Pages: 7©
Copyright for part(s) of this examination may be held by individuals and/or organisations otherthan the Tasmanian Qualifications Authority.
Tasmanian Qualifications Authority
PHYSICSSenior Secondary 5C
Subject Code: PHY5C
External Assessment
2004
Formulae for Written Examination
Students may write physics information on any of these pageswithout restriction but the information must be in the student’sown handwriting.
Physics – Senior Secondary 5C - Formula Sheet
Page 2
Prefixes:
T — tera 1012
G — giga 109
M — mega 106
k — kilo 103
c — centi 10–2
m — milli 10–3
m — micro 10–6
n — nano 10–9
p — pico 10–12
f — femto 10–15
Physics – Senior Secondary 5C - Formula Sheet
Page 3
STUDENT'S NOTES (own handwriting)
Physics – Senior Secondary 5C - Formula Sheet
Page 4
Motion in a Straight Line, Momentum, Force, Centripetal Force
atuv +=
221 atuts +=
22 2 uvas -=
mvp =
mat
mvFun =
DD
=
r
mvFc
2
=
r
vac
2
=
Work, Energy and Power
,cos qFsWD =
WD Energy =D
mghEp =
221 mvEK =
t
WDP =
Gravity, Kepler's Law
G = 6.67 x 10–11
Nm2kg–2 , g = 9.81 ms-2
221
r
mGmF =
mgW =
mF
g =
2
r
GMg =
32
2 4 rGM
Tp
=
Physics – Senior Secondary 5C - Formula Sheet
Page 5
Electrostatics
k electrostatic = 9.00 x 109 Nm2C–2
e = 1.6 x 10–19 C
me = 9.11 x 10–31
kg, mp = 1.67 x 10–27
kg
qF
E =
221
r
QkQF =
2 r
kQE =
q
EPDV pD
==
d
VE =
Magnetism
k magnetic = 2 x 10–7
NA–2
qsin BIF l=
qsin vBqF =
r
kIB =
r
IkIF
l21 =
qBvm
rqsin
=
†
v = EB
Induction
emf = vlBsinq
V = IR
P = VI
Physics – Senior Secondary 5C - Formula Sheet
Page 6
Oscillations, Waves
c = 3.00 x 108 ms-1
Speed of sound in air at 200C = 344 ms-1
1 Tf =
fv l =
RI qq =
sin q isin qr
= v1v2
= n( ) n1 sinq1 = n2 sinq2
dxW l=
mT
v =
Nuclear
me = 9.11 x 10–31 kg = 0.000549 amu
mp = 1.67 x 10–27 kg = 1.007276 amu
mn = 1.67 x 10–27 kg = 1.008665 amu
Mass to energy conversion: 931 MeV = 1 amu
NA = 6.02 x1026 (kg mole)
2mcE =
ANdtdN
==- l
21
693.0
T=l
RateCount OrigRateCount
=== -
o
t
o AA
eNN l
Physics – Senior Secondary 5C - Formula Sheet
Page 7
Quantum
h = 6.63 x 10–34
Js = 4.14 x 10-14 eVs
e = 1.6 x 10–19
C
hfE =
( ) max WhfeVEK -==
lh
p =
