dynamic engineering system - linear motion notes

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  • 8/3/2019 Dynamic Engineering System - Linear Motion Notes

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    Linear MotionMotion with constant acceleration

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    Velocity

    Time

    u

    u = initial velocity

    v

    v = final velocityGradient

    gradient = acceleration

    acceleration = a

    v u

    Rearrange equation:

    t

    1

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    Velocity

    Time

    u

    u = initial velocity

    v

    v = final velocity

    v u

    Rearrange equation:

    t

    area

    under = distance

    graph

    distance = s

    Area 1

    area

    under = area 1 + area 2

    graph

    Area 2

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    We have:

    We also have:

    So,

    Rearrange equation:

    2

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    We have:

    We also have:

    So,

    Rearrange equation:

    3

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    3 Main Equations:

    }

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    Alternative method

    }

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    Alternative method

    }

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    Example 1 - Question

    }

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    Example 2 -Question

    } Find the deceleration of a car that isbrought to rest in 60 m from a speed of 45

    km/h. What is the time taken?

    } t = 9.6 s #

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    Example 3 - Question

    }

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    Example 4 - Question

    }

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    Example 4 - Solution

    } s = 133.3 m. The car hit the cow becausewith the given retardation, the car will

    stop after 133.3 m #

    } v = 16 m/s. The car hit the cow becauseafter 50 m, the car still have velocity, thatmeans the car is still moving #

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    Example 5 - Question

    }

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    Revision

    }

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    Revision

    }

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    Linear MotionVertical motion under gravity

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    Acceleration due gravity = g

    If an object moves

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    Example 1 - Question

    }An object is projected vertically upwardswith an initial velocity of 40 m/s. Calculate

    (a) the maximum height reached, (b) thetime taken to reach the maximum height,(c) the time taken for the object to fallback to its initial point of projection.

    } s = 81.5 m #

    } t = 4.1 s #

    } t = 4.1 s #

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    Revision

    }A brick falls off the top of building. If theheight of the building is 20 m, determine

    the time the bricks takes to reach theground.

    }A ball is thrown vertically upwards with avelocity of 15 m/s. Determine the greatest

    height reached above the point ofprojection.

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    Revision

    }A ball is thrown vertically downwards withan initial velocity with an initial velocity of

    4 m/s from the edge of a cliff. If the ballhits the ground at the base of the cliffafter 2s, determine the height of the cliff.