amercado.mat.utfsm.clamercado.mat.utfsm.cl/seminariolatam-esp_controlypi/casas.pdf · draft 4/33 uc...
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An optimal control problem of anonmontone semilinear elliptic equation
Eduardo CasasUniversity of CantabriaSantander, [email protected]
A joint work with Mariano Mateos (University of Oviedo, Spain) and Arnd Rosch (University ofDuisburg-Essen, Germany)
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The Control Problem
(P) minu∈Uad
J(u) :=1
2
∫Ω
(yu(x)−yd(x))2 dx+ν
2
∫Ω
u2(x) dx (ν > 0)
Seminario Control en Tiempos de Crisis 2020
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The Control Problem
(P) minu∈Uad
J(u) :=1
2
∫Ω
(yu(x)−yd(x))2 dx+ν
2
∫Ω
u2(x) dx (ν > 0)
Uad =u ∈ L2(Ω) : α ≤ u(x) ≤ β a.e. in Ω(−∞ ≤ α < β ≤ +∞)
Seminario Control en Tiempos de Crisis 2020
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The Control Problem
(P) minu∈Uad
J(u) :=1
2
∫Ω
(yu(x)−yd(x))2 dx+ν
2
∫Ω
u2(x) dx (ν > 0)
Uad =u ∈ L2(Ω) : α ≤ u(x) ≤ β a.e. in Ω(−∞ ≤ α < β ≤ +∞)
Ay + b(x) · ∇y + f (x, y) = u in Ω
y = 0 on Γ
Seminario Control en Tiempos de Crisis 2020
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Assumptions on the Linear Operator
• Ω is an open domain in Rn, n = 2 or 3, with Lipschitz boundary Γ
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Assumptions on the Linear Operator
• Ω is an open domain in Rn, n = 2 or 3, with Lipschitz boundary Γ
• Ay = −n∑
i,j=1
∂xj(aij(x)∂xiy) with aij ∈ L∞(Ω),
Seminario Control en Tiempos de Crisis 2020
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Assumptions on the Linear Operator
• Ω is an open domain in Rn, n = 2 or 3, with Lipschitz boundary Γ
• Ay = −n∑
i,j=1
∂xj(aij(x)∂xiy) with aij ∈ L∞(Ω),
• ∃Λ > 0 such thatn∑
i,j=1
aij(x)ξiξj ≥ Λ|ξ|2 ∀ξ ∈ Rn and for a.a. x ∈ Ω
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Assumptions on the Linear Operator
• Ω is an open domain in Rn, n = 2 or 3, with Lipschitz boundary Γ
• Ay = −n∑
i,j=1
∂xj(aij(x)∂xiy) with aij ∈ L∞(Ω),
• ∃Λ > 0 such thatn∑
i,j=1
aij(x)ξiξj ≥ Λ|ξ|2 ∀ξ ∈ Rn and for a.a. x ∈ Ω
• Ay = Ay + b(x) · ∇y + a0(x)y, a0 ≥ 0
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Assumptions on the Linear Operator
• Ω is an open domain in Rn, n = 2 or 3, with Lipschitz boundary Γ
• Ay = −n∑
i,j=1
∂xj(aij(x)∂xiy) with aij ∈ L∞(Ω),
• ∃Λ > 0 such thatn∑
i,j=1
aij(x)ξiξj ≥ Λ|ξ|2 ∀ξ ∈ Rn and for a.a. x ∈ Ω
• Ay = Ay + b(x) · ∇y + a0(x)y, a0 ≥ 0
• b ∈ Lp(Ω) and a0 ∈ Lq(Ω), a0 ≥ 0,
• with p > 2 and q > 1 if n = 2, p ≥ 3 and q ≥ 3
2if n = 3
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References
• N.S. Trudinger: “Linear elliptic equations with measurable coeffi-
cients”, Ann. Scuola Norm. Sup. Pisa 27 (1973) 265–308.
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References
• N.S. Trudinger: “Linear elliptic equations with measurable coeffi-
cients”, Ann. Scuola Norm. Sup. Pisa 27 (1973) 265–308.
• D. Gilbarg and N.S. Trudinger: “Elliptic Partial Differential Equations
of Second Order”, Springer-Verlag, 1983.
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References
• N.S. Trudinger: “Linear elliptic equations with measurable coeffi-
cients”, Ann. Scuola Norm. Sup. Pisa 27 (1973) 265–308.
• D. Gilbarg and N.S. Trudinger: “Elliptic Partial Differential Equations
of Second Order”, Springer-Verlag, 1983.
• L. Boccardo: “Stampacchia-Calderon-Zygmund theory for linear ellip-
tic equations with discontinuous coefficients and singular drift”, ESAIM
Control Optim. Calc. Var. 25 (2019).
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Garding’s Inequality
Lemma. Under the previous assumptionsA ∈ L(H10(Ω), H−1(Ω)) and
there exists a constant CΛ,b such that
〈Az, z〉H−1(Ω),H10 (Ω) ≥
Λ
4‖z‖2
H10 (Ω)− CΛ,b‖z‖2
L2(Ω) ∀z ∈ H10(Ω).
Seminario Control en Tiempos de Crisis 2020
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
• We take 0 < ρ < ess supx∈Ωy(x), z(x) = (y(x)− ρ)+.
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
• We take 0 < ρ < ess supx∈Ωy(x), z(x) = (y(x)− ρ)+.
• Ωρ = x ∈ Ω : ∇z(x) 6= 0.
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
• We take 0 < ρ < ess supx∈Ωy(x), z(x) = (y(x)− ρ)+.
• Ωρ = x ∈ Ω : ∇z(x) 6= 0. |Ωρ| → 0 when ρ→ ess supx∈Ωy(x).
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
• We take 0 < ρ < ess supx∈Ωy(x), z(x) = (y(x)− ρ)+.
• Ωρ = x ∈ Ω : ∇z(x) 6= 0. |Ωρ| → 0 when ρ→ ess supx∈Ωy(x).
• 0 ≥ 〈Az, z〉 ≥ Λ‖∇z‖2L2(Ω)3 − ‖b‖L3(Ωρ)3‖∇z‖L2(Ω)3‖z‖L6(Ω)
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
• We take 0 < ρ < ess supx∈Ωy(x), z(x) = (y(x)− ρ)+.
• Ωρ = x ∈ Ω : ∇z(x) 6= 0. |Ωρ| → 0 when ρ→ ess supx∈Ωy(x).
• 0 ≥ 〈Az, z〉 ≥ Λ‖∇z‖2L2(Ω)3 − ‖b‖L3(Ωρ)3‖∇z‖L2(Ω)3‖z‖L6(Ω)
• ≥ Λ‖∇z‖2L2(Ω)3 − CΩ‖b‖L3(Ωρ)3‖∇z‖2
L2(Ω)3
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A Monotonicity Result
Lemma. If Ay ≤ 0⇒ y ≤ 0 (Gilbarg and Trudinger).
• We take 0 < ρ < ess supx∈Ωy(x), z(x) = (y(x)− ρ)+.
• Ωρ = x ∈ Ω : ∇z(x) 6= 0. |Ωρ| → 0 when ρ→ ess supx∈Ωy(x).
• 0 ≥ 〈Az, z〉 ≥ Λ‖∇z‖2L2(Ω)3 − ‖b‖L3(Ωρ)3‖∇z‖L2(Ω)3‖z‖L6(Ω)
• ≥ Λ‖∇z‖2L2(Ω)3 − CΩ‖b‖L3(Ωρ)3‖∇z‖2
L2(Ω)3
• ‖b‖L3(Ωρ)3 ≥ ΛCΩ
> 0 ∀ρ
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Invertibility of ATheorem. The operator A : H1
0(Ω) −→ H−1(Ω) is an isomorphism.
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Invertibility of ATheorem. The operator A : H1
0(Ω) −→ H−1(Ω) is an isomorphism.
• Set Aty = Ay + tb(x) · ∇y + a0(x)y for t ≥ 0.
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Invertibility of ATheorem. The operator A : H1
0(Ω) −→ H−1(Ω) is an isomorphism.
• Set Aty = Ay + tb(x) · ∇y + a0(x)y for t ≥ 0.
• The injectivity of At is a consequence of the monotonicity.
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Invertibility of ATheorem. The operator A : H1
0(Ω) −→ H−1(Ω) is an isomorphism.
• Set Aty = Ay + tb(x) · ∇y + a0(x)y for t ≥ 0.
• The injectivity of At is a consequence of the monotonicity.
• I = t ∈ [0, 1] : At : H10(Ω) −→ H−1(Ω) is an isomorphism.
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Invertibility of ATheorem. The operator A : H1
0(Ω) −→ H−1(Ω) is an isomorphism.
• Set Aty = Ay + tb(x) · ∇y + a0(x)y for t ≥ 0.
• The injectivity of At is a consequence of the monotonicity.
• I = t ∈ [0, 1] : At : H10(Ω) −→ H−1(Ω) is an isomorphism.
• I is a nonempty relatively open set:
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Invertibility of ATheorem. The operator A : H1
0(Ω) −→ H−1(Ω) is an isomorphism.
• Set Aty = Ay + tb(x) · ∇y + a0(x)y for t ≥ 0.
• The injectivity of At is a consequence of the monotonicity.
• I = t ∈ [0, 1] : At : H10(Ω) −→ H−1(Ω) is an isomorphism.
• I is a nonempty relatively open set: 0 ∈ I and
‖At −At′‖L(H10 (Ω),H−1(Ω)) ≤ C|t− t′|‖b‖L2(Ω)n
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• I is a closed set: Let tk∞k=1 ⊂ I such that tk → t.
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• I is a closed set: Let tk∞k=1 ⊂ I such that tk → t. Let f ∈ H−1(Ω)
and yk∞k=1 ⊂ H10(Ω) such that Atkyk = f .
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• I is a closed set: Let tk∞k=1 ⊂ I such that tk → t. Let f ∈ H−1(Ω)
and yk∞k=1 ⊂ H10(Ω) such that Atkyk = f .
• If yk∞k=1 is bounded in L2(Ω), then Garding’s inequality implies that
yk∞k=1 is bounded in H10(Ω) and, for a subsequence, yk y in H1
0(Ω)
and Aty = limk→∞Atkyk = f .
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• I is a closed set: Let tk∞k=1 ⊂ I such that tk → t. Let f ∈ H−1(Ω)
and yk∞k=1 ⊂ H10(Ω) such that Atkyk = f .
• If yk∞k=1 is bounded in L2(Ω), then Garding’s inequality implies that
yk∞k=1 is bounded in H10(Ω) and, for a subsequence, yk y in H1
0(Ω)
and Aty = limk→∞Atkyk = f .
• If yk∞k=1 is not bounded in L2(Ω), then we take zk = 1‖yk‖L2(Ω)
yk.
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• I is a closed set: Let tk∞k=1 ⊂ I such that tk → t. Let f ∈ H−1(Ω)
and yk∞k=1 ⊂ H10(Ω) such that Atkyk = f .
• If yk∞k=1 is bounded in L2(Ω), then Garding’s inequality implies that
yk∞k=1 is bounded in H10(Ω) and, for a subsequence, yk y in H1
0(Ω)
and Aty = limk→∞Atkyk = f .
• If yk∞k=1 is not bounded in L2(Ω), then we take zk = 1‖yk‖L2(Ω)
yk.
Garding’s inequality implies that zk∞k=1 is bounded in H10 (Ω) and, for
a subsequence, zk z in H10(Ω) and
Atz = limk→∞Atkzk = lim
k→∞
1
‖yk‖L2(Ω)
f = 0.
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• I is a closed set: Let tk∞k=1 ⊂ I such that tk → t. Let f ∈ H−1(Ω)
and yk∞k=1 ⊂ H10(Ω) such that Atkyk = f .
• If yk∞k=1 is bounded in L2(Ω), then Garding’s inequality implies that
yk∞k=1 is bounded in H10(Ω) and, for a subsequence, yk y in H1
0(Ω)
and Aty = limk→∞Atkyk = f .
• If yk∞k=1 is not bounded in L2(Ω), then we take zk = 1‖yk‖L2(Ω)
yk.
Garding’s inequality implies that zk∞k=1 is bounded in H10 (Ω) and, for
a subsequence, zk z in H10(Ω) and
Atz = limk→∞Atkzk = lim
k→∞
1
‖yk‖L2(Ω)
f = 0.
Now, the injectivity implies z = 0, which contradicts ‖z‖L2(Ω) = 1.
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Regularity of the Solution
Theorem. Let y ∈ H10(Ω) satisfy Ay = u for some u ∈ Lp(Ω) with
p > n2 . Then, there exist µ ∈ (0, 1) and CA,µ independent of u such
that y ∈ C0,µ(Ω) and
‖y‖C0,µ(Ω) ≤ CA,µ‖u‖Lp(Ω).
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Regularity of the Solution
Theorem. Let y ∈ H10(Ω) satisfy Ay = u for some u ∈ Lp(Ω) with
p > n2 . Then, there exist µ ∈ (0, 1) and CA,µ independent of u such
that y ∈ C0,µ(Ω) and
‖y‖C0,µ(Ω) ≤ CA,µ‖u‖Lp(Ω).
Theorem. Assume that aij ∈ C0,1(Ω) for 1 ≤ i, j ≤ n, and a0 ∈L2(Ω). We also suppose that Γ is of class C1,1 or Ω is convex. Then,
A : H2(Ω) ∩H10(Ω) −→ L2(Ω) is an isomorphism.
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The Adjoint Equation
Corollary. The adjoint operator A∗ : H10(Ω) −→ H−1(Ω) given by
A∗ϕ = A∗ϕ− div[b(x)ϕ] + a0(x)ϕ
is an isomorphism.
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The Adjoint Equation
Corollary. The adjoint operator A∗ : H10(Ω) −→ H−1(Ω) given by
A∗ϕ = A∗ϕ− div[b(x)ϕ] + a0(x)ϕ
is an isomorphism.
Corollary. Assume that aij ∈ C0,1(Ω) for 1 ≤ i, j ≤ n, and
a0 ∈ L2(Ω). We also suppose that div b ∈ L2(Ω), Γ is of class C1,1 or
Ω is convex. Then, A∗ : H2(Ω)∩H10(Ω) −→ L2(Ω) is an isomorphism.
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The Adjoint Equation
Corollary. The adjoint operator A∗ : H10(Ω) −→ H−1(Ω) given by
A∗ϕ = A∗ϕ− div[b(x)ϕ] + a0(x)ϕ
is an isomorphism.
Corollary. Assume that aij ∈ C0,1(Ω) for 1 ≤ i, j ≤ n, and
a0 ∈ L2(Ω). We also suppose that div b ∈ L2(Ω), Γ is of class C1,1 or
Ω is convex. Then, A∗ : H2(Ω)∩H10(Ω) −→ L2(Ω) is an isomorphism.
Proof. A∗ϕ = A∗ϕ− b(x)∇ϕ + (a0(x)− div b(x))ϕ
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The Semilinear Equation
• f : Ω× R→ R is a Caratheodory function, monotone nondecreasing
with respect to the second variable
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The Semilinear Equation
• f : Ω× R→ R is a Caratheodory function, monotone nondecreasing
with respect to the second variable
• ∀M > 0 ∃φM ∈ Lp(Ω) with p >n
2: |f (x, y)| ≤ φM(x)
for a.a. x ∈ Ω and ∀|y| ≤M
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The Semilinear Equation
• f : Ω× R→ R is a Caratheodory function, monotone nondecreasing
with respect to the second variable
• ∀M > 0 ∃φM ∈ Lp(Ω) with p >n
2: |f (x, y)| ≤ φM(x)
for a.a. x ∈ Ω and ∀|y| ≤M
Theorem. For every u ∈ Lp(Ω) the semilinear equation has a unique
solution yu in H10(Ω) ∩ C(Ω).
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The Semilinear Equation
• f : Ω× R→ R is a Caratheodory function, monotone nondecreasing
with respect to the second variable
• ∀M > 0 ∃φM ∈ Lp(Ω) with p >n
2: |f (x, y)| ≤ φM(x)
for a.a. x ∈ Ω and ∀|y| ≤M
Theorem. For every u ∈ Lp(Ω) the semilinear equation has a unique
solution yu in H10(Ω) ∩ C(Ω). Moreover, there exists a constant Kf
independent of u such that
‖yu‖H10 (Ω) + ‖yu‖C(Ω) ≤ Kf
(‖u‖Lp(Ω) + ‖f (·, 0)‖Lp(Ω) + 1
)
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References
• T. Del Vecchio and M.M. Porzio: “Existence results for a class of
noncoercive Dirichlet problems”, Ricerche Mat. 44 (1995) 421–438.
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References
• T. Del Vecchio and M.M. Porzio: “Existence results for a class of
noncoercive Dirichlet problems”, Ricerche Mat. 44 (1995) 421–438.
• L. Boccardo: “Two semilinear Dirichlet problems “almost” in duality”,
Boll. Unione Mat. Ital. 12 (2019) 349–356.
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A Monotonicity Result
Lemma. Under the assumptions of the above theorem, if y1, y2 ∈H1
0(Ω) ∩ C(Ω) are solutions of the equations
Ayi + b(x) · ∇yi + f (x, yi) = ui, i = 1, 2,
with u1, u2 ∈ Lp(Ω) and u1 ≤ u2 in Ω, then y1 ≤ y2 in Ω as well.
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A Monotonicity Result
Lemma. Under the assumptions of the above theorem, if y1, y2 ∈H1
0(Ω) ∩ C(Ω) are solutions of the equations
Ayi + b(x) · ∇yi + f (x, yi) = ui, i = 1, 2,
with u1, u2 ∈ Lp(Ω) and u1 ≤ u2 in Ω, then y1 ≤ y2 in Ω as well.
• The uniqueness of a solution of the state equation is consequence of
the above lemma.
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R.
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
fk(x, y) = f (x,miny, k)
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
fk(x, y) = f (x,miny, k)⇒ φ(x) ≤ fk(x, y) ≤ φk(x)
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
fk(x, y) = f (x,miny, k)⇒ φ(x) ≤ fk(x, y) ≤ φk(x)
Ayk + b(x) · ∇yk + fk(x, yk) = u
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
fk(x, y) = f (x,miny, k)⇒ φ(x) ≤ fk(x, y) ≤ φk(x)
Ayk + b(x) · ∇yk + fk(x, yk) = u
Ay + b(x) · ∇y = u− φ
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
fk(x, y) = f (x,miny, k)⇒ φ(x) ≤ fk(x, y) ≤ φk(x)
Ayk + b(x) · ∇yk + fk(x, yk) = u
Ay + b(x) · ∇y = u− φA(y − yk) + b(x) · ∇(y − yk) = fk(x, yk)− φ ≥ 0
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Existence: Sketch of Proof
• We redefine f = f − f (·, 0) and u = u− f (·, 0) ∈ Lp(Ω).
• Step 1: ∃φ ∈ Lp(Ω) : |f (x, y)| ≤ φ(x) in Ω×R. We use Schauder’s
Theorem.
• Step 2: ∃φ ∈ Lp(Ω) such that f (x, y) ≥ φ(x) in Ω× R.
fk(x, y) = f (x,miny, k)⇒ φ(x) ≤ fk(x, y) ≤ φk(x)
Ayk + b(x) · ∇yk + fk(x, yk) = u
Ay + b(x) · ∇y = u− φA(y − yk) + b(x) · ∇(y − yk) = fk(x, yk)− φ ≥ 0
⇒ yk ≤ y ⇒ fk(x, yk) = f (x, yk) if k ≥ ‖y‖∞
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
⇒ z1 ≤ yk ∀k ≥ 1
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
⇒ z1 ≤ yk ∀k ≥ 1
Az2 + b(x) · ∇z2 = u− f (x,−‖z1‖C(Ω))
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
⇒ z1 ≤ yk ∀k ≥ 1
Az2 + b(x) · ∇z2 = u− f (x,−‖z1‖C(Ω))
A(z2 − yk) + b(x) · ∇(z2 − yk) = fk(x, yk)− f (x,−‖z1‖C(Ω)) ≥ 0
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
⇒ z1 ≤ yk ∀k ≥ 1
Az2 + b(x) · ∇z2 = u− f (x,−‖z1‖C(Ω))
A(z2 − yk) + b(x) · ∇(z2 − yk) = fk(x, yk)− f (x,−‖z1‖C(Ω)) ≥ 0
⇒ yk ≤ z2
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
⇒ z1 ≤ yk ∀k ≥ 1
Az2 + b(x) · ∇z2 = u− f (x,−‖z1‖C(Ω))
A(z2 − yk) + b(x) · ∇(z2 − yk) = fk(x, yk)− f (x,−‖z1‖C(Ω)) ≥ 0
⇒ yk ≤ z2 ⇒ ‖yk‖C(Ω) ≤ max‖z1‖C(Ω), ‖z2‖C(Ω)
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• Step 3: The general case.
fk(x, y) = f (x, proj[−k,+k](y))
Ayk + b(x) · ∇yk + fk(x, yk) = u
Az1 + b(x) · ∇z1 + f+(x, z1) = u with f+(x, t) = f (x, t+)
Az1 + b(x) · ∇z1 + fk(x, z1) = u + fk(x, z1)− f (x, z+1 ) ≤ u
⇒ z1 ≤ yk ∀k ≥ 1
Az2 + b(x) · ∇z2 = u− f (x,−‖z1‖C(Ω))
A(z2 − yk) + b(x) · ∇(z2 − yk) = fk(x, yk)− f (x,−‖z1‖C(Ω)) ≥ 0
⇒ yk ≤ z2 ⇒ ‖yk‖C(Ω) ≤ max‖z1‖C(Ω), ‖z2‖C(Ω)fk(x, yk) = f (x, yk) ∀k ≥ max‖z1‖C(Ω), ‖z2‖C(Ω)
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Continuity of u→ y and regularity of y
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Continuity of u→ y and regularity of y
Theorem. Let uk∞k=1 ⊂ Lp(Ω) with p > n2 be a sequence weakly
converging to u in Lp(Ω). Then, yuk → yu strongly in H10(Ω) ∩ C(Ω),
where yuk is the solution of the semilinear equation associated to uk.
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Continuity of u→ y and regularity of y
Theorem. Let uk∞k=1 ⊂ Lp(Ω) with p > n2 be a sequence weakly
converging to u in Lp(Ω). Then, yuk → yu strongly in H10(Ω) ∩ C(Ω),
where yuk is the solution of the semilinear equation associated to uk.
Theorem. Suppose that assumption on f holds with p = 2, aij ∈C0,1(Ω) for 1 ≤ i, j ≤ n. We also suppose that Γ is of class C1,1 or Ω
is convex. Then, for every u ∈ L2(Ω) the state equation has a unique
solution yu ∈ H2(Ω) ∩H10(Ω).
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Existence of solution of (P)
• We recall that
(P) minu∈Uad
J(u) :=1
2
∫Ω
(yu(x)−yd(x))2 dx+ν
2
∫Ω
u2(x) dx (ν > 0)
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Existence of solution of (P)
• We recall that
(P) minu∈Uad
J(u) :=1
2
∫Ω
(yu(x)−yd(x))2 dx+ν
2
∫Ω
u2(x) dx (ν > 0)
Theorem. The control problem (P) has at least one solution u.
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Differentiability Assumptions on f
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Differentiability Assumptions on f
• f : Ω× R −→ R is of class C2 w.r.t. the second variable
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Differentiability Assumptions on f
• f : Ω× R −→ R is of class C2 w.r.t. the second variable
• f (·, 0) ∈ Lp(Ω) with p >n
2and
∂f
∂y(x, y) ≥ 0 a.e. in Ω and ∀y ∈ R
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Differentiability Assumptions on f
• f : Ω× R −→ R is of class C2 w.r.t. the second variable
• f (·, 0) ∈ Lp(Ω) with p >n
2and
∂f
∂y(x, y) ≥ 0 a.e. in Ω and ∀y ∈ R
• ∀M > 0 ∃Cf,M :
∣∣∣∣∂f∂y (x, y)
∣∣∣∣ +
∣∣∣∣∂2f
∂y2(x, y)
∣∣∣∣ ≤ Cf,M ∀|y| ≤M
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Differentiability Assumptions on f
• f : Ω× R −→ R is of class C2 w.r.t. the second variable
• f (·, 0) ∈ Lp(Ω) with p >n
2and
∂f
∂y(x, y) ≥ 0 a.e. in Ω and ∀y ∈ R
• ∀M > 0 ∃Cf,M :
∣∣∣∣∂f∂y (x, y)
∣∣∣∣ +
∣∣∣∣∂2f
∂y2(x, y)
∣∣∣∣ ≤ Cf,M ∀|y| ≤M
•
∀M > 0 and ∀ε > 0 ∃δ > 0 such that∣∣∣∣∂2f
∂y2(x, y2)− ∂2f
∂y2(x, y1)
∣∣∣∣ < ε if |y1|, |y2| ≤M, |y2 − y1| ≤ δ
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Differentiability of the Mapping u→ yu
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Differentiability of the Mapping u→ yu
Given p > n2 , let us denote G : Lp(Ω) −→ Y = H1
0(Ω) ∩ C(Ω) the
mapping associating with each control the state G(u) = yu.
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Differentiability of the Mapping u→ yu
Given p > n2 , let us denote G : Lp(Ω) −→ Y = H1
0(Ω) ∩ C(Ω) the
mapping associating with each control the state G(u) = yu.
Theorem. The control-to-state mapping G is of class C2
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Differentiability of the Mapping u→ yu
Given p > n2 , let us denote G : Lp(Ω) −→ Y = H1
0(Ω) ∩ C(Ω) the
mapping associating with each control the state G(u) = yu.
Theorem. The control-to-state mapping G is of class C2 and for every
u, v ∈ Lp(Ω), we have that zv = G′(u)v is the solution of Az + b(x) · ∇z +∂f
∂y(x, yu)z = v in Ω
z = 0 on Γ
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Differentiability of the Mapping u→ yu
Given p > n2 , let us denote G : Lp(Ω) −→ Y = H1
0(Ω) ∩ C(Ω) the
mapping associating with each control the state G(u) = yu.
Theorem. The control-to-state mapping G is of class C2 and for every
u, v ∈ Lp(Ω), we have that zv = G′(u)v is the solution of Az + b(x) · ∇z +∂f
∂y(x, yu)z = v in Ω
z = 0 on Γ
and for v, w ∈ Lp(Ω), zv,w = G′′(u)(v, w) solves the equation Az + b(x) · ∇z +∂f
∂y(x, yu)z +
∂2f
∂y2(x, yu)zvzw = 0 in Ω
z = 0 on Γ
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Analysis of the Cost Functional
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Analysis of the Cost Functional
Theorem. The functional J : L2(Ω) −→ R is of class C2.
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Analysis of the Cost Functional
Theorem. The functional J : L2(Ω) −→ R is of class C2. Moreover,
given u, v, v1, v2 ∈ L2(Ω) we have
J ′(u)v =
∫Ω
(ϕu + νu)v dx
J ′′(u)(v1, v2) =
∫Ω
[1− ϕu
∂2f
∂y2(x, yu)
]zv1zv2 dx + ν
∫Ω
v1v2 dx
where ϕu ∈ H10(Ω)∩C(Ω) is the unique solution of the adjoint equation A∗ϕ− div[b(x)ϕ] +
∂f
∂y(x, yu)ϕ = yu − yd in Ω,
ϕ = 0 on Γ.
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Local Solutions
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Local Solutions
Definition. We say that u ∈ Uad is an Lr(Ω)-weak local minimum of
(P), with r ∈ [1,+∞], if there exists some ε > 0 such that
J(u) ≤ J(u) ∀u ∈ Uad with ‖u− u‖Lr(Ω) ≤ ε.
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Local Solutions
Definition. We say that u ∈ Uad is an Lr(Ω)-weak local minimum of
(P), with r ∈ [1,+∞], if there exists some ε > 0 such that
J(u) ≤ J(u) ∀u ∈ Uad with ‖u− u‖Lr(Ω) ≤ ε.
An element u ∈ Uad is said a strong local minimum of (P) if there exists
some ε > 0 such that
J(u) ≤ J(u) ∀u ∈ Uad with ‖yu − yu‖L∞(Ω) ≤ ε.
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Local Solutions
Definition. We say that u ∈ Uad is an Lr(Ω)-weak local minimum of
(P), with r ∈ [1,+∞], if there exists some ε > 0 such that
J(u) ≤ J(u) ∀u ∈ Uad with ‖u− u‖Lr(Ω) ≤ ε.
An element u ∈ Uad is said a strong local minimum of (P) if there exists
some ε > 0 such that
J(u) ≤ J(u) ∀u ∈ Uad with ‖yu − yu‖L∞(Ω) ≤ ε.
We say that u ∈ Uad is a strict (weak or strong) local minimum if the
above inequalities are strict for u 6= u.
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I - Relationships among these Notions
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I - Relationships among these Notions
• If Uad is bounded in L2(Ω), then
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I - Relationships among these Notions
• If Uad is bounded in L2(Ω), then
1. u is an L1(Ω)-weak local minimum of (P) if and only if it is an
Lr(Ω)-weak local minimum of (P) for every r ∈ (1,+∞).
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I - Relationships among these Notions
• If Uad is bounded in L2(Ω), then
1. u is an L1(Ω)-weak local minimum of (P) if and only if it is an
Lr(Ω)-weak local minimum of (P) for every r ∈ (1,+∞).
2. If u is an Lr(Ω)-weak local minimum of (P) for some r < +∞,
then it is an L∞(Ω)-weak local minimum of (P).
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I - Relationships among these Notions
• If Uad is bounded in L2(Ω), then
1. u is an L1(Ω)-weak local minimum of (P) if and only if it is an
Lr(Ω)-weak local minimum of (P) for every r ∈ (1,+∞).
2. If u is an Lr(Ω)-weak local minimum of (P) for some r < +∞,
then it is an L∞(Ω)-weak local minimum of (P).
3. u is a strong local minimum of (P) if and only if it is an Lr(Ω)-weak
local minimum of (P) for all r ∈ [1,∞).
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II - Relationships among these Notions
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II - Relationships among these Notions
• If Uad is not bounded in L2(Ω), then
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II - Relationships among these Notions
• If Uad is not bounded in L2(Ω), then
1. If u is an L2(Ω)-weak local solution, then u is an L1(Ω)-weak local
solution.
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II - Relationships among these Notions
• If Uad is not bounded in L2(Ω), then
1. If u is an L2(Ω)-weak local solution, then u is an L1(Ω)-weak local
solution.
2. If u is an Lp(Ω)-weak local solution, then u is an Lq(Ω)-weak local
solution for every p < q ≤ ∞.
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II - Relationships among these Notions
• If Uad is not bounded in L2(Ω), then
1. If u is an L2(Ω)-weak local solution, then u is an L1(Ω)-weak local
solution.
2. If u is an Lp(Ω)-weak local solution, then u is an Lq(Ω)-weak local
solution for every p < q ≤ ∞.
3. u is an L2(Ω)-weak local solution if and only if it is a strong local
solution.
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First Order Optimality Conditions
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First Order Optimality Conditions
Theorem. Let u be a local solution of (P) in any of the previous senses,
then there exist two unique elements y, ϕ ∈ H10(Ω) ∩ C(Ω) such that
Ay + b(x) · ∇y + f (x, y) = u in Ω,
y = 0 on Γ, A∗ϕ− div[b(x)ϕ] +∂f
∂y(x, y)ϕ = y − yd in Ω,
ϕ = 0 on Γ,∫Ω
(ϕ + νu)(u− u) dx ≥ 0 ∀u ∈ Uad
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First Order Optimality Conditions
Theorem. Let u be a local solution of (P) in any of the previous senses,
then there exist two unique elements y, ϕ ∈ H10(Ω) ∩ C(Ω) such that
Ay + b(x) · ∇y + f (x, y) = u in Ω,
y = 0 on Γ, A∗ϕ− div[b(x)ϕ] +∂f
∂y(x, y)ϕ = y − yd in Ω,
ϕ = 0 on Γ,∫Ω
(ϕ + νu)(u− u) dx ≥ 0 ∀u ∈ Uad
Moreover, u ∈ H1(Ω) ∩ C(Ω) holds.
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Second Order Conditions
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Second Order Conditions
•Cone of critical directions:
Cu =
v ∈ L2(Ω) : J ′(u)v = 0 and v(x)
≥ 0 if u(x) = α
≤ 0 if u(x) = β
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Second Order Conditions
•Cone of critical directions:
Cu =
v ∈ L2(Ω) : J ′(u)v = 0 and v(x)
≥ 0 if u(x) = α
≤ 0 if u(x) = β
Theorem If u is a local minimum of (P), then J ′′(u)v2 ≥ 0 ∀v ∈ Cu.
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Second Order Conditions
•Cone of critical directions:
Cu =
v ∈ L2(Ω) : J ′(u)v = 0 and v(x)
≥ 0 if u(x) = α
≤ 0 if u(x) = β
Theorem If u is a local minimum of (P), then J ′′(u)v2 ≥ 0 ∀v ∈ Cu.
Conversely, if u ∈ Uad satisfies the first order optimality conditions and
J ′′(u)v2 > 0 ∀v ∈ Cu \ 0, then there exist ε > 0 and κ > 0 such
that
J(u) +κ
2‖u− u‖2
2 ≤ J(u) ∀u ∈ Uad : ‖yu − y‖L∞(Q) ≤ ε.
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Second Order Conditions
•Cone of critical directions:
Cu =
v ∈ L2(Ω) : J ′(u)v = 0 and v(x)
≥ 0 if u(x) = α
≤ 0 if u(x) = β
Theorem If u is a local minimum of (P), then J ′′(u)v2 ≥ 0 ∀v ∈ Cu.
Conversely, if u ∈ Uad satisfies the first order optimality conditions and
J ′′(u)v2 > 0 ∀v ∈ Cu \ 0, then there exist ε > 0 and κ > 0 such
that
J(u) +κ
2‖u− u‖2
2 ≤ J(u) ∀u ∈ Uad : ‖yu − y‖L∞(Q) ≤ ε.
Theorem Let u ∈ Uad. Then J ′′(u)v2 > 0 ∀v ∈ Cu \ 0 if and only
if there exists δ > 0 such that J ′′(u)v2 ≥ δ‖v‖2L2(Ω)
∀v ∈ Cu.
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Approximation of the state equation
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Approximation of the state equation
• We assume that Ω is a polygonal/polyhedral convex domain in Rn
with n = 2 or 3.
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Approximation of the state equation
• We assume that Ω is a polygonal/polyhedral convex domain in Rn
with n = 2 or 3.
• Let Thh>0 be a quasi-uniform family of triangulations of Ω.
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Approximation of the state equation
• We assume that Ω is a polygonal/polyhedral convex domain in Rn
with n = 2 or 3.
• Let Thh>0 be a quasi-uniform family of triangulations of Ω.
Yh = yh ∈ C(Ω) : yh|T ∈ P1(T ) ∀T ∈ Th and yh ≡ 0 on Γ.
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Approximation of the state equation
• We assume that Ω is a polygonal/polyhedral convex domain in Rn
with n = 2 or 3.
• Let Thh>0 be a quasi-uniform family of triangulations of Ω.
Yh = yh ∈ C(Ω) : yh|T ∈ P1(T ) ∀T ∈ Th and yh ≡ 0 on Γ.
a(y1, y2) = 〈Ay1, y2〉H−1(Ω),H10 (Ω)
=
∫Ω
( n∑i,j=1
aij(x)∂xiy1∂xjy2 + [b(x) · ∇y1]y2
)dx.
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Approximation of the state equation
• We assume that Ω is a polygonal/polyhedral convex domain in Rn
with n = 2 or 3.
• Let Thh>0 be a quasi-uniform family of triangulations of Ω.
Yh = yh ∈ C(Ω) : yh|T ∈ P1(T ) ∀T ∈ Th and yh ≡ 0 on Γ.
a(y1, y2) = 〈Ay1, y2〉H−1(Ω),H10 (Ω)
=
∫Ω
( n∑i,j=1
aij(x)∂xiy1∂xjy2 + [b(x) · ∇y1]y2
)dx.
Find yh ∈ Yh such that
a(yh, zh) +
∫Ω
f (x, yh(x))zh(x) dx =
∫Ω
u(x)zh(x) dx ∀zh ∈ Yh.
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Numerical Analysis of the Linear Equa-tion
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Numerical Analysis of the Linear Equa-tion
Theorem [Schatz, 1974]. Let a0 ∈ L2(Ω) be a nonnegative function.
There exists hA > 0 depending on A and ‖a0‖L2(Ω) such that the
variational problem Find yh ∈ Yh such that
a(yh, zh) +
∫Ω
a0(x)yh(x)zh(x) dx =
∫Ω
u(x)zh(x) dx ∀zh ∈ Yh
has a unique solution for every h ≤ hA and for every u ∈ L2(Ω).
Moreover, there exists a constant CA,a0 such that
‖yh‖H10 (Ω) ≤ CA,a0‖A
−1u‖H10 (Ω) ∀h ≤ hA.
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Numerical Analysis of the SemilinearEquation
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Numerical Analysis of the SemilinearEquationTheorem. Let us assume that
f (·, 0) ∈ L2(Ω) and ∀M > 0 ∃Lf,M such that
|f (x, y2)− f (x, y1)| ≤ Lf,M |y2 − y1| ∀|yi| ≤M, i = 1, 2.
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Numerical Analysis of the SemilinearEquationTheorem. Let us assume that
f (·, 0) ∈ L2(Ω) and ∀M > 0 ∃Lf,M such that
|f (x, y2)− f (x, y1)| ≤ Lf,M |y2 − y1| ∀|yi| ≤M, i = 1, 2.
∀M ≥ 1 + ‖y‖C(Ω) ∃hM > 0 such that for every h < hM the discrete
equation has a unique solution yh satisfying ‖yh‖C(Ω) ≤M .
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Numerical Analysis of the SemilinearEquationTheorem. Let us assume that
f (·, 0) ∈ L2(Ω) and ∀M > 0 ∃Lf,M such that
|f (x, y2)− f (x, y1)| ≤ Lf,M |y2 − y1| ∀|yi| ≤M, i = 1, 2.
∀M ≥ 1 + ‖y‖C(Ω) ∃hM > 0 such that for every h < hM the discrete
equation has a unique solution yh satisfying ‖yh‖C(Ω) ≤M . Moreover,
there exist constants KM and K∞,M independent of u such that
‖y − yh‖L2(Ω) + h‖y − yh‖H10 (Ω) ≤ KM
(‖u‖L2(Ω) + 1
)h2
‖y − yh‖L∞(Ω) ≤ K∞,M
(‖u‖L2(Ω) + 1
)h2−n2
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Numerical Analysis of the SemilinearEquationTheorem. Let us assume that
f (·, 0) ∈ L2(Ω) and ∀M > 0 ∃Lf,M such that
|f (x, y2)− f (x, y1)| ≤ Lf,M |y2 − y1| ∀|yi| ≤M, i = 1, 2.
∀M ≥ 1 + ‖y‖C(Ω) ∃hM > 0 such that for every h < hM the discrete
equation has a unique solution yh satisfying ‖yh‖C(Ω) ≤M . Moreover,
there exist constants KM and K∞,M independent of u such that
‖y − yh‖L2(Ω) + h‖y − yh‖H10 (Ω) ≤ KM
(‖u‖L2(Ω) + 1
)h2
‖y − yh‖L∞(Ω) ≤ K∞,M
(‖u‖L2(Ω) + 1
)h2−n2
Further, if there exist other solutions yhh<hM with yh 6= yh for all h,
then limh→0 ‖yh‖C(Ω) =∞.
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A Discrete Mapping uh→ yh
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A Discrete Mapping uh→ yh
Theorem. Let y ∈ Y be the solution of state equation corresponding
to the control u ∈ L2(Ω). Given ρ > 0 arbitrary, there exist ρ∗ > 0 and
h0 > 0 such that the discrete equation has a unique solution yh(u) ∈BYρ∗(y) for every u ∈ Bρ(u) ⊂ L2(Ω) and for all h < h0, where
BYρ∗(y) = y ∈ Y : ‖y − y‖Y ≤ ρ∗.
Furthermore, there exist constants K and K∞ such that
‖yu − yh(u)‖L2(Ω) + h‖yu − yh(u)‖H10 (Ω) ≤ K
(‖u‖L2(Ω) + ρ + 1
)h2
‖yu − yh(u)‖L∞(Ω) ≤ K∞
(‖u‖L2(Ω) + ρ + 1
)h2−n2 ∀u ∈ Bρ(u)
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Numerical Approximation of (P)
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Numerical Approximation of (P)
• Let us define J : L2(Ω)× L2(Ω)→ R given by
J (y, u) =1
2
∫Ω
(y(x)− yd(x))2 dx +ν
2
∫Ω
u2 dx
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Numerical Approximation of (P)
• Let us define J : L2(Ω)× L2(Ω)→ R given by
J (y, u) =1
2
∫Ω
(y(x)− yd(x))2 dx +ν
2
∫Ω
u2 dx
• Let us denote by Uh one of the following two spaces:
Uh = U0h := uh ∈ L2(Ω) : uh|T ∈ P0(T ) ∀T ∈ Th
Uh = U1h := uh ∈ C(Ω) : uh|T ∈ P1(T ) ∀T ∈ Th
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Numerical Approximation of (P)
• Let us define J : L2(Ω)× L2(Ω)→ R given by
J (y, u) =1
2
∫Ω
(y(x)− yd(x))2 dx +ν
2
∫Ω
u2 dx
• Let us denote by Uh one of the following two spaces:
Uh = U0h := uh ∈ L2(Ω) : uh|T ∈ P0(T ) ∀T ∈ Th
Uh = U1h := uh ∈ C(Ω) : uh|T ∈ P1(T ) ∀T ∈ Th
• We set Uh,ad = Uh ∩ Uad.• We approximate Problem (P) by the problem
(Ph) minJ (yh, uh) : (yh, uh) ∈ Yh×Uh,ad satisfies the discrete equation.
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Convergence of (Ph) to (P)
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Convergence of (Ph) to (P)
Theorem. There exists h0 > 0 such that problem (Ph) has at
least one solution (yh, uh) for all h < h0.
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Convergence of (Ph) to (P)
Theorem. There exists h0 > 0 such that problem (Ph) has at
least one solution (yh, uh) for all h < h0. Moreover, if (yh, uh)h<h0
is a sequence of solutions of problems (Ph), then it is bounded in
H10(Ω) × L2(Ω) and there exist subsequences converging weakly in
H10(Ω) × L2(Ω).
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Convergence of (Ph) to (P)
Theorem. There exists h0 > 0 such that problem (Ph) has at
least one solution (yh, uh) for all h < h0. Moreover, if (yh, uh)h<h0
is a sequence of solutions of problems (Ph), then it is bounded in
H10(Ω) × L2(Ω) and there exist subsequences converging weakly in
H10(Ω) × L2(Ω). In addition, if a subsequence, denoted in the same
way, satisfies that (yh, uh) (y, u) in H10(Ω)× L2(Ω) as h→ 0, then
(y, u) ∈ Y × Uad, u is a solution of (P) with associated stated y, and
(yh, uh)→ (y, u) strongly in H10 (Ω)× L2(Ω).
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Error Estimates
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Error Estimates
Theorem. Let u ∈ L2(Ω) be a local minimizer of (P) satisfying the suf-
ficient second order optimality conditions and let uh be the sequence
of minimizers of the problems (Ph) described in the above theorem.
Then, there exists h0 > 0 such that
• If Uad ( L2(Ω), then
‖u− uh‖L2(Ω) ≤ Ch. ∀h < h0
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Error Estimates
Theorem. Let u ∈ L2(Ω) be a local minimizer of (P) satisfying the suf-
ficient second order optimality conditions and let uh be the sequence
of minimizers of the problems (Ph) described in the above theorem.
Then, there exists h0 > 0 such that
• If Uad ( L2(Ω), then
‖u− uh‖L2(Ω) ≤ Ch. ∀h < h0
• If Uad = L2(Ω) and Uh = U ih, i = 0, 1, then
‖u− uh‖L2(Ω) ≤ Ch1+i ∀h < h0
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THANK YOU VERY MUCH FOR YOUR ATTENTION
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