Download - Significant Figures In Calculations
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Significant Figures In Calculations
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Rule 1: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors. Example 1: 39.0 mm X 385 mm X 55 mm = 825,825.00 mm (calculator answer)
The answer is expressed as 830 000 or 8.3 X 105 since 55 mm has two significant figures.
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Rule 2: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer. Example 2: 643.40 mL + 40.0 mL + 55.001 mL = 738.40 mL (calculator answer)
The answer is expressed as 738.4 mL since 40.0 mL has only one decimal place.
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Carry out the following calculations expressing your answers to the correct number of significant figures. Assume that all numbers are measured quantities.
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1. 0.742mL + 0.0259mL =
The first value only had three decimal places, whereas the second had four.
0.768mL (correct answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
0.7679mL (calculator answer)
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2. 4.00 g – 3.5 g =
There is only one decimal place in the second value, whereas the first had two.
0.5 g (correct answer)
0.50 g (calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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3. 22.1 ml + 33.2 ml + 224.08 ml=
There is only one decimal place in the first and second value, where as the third had two.
279.4 (correct answer)279.38 mL(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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4. 35.601 g – 34.1 g =
There is only one decimal place in the second value, whereas the first had three.
1.5 g (correct answer)
1.501 g(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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5. 150.00 g H2O + 0.507 g salt
There are two decimal place in the first value, whereas the second had three.
150.51 g sol. (correct answer)
150.507 g solution(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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6. 67.5 cm - 0.009 cm=
There is only one decimal place in the first value, whereas the second had three.
67.5 cm (correct answer)
67.491 cm(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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7. 0.008 mL + 0.05 mL =
There are two decimal place in the second value, whereas the first had three.
0.06 mL (correct answer)
0.058 mL(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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8. 250.001 g + 2.000 g + 5000.00 g =
There is no decimal place 250001.
5252.00 g (correct answer)5252.001 g(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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9. 4.60 L + 3 L =
There is no decimal place on the second value.
8 L (correct answer)
7.6 L(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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10. 200 mm - 87.3 mm =
There is no decimal place on the first value.
113 mm (correct answer)
112.7 mm(calculator answer)
Remember: When adding and subtracting, limit and round your answer to the least number of decimal places in any of the numbers that make up your answer.
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11. 13.7 cm X 2.5 cm =
34 cm
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
34.25 cm
2 sig. fig
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12. 300 cm X 2.88 cm =
900 cm
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
864 cm1 sig. fig
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13.89 cm
_________90 cm
1 cm
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
= 0.988888889 cm1 sig. fig
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0.00003 g X 727.0 g =
14.
0.021811 sig. fig
0.02 g
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
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5003 mL / 3.78 mL =
15.
1323.544974 mL3 sig. fig
1320 mL
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
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3.44 kg (3.440 kg X 5 kg)
16.
0.2 kg1 sig. fig.
0.2 kg
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
=
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400.00 m2.30 m
17.
173.9130435 m3 sig. fig.
174 m
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
=
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350.00 cm X 0.00072 cm =
18.
0.252 cm
2 sig. fig
0.25 cm
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
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19. A piece of metal is found to have a mass of 1.201 grams. What would be the total mass, in grams of 4002 identical pieces of metal?
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1.201 g X 4002 g =
19.
4806.402 g
4 sig. fig
4806 g
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
4 sig. fig
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20. A piece of glass is found to have a thickness of 0.122 mm. What would be the total thickness of 5.0 identical pieces of glass?
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0.122 mm X 5.0 =
20.
0.61 mm
2 sig. fig
0.61 mm
Remember: When multiplying and dividing, limit and round to the least number of significant figure in any of the factors.
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Significant FiguresPage 21 Answers
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0.0299 ml140 000 m
1280 cm
0.988 g
2475.0 kg0.2 mm23480 ml
3.12 L
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162.2 ml20.0 cg
3.9 dm
7.32 mm
5.8 dm
0.899 L19.8 cm