dwarf ellipticals spheroidal

8
1 Ellipticals Huge mass range: Dwarf spheroidals: 10 7 -10 8 M Blue compact dwarfs: ~10 9 M Dwarf ellipticals: 10 7 -10 9 M Normal (giant) ellipticals: 10 8 -10 13 M cD galaxies in cluster centers: 10 13 -10 14 M cD (NGC 3311) Giant E (NGC 1407) Dwarf spheroidal (Leo I) Dwarf ellipticals M32, NGC 205 HST images Hubble’s law Modified Hubble’s law deVaucouleurs’ R 1/4 law usually fits radial surface brightness distribution + others 1 33 . 3 4 / 1 10 ) ( e R R e I R I 2 1 ) ( o o R R I R I 2 1 ) ( o o R R I R I 2 / 3 2 1 ) ( o o R r I r I Diverges, but at least is projection of simple 3D distribution: cD r 1/4 Ellipticals

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Page 1: Dwarf Ellipticals spheroidal

1

Ellipticals

Huge mass range:• Dwarf spheroidals: 107-108 M

• Blue compact dwarfs: ~109 M

• Dwarf ellipticals: 107-109 M

• Normal (giant) ellipticals: 108-1013 M

• cD galaxies in cluster centers: 1013-1014 M

cD (NGC 3311)

Giant E (NGC 1407)

Dwarf spheroidal (Leo I)

Dwarf ellipticals M32, NGC 205

HST images

• Hubble’s law

• Modified Hubble’s law

• deVaucouleurs’ R1/4 law usually fits radial surface brightness distribution

• + others

133.3

4/1

10)(eR

R

eIRI

2

1

)(

o

o

RR

IRI

2

1

)(

o

o

RR

IRI 2/32

1

)(

o

o

Rr

IrI

Diverges, but at least is projection of simple 3D distribution:

cD

r1/4

Ellipticals

Page 2: Dwarf Ellipticals spheroidal

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True shapes requires statistical analysis

• Oblate = pancakes

• Prolate = footballs[CO figs 25.2, 25.3]

True shapes requires statistical analysis

• Lower luminosity rotationally supported • (Vrot / ) ~ /(1- )

• Higher L pressure supported• (Vrot / ) << 1

From Binney & Tremaine, Galactic Dynamics

= low L ellipticalsx = spiral bulges high L ellipticals

Curve expected for galaxies that are flattened by rotation (i.e. have isotropic random velocity dispersions)

CO pgs. 988-989

(V/)* = 0.7

Rotationally Supported

Ellipticity = 1 – b/a

E galaxy = K star convolved with Gaussian velocity distribution of stars.

K star

Observed Spectrum

Page 3: Dwarf Ellipticals spheroidal

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Statistics of = (1- b/a)

• Oblate, prolate spheroids can’t fit the observed distribution.

• Summing over wide range of true values of would fill in the dip at obs = 0.

• Triaxial spheroids can fit.• Nearly oblate triaxial spheroids seem

best.

3

2

1

0

0 0.2 0.4 0.6 0.8 1.0

0 0.2 0.4 0.6 0.8 1.0

4

3

2

1

0

P (obs)

P (obs)

Oblate, true = 0.7

Prolate, true = 0.5

observed

Triaxial, Axis ratios 1:0.8:0.3

From Binney & Merrifield, Galactic Astronomy

Other evidence for triaxial systems

• Isophotal twists• Kinematics (star motions)

From Binney & Merrifield, Galactic Astronomy

Page 4: Dwarf Ellipticals spheroidal

4

Orbits in E galaxies

• Some families of non-closed orbits in a mildly triaxial potential.

From Binney & Tremaine, Galactic Dynamics

E galaxies are transparent, but 40% still have some dust lanes

• Even if complete star formation at t=0, stars must subsequently have lost gas.

• Detected by:• X-rays (Brehmsstrahlung): 108-1010 M

• H I emission lines: 107-109 M

• H II emission lines: 104-105 M

• But gas can be lost by• Supernova-driven winds

• Ram pressure stripping

Page 5: Dwarf Ellipticals spheroidal

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The Virial Theorem [CO 2.4]

• For gravitationally bound systems in equilibrium• Time-averaged kinetic energy = - ½ time-averaged potential energy.

E = total energyU = potential energy.K = kinetic energy.

E = K + U

• Can show from Newton’s 3 laws + law of gravity:• ½ (d 2I/dt 2 ) - 2K = U where I = miri

2 = moment of inertia.

• Time average < d 2I/dt 2 > = 0, or at least ~ 0.

• Virial theorem -2<K> = <U><K> = - ½ <U>

<E> = <K> + <U><E> = ½ <U>

Mass determinations fromabsorption line widths

• Virial Theorem 2K = -U

K = ½ M<v2> = 3/2 M <r2>

• See pp. 959-962, + Sect. 2.4

• Applied to nuclei of spirals

presence of massive black holes

• Also often applied to• E galaxies

• Galaxy clusters

R

GMU

2

5

3

M32

G

RM r

virial

25

[CO 25.14]

Sorry… I had left out the ½ when I showed this slide in class.

Page 6: Dwarf Ellipticals spheroidal

6

Mass determinations fromabsorption line widths

• Virial Theorem 2K = -U

<v2> = 3 <vr2>

K = ½ M<v2> = 3/2 M <r2>

• See pp. 959-962, + Sect. 2.4•

• Applied to nuclei of spirals

presence of massive black holes•

• Also often applied to• E galaxies

• Galaxy clusters

R

GMU

2

5

3

G

RM r

virial

25

Fourier Transforms

E galaxy = K star convolved with Gaussian velocity distribution of stars.

K star

Star

Galaxy

Ratio

Gaussian fit: • Convolution turns into multiplication in F.T. space.• F.T. of a Gaussian is a Gaussian.

Observed Spectrum

Faber-Jackson relation: Le ~ 04

(Absolute magnitude)

133.3

4/1

10)(eR

R

eIRIIe = surface brightness at Re

Le = luminosity within Re

Page 7: Dwarf Ellipticals spheroidal

7

Mass-Luminosity relationships

133.3

4/1

10)(eR

R

eIRI

From Binney & Merrifield, Galactic Astronomy

CO give different coefficients???

re 01.24Ie

-0.82

L 02.65re

0.65

• Faber-Jackson relation: Le ~ 04

• Dn - 0 correlation.• Dn = diameter within which <I> = 20.75 B

• Fundamental plane in log Re, <I>e, log 0 space• Re = scale factor in R1/4 law

• <I>e = mean surface brightness within Re Different from Ie !

• Intro. to Principle Component Analysis: astro-ph/9905079

mag/arcsec2

Distribution of galaxy types

• Dense regions (cluster centers) predominantly ellipticals.

• Field galaxies predominantly spirals.

• On average, roughly even split between E and S.

E

S

S0

Log (Projected surface density of galaxies)

Fra

ctio

n of

pop

ulat

ion

Total number of galaxies

Dressler 1980

Page 8: Dwarf Ellipticals spheroidal

8

Schechter Luminosity Function (L)dL = L e-L/L* dL

(M)dM = 10 –0.4(+1)M e –10 dM

• The Milky Way is an L* galaxy.

0.4(M * - M)

[CO 25.36]

[BM 4.12]

moreluminous

-22 -20 -18 -16MB

-1

-3

-5

-7

Log

(g

alax

ies/

Mpc

3 )

moreluminous

Problem 24.36: “Point mass M0 at center of MW + mass distributed with density (r) 1/r2. (a) Show that Mr= kr+M0.”

Correct:

Wrong: anything that does not show that you realized that you need to integrate over

G

vRM esc

2

20

0

2

2 R

GmMmvesc

G

vRM esc

20

Problem 24.15: “Assuming that the highest velocity stars are near the escape speed, estimate the mass of the M.W.”

Correct: vesc = vcirc + max vpec = 220 + 65 ~ 300 km s-1.

K.E. = Potential Energy

Wrong: follow example 24.3.1 and calculate mass required to hold star in circular orbit with v = 300 km s-1

rCMrdrr

CMrdvolrMM

rr

r

0 0

22000 44)()(

)()( rdvolr

Black Hole