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Standard Algorithm Tuesday, September 16 2014
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GoalI will be able to connect our diagrams and the distributive property to partial products of the standard algorithm without renaming.
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Multiply by Multiples of 100
21x 4008400
312x30093,600
2,314x200462,800
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Multiply using the Area Model
43x12 43
2
10
2x43= 86
43x10= 430
430+86= 516
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Multiply using an area Model
243x12200 40 3
2
10
200x 2=400
40x2= 80
3x2=6
10x2002000
40x10=400
10x3=3-
2,000 400 400 80 30 + 6 2,916
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Word Problem of the Day
Scientists are creating a material that may replace damaged cartilage in human joints. This hydrogel can stretch to 21 times its original length. If a strip of hydrogel measures 3.2 cm, what would its length be when stretched to capacity? 3.2x 21= 67.2
http://www.seas.Harvard.edu/news-events/press-release/tough-gel-stretches-to-21-times-its-length
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Journal Entry
9/16 Area Model and Standard Algorithm
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64x73
We will solve these problems using both an area model and the standard algorithm
65 X73 19545504745
70 3
4
60
70x4= 2804x3= 12
60x70= 4200 6x3= 18
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814x39800 10 4
9
30
9x800=7200 9x10= 909x4= 36
800x30= 24000 30x10= 30030x4= 120
31746
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624x82
624 x 82
1248 49920 51168
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Problem SetYou may work with one person on the problem set
I will be calling groups to my back table.
Once you are finished please move your number to your new activity.
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Exit TicketDraw an are model and solve the problem using the standard algorithm
78x42= 3276
783x42= 32,886