Transcript
Page 1: Unit 4 test tomorrow!! - Nicole Forrester

βˆ’3(π‘₯ βˆ’ 3) = βˆ’27

βˆ’3π‘₯ βˆ’ 22 ≀ 20 4(π‘₯ + 3) > βˆ’12

βˆ’ 2 ≀ 6

= 𝑑 π‘Ž βˆ’ 𝑏 + 𝑐 = 3𝑑

4(2π‘₯ βˆ’ 7𝑦) = 2(3π‘₯ + 13𝑦)

45 + 175π‘₯ ≀ 300

+ 3 2π‘₯ + 3 4(2π‘₯ βˆ’ 5)

()

βˆ’3π‘₯ βˆ’ 1

Unit 4 test tomorrow!!

Page 2: Unit 4 test tomorrow!! - Nicole Forrester

2(3π‘₯ βˆ’ 4𝑦) = 17 2𝑦 βˆ’ 12π‘₯ = 24 π‘₯ βˆ’ 3𝑦 = 1

βˆ’3π‘₯ βˆ’ 15 > βˆ’6

π‘₯ βˆ’ 𝑦 π‘œπ‘Ÿ 𝑦 βˆ’ π‘₯

Page 3: Unit 4 test tomorrow!! - Nicole Forrester

βˆ’2π‘₯ βˆ’ 4 > βˆ’12

3(π‘₯ βˆ’ 3)βˆ’5

≀ 3

{ 4π‘₯ = βˆ’163π‘₯ βˆ’ 4𝑦 = 24

4π‘₯ βˆ’ 7𝑦 > 14 π‘₯ βˆ’ 8𝑦 ≀ 24 𝑦 > 4π‘₯ βˆ’ 3


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