RIAN DWI ANGGARA PUTRA

111.120.051

JAWAB:

Unit weight

= 18 kN/m3Friction angel

= 30oCohession

= 20oWeight of mass slide= (1/2)(18 kN/m3) (5 meter)2 {[tan(90o-48o)]-[tan(90o-80o)]}

= 162.9 kN/m

Lenght of slide

= H/sin a = 5/sin 48o

= 6,73Horizontal spase= 2 meter1st tensil permit= 18,3 kN2nd tensil permit= 21,8 kN1st shear permit= 0,133 kN2nd shear permit= 0,133 kNT = = 20,05 kN/mV = = 0,133 kN/m

Fos = = 1,92