dynamics 1
DESCRIPTION
Dynamics of structuresTRANSCRIPT
1
Dynamics of Structures
I. Introduction 1.1 Dynamic and Dynamics
Dynamic load--- any load of which its magnitude, direction, and/or point of application varies with
the time. If it is applied to an engineering structure, the resulting deflections and stresses
(response) are also time-varying (dynamic).
If the loading is a known function of time, the corresponding analysis of a specified structural
system is called a deterministic analysis. Otherwise, if the time history of the loading is not
completely known (or only known in a statistical sense---random), the structural response analysis
is nondeterministic.
Static, statics
1.2 Investigation of the Dynamical Behaviour of Structures Design, analysis and testing
Fig.1.1 Steps in a dynamic investigation
1.3 Degrees of Freedom The number of independent coordinates necessary to specify the configuration or position of a
system at any time is referred to as the number of degrees of freedom (DOF).
The analytical models in analysis stage fall into two basic categories:
discrete-parameter models
continuous models
Figure 1.2 shows these models of a cantilever beam (small deformation). The discrete-parameter
models here are called lumped-mass models because the mass of the system is assumed to be
represented by a small number of point masses, or particles. They are described by finite DOF systems,
while a continuous model represents an infinite DOF system (Fig.1.2c).
Existing Structure or
Design, drawings and data
Analytical model
(assumption, sketches, etc.)
Dynamic Bahviour
(Solutions of DE's)
Mathematical Model
(Differential equations)
Dynamic Testing
Physical Model
Meet
requirement Stop
Design
Analysis
Testing
Yes
No
2
(a) One DOF model (b) Three DOF model (c) Distributed mass model
Fig.1.2 Discrete-parameter and continuous analytical models of a cantilever beam.
However, in cases where the mass of the system is quite uniformly distributed throughout, an
alternative approach to limiting the number of degrees of freedom may be preferable. This procedure is
based on the assumption that the deflected shape of the structure can be expressed as the sum of a
series of specified displacement patterns. The amplitudes of these patterns may be considered to be the
displacement coordinates of the system, and the infinite number of DOF of the actual beam is
represented by the infinite number of terms included in the series. Generally, the expression for the
displacement of any one-dimensional structure might be
n
nn xZxu )()(
where n(x) represents a geometric shape function which is compatible with the prescribed geometric-
support conditions and maintains the necessary continuity. Its contribution to the resulting shape of the
structure depends upon the amplitude Zn, which will be referred to as generalised coordinates.
1.4 Formulation of the Equations of Motion Various types of force
Elastic force ukf s , (u=u2-u1)
k is called spring constant (N/m)
Viscous force ucf D
c is called coefficient of viscous damping
(damping constant) (N s/m)
Inertial force auu
f mmdt
dm
dt
dI
)(
A force developed by the moving mass is proportional to its acceleration and opposing it----
d'Alembert force. Typical inertia forces are shown in Fig.1.3.
Fig.1.3 Inertia forces
Direct equilibrium (using d'Alembert's principle)
From the mathematical expressions of Newton's second law of motion
uu
p mdt
dm
dt
dt )()(
----suitable for many simple problems
Other methods to form the equation of motion include principle of virtual displacement and
variational approach based on Hamilton's principle (well-known principle of minimum potential
energy in static analysis).
u(t)
x
u(x, t)
x
u3(t)
x
u1(t) u2(t)
fs
fs
u1 u2
u1 u2
fD
fD
max
may
)(12
22 cbm
I o
b
c
max
may
2
2
1rmI o
r
3
II. Single-Degree-of-Freedom Systems (SDOF)
2.1 Basic Dynamic System and its Equation of Motion The essential physical properties of any linearly elastic structural or mechanical system subjected to an
external source of excitation or dynamic loading are its mass, elastic properties and energy-loss
mechanism or damping. In the simplest model of a SDOF system, each of these properties is assumed
to be represented by a single physical element (mass block, spring and dashpot). A sketch of such a
system is shown in Fig. 2.1
(a) basic components (b) free body diagram
Fig.2.1 SDOF model
Derivation of the equation of motion by d'Alembert's principle
(1) select free body
(2) apply external and internal loads
(3) add inertia force
(4) consider the equilibrium of the body
)(tpfff SDI (2.1)
Substituting expressions of the relevant forces, the final equation of motion is
)()()()( tptuktuctum (2.2)
Derivation of the equation of motion by virtual displacement principle
If the mass is given a virtual displacement u compatible with the system's constraints, the total virtual
work done by the equilibrium system of forces must be zero
0)( utpufufuf SDI (2.3)
Considering u is arbitrary and nonzero, the same equation of motion as Eq.(2.2) can be obtained.
Example 1: Influence of weight (gravitational forces)
Rotating the model of Fig2.1(a) clockwise to a vertical position (90 degree) as shown in Fig.2.2,
the influence of weight of the mass must be considered in equilibrium equation of the system.
Fig.2.2 Influence of weight Fig.2.3 Influence of support excitation
m
k
c p(t)
u(t)
p(t)
u(t)
fI(t) fs(t)
fD W
st
ur(t)
u(t)
unstretched
length
ut(t)
u(t)
ug(t)
Fixed
line
c
k/2 k/2
m p(t)
4
)()()()( tpWtuktuctum (2.4)
Because rst uu and kWst / is the static displacement of the mass on the linear spring and
ur is the displacement of the mass measured relative to the static equilibrium position, the equation of
motion after substituting these relation into Eq.(2.4) is simplified to
)()()()( tptuktuctum rrr (2.5)
Example 2: Influence of support movement
Dynamic stresses and deflections can be induced in a structure not only by a time-varying applied
load, but also by motions of its support points such as the motions of a building caused be
earthquake etc. (Fig.2.3).
Since the inertial force in this case is given by
)()( tumtf t
I , (2.6)
the equilibrium equation leads
)()()()( tptuktuctum t (2.4)
Where total displacement ut , the displacement of the structure's base relative to a fixed reference axis
ug and the structure's displacement relative to the support u has a relation of
)()()( tututu g
t . (2.5)
The equation of motion of Eq.(2.4) can more conveniently be written
)()()()()()()( tptptumtptuktuctum effg (2.6)
2.2 Analysis of SDOF System The solution of the general equation (2.2) of motion is
u(t)=up(t)+uc(t) (2.7)
where up(t) is a particular solution related directly to p(t) and uc(t) a complementary solution. To find
up(t) and uc(t), it is convenient to rewrite Eq.(2.2) as
)(22
2 tpk
uuu (2.8)
where 2=k/m and is called the (undamped) circular frequency and is a dimensionless quantity
called the viscous damping factor and
cc
c
m
c
2 . (2.9)
cc is critical damping coefficient. Both and are very important parameters determining the response
of a SDOF system.
2.2.1 Free vibration of undamped SDOF system
The equation of motion 02uu (2.10)
The solution tu
tuu sin)0(
cos)0(
)sin()cos( 1tt (2.11)
where
/)0(
)0(tan and
)0(
/)0(tan ,
)0()0( 1
2
2
u
u
u
uuu
(2.12)
The natural frequency is defined by 2
f , which has a unit of Hz (=1cycle/s). Its reciprocal is the
undamped natural period T=1/f =2 / . The rotating vector representation in complex plane and general
response curve in time domain are shown in Fig.2.4 and Fig.2.5 respectively.
5
Fig.2.4 The vector representation of displacement Fig.2.5 General response curve in time domain
in complex plane
2.2.2 Free vibration of damped SDOF system
The equation of motion 02 2uuu (2.13)
Assume a solution of the form rtCeu , we obtain the characteristic equation
02 22 rr (2.14)
and 12
2
1
r
r (2.15)
The solution depends on the value of which can be used to distinguish three cases:
>1, i.e., c>cc overdamped case
The solution ]11[ 2
2
2
1 tshCtchCeu t
]11
)0()0(1)0([ 2
2
2 tshuu
tchue t (2.16)
=1, i.e., c=cc, critically-damped case
The solution ]))0()0(()0([)( 21 tuuuetCCeu tt (2.17)
Example 3: An example for both nonoscillatory responses is seen in Fig. 2.6
Fig.2.6 Nonoscillatory response systems
<1, i.e., c<cc underdamped case
Diir
r2
2
11 (2.18)
t
R
I
t
u(0)
ù(0)/
/ T=2 /
u(0) ù(0)
t
u(t)
0.8
1.6
=1
=2
u(t) (cm)
0.8 1.6 2.4
t (sec)
srad
scmu
u
/5
/20)0(
0)0(
6
and 21D is called damped circular frequency. The solution of Eq.(2.13) is
]sin)0()0(
cos)0([ tuu
tueu D
D
D
t
)cos( te D
t (2.19)
where
)0(
)0()0(tan and
)0()0()0(
2
2
u
uuuuu
DD
(2.20)
The free vibration response of undercritically damped (underdamped) system with zero initial velocity
is shown in Fig. 2.7.
Fig.2.7 Free vibration response of underdamped system
Logarithmic decrement of damping which is defined by
21
2ln
21n
n
u
u (2.21)
2.2.3 Response of SDOF system to harmonic loading
Assume a SDOF system is subjected to a load varying harmonically with time, saying sine- (or/and
cosine-) wave form. Without loss generality, p(t) in Eq.(2.2) can be assumed a force having an
amplitude p0 and circular frequency and
tptuktuctum sin)()()( 0 (2.22)
A complementary solution uc(t) and the particular solution up(t) of above equation are respectively
t
DDc etBtAu )sincos( (2.23)
]cos2sin)1[()2()1(
1 2
222
0 ttk
pu p (2.24)
where = / is defined as the ratio of the applied loading frequency to the natural vibration
frequency (frequency ratio). The unknown constant A and B should be determined from the initial
condition of the system. For example, if 0)0()0( uu , then
222
22
0
222
0
)2()1(
)1(2 and
)2()1(
2
Dk
pB
k
pA
2 / D 4 / D / D 3 / D
u1
u2
te
)0(uD
u(t)
t
0)0(u
7
(a) Response of undamped system ( =0). From Eqs.(2.23) and (2.24), we have
tk
ptBtAu sin
1
1sincos
2
0 . (2.25)
Considering an initial condition of zero displacement and velocity, the above solution becomes
)sin(sin1
12
0 ttk
pu . (2.26)
Response ratio
)sin(sin1
1
/
)()(
2
0
ttkp
tutR (2.27)
(b) Steady-state harmonic response of damped system
The response is given by Eq.(2.24) because complementary will decay soon (with no interest) in
damped system. Eq.(2.24) can be written as
)sin()( ttu p . (2.28)
Where 2222
0
1
2 tanand
)2()1(
1
k
p (2.29)
Magnification factor
2220 )2()1(
1
/ kpD (2.30)
Fig.2.8 Variation of magnification factor with frequency ratio
0
30
60
90
120
150
180
0 0.5 1 1.5 2 2.5
Ph
ase
angle
Frequency ratio
Fig.2.9 Variation of phase angle with frequency ratio
0
1
2
3
4
5
0 1 2
Mag
nif
icat
ion
fac
tor
D
Frequency ratio
8
(c) Resonant response
It is apparent that from Fig.2.8 the steady-state response amplitude of an undamped system tends
towards infinity as the frequency ratio approaches unity. For some other lower value of damping, it is
seen that the maximum steady-state response amplitude occurs at a frequency ratio slightly less than
unity. To find the maximum or peak value of dynamic magnification factor, the differentiating result of
Eq.(2.30) with respect to will give
221peak (2.31)
and 2
max
12
1D (2.32)
Even so, the response resulting from the unity frequency ratio, i.e., the frequency of the applied loading
equals to the undamped natural vibration frequency, is called resonance. Under this condition,
2
1maxD (2.33)
(the difference between Eqs.(2.32) and (2.33) is only 2 percent for =0.2). At the resonant exciting
frequency ( =1), the displacement response becomes
2
cos)sincos( 0 t
k
petBtAu t
DD (2.34)
If the system starts from rest (zero velocity and displacement initial conditions), then
]cos)sin1
[(cos2
1
2
0 tettk
pu t
DD (2.35)
The response ratio kp
u
/0
has an envelope of 2
1.
(d) Vibration isolation
Two types of isolation problems:
Prevent oscillatory forces of the system from support
A rotating unbalance SDOF system is shown in left figure and its
steady-state displacement response is
)sin()( 0 tk
Dptu p
The force transfer to the foundation can be estimated on
)sin()( 0 tDptkufS
)cos(2)cos()( 0
0 tDptk
DcptucfD
Fig. 2.10
The total maximum force transfer to the foundation is
2
0max
2/122
max )2(1|)( Dpfff Ds , and 2
0max )2(1/ Dpf
Transmissibility
Isolate harmful support movement from a structural system
The governing equation of relative displacement is
)()()()()( tptumtuktuctum effg (2.36)
A harmonic support movement leads a steady-state relative
displacement according to Eqs.(2.24) or (2.28) for the Eq.(2.36)
)sin()sin()( 0 tDk
pttu p
Fig. 2.11
tptp sin)( 0
u(t)
k c
m
f=fS+fD
tuug sin0
ut(t)=ug(t)+u(t)
k c
m
9
]cos2sin)1[()2()1(
2
222
2
0 ttu
The total displacement is )()()( ttt g
tuuu
(Note: the main contribution to u(t) is only from up(t)).
Similarly 2
0max )2(1/ Duu t (2.37)
Fig.2.12 Variation of transmissibilitywith frequency ratio
2.3 Response to Impulsive Loading Property
The load is of short duration
Damping has much less importance in controlling the maximum response of a structure because
the maximum response to a particular impulsive load will be reached in a very short time, before the
damping forces can absorb much energy from the structure.
Two phases: forced and free vibration during and after loading respectively.
Example 4: Response of sine wave impulse
Phase 1
During this phase, the structure is subjected to a single half -
sine wave loading as shown in the right figure. Assuming
that the system starts from rest, the undamped response
ratio, including the transient as well as the steady-state term,
is given by Eq.(2.27)
)sin(sin1
1
/
)()(
2
0
ttkp
tutR (t1 t) (2.38)
where
112
2
tt and
11 2t
T
t Fig.2.13
Phase 2
The free vibration which occurs during this phase (t t1) depends on the displacement u(t1) and velocity
)( 1tu existing at the end of Phase I. In terms of the response ratio, it depends on the values of R(t1) and
)( 1tR . Considering the displacement response of free vibration of undamped system Eq.(2.11), we
have
t-t1
Phase I
p0
t
p(t)
t1
Phase II
0
1
2
3
4
5
0 0.5 1 1.5 2 2.5
Tra
nsm
issi
bil
ity
Frequency ratio
10
)(sin)(
)(cos)()( 11
11 tttR
tttRtR
(t t1) (2.39)
Note that from Eq.(2.38) sin1
)(21tR and )cos1(
1)(
21tR , then
)()2
sin()2
cos(1
2)]sin([sin
1
)]sin()cos1()cos([sin1
)(
122
2
ttttt
tttR
(2.40)
The maximum (displacement) response can occur in either Phase I or Phase II depending on the ratio of
load duration t1 to the period of vibration of the structure.
However, if =1, both Eq.(2.38) and Eq.(2.40) are not suitable. Please derive the similar expressions
for the displacement response (in terms of response ratio).
Exercise: Response for rectangular and/or triangular impulses
Response of undamped system to a very short duration impulse
Let the undamped system be at rest for 0 t. The equation of
motion and initial conditions are
1
1
0
0 )()()(
tt
tttptkutum (2.41)
and 0)0()0( uu (2.42) Fig.2.14
Integrating Eq.(2.41) with respect to time and incorporating the initial conditions, we have
1
01 )]()([)(
t
dttkutptum )0 ( )( 10
1
tdttpt
Hence 1
01 )(
1)(
t
dttpm
tu and 0)( 1tu when t1 0. The impulse response is
)( )(sin)(
)(cos)()(sin)(
)( 110
1111
1
1
ttttm
dttptttutt
tuttu
t
(2.43)
It can be proved that the impulse response in damped system is
)( )(sin)(
)( 11
)(01
1
1
ttttem
dttpttu D
tt
D
t
(2.44)
If 1)(1
0
t
dttp , Eqs.(2.43) and (2.44) are called unit impulse response functions which are shown
respectively for undamped and damped systems as
)( )(sin1
)( 111 ttttm
tth (2.45)
)( )(sin1
)( 11
)(
11 tttte
mtth D
tt
D
(2.46)
t1<<T
t
p(t)
t1
11
2.4 Response to Arbitrary Loading*
General arbitrary loading, Duhamel integral (Time-domain)
For an arbitrary loading as shown in Fig.2.15. it can be considered as a combination of numerous
(infinite in fact) successive unit impulses (loading). At time t= , the loading acting during the interval
of time d represents a very short-duration impulse p( )d on the system, which leads a displacement
response increment effected from that time t- 0 .
Hence the response increment due to p( )d can be
calculated based on either Eq.(2.43) or Eq.(2.45)
for undamped system
)( )(sin)(
)( ttm
dptdu (2.47)
For linearly elastic system, the total response can
be obtained by summing all these differential
response increment developed during the load
history, that is a Duhamel integral
)0( )(sin)(1
)(0
tdtpm
tut
(2.48)
It is seen that Eq.(2.48) suggests the loading was
initiated at t=0 and the system was at rest at that
time. If the initial conditions are not zeros, the
additional free vibration response must be added to
this solution.
Fig.2.15
)0( )(sin)(1
sin)0(
cos)0()(0
tdtpm
tu
tutut
(2.49)
Should the nonzero initial conditions be produced by loading p(t) for t<0, the response can also be
found through Eq.(2.48) by changing the lower limit of the integral (from zero to minus infinity).
Similarly, the under critically damped response can be derived
t
D
t
D
dttepm
tu0
)( )(sin)(1
)( (2.50)
Arbitrary periodic loading, Fourier series expansion
Any periodic loading can be express as a series of harmonic loading via Fourier expansion
11
0 sincos)(n
nn
n
nn tbtaatp (2.51)
in which T
nn
2 and T is the period of the loading p(t).
T
dttpT
a0
0 )(1
sin)(2
and cos)(2
00
T
nn
T
nn dtttpT
bdtttpT
a (2.52)
Undamped steady-state response (superposition) ( /nn )
120 )sincos(
1
11)(
n
nnnn
n
tbtaak
tu (2.53)
Damped steady-state response (superposition)
1222
22
0)2()1(
)sin2)1(cos2)1(1)(
n nn
nnnnnnnnnn tabtbaa
ktu (2.54)
d
p( )
t
p(t)
t- 0
Response increment
t-
du(t)
12
References
[1] R. W. Clough and J Penzien. Dynamics of Structures. McGraw-Hill Inc., 2nd
edition, 1993,
Singapore.
[2] M. Paz. Structural Dynamics--theory and computation. Van Nostrand Reinhold Company Inc., 2nd
edition, 1985, New York.
[3] R. R. Craig. Structural Dynamics--an introduction to computer methods. John Wiley & Sons, 1981,
Canada.
[4] G. Vertes. Structural Dynamics. Developments in civil engineering; V.11. Elsevier, 1985,
Amsterdam.
[5] Wu Z. J., Han F. and Wu H. J. Elasticity, University Press of Beijing Institute of Technology, 2010,
ISBN 978-7-5640-3267-8. Beijing.