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MathematicsRelations and Functions: Multiplying Polynomials
Science and Mathematics Education Research Group
Supported by UBC Teaching and Learning Enhancement Fund 2012-2015
Department of Curr iculum and Pedagogy
F A C U L T Y O F E D U C A T I O Na place of mind
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Factoring Polynomials II
Retrieved from http://catalog.flatworldknowledge.com/bookhub/reader/6329?e=fwk-redden-ch06_s01
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Multiplying Polynomials I
Multiply completely:
5
6
5
6
5
26E.
12D.
12C.
8B.
8A.
x
x
x
x
x
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Solution
Answer: C
Justification:
Multiplying polynomials is to multiply factors in a division statement into one single expression.
In order to multiply polynomials, we multiply coefficients with coefficients, and variables with variables.
For coefficients, we multiply 2 with 6, which is 12.
For variables, we multiply with , which is
()
Multiplying them back together, we get 12 Our answer is C.
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Multiplying Polynomials II
Multiply completely:
zx
zyx
zyx
zx
zx
5
46
45
6
5
E.
6D.
6C.
6B.
6A.
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Solution
Answer: A
Justification:
In order to multiply polynomials, we multiply coefficients with coefficients, and variables with variables
For coefficients, we multiply 2 with -3, which is -6.
For x, we multiply with , which is
For y, we multiply with , which is
For z, there is only 1 z; thus it is just z
() ()
Multiplying them back together, we get 6 Our answer is A.
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Multiplying Polynomials III
Expand:
)7(E.
)12(D.
)12(C.
)12(B.
)1(A.
2
2
2
2
2
xx
xx
xx
x
x
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Solution
Answer: C
Justification:
In order to multiply polynomials with more than 1 term, we have to “distribute” our multiplication to each term as such!
Multiplying each term over and under, we get:
= =
Our answer is C.
It’s like fishing!
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Multiplying Polynomials IV
Expand:
)4129(E.
)4129(D.
)4129(C.
)4129(B.
)49(A.
2
2
2
2
2
xx
xx
xx
xx
x
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Solution
Answer: E
Justification:
Notice that this question can also be written as a multiple of two factors as such!
Multiplying each term over and under, we get:
= =
Our answer is E.
≠
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Multiplying Polynomials V
Expand:
2
23
23
22
23
3E.
)132(D.
)132(C.
)12(B.
)122(A.
x
xx
xx
xx
xxx
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Solution
Answer: D
Justification:
Notice that this question cannot be written as a multiple of two factors as such!
Due to the order of operation, we must evaluate the exponents first!
= =
≠ ()
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Solution Continued
Now, this question can be written as multiple of two factors as such!
Since there is a negative sign in front of it, we multiply to all terms.
Thus, our answer is D.
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Multiplying Polynomials VI
Expand:
3223
3223
3223
3223
33
6E.
33D.
C.
2B.
A.
yyxx
yxyyxx
yxyyxx
yyxx
yx
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Solution
Answer: D
Justification:
Notice that this question can be written as a multiple of three factors as such!
Due to the order of operation, we must evaluate the first exponents first!
Then, we multiply this result with the last factor
Thus, the answer is D.
≠ ()
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Multiplying Polynomials VII
Expand:
54322345
541322345
541322345
542345
5445
510105E.
510105D.
510105C.
5105B.
55A.
yxyyxyxyxx
yyxyxyxyxx
yyxyxyxyxx
yyyxxx
yyxx
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Solution
Answer: E
Justification:
We can solve this problem by using Pascal’s triangle
Retrieved from http://en.wikipedia.org/wiki/Pascal's_triangle#/media/File:Pascal%27s_triangle_5.svg
Pascal’s triangle is a triangular model that starts with 1 at the top, continues to place number below in a triangular shape, and has pattern that each number of a row is the two numbers above added together excluding the edges.
It is found that row of the Pascal’s triangle represents the coefficients of the terms in a polynomial , where n is a positive integer.
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Solution Continued
Since n = 5 for our example, we know that the coefficients of the terms of are at the 6th row of the Pascal’s triangle. (1)
However, we have a negative sign between x and y:
This means that each term will have an alternating sign in a descending order from the first term. (2)
For example, when we have , we should get: . As you can see, the coefficients of these terms are +1, 2, and +1, respectively. They alternate sign as they progress.
22 2 yxyx
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Solution Continued
Retrieved from http://en.wikipedia.org/wiki/Pascal's_triangle#/media/File:Pascal%27s_triangle_5.svg
Thus, incorporating both (1) and (2), our solution will look as below:
Thus, our answer is E.
54322345 510105 yxyyxyxyxx
+ Alternate signs