases, makes ethers with R-Br (or RX) by SN1 (No reaction at methyl and 1o RBr)
Problem
Br H
HO
CH32S
Br H
HO
CH3
HH
HH
rearrangement
a
b
c
H O
O HH3C
H
SN1
SN1
E1
CH3
H
OH3C H
OH3C
SN1E1
H O CH3
O H
CH3
2S
2R
2S
achiral
HO
CH3HO
H3C
HO
CH3
HO
CH3
HO
H3C
HO
CH3
H H
H
de
f
a
b
c = f
c = f e
d
c' = not shownc
b
a
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3. Carboxylic acids as weak nucleophile/bases, makes esters with R-Br (or RX) by SN1
Alcohol reactions in strong acid (HCl, HBr, HI, H2SO4, TsOH are available): (HBr = SN2 and SN1), (H2SO4/ = E1) in our course. 1. Methyl and primary alcohols + HBr SN2 reactions (no rearrangement)
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2. Secondary and tertiary alcohols + HBr SN1 reactions (possible rearrangement)
3. Methyl and primary alcohols + PCl3 or PBr3 SN2 reactions (no rearrangement) (PX3 Lewis acids are available)
4. Secondary and tertiary alcohols + PCl3 or PBr3 SN1 reactions (possible rearrangement)
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5. Methyl and primary alcohols + SOCl2 or SOBr2 SN2 reactions (no rearrangement) (SOX2 Lewis acids are available)
6. Secondary and tertiary alcohols + SOCl2 or SOBr2 SN1 reactions (possible rearrangement)
Problem
OH O
S
O Br
Br
OS
O
H
O
SBr
O
H
SN1 at secondary and tertiary alcohols
synthesis of an alkyl chloride from an alcohol + thionyl chloride (SOCl2) [can also make RBr from SOBr2]
O
SBr
O
H
BrH
RR
R
RR
acyl-like substitution
SBr
O
Br
Br
Br
OH
RS
Br
O
Br
BrBrtop/bottom attack
S
7. How to avoid rearrangement at secondary ROH RBr (two steps, a. TsCl/pyridine b. NaBr = SN2)
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8. Alcohols + H2SO4/ = E1 (alkene products, possible rearrangements)
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9. Alcohols + CrO3/C5H6N (PCC) (oxidizes primary ROH to aldehyde and secondary ROH to ketone)
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10. Alcohols + CrO3/H2O (Jones) (oxidizes primary ROH to carboxylic acid and secondary ROH to ketone)
ProblemH3C
CH2
CH
OH
H
Cr
O
OO
H3CCH2
CCH3
OH
H
Cr
O
OO
HO
H HO
H
H3CCH2
CH
OH
H
H3CCH2
CH
O
Jones = CrO3 / H2O / acidprimary alcohols oxidize to carboxylic acids(acidic water hydrates the carbonyl group,
which oxidizes a second time )
primary alcohols
aldehydes (continue in water)
HO
HH
OH
H
H3CCH2
CH
OH
H3CCH2
CH
OH
HO
H
H3CCH2
C
OH
O
H
H
H
HO
HH3C
CH2
C
O
O
H H
H
HO
H
HO
H
H3CCH2
C
O
OH
hydration ofthe aldehyde
second oxidation of the carbonyl hydrate
H
O
H
resonance
carboxylic acids
Cr
O
OOH3C
CH2
CH
OH
H
Cr
O
O
O
H3CCH2
CH
O
H
Cr
O
O
O
Cr
O
O
O
HO
H
H
HO
H
H
Cr
O
OO H3CCH2
CO
O
H
Cr
O
O
O
H
H
H3CCH2
CO
O
H
Cr
O
O
O
H
HO
H
H
Cr
O
O
O
HO
H
H
E2
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11. THP protection of alcohols, ROH + DHP (TsOH cat.) THP ether, which can be deprotected with H2SO4/H2O
Problem
O
OOTsH
O
DHP = dihydropyran
resonance
OO O
HO
RH
O O
THP = tetrahydropyranprotected alcohol
OTHP
=
THP ethers do not react under strongbase/nucleophiles and neutral conditions(protected). They are hydrolyzed backto the alcohol under acid conditions
(deprotected).
a. protection conditions - alkene addition reaction
O
O
OTsH
THP protected alcohol
H3OH2O
regenerated alcohol
b. deprotection conditions - aqueous acid conditions hydrolyzes acetal back to alcohol
O O
OHH
H
OHH
O O
H
OO
OHH
etc.
H
desired alcohol
THP = tetrahydropyranprotected alcohol
H
H
O
H
OH
discard
Epoxides in Strong Base/Nucleophile mixtures: backside attack at least hindered carbon. 1. Hydroxide
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2. Alkoxides
3. Organometallics (Li and Mg)
4. Terminal acetylides
Problem SH2C
C
O
CH3H
Na
CCRS
H2CC
O
CH3H R
CC
H2C
CO
H3C H
S OH2H
RC
C
H2C
CO
H3C H
H
Na
CCR 2. workup
chiral centerdid not invert
S
5. Cyanide
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6. Lithium aluminum hydride and sodium borohydride (or deuterides)
7. Dithiane anion
8. Enolates
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9. Reactions with LDA (lithium diisopropylamide = strong, bulky base removes a proton, made from diisopropylamine + n-butyl lithium)
Epoxides in Strong Acid/Electrophile mixtures 1. Aqueous acid
2. Alcohol + TsOH
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Carbonyl Groups in Strong Base/Nucleophile mixtures Aldehydes 1. Hydroxide – hydration
Problem
HC
CH3
O
OC
O
CH3
HO
H
HO
C
O
CH3
H
H
attack from both faces R and S
OH
Na
H H
Na
equilibriumfavors C=O equilibrium
favors C=O
carbonylhydrate
HC
CH3
O
OH
Na
H2O
2. Alkoxide – hemi-acetal formation
Problem
HC
CH3
O
OH3C
Na
CH3OH
HC
CH3
O
OC
O
CH3
HO
H
CH3 OC
O
CH3
H
H
attack from both faces R and S
OH3C
Na
H3C H3C
Na
equilibriumfavors C=O equilibrium
favors C=O
hemi-acetal
3. Organometallics (Li and Mg reagents)
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4. Terminal acetylides
5. Cyanide
Problem
HC
CH3
ONa
HC
CH3
O
Na
CNC
N
C
O
CH3
HO
H
H H
CN
C
O
CH3
H
H
attack from both faces R and S
CN 2. workup
6. Lithium aluminum hydride or sodium borohydride (or deuteride)
7. Enolates (with various electrophiles)
Problem
Li
N
HC
CH2
O
H
2.
2.
2.
3. workup
Br
O
H
O
3. workup
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8. Dithiane anion - reacts with various electrophiles, can react once (make aldehydes) or twice (make ketones)
Problem
Li
S
C
S
H
2.
2.
2.
Br
O
H
O
3. HgCl2/H2O
3. HgCl2/H2O
3. HgCl2/H2O
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9. Sulfur ylid (make from a. diphenylsulfide + RBr (SN2) b. sulfur salt + n-butyl lithium c. carbonyl compound)
ProblemH
CCH3
O
PhS
C
Ph
PhS H2C
Ph
Br
PhS
HC
PhBr
CH3CH3
H CH2
Li CH3
H
HC
CH3
O
PhS H
C
Ph
CHO
PhS
Ph
O
CH3
CH3
trans is preferred
PhS
Ph
H2CBr
CH3n-butyl lithium
1 2
3
3
2
1
SN2
sulfur salt
sulfur ylid
10. Phosphorous ylid (Wittig reaction = make from a. triphenylphosphine + RBr (SN2) b. phosphorous salt + n-butyl
lithium c. carbonyl compound)
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11. Wittig reaction that makes alkynes from aldehydes. (J.O.C., 1982, 47, 1837-1845)
Problem HC
R
O
Br
CH2
Li
n-butyl lithium
1
2
1
(H3CO)P
O(H3CO)
phosphorous salt
CN
N
H H
O
H R(H3CO)
P
O(H3CO)
CN
N
H
(H3CO)P
O(H3CO)
CN
N
C
O
H
R
H
N
C
P(H3CO)
(H3CO) O
CH
O
HR
N
C C
N R
HH
N
P(H3CO)
(H3CO) O
O
C RCH
terminal alkyne
(H3CO)P
O(H3CO)
CN
N
H H terminal alkyne
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Ketones (and carbon dioxide) 1. Hydroxide – hydration
2. Hydroxide with carbon dioxide makes bicarbonate makes carbonic acid (an inorganic example)
OC
OProblem
OC
O
O
H
H
attack from both faces
OH
Na Na
equilibriumfavors C=O equilibrium
favors C=O
OH
Na
H2O acidify
OC
O
OH
bicarbonate
H
OC
O
OH
H
carbonic acid 3. Alkoxide – makes hemi-ketal
Problem
H3CC
CH2
O
OC
O
CH2
O
H
HO
C
O
CH2
H
attack from both faces R and S
OH3C
Na
H3C H3C
Na
equilibriumfavors C=O equilibrium
favors C=O
hemi-ketal
H3CC
CH2
O
OH3C
Na
H2OCH3
CH3CH3
CH3
CH3
CH3
4. Organometallics (Li and Mg reagents)
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5. Organometallics (Li and Mg reagents) + CO2 (special carbonyl) 2. workup
6. Terminal acetylides
7. Cyanide
8. Lithium aluminum hydride (more reactive) or sodium borohydride (less reactive) (…or deuterides)
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9. Enolates - many variations
Problem
Li
N
CH3
CCH2
O
H
2.
2.
2.
3. workup
Br
O
H
O
3. workup-78oC
2. workup
H3CC
CH2
O
H N
Li
H3CC
CH2
O
resonance
Br
O
CH
O
CH3
H3CC
CH2
O
H2C
CH3
2.
2.
H3CC
CH2
O
H3CC
CH2
O
H2C
CH2
O
3. workup
OH2H
H3CC
CH2
OH2C
CH2
OH
H3CC
CH2
O
H3CC
CH2
O
CHCH3
O
3. workup
OH2H
H3CC
CH2
O
CHCH3
OH
-78oC
10. Dithiane anion – many variations
Problem
Li
S
C
S
H
2.
2.
2.
Br
O
CH3C
O
CH3
3. HgCl2/H2O
3. HgCl2/H2O
3. HgCl2/H2O
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11. Sulfur ylid (make from a. diphenylsulfide + RBr (SN2) b. sulfur salt + n-butyl lithium c. carbonyl compound)
12. Phosphorous ylid (Wittig reaction = make from a. triphenylphosphine + RBr (SN2) b. phosphorous salt + n-butyl
lithium c. carbonyl compound)
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Esters (and carbonates) 1. Hydroxide (hydrolysis is also called saponification = soap making)
Problem
ester
R'
O
OR R'
O
O
O
tetrahedral intermediate = (T.I.)
R
H
OH
RO
R'
O
elimination
overall = acyl substitution
OH
addition
ester
R'
O
OR
OH
RO
R'
O
O
H
2. Alkoxide (Transesterification)
Problem
ester
R'
O
OR R'
O
O
O
tetrahedral intermediate = (T.I.)
R
H3C
the nucleophileattacks theelectrophileO
H3CR
O
R'
O
elimination
overall = acyl substitution
OH3C
addition
ester
R'
O
OR
OH3C
3. Organometallics (Li and Mg reagents)
ester
R
O
O R
O
O
tetrahedral intermediate(T.I.)
the nucleophile attacks the electrophile
CH2
H3C O
ketone is more reactivethan the ester
ethoxidesimilar energy
to T.I. intermediate
R
Oreaction
option notpossible toaldehydes
and ketones
elimination
overall = acyl substitution
CH2
H3C
R
O
H2O H
2. workup
R
OH
3o alcohol with two identical groups at alcohol carbon.
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4. Lithium aluminum hydride or sodium borohydride (or deuteride)
Problem
esterR'
O
OR
ester
R
O
O R
O
O
Dtetrahedral intermediate
(T.I.)
O
aldehyde is more reactivethan the ester
R
O
Delimination
overall = acyl substitution
R
O
DD
H2O H
2. workup
R
O
DD
H1o alcohol with two identical groups at alcohol carbon.
Al DD
D
D
Li
addition
Al DD
D
DLi
2. workup
LiAlD4
5. Diisobutylaluminium hydride (DIBAH)
6. Amines
7. Lithium diisopropylamide (LDA), run at -78oC
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8. Cuprate reactions – three variations for us that complement the lithium and magnesium organometallics
34
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Carbonyls (aldehydes, ketones, esters, amides, nitriles) in Strong Acid/Electrophile mixtures 1. Aqueous acid makes carbonyl hydrates
Problem
CH3
C
O
H3C
C
O
H3C CH3
C
O
C
O
H3C CH3
O
HOH H
C
O
H3C CH3
H H
H3C CH3H
OH
H H
HO
H
C
O
H3C CH3
O
H
H
O H H3O
H
H2SO4H2O
H
2. Carbonyl (aldehyde or ketone) + ROH + TsOH (-H2O) makes hemi-acetals and acetals and hemi-ketals and ketals
Problem
HC
O
H3C
C
O
R HC
O
C
O
R H
O
H
C
O
R H
H H
R HH3C
OH
H3C H
HO
H
C
O
R H
O
H
H3C
hemi-acetal
resonance
OH TsO HTs
C
O
R H
O
H
H3C
H
C
OH3C
HR
resonance
C
OH3C
HR
H3CO
H
C
O
R H
O
H
H3C
H3CCH3
O
HC
O
R H
OH3C
H3C
acetal
remove H2O
TsOHCH3OH
(-H2O)hemi-acetal
TsOHCH3OH acetal
OH TsCH2
OH
several steps
CH3C H
O
hemi-acetal
acetal favored by removal of water
several stepscarbonyl favored by
addition of water
H2C
OH
CH3C H
OOC
H3C H
OOH
O
H
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HOOH
OTsH
OTs
OH
O
OH
TsO H
OH
O
OH
HOH
O
O
H
O OH
O O
H
OHH
OHH
H
H
OH
O
OH
O
O
H
ketone
hemi-ketal
Making a ketal (acetals are similar)
resonance
water controls the direction of equilibrium
OO
HO
H
resonance
ketal
ProblemHO
OH
O OTsH
Problem
OO
Hydrolysis of a ketal back to a ketone and ethylene glycol (acetals are similar and go back to aldehydes and ethylene glycol)
(H2SO4/H2O)
HH
O O
OHH
H OOH
OHH
O
O
H
O
O
H OH
O
OH
H
OHH
OHH
OHH
H
OH
O
OH
OH
O
OH
H
OH
OH
resonance
OHH
OHH
H
O
ketal
ketone
O O H3OH2O
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3. Carbonyl (aldehyde or ketone) + RNH2 + TsOH (-H2O) / pH = 5, makes imines that can be reduced (a. NaH3BCN b. workup) to amines.
Problem
TsOH(-H2O)
N
OTsH
OTs
OH
N
TsO H
OH
N
HOH
N
H
H
OH
N
N
ketone oraldehyde
Making an imine from a ketone or aldehyde and NH3, RNH2 or R2NH. Then making the imine into a 1o, 2o or 3o amine using NaH3BCN and workup.
resonance
water controls the direction of equilibrium
O OH
OH
resonance
imine
HH
HHH
pH 5(-H2O)
NH3, RNH2 or R2NH
RH2N
N
remove to for imine
N
Reduce imine to amine with 1. sodium cyanoborohydride and 2. workup
BH
H
H
C N
NaN
H
Na
2. workup
OH2HN
H
H
TransformationsC=O + NH3 primary aminesC=O + 1o amines secondary aminesC=O + 2o amines tertiary amines
imineamine
O
NH2
1. NaH3BCN2. workup
H
H
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4. Carbonyl (aldehyde or ketone) + R2NH + TsOH (-H2O) / pH = 5, makes enamine that can be alkylated and hydrolyzed back to a ketone
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5. Fischer esterification (RCO2H + R’OH RCO2R’ + H2O using TsOH as acid catalyst)
Problem
(-H2O)
TsOHCH3OH
C
O
R O
C
O
R O
O
H
C
O
R O
H
H3CO
H
H3C H
C
O
R O
O
H
H3C
carboxylic acid
T.I.
resonance
equilibrium is controlled by water, removing water shifts it to the right and adding water shifts it to the left
OH Ts
O HTs
C
O
R O
O
H
H3C
H
= B
= C
H H C
O
R O
H
H
resonance
C
O
R O
H
H
H
O Ts
HH
C
O
R O
H
CH3
resonance
C
O
R O
H
CH3
resonance
C
O
R O
H
CH3
HO
H
O Ts
C
O
R OCH3
ester
water can be distilled out and removedfrom the equilibrium
C
O
R OH H3C
OH
alcohol
6.
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Acid chlorides (and chloroformates, phosgene and equivalents, sulfur, nitrogen and phosphorous)
1. Making an acid chloride (from RCO2H + SOCl2)
2. Alcohols make esters
3. Amines make amides
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4. Organometallics (Li and Mg reagents) make tertiary alcohols
5. Lithium aluminum hydride or sodium borohydride make primary alcohols
6. Diisobutylaluminium hydride (DIBAH) makes ketones
7. Carboxylic acids make anhydrides
8. Water remakes the carboxylic acid (not desired)
9. Aromatics + AlCl3 makes aromatic ketones
10. Cuprates make ketones
Anhydrides (organic and mixed) 1. Hydroxide
2. Alkoxide
3. Organometallics (Li and Mg reagents)
4. Lithium aluminum hydride or sodium borohydride
5. Diisobutylaluminium hydride (DIBAH)
6. Amines
7. Lithium diisopropylamide (LDA)
8.
Acids 1. Hydroxide
2. Alkoxide
3. Organometallics (Li and Mg reagents)
4. Lithium aluminum hydride or sodium borohydride
5. Diisobutylaluminium hydride (DIBAH)
6. Amines
7. Lithium diisopropylamide (LDA)
8.
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Amides (primary, secondary and tertiary) 1. Hydroxide
2. Alkoxide
3. Organometallics (Li and Mg reagents)
4. Lithium aluminum hydride or sodium borohydride
5. Diisobutylaluminium hydride (DIBAH)
6. Amines
7. Lithium diisopropylamide (LDA)
8.
Nitriles 1. Hydroxide
2. Alkoxide
3. Organometallics (Li and Mg reagents)
4. Lithium aluminum hydride or sodium borohydride
5. Diisobutylaluminium hydride (DIBAH)
6. Amines
7. Lithium diisopropylamide (LDA)
8.
Carbonyl Groups in Strong Protic or Lewis Acid Conditions 7. Aldehydes
8. Ketones (and carbon dioxide)
9. Esters (and carbonates)
10. Acid chlorides (and chloroformates, phosgene and equivalents, sulfur, nitrogen and phosphorous)
11. Anhydrides (organic and mixed)
12. Acids
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13. Amides (primary, secondary and tertiary)
14. Nitriles
15.
Miscellaneous (Various name reactions) 1. Baeyer Villigar reaction
2. Iodoform reaction
3. Nitrile synthesis from primary amide and SOCl2
CR
O
NH resonance Base
BaseH
CR NCR N
resonance
H
H HCR N
ClH
synthesis of a nitrile from an 1o amide + thionyl chloride (SOCl2)
resonance
resonanceS
Cl
O
ClC
R
O
NH
S
O Cl
Cl
H
CR
O
NH
S
O Cl
Cl
CR
O
NH
S
O Cl
Cl
HH
CR
O
N
S
O Cl
Cl
HCl
OS
O
Cl
CR
O
N
SCl
O
H
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4. Hydrolysis of nitriles (moderate acid makes 1o amide, strong acid/heat makes carboxylic acids)
H3CC
N
H3CC
N CNH3C
O
HH
CN
H
H3C
OH
CN
H
HH3C
OH
CN
H
HH3C
OH
CN
H
HH3C
O
HO
H
HCl / H2O hydrolysis of a nitrile to an amide (in H2SO4 / H2O / hydrolysis continues on to a carboxylic acid)
H
O
H
H HH3C
CN
H
OH H
H
H
O
H
CN
H
HH3C
OH
O
H
H H
stop here in HCl/H2O(continue on in H2SO4/H2O)
O
H
H HC
N
H
HH3C
OH
see resonance structuresdirectly above
H
O
HC
N
H
HH3C
OH
O H
H H
O
H
CN
H
HH3C
OH
O
HO
H
H H
CN
H
HH3C
OH
O
H
HC N
H
H
H3C
OH
H
H3CC
OH
O
H
H3CC
OH
O
H
N
H
H
H H3CC
OH
ON
H
H
H
H
most stable cation drivesequilibrium to completion
resonance
resonanceresonance
resonance
resonance
hydroxamic acid
1o amides
OH
carboxylic acids (in H2SO4/)
O
H
H H
5. Ritter reaction
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6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.
19. Cuprates DIBAH Nitriles Thionyl chloride
45
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CN
OH
OH3C methyl RBr = only SN2primary RBr = mainly SN2secondary RBr = mainly SN2tertiary RBr = only E2
methyl RBr = only SN2primary RBr = SN2 > E2secondary RBr = E2 > SN2tertiary RBr = only E2
methyl RBr = only SN2primary RBr = SN2 > E2secondary RBr = SN2 > E2tertiary RBr = only E2
methyl RBr = only SN2primary RBr = SN2 > E2secondary RBr = SN2 > E2tertiary RBr = only E2
Li
S
CCR
H3C
H2C CH2
O H
BrH
primary alcoholH3C
H2C CH2
O H
H
Br
H3C
H2C CH2
O
H
H
BrSN2
no rearrangement
BrH
O
H
H H
primary bromoalkane
Br
pKa = -9
water is a good leaving group
H2CC
O
CH3H
SH2C
C
O
CH3H
CH2
H2C
CO
H3C H
S OH2H
CH2
H2C
CO
H3C H
H
RNa
2. workup
OH
S
Al D
D
D
D
Li
S
S
H3CC
CH2
O
H3CC
CH2
O
CH3C
O
C
O
H3C
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IBrIBr CN
I
IC
N
a b
O Br
Br I
IO
c dH H2O
O
O O
H
eO
CH3
Li
O
CH3
Li 2. workup
OH2H
O
CH3
HH2O
Cl
Li
Cl
f
H
O Na
H
O
C
2. workup
OH2H
H2O
Cl
LiCl
C N
N
Na
H
O
C N
H
C CH
2. workup
OH2H
OO O
HH2Og Na Na
h H
CH3
ClH
H
H
CH3Cl
H
H
Cl
CH3
47
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H3CC
CH
OH
H
H H3CC
C
H
H
O
H
H
CC
H
HH3C
O
H
O
H
H
H
CC
H
HH3C
OH
OH
H
HCC
H
HH3C
OH
H
CC
H
HH3C
OH
H
CC
H
HH3C
O
H
OH
H
HH
OH
There isn't any lone pair, so you have to use the pi electrons as the nucleophile.i
BrBrBr
Br
jBra little tricky,
requires 3 arrowsto make bridge
Br
BrBr Br
O
k Bra little tricky,requires 3 arrows
H
O
H HH
H
O
H
Br
OH
OH2HBr
O
O
O
O
HO
H
O
OH
O
H
O
OH
H
O
OOO
HO O
H
O
HHO
HH
H
common name = ________________
Remove H2O shifts equilibrium to the _________________
Adding H2O shifts equilibrium to the _________________
functional group = _____________
H
O
H
O
OH
Hydrolysis of a ketal back to a ketone and ethylene glycol (acetals are similar and go back to aldehydes and ethylene glycol)l
(H2SO4/H2O)
O
O
H
O
HH
O
HH
H
O
HO
HH
O
HHH
H
O
HH
H
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Na
O H
R
C
O
O
H
O
H
R
H
O
H
CR
O
O
R
O
H
R
C
O
O
H
O R
H
O
R
R
C
O
O2. workup(neutralize carboxylate)
R
C
O
O
H
H
ester
alcohol
carboxylic acid
Na Na
NaR
C
O
O
m ester base hydrolysis = saponification
R
C
O
Cl
R
O
H
CR
O
O
R
ClR
C
O
O
R
acid chloride
n ester synthesis from acyl substition at an acid chloride with an alcohol
H
H
Cl
R
C
O
O
R
ClH
R
C
O
Cl
R
N
H
CR
O
N
R
Cl
R
C
O
N
R
acid chloride
o secondary amide synthesis from acyl substition at an acid chloride with a primary amine
H
HCl
R
C
O
N
R
ClH
H H
H H
C
R
O
O
H S
Cl
O
Cl C
R
O
O
H
S
O Cl
Clresonance
C
R
O
O
H
S
O Cl
Cl
C
R
O
O
H
S
O Cl
Cl
Base
C
R
O
O
S
O Cl
Cl
BaseH
C
R
O
O
SCl
O
Cl
OS
Cl
O
CR OCR O
resonance
C
R
Cl
O
p synthesis of an acid chloride from an acid + thionyl chloride (SOCl2)
acylium ion
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H2C
R O
H S
Cl
O
Cl
H2C
R O
S
O Cl
Cl
BaseH
OS
Cl
O
H Base
H2C
R O
S
O Cl
Cl
H2C
R O
SCl
O
Cl
CH2
R
Cl
q synthesis of an alkyl chloride from an alcohol + thionyl chloride (SOCl2) [can also make RBr from SOBr2]
SN2 at methyl and primary alcohols
CH
R O
H S
Cl
O
Cl
CH
R O
S
O Cl
Cl
BaseH
OS
Cl
O
H Base
CH
R O
S
O Cl
Cl
CH
R O
SCl
OCl
C
R
R
RR
R
R
H
C
R
R
H
ClSN1 at secondary and tertiary alcohols
r synthesis of an alkyl chloride from an alcohol + thionyl chloride (SOCl2) [can also make RBr from SOBr2]
C
R
O
N
H S
Cl
O
Cl C
R
O
N
H
S
O Cl
Clresonance
C
R
O
N
H
S
O Cl
Cl
C
R
O
N
H
S
O Cl
Cl
Base
C
R
O
N
S
O Cl
Cl
BaseH
C
R
O
N
SCl
O
Cl
OS
Cl
O
CR NCR N
resonance
HH H H
H
H
H HCR N
ClH
r synthesis of a nitrile from an 1o amide + thionyl chloride (SOCl2)
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There isn't any lone pair, so you have to use the pi electrons as the nucleophile.s
HC
CH2
CH2
H3C C
CH2
CH3
H3C
H
C
CH2
CH3
H3C
H
OH
H
C
CH2
CH3
H3C
H
O
H
O
H
H H
O H
OH H
O
H
H HH
hydration of an alkene with aqueous acidform most stable carbocation
( rearrangements are possible )
There isn't any lone pair, so you have to use the pi electrons as the nucleophile.t
HC
CH CH2
H3C C
C CH3
H3C
H
C
C CH3
H3C
O
H
H H
O HO
H
H H
H
hydration of an alkene with aqueous acidform most stable carbocation
( rearrangements are possible )
CH3 CH3
H
HH
CH3
C
C CH3
H3C
HH
O
HH
H3C
OH
H
C
C CH3
H3C
HH
O
H
H3C
There isn't any lone pair, so you have to use the pi electrons as the nucleophile.s
HC
CH2
CH2
H3C C
CH2
CH3
H3C
H
C
CH2
CH3
H3C
H
OH
CH3
C
CH2
CH3
H3C
H
O
CH3
O
H
H CH3
O CH3
OH CH3
O
H
H CH3H
hydration of an alkene with aqueous acidform most stable carbocation
( rearrangements are possible )
(CH3OH / TsOH)
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There isn't any lone pair, so you have to use the pi electrons as the nucleophile.t
HC
CH CH2
H3C C
C CH3
H3C
H
C
C CH3
H3C
O
H
H3C H
O HO
H
H CH3
H3C
ether synthesis from an alkene with alcoholic acidform most stable carbocation
( rearrangements are possible )
CH3 CH3
H
HH
CH3
C
C CH3
H3C
HH
O
HCH3
H3C
OH3C
H
C
C CH3
H3C
HH
O
CH3
H3C
(CH3OH / TsOH)
O
O
O
O
HO
H
O
OH
O
H
O
OH
H
O
OOO
HO O
H
O
HHO
HH
H
common name = ________________
Remove H2O shifts equilibrium to the _________________
Adding H2O shifts equilibrium to the _________________
functional group = _____________
H
O
H
O
OH
Hydrolysis of a ketal back to a ketone and ethylene glycol (acetals are similar and go back to aldehydes and ethylene glycol)l
(H2SO4/H2O)
O
O
H
O
HH
O
HH
H
O
HO
HH
O
HHH
H
O
HH
H
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H3CC
N
H3CC
N CNH3C
O
HH
CN
H
H3C
OH
OH
H
H
CN
H
HH3C
OH
CN
H
HH3C
OH
CC
H
HH3C
O
H
HO
H
HCl / H2O hydrolysis of a nitrile to an amide (in H2SO4 / H2O hydrolysis continues on to a carboxylic acid)i
H
O
H
H HH3C
CN
H
OH H
H
H
O
H
CN
H
HH3C
OH
O
H
H H
stop here in HCl/H2O(continue on in H2SO4/H2O)
O
H
H HC
N
H
HH3C
OH
see resonance structuresdirectly above
H
O
HC
N
H
HH3C
OH
O H
H H
O
H
CN
H
HH3C
OH
O
HO
H
H H
CN
H
HH3C
OH
O
H
H
C N
H
H
H3C
OH
O
H
H
H3C
C
O
H
O
H
H3C
C
O
H
O
H
N
H
H
H H3C
C
O
H
O N
H
H
H
H
most stable cation drivesequilibrium to completion
53
y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
H3C
CH2
C
H
O
H
H
Cr
O
OO H3C
CH2
C
H
O
H
H
Cr
O
O
O
H3C
CH2
C
H
O
H
Cr
O
O
ON
N H
N
H3C
CH2
C
H
OCr
O
O
O
N H
PCC = pyridinium chlorochromate oxidation of primary alcohol to an aldehyde (no water to hydrate the carbonyl group)
primary alcohols
aldehydes
H3C
CH2
C
CH3
O
H
H
Cr
O
OO H3C
CH2
C
CH3
O
H
H
Cr
O
O
O
H3C
CH2
C
CH3
O
H
Cr
O
O
ON
N H
N
H3C
CH2
C
CH3
OCr
O
O
O
N H
PCC = pyridinium chlorochromate oxidation of secondary alcohol to a ketone
secondary alcohols
ketones
54
y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
H3C
CH2
C
H
O
H
H
Cr
O
OO H3C
CH2
C
H
O
H
H
Cr
O
O
O
H3C
CH2
C
H
O
H
Cr
O
O
O
H3C
CH2
C
H
OCr
O
O
O
Jones = CrO3 / H2O / acid primary alcohols oxidize to carboxylic acids
(water hydrates the carbonyl group, which oxidizes a second time )
primary alcohols
aldehydes
H
O
HH
O
H
H
H
O
H
H
H3C
CH2
C
H
O
H
H3C
CH2
C
H
O
H
H
O
H
H3C
CH2
C
O
H
O
H
H
H
H
O
HH3C
CH2
C
O
O
H H
H
O
H
H
Cr
O
OO
H
H3C
CH2
C
O
O
H H
H Cr
O
O
O
H
O
H
H3C
CH2
C
O
O
H H
Cr
O
O
O
H
O
H
H
H
O
H
H3C
CH2
C
O
OH
H
O
H
H
Cr
O
O
O
hydration of the aldehyde
second oxidation of the carbonyl hydrate
55
y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
Na
CN
H3CCH2
BrC
N
H2C
CH3
H2CC
O
CH3H
HC
CH3
O
Na
CN
Na
CN
CN
H2C
CO
H3C H
CN
C
O
CH3
H
O
H
H H
O
H
H H
CN
H2C
CO
H3C H
CN
C
O
CH3
H
H
H
Na
CHC
H3CCH2
BrC
HC
H2C
CH3
H2CC
O
CH3H
HC
CH3
O
Na
CHC
Na
CHC
CHC
H2C
CO
H3C H
CHC
C
O
CH3
H
O
H
H H
O
H
H H
CHC
H2C
CO
H3C H
CHC
C
O
CH3
H
H
H
CH2
Li
C
Li
H3CCH2
Br
H2CC
O
CH3H
HC
CH3
O
CH2
H2C
CO
H3C H
CC
O
CH3
H
O
H
H H
O
H
H H
too many side reactionspoor yields
H2C
CH2
H3C CH2
H2C
CO
H3C H
H2C
CH2
H3C
H
C
Li
CC
O
CH3
H
H
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
Al
D
DD
D
B
D
DD
D
Na
Li
H3CCH2
BrD
H2C
CH3
H2CC
O
CH3H
HC
CH3
O
D
H2C
CO
H3C H
DC
O
CH3
H
O
H
H H
O
H
H H
D
H2C
CO
H3C H
DC
O
CH3
H
H
H
Al
D
DD
D
Li
H3CCH2
CH
O
Reaction continues with aldehydes, IF in water (= Jones).
O
H
H HH3C
CH2
CH
OH
resonance
OH H
H3CCH2
CH
O
H
O
H HOH2
H3CCH2
CH
O
H
O
H
Cr
O
OO
H3CCH2
CH
O
O
H
H
CrO
O O
H2O
H3CCH2
CH
O
O
H
CrO
O O
OH2
Cr
O
O
O
H3C
H2C
CO
O
H
carbonylhydrate
aldehyde(from 1o alcohol)
carboxylic acids
H3C
CH2
C
H
O
H
H
Cr
O
OO H3C
CH2
C
H
O
H
H
Cr
O
O
O
H3C
CH2
C
H
O
H
Cr
O
O
ON
N H
N
H3C
CH2
C
H
OCr
O
O
O
N H
PCC = pyridinium chlorochromate oxidation of primary alcohol to an aldehyde (no water to hydrate the carbonyl group)
PCC: base = pyridine
Jones: base = water
primary alcohols
aldehydes
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Possible Keys –Check for mistakes. I often make a few with all of the necessary computer clicks.
IBrIBr CN
I
IC
N
a b
HO Br
Br I
I
Oc dH H2O
O
OO
e
O
CH3
Li
O
CH3
Li 2. workup O
CH3
H
Cl
H2O
Li
Cl
OH2H
f
H
O Na
H
O
C
2. workup
OH2H
H2O
ClLiC N
N
Na
H
O
C N
H
Cl
C CH
2. workup
OH2H
O
O OH H2Og
H
CH3
ClH
H
H
CH3
H
H
CH3
ClCl
h
from best R+
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H3CC
CH
OH
H
H H3CC
C
H
H
O
H
H
CC
H
HH
O
H
O
H
H
H
CC
H
HH
OH
OH
H
H
CC
H
HH
OH
H
CC
H
HH
OH
H
CC
H
HH
O
H
OH
H
HH
OH
resonance
There isn't any lone pair, so you have to use the pi electrons as the nucleophile.i
Br
Br
ja little tricky,
requires 3 arrowsto make bridgeBrBr
Br
Br
BrBr Br
O
k Bra little tricky,requires 3 arrows
H
O
H HH
H
O
H
Br
OH
OH2HBr
water is better than bromide
O
HO
OH
OTsHO
H
OTs
O
H
O
OH
TsO H
O
H
O
OH
HO
H
O
O
H
O OH
O O
H
O
HHO
HH
H
common name = ________________
common name = ________________ Remove H2O shifts equilibrium to the _________________
Adding H2O shifts equilibrium to the _________________
functional group = _____________
H
O
H
O
OH
O
H
O
O
H
ketal
ketone
hemi-ketal
right
left
Making a ketal (acetals are similar)l
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
Na
O H
R
C
O
O
H
O
H
R
H
O
H
CR
O
O
R
O
H
R
C
O
O
H
O R
H
O
R
R
C
O
O2. workup(neutralize carboxylate)
R
C
O
O
H
H
ester
alcohol
carboxylic acid
Na Na
NaR
C
O
O
resonance
m ester base hydrolysis = saponification
R
C
O
Cl
R
O
H
CR
O
O
R
ClR
C
O
O
R
acid chloride
n ester synthesis from acyl substition at an acid chloride with an alcohol
H
H
Cl
R
C
O
O
R
ClH
ester
R
N
H
CR
O
N
R
Cl
R
C
O
N
R
acid chloride
o secondary amide synthesis from acyl substition at an acid chloride with a primary amine
H
H
R
C
O
N
R
ClH
H H
H H
Cl
R
C
O
Cl
2o amide
C
R
O
O
H S
Cl
O
Cl C
R
O
O
H
S
O Cl
Clresonance
C
R
O
O
H
S
O Cl
Cl
C
R
O
O
H
S
O Cl
Cl
Base
C
R
O
O
S
O Cl
Cl
BaseH
C
R
O
O
SCl
O
Cl
OS
O
CR OCR O
resonanceC
R
Cl
O
p synthesis of an acid chloride from an acid + thionyl chloride (SOCl2)
acylium ion
Cl
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
Problem - Identify the nucleophile (Lewis base) and the electrophile (Lewis acid) in each equation and show the products of the following reactions. Add the curved arrows to show how each reaction proceeds.
a
b
c
d
CN Br
O I
NH2H3C BrH3C
SH I
e
f
g
OH IH3C
O
O
Br
O
Cl
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
h
OH
H
CH2C
H3C
CH3
Hreact with carbon
i
OH
H CH2C
H3C
CH3
H
react with proton
j
k
l
m
n
OH CH3C
H3C
O
CH2
NH3C H
HH
CH C HCH2H3C
OH CH3CH3C
O
CH2
CH3C CH3
O
OH S
O
O
OH
Problem - Which of the structures below can be a Lewis acid (show an arrow pushing reaction with base B:), a Lewis base (show a reaction with acid HA) or both an acid and a base (show both reactions)?
NH3 H2O CH4 Cl CH3OHO
H C
O
O
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
1. Mechanism for free radical substitution of alkane sp3 C-H bonds to form sp3 C-Br bonds at weakest C-H position
H3C
H2C
CH3 H3CCH
CH3
Br
BrBr
overall reactionh
BrH
1. initiation
BrBrh BrBr H = 46 kcal/mole
weakest bond ruptures first
2b propagation
H3CC
CH3
H
BrBrH3C
CCH3
H Br
BrH = -22 kcal/mole (overall)
BE = +46 kcal/moleBE = -68 kcal/mole
2a propagation
H3CC
CH3
H H
Br BrH
H3CC
CH3
H
H = +7 kcal/mole (overall)
BE = +95 kcal/moleBE = -88 kcal/mole
H = -15
both steps
3. termination = combination of two free radicals - relatively rare because free radicals are at low concentrations
BrH3C
CCH3
H
H3CC
CH3
H Br
H3CC
CH3
H
CH3
CH3C
H
CH
CH3
H3C CHCH3
CH3
H = -68 kcal/mole
H = -80 kcal/mole
very minor product
2. Free radical addition mechanism of H-Br alkene pi bonds (alkenes can be made from E2 or E1 reactions at this point in course) (anti-Markovnikov addition to alkenes)
H3C
H2C
CH2
Br
H3C
HC
CH2
HBrR2O2 (cat.)
h
overall reaction
1. initiation (two steps)
RO
OR h R
OO
R
BrHR
O RO
H Br
H = 40 kcal/mole
H = -23 kcal/mole
BE = +88 kcal/moleBE = -111 kcal/mole
(cat.)
reagent
2a propagation
H3C
HC
CH2Br
H3CC
CH2
Br
H
H = -5 kcal/mole
BE = +63 kcal/mole BE = -68 kcal/mole
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y:\files\classes\315\315 Handouts\arrow pushing mechs & rxn summary.doc
H = -15
both steps(2a + 2b)
2b propagation
H3CC
CH2
Br
H
BrH H3C
H2C
CH2
BrBr
H = -10 kcal/mole
BE = +88 kcal/mole BE = -98 kcal/mole
Na
CN
CH2
Li
CCH
Na
N
H3CCH2
Br
HC
H
O
C
H2CC
O
O
H
H HLi
CH3H
Al
H
HH
H
B
H
HH
H
Na
Li
Cr
O
O
O