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GATE SOLUTION ECE Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED 28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com ELECTRONICS ENGINEERING GATE SOLUTION

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Page 1: ELECTRONICS ENGINEERING - engineersinstitute.com€¦ · For a narrow base PNP BJT, the excess minority carrier concentrations ( nE for emitter, pB for base, nC for collector) normalized

GATE SOLUTION ECE

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

ELECTRONICSENGINEERING

GATE SOLUTION

Page 2: ELECTRONICS ENGINEERING - engineersinstitute.com€¦ · For a narrow base PNP BJT, the excess minority carrier concentrations ( nE for emitter, pB for base, nC for collector) normalized

GATE SOLUTION ECE

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

2017 By Engineers Institute of India

ALL RIGHTS RESERVED. No part of this work covered by the copyright herein may bereproduced, transmitted, stored or used in any form or by any means graphic, electronic, ormechanical & chemical, including but not limited to photocopying, recording, scanning,digitizing, taping, Web distribution, information networks, or information storage andretrieval systems.

Engineers Institute of India

28-B/7, Jia Sarai, Near IIT Hauz Khas New Delhi-110016

Tel: 011-26514888

For publication information, visit www.engineersinstitute.com

ISBN: 978-93-5137-754-2

Price: Rs. 575/-

Page 3: ELECTRONICS ENGINEERING - engineersinstitute.com€¦ · For a narrow base PNP BJT, the excess minority carrier concentrations ( nE for emitter, pB for base, nC for collector) normalized

GATE SOLUTION ECE

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

Contents

1. Network Theory ................................... 01-76

2. Electronic Devices & Circuits ................ 77-134

3. Analog Electronics ................................ 135-238

4. Digital Electronics ................................. 239-305

5. Microprocessor .................................. 306-318

6. Signal System ...................................... 319-387

7. Communication ...................................... 388-477

8. Control System ...................................... 478-582

9. Electromagnetic Theory ....................... 583-665

Page 4: ELECTRONICS ENGINEERING - engineersinstitute.com€¦ · For a narrow base PNP BJT, the excess minority carrier concentrations ( nE for emitter, pB for base, nC for collector) normalized

GATE SOLUTION ECE

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

Page 5: ELECTRONICS ENGINEERING - engineersinstitute.com€¦ · For a narrow base PNP BJT, the excess minority carrier concentrations ( nE for emitter, pB for base, nC for collector) normalized

GATE-2017 SET-1 ELECTRONICS ENGINEERING

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GATE-2017 (set-1)

Section: Electronics and Communication Engineering

1. The open loop transfer function

( 1)( )

( 2)( 3)p

sG s

s s s

where p is an integer, is connected in unit feedback configuration as shown in the figure

Given that the steady state error is zero for unit step input and is 6 for unit ramp input, the valueof the parameter p is ___________Ans: (1)Steady state is zero for step input and finite for ramp input, i.e., it is a type 1 system.

2. The clock frequency of an 8085 microprocessor is 5 MHz. If the time required to execute aninstruction is 1.4 s, then the number of T-states needed for executing the instruction is(a) 1 (b) 6 (c) 7 (d) 8Ans: (c)

Execution time1

clock frequency number of T states

66

11.4 10 7

5 10 statesT

3. A bar of Gallium Arsenide (GaAs) is doped with Silicon such that the Silicon atoms occupyGallium and Arsenic sites in the GaAs crystal. Which one of the following statements is true?(a) Silicon atoms act as p-type dopants in Arsenic sites and n-type dopants in Gallium sites(b) Silicon atoms act as n-type dopants in Arsenic sites and p-type dopants in Gallium sites(c) Silicon atoms act as p-type dopants in Arsenic as Gallium sites(d) Silicon atoms act as n-type dopants in Arsenic as Gallium sitesAns: a

4. For a narrow base PNP BJT, the excess minority carrier concentrations ( En for emitter, Bp

for base, Cn for collector) normalized to equilibrium minority carrier concentrations ( 0En for

emitter, 0Bp for base, nC0 for collector) in the quasi-neutral emitter, base and collector regions

are shown below. Which one of the following biasing modes in the transistor operation in?

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GATE-2017 SET-1 ELECTRONICS ENGINEERING

2 | P a g e

(a) Forward active (b) Saturation (c) Inverse active (d) CutoffAns: c

5. Consider a stable system with transfer function1

1

11

...( )

...

p pp

q qq

s b s bG s

s a s a

where 1, ..., pb b and 1, ..., qa a are real valued constants. The slope of the Bode log magnitude

curve of G(s) converges to –60 dB/decade as . A possible pair of values for p and q is(a) p = 0 and q = 3 (b) p = 1 and q = 7 (c) p = 2 and q = 3 (d) p = 3 and q = 5Ans: (a)As there is no pole or zero at origin so initial slope will be zero.Now for –60 dB/dec slop q – p = 3So P = 0, q = 3

6. Which of the following can be the pole-zero configuration of a phase-lag controller (lagcompensator)?

Ans: aFor phase lag controller,

( )c

S ZT s

S P

And 1Z

P

Z P

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GATE-2017 SET-1 ELECTRONICS ENGINEERING

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7. An Silicon device is fabricated with uniform and non-degenerate donor doping concentrationsof ND1 = 1 X 1018 cm-3 and ND2 = 1 X 1015 cm-3 corresponding to the n+ and n legionsrespectively. At the operational temperature T. assume complete impurity ionization, kT/q =25 mV. and intrinsic carrier concentration to be n£ = 1 X 1010 cm-3. What is the magnitude ofthe built-in potential of this device?Ans:

8. Consider the 5 5 matrix

1 2 3 4 5

5 1 2 3 4

4 5 1 2 3

3 4 5 1 2

2 3 4 5 1

A

It is given that A has only one real eigenvalue. Then the real eigenvalue of A is(a) –2.5 (b) 0 (c) 15 (d) 25Ans: c

9. Consider the following statements about the linear dependence of the real valued functions2

1 2 31, & ,y y x y x over the field of real numbers

I. 1 2 3, &y y y are linearly independent on –1 0x

II. 1 2 3, &y y y are linearly dependent on 0 1x

III. 1 2 3, &y y y are linearly independent on 0 1x

IV. 1 2 3, &y y y are linearly independent on 0 1x

Which one among the following is correct?(a) Both I and II are true(b) Both I and III are true(c) Both II and IV are true(d) Both III and IV are trueAns: b

10. The voltage of an electromagnetic wave propagating in a coaxial cable with uniform

characteristic impedance is ( ) l j tV l e Volts, where l is the distance along the length of the

cable in metres, 1(0.1 40)j m is the complex propagation constant, and92 10 rad/s is the angular frequency. The absolute value of the attenuation in the cable

in dB/metre is _________Ans: (20)

1(0.1 40)Y

m

10.1 atten uation constant

m

Non attenuation 10

dB& 20log 0.868

metere in dB e

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GATE-2017 SET-1 ELECTRONICS ENGINEERING

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11. Consider the D-Latch shown in the figure, which is transparent when its clock input CK is highand has zero propagation delay. In the figure, the clock signal CLK1 has a 50% duty cycle andCLK2 is a one-fifth period delayed version of CLK1. The duty cycle at the output of the latchin percentage is ____________

Ans: (30)

/ /

/

2 53

30% .10

c k c k

c k

T TT

Tduty cycle

12. Let 1 2( , )X X be independent random variables. X1 has mean 0 and variance 1, while X2 has

mean 1 and variance 4. The mutual information I(X1 ; X2) between X1 and X2 is bits is________Ans: (0)

11 2 1

2

1 1

( , ) ( )

( ) ( ) 0

XI X X H X H

X

H X H X

13. The rank of the matrix

5 10 10

1 0 2 is

3 6 6

M

(a) 0 (b) 1 (c) 2 (d) 3Ans: c

14. In the circuit shown, the positive angular frequency (in radians per second) at which the

magnitude of the phase difference between the voltage V1 and V2 equal4

radians, is

_________

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GATE-2017 SET-1 ELECTRONICS ENGINEERING

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Ans: (1)

1

100 2 1 100 1

1 1 22V

j j

2

100(1 )

100 121 1 22

jj

Vj j

Now 11

2

1 1tan

1 2

V

V j

Here 1tan 14 sec

rad

15. The Miller effect in the context of a Common Emitter amplifier explains(a) An increase in the low-frequency cutoff frequency(b) An increase in the high-frequency cutoff frequency(c) A decrease in the low-frequency cutoff frequency(d) A decrease in the high-frequency cutoff frequencyAns: d

16. Consider a single input single output discrete-time system with x[n] as input and y[n] as output,where the two are related as

[ [ ]], for 0 10[ ]

[ ] [ 1], otherwise

n x n ny n

x n x n

Which one of the following statements is true about the system(a) It is causal and stable(b) It is causal but not stable(c) It is not causal but stable(d) It is neither causal nor stableAns: a causal, as output depends upon present and past input.

stable as , ( )n y n is finite.

17. Consider the following statements for continuous-time linear time invariant (LTI) systems.I. There is no bounded input bounded output (BIBO) stable system with a pole in the

right half of the complex plane.II. There is no causal and BIBO stable system with a pole in the right half of the complex

plane.Which one among the following is correct?(a) Both I and II are true(b) Both I and II are not true(c) Only I is true(d) Only II is trueAns: (d)S-1: If a system is nor causal, then with RHS pole system will be stable.S-2: For causal system if pole is in RHS then the system will be unstable.

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GATE-2017 EC SET-2 ELECTRONICS ENGINEERING

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GATE-2017 (set-2)

Section: Electronics and Communication Engineering

1. An LTI system with unit sample response h[n] = 5 – 7[n – 1] + 7[n – 3] – 5[n – 4] is a(a) Low-pass filter (b) high-pass filter (c) band-pass filter (d) band-stop filter

Ans: (c)Apply Z transform

1 3 4

3 4

( ) 5 7 7 5

( ) 5 7 7 5j j j

H z z z z

H w z e e

Now ( ) 0 & ( ) 0H o H

BPF

2. For the circuit shown in the figure, P and Q are the input and Y is the output.

The logic implemented by the circuit is(a) XNOR (b) XOR (c) NOR (d) OR

Ans: (b)Case-1: 1,P PMOS OFF

NMOS ON

y

Case-2: 0,P PMOS ON

NMOS OFF

y

Truth table:

0 0 0

0 1 1

1 0 1

1 1 0

P y

clearly y P

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GATE-2017 EC SET-2 ELECTRONICS ENGINEERING

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3. The output V0 of the diode circuit shown in the figure is connected to an averaging DCvoltmeter. The reading on the DC voltmeter in Volts, neglecting the voltage drop across thediode, is ____________

Ans: 3.15 to 3.21

4. The general solution of the differential equation2

2 2 5 0d y dy

ydxdx

in terms of arbitrary constant K1 and K2 is

(a) ( 1 6 ) ( 1 6 )1 2

x xK e K e (b) ( 1 8 ) ( 1 8 )1 2

x xK e K e

(c) ( 2 6 ) ( 2 6 )1 2

x xK e K e (d) ( 2 8 ) ( 2 8 )1 2

x xK e K e

Ans: a2

( 1 6 ) ( 1 6 )1 2

( 2 5) 0

1 6x x

D D y

D

y k e k e

5. Consider an n-channel MOSFFT having width W, length L, electron mobility in the channeln and oxide capacitance per unit area Cox. If gate-to-source voltage VGS = 0.7V, drain-to-

source voltage 20.1 , ( ) 100 / ,DS n oxV V C A V threshold voltage 0.3THV V and

( / ) 50,W L then the transconductance mg (in mA/V) is ________

Ans: 0.45 to 0.55

6. The input x(t) and the output y(t) of a continuous-time system are related as

( ) ( ) .t

t Ty t x u du

The system is(a) Linear and time-variant(b) Linear and time-invariant(c) Non-linear and time-variant(d) Non-linear and time-invariantAns: bLinear and time invariant

Here time variant because of limits.

7. The residues of a function

3

1( )

( 4)( 1)f z

z z

are

(a)1 1

&27 125

(b)

1 1&

125 125

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GATE-2017 EC SET-2 ELECTRONICS ENGINEERING

3 | P a g e

(c)1 1

&27 5

(d)

1 1&

125 5

Ans: b

3

1( )

( 4)( 1)f z

z z

Residue at z = 4

4 34

1 1( )

125( 1)z

z

residuez

Residue at z = –1,

2

1 21

31

1 1(Res.)

2 4

1 2 1

2 125( 4)

z

z

z

d

zdz

z

8. Consider the state space realization

1 1

2 2

( ) ( )0 0 0( ),

0 9( ) ( ) 45

x t x tu t

x t x t

with the initial condition 1

2

(0) 0,

(0) 0

x

x

where u(t) denotes the unit step function. The value of 2 21 2lim ( ) ( ) is ________

tx t x t

Ans: 5

1 11 1

2

(0)( ) ( ) ( ) ...(1)

(0)

xx t L SI A SI A BU S

x

Here 1

2

(0)0 0 0& & 0

0 9 45 (0)

xA B

x

From (1),

1( ) ( ) ( ) ...(2)x t SI A B S

1

0Now [ ]

0 9

9 01( )

0( 9)

SSI A

S

SSI A

SS S

From (2)

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GATE-2017 EC SET-2 ELECTRONICS ENGINEERING

4 | P a g e

1

2

9 0 01 1( )

0 5 45( 9) 5

100

451

09

0( )

45( )

( 9)

Sx t

S S

S

SS

x t

x tS S

1 2

2 21 2

0

45( ) 0, ( )

( 9)

45Now lim ( ) ( ) lim 5

( 9)x S

x t x tS S

Sx t x t

S S

9. The smaller angle (in degrees) between the planes 1 & 2 2 0x y z x y z is ___Ans: (54.73º)

1, 2 2 0x y z x y z

1Now ( ) ( ) ( )x y zx y z a x y z a x y z ax y z

1 x y za a a

2Now (2 2 ) (2 2 ) (2 2 )x y zx y z a x y z a x y z ax y z

2 2 2x y za a a

1 2

1 2

.Now cos

2 1 2 3 1cos 54.73º

3 9 3 3 3

10. In the figure, D1 is a real silicon pn junction diode with a drop of 0.7 V under forward biascondition and D2 is a Zener diode with breakdown voltage of –6.8 V. The input Vin(t) is aperiodic square wave of period T, whose one period is shown in the figure.

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GATE-2017 EC SET-2 ELECTRONICS ENGINEERING

5 | P a g e

Assuming 10 << T, where is the time constant of the circuit, the maximum and minimumvalues of the output waveform are respectively,(a) 7.5 V and –20.5V(b) 6.1 V and –21.9 V(c) 7.5 V and –21.2 V(d) 6.1 V and –22.6 VAns: a

11. Consider the random process( ) ,X t U Vt

where U is a zero-mean Gaussian random variable and V is a random variable uniformlydistributed between 0 and 2. Assume that U and V are statistically independent. The meanvalue of the random process at t = 2 is __________Ans: (2)

( ) [ ] [ ]E x t E E Vt

( ) 0 [ ]E x t E Vt

Now [ (2)] [2 ] 2 [ ] 2 1 2E X E V E V

12. In the circuit shown, V is a sinusoidal voltage source. The current I is in phase with voltage

V. The ratioamplitude of voltage across the capacitor

is ________.amplitude of voltage across the resistor

Ans: 0.2Current I is in phase with voltage V, So circuit is in resonance.

1Quality factor

1 5= 0.2

5 5

C

R

V L

V R C

13. In a DRAM,(a) Periodic refreshing is not required(b) Information is stored in a capacitor(c) Information is stored in a latch(d) Both read and write operations can be performed simultaneously

Ans: bDRAM uses MOS capacitor to store information.

14. Which of the following statements is incorrect?(a) Lead compensator is used to reduce the settling time.

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ECE-GATE SOLUTIONS 1. NETWORK THEORY [1]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

1. NETWORK THEORYLast 18 Years Questions

1.1 KVL & KCL

GATE-20161. In the given circuit, each resistor has a value equal to 1 [2-Makrks] (SET-2)

What is the equivalent resistance across the terminals a and b ?(a)1/6 (b) 1/3 (c) 9/20 (d) 8/15

2. In the circuit shown in the figure, the magnitude of the current (in amperes) through R2 is___ [2-Makrks] (SET-2)

3. In the figure shown, the current (in ampere) is __________ [2-Makrks] (SET-3)

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ECE-GATE SOLUTIONS 1. NETWORK THEORY [2]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

GATE-20154. In the network shown in the figure, all resistor are identical with R = 300. The

resistance Rab (in ) of the network is _______ [1-Makrk] (SET-1)

5. In the given circuit, the values of V1 and V2 respectively are [1-Makrk] (SET-1)

(a) 5V , 25V (b) 10V , 30V (c) 15V , 35V (d) 0V , 20V

6. The 2-port admittance matrix of the circuit shown is given by [1-Makrk] (SET-2)

(a)0.3 0.2

0.2 0.3

(b)15 5

5 15

(c)3.33 5

5 3.33

(d)0.3 0.4

0.4 0.3

7. In the circuit shown, the voltage VX (in Volts) is __________ [1-Makrk] (SET-3)

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ECE-GATE SOLUTIONS 1. NETWORK THEORY [3]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

8. The ABCD parameters of the following 2-port network are [2-Makrks] (SET-3)

(a)3.5 2 20.5

20.5 3.5 2

j

j

(b)3.5 2 30.5

0.5 3.5 2

j

j

(c)10 2 0

2 0 10

j

j

(d)7 4 0.5

30.5 7 4

j

j

GATE-20149. Consider the configuration shown in the figure which is a portion of a larger electrical

network (SET-1)

For R=1Ω and current1 4 52 , 1 , 4i A i A i A, which

one of the following is TRUE?(a) 6 5i A

(b) 6 4i A

(c) Data is sufficient to conclude that the supposed currentare impossible

(d) Data is insufficient to identify the currents 2 3, ,i i and i6

10. A good current buffer has (SET-1)(a) Low input impedance and low output impedance(b) Low input impedance and high output impedance(c) High input impedance and low output impedance(d) High input impedance and high output impedance

11. A Y-network has resistance of 10 each in two of its arms, while the third arm has aresistance of 11 in the equivalent -network, the lowest value (in Ω) among the threeresistance is ___. (SET-1)

12. For the Y-network shown in the figure, the value of R1 (in Ω) in the equivalent Δ-network is ____. SET-III

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ECE-GATE SOLUTIONS 1. NETWORK THEORY [4]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

13. The circuit shown in the figure represents a (SET-4)

(a) Voltage controlled voltage source (b) voltage controlled current source(c) Current controlled current source (d) current controlled voltage source

14. The equivalent resistance in the infinite ladder network shown in the figure is Re.

The value of Re/R is ___________ (SET-4)

GATE-201115. In the circuit shown below, the current I is equal to (2- Marks)

(a) 1.4 0ºA (b) 2.0 0ºA (c) 2.8 0ºA (d) 3.2 0ºA

GATE-201016. In the circuit shown, the power supplied by the voltage source is- (2- Marks)

(a) 0 W (b)5 W (c) 10 W (d) 100 W

ECE-GATE SOLUTIONS 1. NETWORK THEORY [4]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

13. The circuit shown in the figure represents a (SET-4)

(a) Voltage controlled voltage source (b) voltage controlled current source(c) Current controlled current source (d) current controlled voltage source

14. The equivalent resistance in the infinite ladder network shown in the figure is Re.

The value of Re/R is ___________ (SET-4)

GATE-201115. In the circuit shown below, the current I is equal to (2- Marks)

(a) 1.4 0ºA (b) 2.0 0ºA (c) 2.8 0ºA (d) 3.2 0ºA

GATE-201016. In the circuit shown, the power supplied by the voltage source is- (2- Marks)

(a) 0 W (b)5 W (c) 10 W (d) 100 W

ECE-GATE SOLUTIONS 1. NETWORK THEORY [4]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

13. The circuit shown in the figure represents a (SET-4)

(a) Voltage controlled voltage source (b) voltage controlled current source(c) Current controlled current source (d) current controlled voltage source

14. The equivalent resistance in the infinite ladder network shown in the figure is Re.

The value of Re/R is ___________ (SET-4)

GATE-201115. In the circuit shown below, the current I is equal to (2- Marks)

(a) 1.4 0ºA (b) 2.0 0ºA (c) 2.8 0ºA (d) 3.2 0ºA

GATE-201016. In the circuit shown, the power supplied by the voltage source is- (2- Marks)

(a) 0 W (b)5 W (c) 10 W (d) 100 W

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ECE-GATE SOLUTIONS 1. NETWORK THEORY [5]

Published by: ENGINEERS INSTITUTE OF INDIA-E.I.I. ALL RIGHT RESERVED28B/7 Jiasarai Near IIT Hauzkhas Newdelhi-110016 ph. 011-26514888. www.engineersinstitute.com

17. The current I in the circuit shown is: (2-Marks)

(a) –jA (b) jA (c) 0 A (d) 20 A

GATE-200918. In the inter connection of ideal source shown in the figure, it is known that 60V source is

absorbing power (1- Mark)

Which of the following can be the value of the current source I?(a) 10 A (b) 13 A (c) 15 A (d) 18 A

19. If the Transfer function of the following network is

0

1

V s 1

V s 2 sCR

then value of load

resistor LR is (2-Marks)

(a) R/4 (b) R/2 (c) R (d) 2R20. A fully charge mobile phone with a 12V battery is good for a 10 minute talk-time,

assume that, during the talk time the battery delivers a constant current of 2A and itsvoltage drop linearly from 12V to 10V as shown in the figure. How much energy doesthe battery deliver during this talk time? (1-Mark)

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2. ELECTRONIC DEVICES & CIRCUITSLast 18 Years Questions

2.1 SEMICONDUCTOR PHYSICS

GATE-20161. A small percentage of impurity is added to an intrinsic semiconductor at 300 K. Which

one of the following statements is true for the energy band diagram shown in thefollowing figure? [1-Mark](SET-1)

(a) Intrinsic semiconductor doped with pentavalent atoms to form n-type semiconductor(b) Intrinsic semiconductor doped with trivalent atoms to form n-type semiconductor(c) Intrinsic semiconductor doped with pentavalent atoms to form p-type semiconductor(d) Intrinsic semiconductor doped with trivalent atoms to form p-type semiconductor

2. The figure below shows the doping distribution in a p-type semiconductor in log scale.

The magnitude of the electric field (in kV/cm) in the semiconductor due to nonuniform doping is _________ [2-Marks]

3. Consider a silicon sample at T = 300 K, with a uniform donor density = 5 × 1016

cm−3, illuminated uniformly such that the optical generation rate is = 1.5 × 1020

cm−3 −1 throughout the sample. The incident radiation is turned off at = 0. Assumelow-level injection to be valid and ignore surface effects. The carrier lifetimes are 0=0.1 µs and 0 = 0.5 µs. [2-Marks] (SET-1)

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The hole concentration at = 0 and the hole concentration at = 0.3 µs, respectively,are(a) 1.5 × 1013 cm−3 and 7.47 × 1011 cm−3

(b) 1.5 × 1013 cm−3 and 8.23 × 1011 cm−3

(c) 7.5 × 1013 cm−3 and 3.73 × 1011 cm−3

(d) 7.5 × 1013 cm−3 and 4.12 × 1011 cm−3

GATE-20154. A silicon sample is uniformly doped with donor type impurities with a concentration of

1016/cm3. The electron and hole munities in the sample are 1200cm2/V-s and 400cm2/V-srespectively. Assume complete ionization of impurities. The charge of an electron is 1.610–19C. The resistivity of sample (in -cm) is ________. [1-Mark] (SET-1)

5. An n-type silicon sample is uniformly illuminated with light which generates 1020

electron-hole pairs per cm3 per second. The minority carrier lifetime in the sample is 1s.In the steady state, the hold concentration in the sample is approximately 10x, where x isan integer. The value of x is __________. [1-Mark] (SET-2)

6. A piece of silica is doped uniformly with phosphorous with a doping concentration of1016/cm3. The expected value of mobility versus doping concentration for siliconassuming full dopant ionization is shown below. The charge of an electron is 1.6 10–9 C.The conductivity (in S cm–1) of the silicon sample at 300 K is ___. [1-Mark] (SET-2)

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7. A dc voltage of 10 V is applied across an n-type silicon bar having a rectangular cross-section and a length of 1 cm as shown in figure. The donor doping concentration ND andthe mobility of electrons n are 1016cm–3 and 1000 cm2V–1s–1, respectively. The average

time (in s) taken by the electrons to move from one end of the bar to other end is ____.[2-Marks] (SET-2)

8. The energy band diagram and the electron density profile n(x) in a semiconductor are

shown in the figures. Assume that 15 3( ) 10qax

kTn x e cm , with = 0.1V/cm and x

expressed in cm. Given 2 10.026V, 36 ,andnkT D T

D cm sq q

. The electron current

density (in A/cm2) at x = 0 is ________. [2-Marks] (SET-2)

(a) 24.4 10 (b) 22.2 10 (c) 0 (d) 22.2 10

GATE-20149. The doping concentrations on the p-side and n-side of a silicon diode are 16 31 10 cm and

17 31 10 cm , respectively. A forward bias of 0.3V is applied to the diode. At T=300K, the

intrinsic carrier concentration of silicon 10 31.5 10in cm and 26 .kT

mVq The electron

concentration at the edge of the depletion region on the p-side is (SET-1)(a) 9 32.3 10 cm (b) 16 31 10 cm (c) 17 31 10 cm (d) 6 32.25 10 cm

10. A silicon bar is doped with donor impurities ND = 2.25 1015 atoms/cm3. Given theintrinsic carrier concentration of silicon at T = 300K is ni = 1.5 1010/cm3. Assumingcomplete impurity ionization, the equilibrium electron and hole concentrations are(SET-2)(a) 16 3 5 3

0 01.5 10 , 1.5 10n cm p cm (b) 10 3 15 30 01.5 10 , 1.5 10n cm p cm

(c) 15 3 10 30 02.25 10 , 1.5 10n cm p cm (d) 15 3 5 3

0 02.25 10 , 1 10n cm p cm

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11. Assume electronic charge q = 1.6 10-19C, kT/q = 25mV and electron mobilityn = 1000cm2/V-s. if the concentration gradient of electrons injected into a P- type siliconsample is 1 1021/cm4, the magnitude of electron diffusion current density (in A/cm2) is_________. (SET-2)

12. When a silicon diode having a doping concentration of NA = 9 1016 cm-3 on p-side and ND

= 1 1016 cm-3 on n – side is reverse biased, the total depletion width is found to be 3m.given that the permittivity of silicon is 1.04 10-12F/cm, the depletion width on the p-sideand the maximum electric field in the depletion region, respectively, are (SET-2)(a) 52.7μm and 2.3×10 V/cm (b) 50.3μm and 4.15×10 V/cm

(c) 50.3μm and 0.42×10 V/cm (d) 52.1μm and 0.42×10 V/cm

13. A thin P-type silicon sample is uniformly illuminated with light which generates excesscarriers. The recombination rate is directly proportional to (SET-3)(a) The minority carrier mobility(b) The minority carrier recombination lifetime(c) The majority carrier concentration(d) The excess minority carrier concentration

14. At T = 300K, the hole mobility of a semiconductor 2pμ = 500cm /V-s and

kT = 26mV

q. The

hole diffusion constant Dp in cm2/s is _________. (SET-3)

15. The donor and accepter impurities in an abrupt junction silicon diode are 1 1016 cm-3 and5 1018 cm-3, respectively. Assume that the intrinsic carrier concentration in silicon ni =

1.5 1010 cm-3 at 300 , 26kT

K mVq and the permittivity of silicon 121.04 10 /si F cm

The built-in potential and the depletion width of the diode under thermal equilibriumconditions, respectively, are (SET-3)(a) 0.7v and 1 10-4cm (b) 0.86 V and 1 10-4cm(c) 0.7 V and 3.3 10-5 cm (d) 0.86V and 3.3 10-5cm

16. At T = 300K, the band gap and the intrinsic carrier concentration of GaAs are 1.42eV and106cm, respectively. In order to generate electron hole pairs in GaAs, which one of thewavelength ( )C ranges of incident radiation, is most suitable? (Given that: Plank’sconstant is 6.62 10-34J-s, velocity of light is 3 1010cm/s and charge of electron is1.6 10-19C. (SET-4)(a) 0.42 m < C < 0.87m (b) 0.87 m < C < 1.42m(c) 1.42 m < C < 1.62m (d) 1.62m < C < 6.62m

17. In the figure, ln (i), is plotted as a function of 1/T, where i is the intrinsic resistivity ofsilicon, T is the temperature, and the plot is almost linear. (SET-4)The slope of the line can be used to estimate(a) Band gap energy of silicon (Eg)

(b) Sum of electron and hole mobility in silicon n pμ + μ(c) Reciprocal of the sum of electron and hole mobility in

silicon 1

n pμ + μ

(d) Intrinsic carrier concentration of silicon (nj)

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ECE-GATE SOLUTIONS 2. ELECTRONIC DEVICES & CIRCUITS-EDC [81]

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18. The cut – off wavelength (in m) of light that can be used for intrinsic excitation of asemiconductor material of band gap Eg =1.1eV is ______. (SET-4)

19. Consider a silicon sample doped with ND = 1 1015/cm3 donor atoms. Assume that theintrinsic carrier concentration ni = 1.5 1010/cm3. If the sample is additionally doped withNA = 1 1018/cm3 acceptor atoms, the approximate number of electron/cm3 in the sample,at T = 300K, will be _______. (SET-4)

20. An N-type semiconductor having uniform doping is biased as shown in the figure

If EC is the lowest energy level of the conduction band, EV is the highest energy level of thevalance band and EF is the Fermi level, which one of the following represents the energyband diagram for the biased N-type semiconductor? (SET-4)(a) (b)

(c) (d)

GATE-201321. In IC technology, dry oxidation (using dry oxygen) as compared to wet oxidation (using

steam or water vapour) produces (1-Mark)(a) superior quality oxide with a higher growth rate(b) inferior quality oxide with a higher growth rate(c) inferior quality oxide with a lower growth rate(d) superior quality oxide with a lower growth rate

GATE-201122. Drift current in semiconductors depends upon (1-Mark)

(a) Only the electric field(b) Only the carrier concentration gradient(c) Both the electric field and the carrier concentration(d) Both the electric field and the carrier concentration gradient

GATE-201023. Thin gate oxide in a CMOS process is preferably gown using (1-Mark)

(a) Wet oxidation (b) dry oxidation(c) Epitaxial deposition (d) ion implantation

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ECE-GATE SOLUTIONS 3. ANALOG ELECTRONICS [135]

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3. ANALOG ELECTRONICSLast 18 Years Questions

3.1 DIODE

GATE-2016

1. Assume that the diode in the figure has = 0.7 , but is

otherwise ideal.

The magnitude of the current i2 (in mA) is equal to________ (SET-2)

2. The figure shows a half-wave rectifier with a 475 F filter capacitor. The load draws a

constant current = 1 A from the rectifier. The figure also shows the input voltage , the

output voltage and the peak-to-peak voltage ripple on . The input voltage is a

triangle-wave with an amplitude of 10 V and a period of 1 ms. (SET-2)

The value of the ripple (in volts) is ________

3. The diodes D1 and D2 in the figure are ideal and

the capacitors are identical. The product RC is

very large compared to the time period of the ac

voltage. Assuming that the diodes do not

breakdown in the reverse bias, the output

voltage VO (in volt) at the steady state is

__________ (SET-3)

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ECE-GATE SOLUTIONS 3. ANALOG ELECTRONICS [136]

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GATE-2015

4. In the circuit shown below, the Zener

diode is ideal and the Zener voltage is

6V. The output voltage V0 (in volts) is

_____ (SET-1)

5. If the circuit shown has to function as a clamping circuit, then which one of the followingconditions should be satisfied for the sinusoidal signal of period T? (SET-2)

(a) RC << T

(b) RC = 0.35 T

(c) RC T

(d) RC >> T

6. The diode in the circuit given below has VON = 0.7V but is ideal otherwise. The current (inmA) in the 4 k resistor is _______. (SET-2)

7. In the circuit shown, diodes D1, D2 and D3 areideal, the inputs E1, E2 and E3 are “0 V” for logic‘0’ and “10 V” for logic ‘1’. What logic gate doesthe circuit represent? (SET-3)

(a) 3-input OR gate(b) 3-input NOR gate(c) 3-input AND gate(d) 3-input XOR gate

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ECE-GATE SOLUTIONS 3. ANALOG ELECTRONICS [137]

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8. In the circuit shown, assume

that the diodes D1 and D2 are

ideal. The average value of

voltage Vab (in Volts), across

terminals ‘a’ and ‘b’ is

________ (SET-3)

GATE-20149. In the figure, assume that the forward voltage drops of the PN diode D1 and Schottky diode

D2 are 0.7 V and 0.3V, respectively. If ON denotes conducting state of the diode and OFFdenotes non-conducting state of the diode, then in the circuit, SET-1

(a) Both D1 and D2 are ON

(b) D1 is ON and D2 is OFF

(c) both D1 and D2 are OFF

(d) D1 is OFF and D2 is ON

10. The figure shows a half-wave rectifier.The diode D is ideal. The average steady-state current (in Amperes) through thediode is approximately ____________.

SET-2

11. The diode in the circuit shown has Von = 0.7 Volts but is ideal otherwise. If Vi = 5sin ( )Volts, the minimum and maximum values of Vo (in Volts) are, respectivelySET-2

(a) –5 and 2.7(b) 2.7 and 5(c) –5 and 3.85(d) 1.3 and 5

12. Two silicon diodes, with a forward voltage drop of 0.7V, are used in the circuit shown inthe figure. The range of input voltage Vi for which the output voltage Vo = Vi is

SET-4

(a) – 0.3V < Vi< 1.3V(b) – 0.3V < Vi< 2V(c) – 1.0V < Vi< 2.0V(d) – 1.7V < Vi< 2.7V

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ECE-GATE SOLUTIONS 3. ANALOG ELECTRONICS [138]

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GATE-201313. In the circuit shown below, the knee current of the

ideal Zener diode is 10mA. To maintain 5V acrossRL, the minimum value of RL in and theminimum power rating of the Zener diode in mW,respectively, are [2-Marks](a) 125 and 125(b) 125 and 250(c) 250 and 125(d) 250 and 250

14. A voltage 1000sin t volts is applied across YZ.Assuming ideal diodes, the voltage measured across WXin volts, is [2-Marks](a) Sin t(b) (sin t +|sin t |)/2(c) (sin t -|sin t |)/2(d) 0 for all t

GATE-201215. The diodes and capacitors in the circuit shown

are ideal. The voltage v(t) across the diode D1 is[1-Mark]

(a) cos ( t ) -1(b) sin ( t )(c) 1-cos ( t )(d) 1-sin ( t )

GATE-2011Statement for Linked Answer Q. 16 and Q. 17.In the circuit shown below, assume that the voltage dropacross a forward biased diode is 0.7 V. The thermal

voltageT

V 25mV.t

k

q The small signal input

V cos( )i pv t where V 100 mV.p

16. The bias current DCI through the diodes is(a) 1 mA (b) 1.28 mA (c) 1.5 mA (d) 2 mA [2-Marks]

17. The ac output voltage acv is

(a) 0.25 cos( )mVt (b) 1cos( )mVt (c) 2 cos( )mVt (d) 22 cos( )mVt [2-Marks]

GATE-200918. In the circuit below, the diode is ideal. The voltage V is

given by [2-Marks]

(a) min(V ,1)i (b) max(V ,1)i

(c) min( V ,1)i (d) max( V ,1)i

ECE-GATE SOLUTIONS 3. ANALOG ELECTRONICS [138]

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GATE-201313. In the circuit shown below, the knee current of the

ideal Zener diode is 10mA. To maintain 5V acrossRL, the minimum value of RL in and theminimum power rating of the Zener diode in mW,respectively, are [2-Marks](a) 125 and 125(b) 125 and 250(c) 250 and 125(d) 250 and 250

14. A voltage 1000sin t volts is applied across YZ.Assuming ideal diodes, the voltage measured across WXin volts, is [2-Marks](a) Sin t(b) (sin t +|sin t |)/2(c) (sin t -|sin t |)/2(d) 0 for all t

GATE-201215. The diodes and capacitors in the circuit shown

are ideal. The voltage v(t) across the diode D1 is[1-Mark]

(a) cos ( t ) -1(b) sin ( t )(c) 1-cos ( t )(d) 1-sin ( t )

GATE-2011Statement for Linked Answer Q. 16 and Q. 17.In the circuit shown below, assume that the voltage dropacross a forward biased diode is 0.7 V. The thermal

voltageT

V 25mV.t

k

q The small signal input

V cos( )i pv t where V 100 mV.p

16. The bias current DCI through the diodes is(a) 1 mA (b) 1.28 mA (c) 1.5 mA (d) 2 mA [2-Marks]

17. The ac output voltage acv is

(a) 0.25 cos( )mVt (b) 1cos( )mVt (c) 2 cos( )mVt (d) 22 cos( )mVt [2-Marks]

GATE-200918. In the circuit below, the diode is ideal. The voltage V is

given by [2-Marks]

(a) min(V ,1)i (b) max(V ,1)i

(c) min( V ,1)i (d) max( V ,1)i

ECE-GATE SOLUTIONS 3. ANALOG ELECTRONICS [138]

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GATE-201313. In the circuit shown below, the knee current of the

ideal Zener diode is 10mA. To maintain 5V acrossRL, the minimum value of RL in and theminimum power rating of the Zener diode in mW,respectively, are [2-Marks](a) 125 and 125(b) 125 and 250(c) 250 and 125(d) 250 and 250

14. A voltage 1000sin t volts is applied across YZ.Assuming ideal diodes, the voltage measured across WXin volts, is [2-Marks](a) Sin t(b) (sin t +|sin t |)/2(c) (sin t -|sin t |)/2(d) 0 for all t

GATE-201215. The diodes and capacitors in the circuit shown

are ideal. The voltage v(t) across the diode D1 is[1-Mark]

(a) cos ( t ) -1(b) sin ( t )(c) 1-cos ( t )(d) 1-sin ( t )

GATE-2011Statement for Linked Answer Q. 16 and Q. 17.In the circuit shown below, assume that the voltage dropacross a forward biased diode is 0.7 V. The thermal

voltageT

V 25mV.t

k

q The small signal input

V cos( )i pv t where V 100 mV.p

16. The bias current DCI through the diodes is(a) 1 mA (b) 1.28 mA (c) 1.5 mA (d) 2 mA [2-Marks]

17. The ac output voltage acv is

(a) 0.25 cos( )mVt (b) 1cos( )mVt (c) 2 cos( )mVt (d) 22 cos( )mVt [2-Marks]

GATE-200918. In the circuit below, the diode is ideal. The voltage V is

given by [2-Marks]

(a) min(V ,1)i (b) max(V ,1)i

(c) min( V ,1)i (d) max( V ,1)i

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ECE-GATE SOLUTIONS 4. DIGITAL ELECTRONICS [239]

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4. DIGITAL ELECTRONICSLast 18 Years Questions

4.1 NUMBER SYSTEM & CODE CONVERSION

GATE-20161. Identify the circuit below. [2-Marks] (Set-1)

(a) Binary to Gray code converter (b) Binary to XS3 converter(c) Gray to Binary converter (d) XS3 to Binary converter

GATE-20142. The number of bytes required to represent the decimal number 1856357 in packed BCD

(Binary Coded Decimal) form is __________ . (SET-2)

GATE-20083. The two numbers represented in signed 2’s complement form are P = 11101101 and

Q = 11100110. If Q is subtracted from P, the value obtained in signed 2’s complementfrom is (2-Marks)(a) 100000111 (b) 00000111 (c) 11111001 (d) 111111001

GATE-20074. X = 01110 and Y = 11001 are two 5-bit binary numbers represented in two’s

complement format the sum of X and Y represented in two’s complement format using6 bits is (1-Mark)(a) 100111 (b) 001000 (c) 000111 (d) 101001

GATE-20065. A new Binary Coded Pentary (BCP) number system is proposed in which every digit of

a base-5 number is represented by its corresponding 3-bit binary code. For example, thebase-5 number 24 will be represented by its BCP code 010100. In this numberingsystem, the BCP code 100010011001 corresponds to the following number in base-5system. (2-Marks)(a) 423 (b) 1324 (c) 2301 (d) 4231

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ECE-GATE SOLUTIONS 4. DIGITAL ELECTRONICS [240]

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GATE-20056. Decimal 43 in Hexadecimal and BCD number system is respectively (1-Mark)

(a) B2, 01000011 (b) 2B, 01000011(c) 2B, 00110100 (d) B2, 01000100

GATE-20047. The range of signed decimal numbers that can be represented by 6-bit 1’s complement

number is(a) – 31 to + 31 (b) – 63 to + 63 (1-Mark)(c) – 64 to + 63 (d) – 32 to + 31

8. 11001, 1001 and 111001 correspond to the 2’s complement representation of which one ofthe following sets of number? (2-Marks)(a) 25, 9 and 57 respectively (b) –6, –6 and –6 respectively(c) –7, –7 and –7 respectively (d) –25, –9 and –57 respectively

GATE-20029. 4-bit 2’s complement representation of a decimal number is 1000. The number is

(1-Mark)(a) + 8 (b) 0 (c) – 7 (d) – 8

GATE-200110. The 2’s complement representation of – 17 is (1-Mark)

(a) 101110 (b) 101111 (c) 111110 (d) 110001

ANSWER KEY

1 2 3 4 5 6 7 8 9 10

c 4 b c d b a c d b

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ECE-GATE SOLUTIONS 4. DIGITAL ELECTRONICS [241]

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SOLUTIONS

1. (c)From the given circuit

Clearly it is a Gray to Binary converter.

2. (4)One decimal digit is represented by 4bits in BCD form. So in packed BCD two decimaldigits are given by 8bits i.e., 1 byte. We start pairing the decimal number from right to left.

E.g. 0 1 8 5 6 3 5 7 .Clearly 4 bytes are required.

3. (b)11101101, 11100110

2' complement of (1' complement of ) 1 00011001 1 00011010

P Q

s Q s Q

Now, (2' complement form of )

11101101 00011010

1 00000111

00000111

P Q P s Q

discard carry

4. (c)Given x = 01110 (5 bit binary number)

and y = 11001 (5 bit binary number)

if z represents the sum of x and y in 2’s complement format then

sum

01110 11001

1 00111

carry discarded

z x y

So z = 00111

For 6 bit representation, z becomes 000111.

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ECE-GATE SOLUTIONS 4. DIGITAL ELECTRONICS [242]

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5. (d)

The base -5 number 24 will be represented by its BCP code 010100

52 4

24 010 100

BCP code for 100 010 011001 4231

6. (b)

Decimal number = 43

For hexadecimal form, we divide 43 by 16, we get 2B

10 16

10

4 3

(43) (2 )

and (43) (01000011)BCD

B

7. (a) The range of signed decimal number is from 1 n 12 1 to 2 1n where n is

number of bits.

For 6 bit 1’s compliment number the range is 6 1 6 12 1 to 2 1 31 to 31

8. (c) 2’ & complement representation of 1001, 11001, 111001; they all indicate same

number because here MSB is copied and that number is 1’s complement of (1001 – 0001)

= 1’s Complement of 1000 = 0111.

= Decimal equivalent = –7.

9. (d)

Given 2’s complement representation =1000

then number = (1’s complement of 1000) + 1 = 0111 + 0001 =1000

Given number = –8.

10. (b)

2’s complement of -17 is nothing but the (1’s complement of + 17) +1.

Binary representation of +17 is = 010001

1’s complement of + 17 is = 101110

2’s complement of + 17 is = 101111

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ECE-GATE SOLUTIONS 4. DIGITAL ELECTRONICS [243]

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4.2 BOOLEAN ALGEBRA

GATE-2016

1. Following is the K-map of a Boolean function of five variables P, Q, R, S and X. Theminimum sum-of-product (SOP) expression for the function is [2-Marks](SET-3)

(a) P Q S X P Q S X Q R S X Q R S X (b) Q S X QS X

(c) Q S X Q S X (d) Q S Q S

GATE-20152. The Boolean expression ( , , )F X Y Z X Y Z X Y Z X Y Z X Y Z converted into

the canonical product of sum (POS) from is [2-Marks](SET-1)

(a) ( ) ( ) ( ) ( )X Y Z X Y Z X Y Z X Y Z

(b) ( ) ( ) ( ) ( )X Y Z X Y Z X Y Z X Y Z

(c) ( ) ( ) ( ) ( )X Y Z X Y Z X Y Z X Y Z

(d) ( ) ( ) ( ) ( )X Y Z X Y Z X Y Z X Y Z 3. A 3-input majority gates is defined by the logic function ( , , )M a b c ab bc ca .

Which one of the following gates is represented by the function

( , , ) , ( , , ) ,M M a b c M a b c c ? [2-Marks] (SET-1)

(a) 3-input NAND gate (b) 3-input XOR gate(c) 3-input NOR gate (d) 3-input XNOR gate

4. A function of Boolean variables X, Y, and Z is terms of the min-terms as

( , , ) (1,2,5,6,7)F X Y Z Which one of the product of sums given below is equal to the

function ( , , )F X Y Z ? (SET-2)

(a) ( ).( ).( )X Y Z X Y Z X Y Z

(b) ( ).( ).( )X Y Z X Y Z X Y Z

(c) ( ).( ).( ).( ).( )X Y Z X Y Z X Y Z X Y Z X Y Z

(d) ( ).( ).( ).( ).( )X Y Z X Y Z X Y Z X Y Z X Y Z GATE-2014

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ECE-GATE SOLUTIONS 5. MICROPROCESSOR [306]

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5. MICROPROCESSORLast 18 Years Questions

GATE-2016

1. In an 8085 system, a PUSH operation requires more clock cycles than a POP operation.Which one of the following options is the correct reason for this? [2-Marks] (SET-1)(a) For POP, the data transceivers remain in the same direction as for instruction fetch

(memory to processor), whereas for PUSH their direction has to be reversed.(b) Memory write operations are slower than memory read operations in an 8085 based

system.(c) The stack pointer needs to be pre-decremented before writing registers in a PUSH,

whereas a POP operation uses the address already in the stack pointer.(d) Order of registers has to be interchanged for a PUSH operation, whereas POP uses

their natural order

2. An 8 Kbyte ROM with an active low Chip Select input ( )CS is to be used in an 8085

microprocessor based system. The ROM should occupy the address range 1000H to2FFFH. The address lines are designated as 15 to 0, where 15 is the most significant

address bit. Which one of the following logic expressions will generate the correct CSsignal for this ROM? [2-Marks] (SET-2)

(a) 15 14 13 12 13 12( . . )A A A A A A (b) 15 14 13 12. .( )A A A A

(c) 15 14 13 12 13 12. .( . . )A A A A A A (d) 15 14 13 12.A A A A

3. In an 8085 microprocessor, the contents of the accumulator and the carry flag are A7 (inhex) and 0, respectively. If the instruction RLC is executed, then the contents of theaccumulator (in hex) and the carry flag, respectively, will be [1-Mark] (SET-3)(a) 4E and 0 (b) 4E and 1 (c) 4F and 0 (d) 4F and 1

GATE-20154. In an 8085 microprocessor, the shift registers which store the result of an addition and the

overflow bit are, respectively [1-Mark] (SET-1)(a) B and F (b) A and F (c) H and F (d) A and C

5. A 16Kb (= 16,384 bit) memory array is designed as a square with an aspect ratio of one(number of rows is equal to the number of columns). The minimum number of addresslines needed for the row decoder is _______ [1-Mark] (SET-1)

6. In an 8085 microprocessor, which one of the following instructions changes the contentof the accumulator? [1-Mark] (SET-2)(a) MOV B, M (b) PCHL (c) RNZ (d) SBI BEH

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ECE-GATE SOLUTIONS 5. MICROPROCESSOR [307]

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7. Which one of the following 8085 microprocessor programs correctly calculates theproduct of two 8-bit numbers stored in registers B and C? [1-Mark] (SET-3)(a) MVI A, 00H (b) MVI A, 00H

JNZ LOOP CMP CCMP C LOOP DCR B

LOOP DCR B JNZ LOOPHLT

(c) MVI A, 00H (d) MVI A, 00HLOOP ADD C ADD C

DCR B JNZ LOOPJNZ LOOP LOOP INR BHLT HLT

GATE-20008. The number of hardware interrupts (which require an external signal to interrupt) present

in an 8085 microprocessor are: [1-Mark](a) 1 (b) 4 (c) 5 (d) 13

9. In the 8085 microprocessor the RST 6 instruction transfer the program execution to thefollowing location. (1-Mark)(a) 30H (b) 24H (c) 48H (d) 60H

10. The contents of Register (B) and accumulator (A) of 8085 microprocessor are49 & 3H AH respectively. The contents of A & the status of carry flag (c) and sign flag(s) after executing SUB B instructions are. [2-Marks](a) A = F1, CY= 1, S = 1 (b) A = 0F, CY = 1, S = 1(c) A = F0, CY = 0, S = 0 (d) A = 1 F, CY = 1, S = 1

GATE-200211. Consider the following assembly language program. [2-Marks-]

MVI B, 87HMOV A, B

START JMP NEXTMVI B, 00HXRA BOUT PORT 1HLT

NEXT XRA BJP STARTOUT PORT 2HLT

The execution of the above program in an 8085 microprocessor will result in –(a) An output of 87H at PORT 1(b) An output of 87H at PORT 2(c) Infinite looping of the program execution with accumulator data remaining at 00H(d) Infinite looping of the program execution with accumulator data alternating between

00H & 87H

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ECE-GATE SOLUTIONS 5. MICROPROCESSOR [308]

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GATE-200312. In an 8085 microprocessor, the instruction CMP B has been executed while the content of

the accumulator is less than that of register B. As result. [2-Marks](a) Carry flag will be set but zero flag will be reset(b) Carry flag will be reset but zero flag will be set(c) Both carry flag & zero flag will be reset(d) Both carry flag & zero flag will be set

GATE-200413. The 8255 programmable peripheral interface is used as described below- [2-Marks]

(i) An A/D converter is interfaced to a microprocessor through an 8255. Theconversion is initiated by a signal from the 8255 on port C. A signal on port Ccauses data to be strobed into port A.

(ii) Two computer exchange data using a pair of 8255. Port A works as bidirectionaldata port supported by appropriate handshaking signals.

The appropriate modes of operation of the 8255 for (i) and (ii) would be.(a) Mode 0 for (i) and mode 1 for (ii) (b) Mode 1 for (i) and mode 2 for (ii)(c) Mode 2 for (i) and mode 0 for (ii) (d) Mode 2 for (i) and mode 1 for (ii)

14. The number of memory cycles required to execute the following 8085 instructions.(I) LDA 3000H [2-Marks](II) LXI D, F0FI H would be-(a) 2 for (I) and 2 for (II) (b) 4 for (I) and 3 for (II)(c) 3 for (I) for 3 for (II) (d) 3 for (I) and 4 for (II)

15. Consider the sequence of 8085 instructions given below: [2-Marks]LXI H, 9258MOVA, MCMAMOV M, AWhich one of the following is performed by this sequence?(a) Contents of location 9258 are moved to the accumulator(b) Contents of location 9258 are compared with the contents of the accumulator.(c) Contents of location 9258 are complemented and stored in location 9258(d) Contents of location 5892 are complemented and stored in location 5892.

16. It is desired to multiply the number 0AH by 0BH and store the result in the accumulator.The numbers are available in register B & C respectively. A part of the 8085 program forthis purpose is given below: [2-Marks]MVI A, 00HLOOP;…….HLT ENDThe sequence of instruction to the complete the program would be.(a) JNZ loop, ADD B, DCRC (b) ADD B, JNZ loop, DCRC(c) DCRC, JNZ loop, ADD B (d) ADDB, DCRC, JNZ loop

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ECE-GATE SOLUTIONS 5. MICROPROCESSOR [309]

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GATE-2005Common data for question 17 and 18Consider an 8085 microprocessor systemThe following program starts at location 0100H,

LXI SP, 00FFLXI H, 0107MVI A, 20HSUB M

17. The content of accumulator when the program counter reaches 0109H is (2-Marks)(a) 20H (b) 02H (c) 00H (d) FFH

18. If in addition following code exists from 0109H onwards [2-Marks]ORI 40HADD MWhat will be result in the accumulator after the last instruction is executed?(a) 40H (b) 20H (c) 60H (d) 42H

GATE-200619. Following is the segment of a 8085 assembly language program: (2-Marks)

LXI SP, EFFFHCALL 3000H3000H: LXI H, 3CF4HPUSH PSWSPHLPOP PSWRET

On completion of RET execution, the contents at SP is(a) 3 CFOH (b) 3CF8H (c) EFFDH (d) EFFFH

GATE-200720. An 8255 chip is interfaced to an 8085 microprocessor system as an I/O mapped I/O as

shown in the figure. The address lines A0 and A 1of the 8085 are used by the 8255 chip todecode internally its three ports and the control register. The address lines A3 to A7 as

well as the IO/ M signal are used for address decoding. The range of address for whichthe 8255 chip would get selected is (2-Marks)

(a) F8H-FBH (b) F8H-FCH (c) F8H-FFH (d) F0H-F7H

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ECE-GATE SOLUTIONS 6. SIGNAL SYSTEM [319]

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6. SIGNAL SYSTEMLast 18 Years Questions

6.1 LINEAR TIME INVARIANT

GATE-2016

1. Which one of the following is an eigen function of the class of all continuous-time,linear, time- invariant systems (u( ) denotes the unit-step function)?

[1-Mark] (SET-1)

(a) 0 ( )j te u t (b) 0cos( )t (c) 0j te (d) 0sin( )t

2. The energy of the signalsin(4 )

( )4

tx t

t

is _______ [1-Mark] (SET-2)

3. If the signalsin( ) sin( )

( ) *t t

x tt t

with * denoting the convolution operation, then x(t) is

equal to [1-Mark] (SET-3)

(a)sin( )t

t(b)

sin(2 )

2

t

t(c)

2sin( )t

t(d)

2sin( )t

t

4. A signal2

2cos cos( )3

t t

is the input to an LTI system with the transfer function

( ) s sH s e e [2-Marks] (SET-3)If C denotes the kth coefficient in the exponential Fourier series of the output signal, thenC3 is equal to(a) 0 (b) 1 (c) 2 (d) 3

GATE-2015

5. The result of the convolution 0( ) * ( )x t t t is [1-Mark] (SET-1)

(a) 0( )x t t (b) 0( )x t t (c) 0( )x t t (d) 0( )x t t

6. The waveform of a periodic signal x(t) is shown in the figure [1-Mark] (SET-1)

A signal g(t) is defined by1

( )2

tg t x

. The average power of g(t) is ______

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ECE-GATE SOLUTIONS 7. COMMUNICATION [388]

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7. COMMUNICATIONLast 18 Years Questions

7.1 ANALOG COMMUNICATION

GATE-2016

1. A continuous -time sinusoid of frequency 33 Hz is multiplied with a periodic Diracimpulse train of frequency 46 Hz. The resulting signal is passed through an ideal analoglow-pass filter with a cut-off frequency of 23 Hz. The fundamental frequency (in Hz) of theoutput is _____ [1-Mark] (SET-1)

2. A super heterodyne receiver operates in the frequency range of 58 MHz − 68 MHz. The

intermediate frequency fIF and local oscillator frequency fLO are chosen such that fIF ≤ fLO.

It is required that the image frequencies fall outside the 58 MHz − 68 MHz band. The

minimum required (in MHz) is _______ [1-Mark] (SET-1)

3. The amplitude of a sinusoidal carrier is modulated by a single sinusoid to obtain the

amplitude modulated signal ( ) = 5 cos 1600 + 20 cos 1800 + 5 cos 2000 . The

value of the modulation index is __________ [1-Mark] (SET-1)

4. For a superheterodyne receiver, the intermediate frequency is 15 MHz and the localoscillator frequency is 3.5 GHz. If the frequency of the received signal is greater than thelocal oscillator frequency, then the image frequency (in MHz) is _______

[1-Mark](SET-3)

GATE-2015

5. Consider the signal ˆ ˆ( ) ( )cos(2 ) ( )sin(2 ) where ( )c cs t m t f t m t f t m t denotes the

Hilbert transform of m(t) and the bandwidth of m(t) is very small compared to fc.The signal s(t) is a [1-Mark](SET-3)(a) High-pass signal (b) Low-pass signal(c) Band-pass signal (c) Double sideband suppressed carrier signal

6. In the system shown in figure (a), m(t) is a low-pass signal with bandwidth W Hz. Thefrequency response of the band-pass filter H(f) is shown in figure (b). If it is desired thatthe output signal z(t) = 10x(t), the maximum value of W (in Hz) should be strictly lessthan ___ [2-Marks](SET-1)

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ECE-GATE SOLUTIONS 7. COMMUNICATION [389]

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7. A message signal m(t) = Am sin(2fmt) is used to modulate the phase of carrier Ac cos

(2fct) to get the modulated signal y(t) = Ac cos(2fct+m(t)). The bandwidth of y(t)[1-Mark](SET-3)

(a) depends on Am but not on fm (b) depends on fm but not on Am

(c) depends on both Am and fm (d) does not depend on Am and fm

8. The complex envelope of the band pass signalsin( / 5)

( ) 2 sin/ 5 4

tx t t

t

,

centered about1

2f Hz is [2-Marks](SET-3)

(a) 4sin( / 5)

/ 5

jte

t

(b) 4sin( / 5)

/ 5

jte

t

(c) 4sin( / 5)2

/ 5

jte

t

(d) 4sin( / 5)2

/ 5

jte

t

GATE-2014

9. In a double sideband (DSB) full carrier AM transmission system, if the modulation indexis double, then the ratio of total sideband power to the carrier power increases by a factorof _______.

10. Consider an FM signal 1 2 2( ) cos[2 sin 2 sin 2 ]cf t f t f t f t . The maximum

deviation of the instantaneous frequency from the carrier frequency fc is

(A) 1 1 2 2f f (B) 1 2 2 1f f (C) 1 2 (D) 1 2f f

11. Consider a sinusoidal modulation in AM system. Assuming no over modulation, the

modulation index ( ) when the maximum and minimum values of the envelope

respectively are 3V and 1V, is______________.

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ECE-GATE SOLUTIONS 7. COMMUNICATION [390]

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12. In the figure M(f) is the Fourier transform of the message signal m(t) where A =100Hz

and B= 40 Hz. Given v(t) cos(2 ) ( ) cos2 ( ) c cf t and w t f A t where fc >A.

The cut-off frequencies of both the filters are fc.

The bandwidth of the signal at the output of the modulator (in Hz) is_____________.

GATE-201213. The signal m(t) as shown is applied both to a phase modulator (with kp as the phase

constant) and a frequency modulator with (kf as the frequency constant) having the samecarrier frequency

The ratio /p fk k (in rad/Hz) for the same maximum phase deviation is [2-Marks]

(a) 8 (b) 4 (c) 2 (d)

GATE-2011

14. X(t) is a stationary random process with autocorrelation function 2R ( ) exp( ).x Thisprocess is passed through the system below. The power spectral density of the outputprocess Y(t) is

[2-Marks](a) 2 2 2(4 1) exp( )f f (b) 2 2 2(4 1) exp( )f f

(c) 2 2(4 1) exp( )f f (d) 2 2(4 1) exp( )f f

y t( )+

H( ) = 2f j f

x t( )

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ECE-GATE SOLUTIONS 7. COMMUNICATION [391]

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15. A message signal m(t) = cos 2000 4 cos 4000t t modulates the carrier ( ) cos2 cc t f t where cf = 1 MHz to produce an AM signal. For demodulating the generated AM signalusing an envelope detector, the time constant RC of the detector circuit should satisfy(a) 0.5 ms < RC < 1 ms (b) 1 s RC 0.5 ms (c) RC 1 s (d) RC 0.5ms [2-Marks]

16. The List-I (lists the attributes) and the List-II (lists of the modulation systems). Match theattribute to the modulation system that best meets it. [1-Mark]

List-IA. Power efficient transmission of signalsB. Most band width efficient transmission of voice signalsC. Simplest receiver structureD. Bandwidth efficient transmission of signals withsignificant dc component

List-II1. Conventional AM2. FM3. VSB4. SSB-SC

A B C D(a) 4 2 1 3(b) 2 4 1 3(c) 3 2 1 4(d) 2 4 3 1

GATE-201017. Suppose that the modulating signal is ( ) 2 cos(2 )mm t f t and the carrier signal is

C C( ) A cos(2 ).cx t f t Which one of the following is a conventional AM signal withoutover-modulation? [1-Mark](a) C( ) A ( ) cos(2 )cx t m t f t (b) C( ) A [1 ( )] cos(2 )cx t m m t f t

(c) CC

A( ) A cos(2 ) ( ) cos(2 )

4c cx t f t m t f t

(d) C C( ) A cos(2 ) cos(2 ) A sin(2 )sin(2 )m c m cx t f t f t f t f t

18. The Nyquist sampling rate for the signalsin(500 ) sin(700 )

( )t t

s tt t

is given by

[2-Marks](a) 400Hz (b) 600Hz (c) 1200Hz (d) 1400Hz

19. Consider an angle modulates signal x(t) =66cos[2 10 2sin(8000 ) 4 cos(8000 )]V.t t t The average power of x(t) is

(a) 10 W (b) 18 W (c) 20 W (d) 28 W

20. X(t) is a stationary process with the power spectral density S ( ) 0x f for all f. The process

is passed through a system shown below [2-Marks]Let YS ( )f be the power spectral density of Y(t). Which one of the following statements is

correct?

y t( )++

ddt

Delay = 0.5 ms

x t( )

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ECE-GATE SOLUTIONS 8. CONTROL SYSTEM [478]

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8. CONTROL SYSTEMLast 18 Years Questions

8.1 BLOCK DIAGRAM AND SIGNAL FLOW GRAPHGATE-2016

1. The block diagram of a feedback control system is shown in the figure. The overall closed-

loop gain G of the system is [1-Mark](SET-3)

(a) 1 2

1 11

G GG

G H

(b) 1 2

1 2 1 11

G GG

G G G H

(c) 1 2

1 2 11

G GG

G G H

(d) 1 2

1 2 1 2 11

G GG

G G G G H

GATE-2015

2. By performing cascading and/or summing/differencing operations using transfer functionblocks G1 (s) and G2 (s), one CANNOT realize a transfer function of the form

[1-Mark] (SET-2)

(a) G1(s)G2(s) (b) 1

2

( )

( )

G s

G s

(c) 1 21

1( ) ( )

( )G s G s

G s

(d) 1 2

1

1( ) ( )

( )G s G s

G s

3. For the signal flow graph shown in the figure, the value of ( )

( )

C s

R sis [1-Mark](SET-2)

(a) 1 2 3 4

1 2 1 3 4 2 2 3 3 1 2 2 4 1 21

G G G G

G G H G G H G G H G G G G H H

(b) 1 2 3 4

1 2 1 3 4 2 2 3 3 1 2 2 4 1 21

G G G G

G G H G G H G G H G G G G H H

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ECE-GATE SOLUTIONS 8. CONTROL SYSTEM [479]

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(c)1 2 1 3 4 2 2 3 3 1 2 2 4 1 2

1

1 G G H G G H G G H G G G G H H

(d)1 2 1 3 4 2 2 3 3 1 2 2 4 1 2

1

1 G G H G G H G G H G G G G H H

GATE-20144. For the following system,

When X1(s) = 0, the transfer function2

( )

( )

Y s

X sis (SET-2)

(a)2

1s

s

(b)

1

1s (c)

2

( 1)

s

s s

(d)1

( 2)

s

s s

5. Consider the following block diagram in the figure.

The transfer function( )

( )

C s

R sis (SET-3)

(a) 1 2

1 21

G G

G G(b) 1 2 1 1G G G (c) 1 2 2 1G G G (d) 1

1 21

G

G G

GATE-2013

6. The signal flow graph for a system is given below. The transfer function( )

( )

Y s

U sfor this

system is [2-Marks]

(a)2

s+1

5s +6s+2(b)

2

s+1

5s +6s+2(c)

2

s+1

s +4s+2(d)

2

1

5s +6s+2

ECE-GATE SOLUTIONS 8. CONTROL SYSTEM [479]

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(c)1 2 1 3 4 2 2 3 3 1 2 2 4 1 2

1

1 G G H G G H G G H G G G G H H

(d)1 2 1 3 4 2 2 3 3 1 2 2 4 1 2

1

1 G G H G G H G G H G G G G H H

GATE-20144. For the following system,

When X1(s) = 0, the transfer function2

( )

( )

Y s

X sis (SET-2)

(a)2

1s

s

(b)

1

1s (c)

2

( 1)

s

s s

(d)1

( 2)

s

s s

5. Consider the following block diagram in the figure.

The transfer function( )

( )

C s

R sis (SET-3)

(a) 1 2

1 21

G G

G G(b) 1 2 1 1G G G (c) 1 2 2 1G G G (d) 1

1 21

G

G G

GATE-2013

6. The signal flow graph for a system is given below. The transfer function( )

( )

Y s

U sfor this

system is [2-Marks]

(a)2

s+1

5s +6s+2(b)

2

s+1

5s +6s+2(c)

2

s+1

s +4s+2(d)

2

1

5s +6s+2

ECE-GATE SOLUTIONS 8. CONTROL SYSTEM [479]

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(c)1 2 1 3 4 2 2 3 3 1 2 2 4 1 2

1

1 G G H G G H G G H G G G G H H

(d)1 2 1 3 4 2 2 3 3 1 2 2 4 1 2

1

1 G G H G G H G G H G G G G H H

GATE-20144. For the following system,

When X1(s) = 0, the transfer function2

( )

( )

Y s

X sis (SET-2)

(a)2

1s

s

(b)

1

1s (c)

2

( 1)

s

s s

(d)1

( 2)

s

s s

5. Consider the following block diagram in the figure.

The transfer function( )

( )

C s

R sis (SET-3)

(a) 1 2

1 21

G G

G G(b) 1 2 1 1G G G (c) 1 2 2 1G G G (d) 1

1 21

G

G G

GATE-2013

6. The signal flow graph for a system is given below. The transfer function( )

( )

Y s

U sfor this

system is [2-Marks]

(a)2

s+1

5s +6s+2(b)

2

s+1

5s +6s+2(c)

2

s+1

s +4s+2(d)

2

1

5s +6s+2

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ECE-GATE SOLUTIONS 8. CONTROL SYSTEM [480]

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GATE-2011Common data question for 7 & 8

The input-output transfer function of a plant,2

100( )

( 10)H s

s s

. The plant is placed in a unity

negative feedback configuration as shown in the figure below.

7. The signal flow graph that does not model the plant transfer function H(s) is [2-Marks]

8. The gain margin of the system under closed loop unity negative feedback is [2-Mark]

(a) 0 dB (b) 20 dB (c) 26 dB (d) 46 dB

GATE-2010

9. The transfer functionY( )

R( )

s

sof the system shown in [1-Mark]

(a) 0 (b)1

1s (c)

2

1s (d)

2

3s

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ECE-GATE SOLUTIONS 8. CONTROL SYSTEM [481]

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GATE-2004

10. Consider the signal flow graph shown in the figure. The gain 5

1

x

xis [2-Marks]

(a)1 ( )be cf dg

abc

(b)

1 ( )

bedg

be cf dg

(c)1 ( )

abcd

be cf dg bedg (d)

1 ( )be cf dg bedg

abcd

GATE-2003

11. The signal flow graph of a system is shown in the figure. The transfer functionC( )

R( )

s

sof the

system is [2-Marks]

(a)2

6

29 6s s (b)

2

6

29 6

s

s s (c)

2

( 2)

29 6

s s

s s

(d)2

( 27)

29 6

s s

s s

GATE-200212. The system shown in the figure remains stable when [2-Marks]

(a) K < –1 (b) –1 < K < 1 (c) 1 < K < 3 (d) K < –3

C( )s

R( )s 11s–2 –4 –3

1s6

1

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ECE-GATE SOLUTIONS 9. ELECTROMAGNETIC THEORY [583]

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9. ELECTROMAGNETIC THEORYLast 18 Years Questions

9.1 MEXWELL’S EQUATIONS

GATE-20161. Faraday’s law of electromagnetic induction is mathematically described by which one of

the following equations? [1-Mark] (SET-3)

(a) 0B

(b) VD

(c)B

Et

(d)

DH E

t

GATE-20152. In a source free region in vacuum, if the electrostatic potential 2 2 22x y cz , the value

of constant c must be ________. [1-Mark] (SET-2)

3. A vector field 22 zD a z a exists inside a cylindrical region enclosed by the surfaces

= 1, z = 0 and z = 5. Let S be the surface bounding this cylindrical region. The surface

integral of this fled on S .S

D ds is __________. [2-Marks] (SET-3)

4. A coaxial capacitor of inner radius 1 mm and outer radius 5 mm has a capacitance per unitlength of 172 pF/m. if the ratio of outer radius to inner radius is doubled, the capacitanceper unit length (in pF/m) is ______ [2-Marks] (SET-3)

GATE-20145. The force on a point charge +q kept at a distance d from the surface of an infinite grounded

metal plate in a medium of permittivity is (SET-1)

(a) 0 (b)2

216

q

d away from the plate

(c)2

216

q

d towards the plate (d)

2

24

q

d towards the plate

6. Given the vector ˆ ˆ(cos )(sin ) (sin )(cos )x yA x y a x y a , where ˆ ˆ,x ya a denote unit vectors

along x, y directions, respectively. The magnitude of curl of A is ________. (SET-3)

7. Given ˆ ˆ ˆx y zF za xa ya

. If S represents the portion of the sphere

2 2 2 1 for 0, then .S

x y z z F ds

is _________. (SET-4)

8. If 3 2 2 2ˆ ˆ ˆ(2 3 ) (6 3 ) (6 )E y yz x xy xz y xyz z

is the electric field in a source freeregion, a valid expression for the electrostatic potential is (SET-4)(a) 3 2xy yz (b) 3 22xy xyz

(c) 3 2y xyz (d) 3 22 3xy xyz9. The electric field (assumed to be one – dimensional)

between two points A and B is shown. Let A and

B be the electrostatic potentials at A and B,

respectively. The value B - A in volts is_________. (SET-4)

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ECE-GATE SOLUTIONS 9. ELECTROMAGNETIC THEORY [584]

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GATE-201210. The direction of vector A is radially outward from the origin, with |A| =krn where

2 2 2 2r x y z and k is a constant. The value of n for which . 0A is [2-Marks]

(a) –2 (b) 2 (c) 1 (d) 0

Statements for linked answer question 11 and 12

An infinitely long uniform solid wire of radius a carries a uniform dc current of density j

11. The magnetic field at a distance r from the centre of the wire is proportional to [2-Marks]

(a) 21/r for r a and r for r a (b) 0 1/for r a and r for r a

(c) 1/r for r a and r for r a (d) 20 1/for r a and r for r a 12. A hole of radius b(b<a) is now drilled along the length of the wire at a distance d from the

centre of the wire as shown below [2-Marks]

The magnetic field inside the hole is(a) Uniform and depends only on d (b) uniform and depends only on b(c) Uniform and depends on both b and d (d) non uniform

GATE-201113. Consider a closed surface S surrounding a volume V. if r

is the position vector of a point

inside S, with n the unit normal on S, the value of the integral ˆ5 .S

r n dS is

[1-Mark]

(a) 3V (b) 5V (c) 10V (d) 15V

14. The electric and magnetic fields for a TEM wave of frequency 14 GHz in a homogeneous

medium of relative permittivity r and relative permeability 1r are given by

( 280 )

( 280 )

/

3 /

j t yp z

j t yx

E E e u V m

H e u A m

[2-Marks]

Assuming the speed of light in free space to be 83 10 / ,m s intrinsic impedance of free

space to be 120 , the relative permittivity r of the medium and the electric field

amplitude Ep are

(a) 3, 120r pE (b) 3, 360r pE

(c) 9, 360r pE (d) 9, 120r pE

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ECE-GATE SOLUTIONS 9. ELECTROMAGNETIC THEORY [585]

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GATE-2010

15. If A

= 2 , .x y cxy a x a then A dl over the path shown in fig is [2-Marks]

(a) 0 (b)2

3(c) 1 (d) 2 3

GATE-2009

16. If a vector field is related to another vector field through which of the

following is true? Note: C and refer to any closed contour and any surface whose

boundary is C. [2-Marks]

(a) (b)

(c) (d)

17. A magnetic field in air is measured to be . What current

distribution leads to this field? [2-Marks][Hint: The algebra is trivial in cylindrical coordinates].

(a) (b)

(c) (d)

GATE-200818. For static electric and magnetic fields in an inhomogeneous source-free medium, which of

the following represents the correct form of two of Maxwell’s equations? [1-Mark]

(a) (b)

(c) (d)

V

CC S

V. A. Sdl d

CC S

V. A.dl dS

^

02 2

0

B 1J , 0

zr

x y

J 0, 0r

. E 0

B 0

E 0

B 0

ECE-GATE SOLUTIONS 9. ELECTROMAGNETIC THEORY [585]

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GATE-2010

15. If A

= 2 , .x y cxy a x a then A dl over the path shown in fig is [2-Marks]

(a) 0 (b)2

3(c) 1 (d) 2 3

GATE-2009

16. If a vector field is related to another vector field through which of the

following is true? Note: C and refer to any closed contour and any surface whose

boundary is C. [2-Marks]

(a) (b)

(c) (d)

17. A magnetic field in air is measured to be . What current

distribution leads to this field? [2-Marks][Hint: The algebra is trivial in cylindrical coordinates].

(a) (b)

(c) (d)

GATE-200818. For static electric and magnetic fields in an inhomogeneous source-free medium, which of

the following represents the correct form of two of Maxwell’s equations? [1-Mark]

(a) (b)

(c) (d)

A

V A,

CS

CC S

A. V. Sdl d

CC S

V. A.dl dS

CC S

A. V.dl dS

^ ^

0 2 2 2 2B B

x yy x

x y x y

^

02 2

0

B 1J , 0

zr

x y

^

02 2

0

B 2J , 0

zr

x y

^

02 2

0

B 1J , 0

zr

x y

. E 0

. B 0

E 0

. B 0

ECE-GATE SOLUTIONS 9. ELECTROMAGNETIC THEORY [585]

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GATE-2010

15. If A

= 2 , .x y cxy a x a then A dl over the path shown in fig is [2-Marks]

(a) 0 (b)2

3(c) 1 (d) 2 3

GATE-2009

16. If a vector field is related to another vector field through which of the

following is true? Note: C and refer to any closed contour and any surface whose

boundary is C. [2-Marks]

(a) (b)

(c) (d)

17. A magnetic field in air is measured to be . What current

distribution leads to this field? [2-Marks][Hint: The algebra is trivial in cylindrical coordinates].

(a) (b)

(c) (d)

GATE-200818. For static electric and magnetic fields in an inhomogeneous source-free medium, which of

the following represents the correct form of two of Maxwell’s equations? [1-Mark]

(a) (b)

(c) (d)

V A,

CC S

A. V. Sdl d

CC S

A. V.dl dS

^ ^

0 2 2 2 2B B

x yy x

x y x y

^

02 2

0

B 2J , 0

zr

x y

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ECE-GATE SOLUTIONS 9. ELECTROMAGNETIC THEORY [586]

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19. Two infinitely long wires carrying current are as shown in the figure below. One wire is inthe y-z plane and parallel to the y-axis. The other wire is in the x-y plane and parallel to thex-axis. Which components of the resulting magnetic field are non-zero at the origin?

[1-Mark]

(a) x, y, z components (b) x, y components(c) y, z components (d) x, z components

1 A

1 A

X

Y

Z