electrochemistry lesson 25
TRANSCRIPT
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Dissociation equation :
Setup of the apparatus
Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : I
PbI2 Pb2+ + 2 I
Cation : Pb2+
2 I I2 + 2 e Pb2+ + 2 e Pb
Dark purplish solid with
some pungent brown gas isreleased.
Grey solid is deposited at thenegative electrode.
Oxidation Reduction
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Dissociation equation :
Setup of the apparatus
Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : OH ; Br
KBr K+ + Br
Cation : H+ ; K+
4 OH O2 + 2 H2O + 2e 2 H+ + 2 e H2
Bubbling is observed.
Colourless gas evolvedignite the glowing wooden
splinter.
Bubbling is observed.
Colourless gas evolved
resulted a pop sound to be
heard when put close to a
burning wooden splinter
Oxidation Reduction
H2O H+ + OH
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Dissociation equation :
Setup of the apparatus
Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : OH ; Cl
FeCl2 Fe2+ + 2 Cl
Cation : H+ ; Fe2+
Reduction
H2O H+ + OH
Bubbling is observed.
Colourless gas evolved
resulted a pop sound to be
heard when put close to a
burning wooden splinter
2 H+ + 2 e H24 OH O2 + 2 H2O + 2e
Bubbling is observed.
Colourless gas evolved
ignite the glowing wooden
splinter.
Oxidation
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Dissociation equation :
Setup of the apparatus
Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : OH ; Cl
CuCl2 Cu2+ + 2 Cl
Cation : H+ ; Cu2+
4 OH O2 + 2 H2O + 2e Cu2+ + 2 e Cu
Bubbling is observed.
Colourless gas evolvedignite the glowing wooden
splinter.
Brown colour solid deposited
around the electrode,resulting the blue colour of
CuSO4 faded with time.
Oxidation Reduction
H2O H+ + OH
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Dissociation equation :
Setup of the apparatus
Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : OH ; conc. NO3
Pb(NO3)2 Pb2+ + 2NO3
Cation : H+ ; conc. Pb2+
4 OH O2 + 2 H2O + 2e Pb2+ + 2 e Pb
Bubbling is observed.
Colourless gas evolvedignite the glowing wooden
splinter.
Oxidation Reduction
H2O H+ + OH
Grey solid is deposited
around the electrode.
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Dissociation equation :
Setup of the apparatus
Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : OH ; NO3- Cation : H+ ; Ag+
Oxidation Reduction
H2O H+ + OH
Silver electrode corroded
and become thinner.
Ag+ + e AgAg Ag+ + e
AgNO3 Ag+ + NO3
Silver colour solid deposited
around the electrode,
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6.4 Application of Electrolysis in Industrial
6.4.1 Extraction of aluminium from its ore (bauxite)
When aluminium oxide is dissolved in molten cryolite
Al2O3 (l) 2 Al3+ (l) + 3 O2 (l)
Electrolyte mixture is then placed in carbon-lined iron vat (cathode).
The heating effect of the electric current melts the electrolyte
mixture, producing Na+, Al3+, O2- and F- ions
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During electrolysis, aluminium is preferentially discharged at
the cathode.
Cathode : Al3+ + 3 e Al
At the anode, oxygen is released instead of fluorine.Anode : 2 O2 O2 + 4 e
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In industrial process, chlorine gas, together with sodium
metal, is prepared using molten sodium chloride (brine) using
mercury-cathode cell.
Mercury is specially used to attract the sodium formed in
cathode and form an alloy named amalgam
This method is not environment friendly as the mercury used
is poisonous.
Half equation occur at cathode
Half equation occur at anode
Na+ + e- Na
2Cl- Cl2 + 2 e-
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6.4.2 Purification of copper in industries
Pure copper can only be obtained under such method. The set-up of
purifying copper is shown in diagram below.
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Electrodes Positive terminal Negative terminal
Ions gathered
Observation
Halfequation
Process occur
Anion : OH ; SO42- Cation : H+ ; Cu2+
Oxidation Reduction
Copper electrode
corroded at anode andbecome thinner.
Cu2+ + 2 e CuCu Cu2+ + 2 e
Brown colour solid
deposited around theelectrode,
The blue colour of CuSO4
remain unchanged.
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6.4.3 Electroplating method.
Electroplating method is one way of applying these finishes. Forks,
spoons, and jewellery are often electroplated to give the objects the
appearance of silver or gold while still keeping the cost of the objects
low.
At anode
Observation : silver plate is
corroded.
Half equation : Ag Ag+ + e
At cathode
Observation : silver is coated
around the bracelet
Half equation : Ag+ + e Ag
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6.5 Chemical Cell
As mentioned early in the topic, there are 2 types of conversion of
energies. In electrolytic cell, the conversion energy takes place
where . energy is converted to . energy.
In this sub-topic, the conversion takes place where CHEMICALenergy to ELECTRICAL energy. This conversion of energy is
known as CHEMICAL CELL (sometimes called as voltaic cell)
The following experiment shows basically how a simple chemical
cell works.
chemical electrical
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Electrical energy
produced. Voltagedecrease as reactant
decrease with time
Magnesium oxidise
to form magnesium
ion, while hydrogen
ion reduced to H2
No chemical
reaction takeplace
No chemical
reaction take
place
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Discussion :
A chemical cell basically worked when there is a difference between
the electrodes potential of 2 different metals. Each metal
possessed its own electrode potential. When 2 different metals
contact each other, they shall be a potential difference betweenthe metals in the form of electromotive forces (e.m.f.) in the form of
voltage.
In fact, electrochemical series is build base on the electrode
potential possessed by each metal. Table below shows the value of
the electrode potential of some metals in the electrochemical series
If both are the same metal, theres no difference in electrode
potential, thus theres no e.m.f. [Exp 2]
Metal Ag+ Cu2+ H+ Pb2+ Sn2+ Fe2+ Zn2+ Al3+ Mg2+ Na+ K+
Eo (V) +0.80 +0.34 0.00
0.14
0.23
0.44
0.76
1.66
2.38
2.71
2.91
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Higher the position in electrochemical series, the more stable it is as
a positive ion. Since magnesium has higher position than copper, so
magnesium tends to donate electron to form a more stable
magnesium ion.
Half equation : Mg (s) Mg2+ (aq) + 2 e- [Magnesium corroded]
This is also supported by the deflection of needle where the
deflection move to right (where electron is
donated by magnesium). Since magnesium donate electrons,
it is the of the cell. In the solution now contain Mg2+ (from Mg) ; Na+ (from salt)
and H+(from aqueous solution), so theres a selection of ions
to be discharge in copper electrode, which act as
. of the cell as it tend to receiveelectron from magnesium plate. In cathode, one with lower
position in ECS will be selected, so hydrogen will be selected.
negative terminal (anode)
positive terminal (cathode)
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Half equation : 2 H+ (aq) + 2e- H2 (g)
[hydrogen gas evolve at copper electrode]
In chemical cell, when the anode and cathode are recognised, an
overall equation can be written by
Anode : Mg (s) Mg2+ (aq) + 2 e- [electrons are donated]
Cathode : 2 H+ (aq) + 2e- H2 (g) [electrons are received]
Overall :
In short, when there are 2 different metals, the higher position metal
in ECS will be the of the cell (donate electrons) while the
metal with the lower position in ECS will be the of the
cell (receive electrons)
Mg (s) + 2 H+ (g) Mg2+ (aq) + H2 (g)
anode
cathode
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6.6 Daniel Cell
A Daniel cell is typical chemical cell that is builds by 2 different
metals immerse in each of its aqueous solution separately
connected by wires and salt bridge or porous pot as shown in the
diagram.V
V
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Salt bridge contains inert ion or salts that does not react with
electrolyte such as sodium chloride, potassium chloride or
sulphuric acid. The function of the salt bridge / porous pot in
the Daniel cell
Similar to the simple chemical cell, the electrodes are divided
to anode and cathode where
Electrode Anode Cathode
Function
Terminal
To complete the chemical cell
To separate between the 2 chemical cells.
To donate electrons To receive electrons
Negative terminal Positive terminal