Download - Kwl chart--moles
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KWL CHART--MOLESWhat do I know about moles?
What do I want to know about moles?
What have I learned about moles today?
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MOLES This unit test contains 6 types of
problems:1. Molar mass and % composition—must
be able to write a chemical formula2. Grams to moles (using molar mass)3. Moles to particles/atoms/molecules
(using Avogadro’s #)4. Grams to moles to particles (using
molar mass and Avogadro’s #)5. Empirical formulas6. Molecular formulas
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MOLE
The SI (metric) unit used to measure the amount of a substance
1 mole is always equal to:--Molar mass (g/mole)--Avogadro’s number of particles (6.02 x
1023)--22. 4 Liters of a GAS (AKA molar volume)
These may be used as conversion factors when working mole problems.
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ACTIVATOR Define molar mass AND Avogadro’s number.
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1 mole of this substance
# of atoms/molecules/particles
Mass of 1 mole (molar mass) g/mole
Volume of 1 mole
table sugar (sucrose)--C12H22O11
342.0
Sodium chloride--NaCl
58.5
Cupric sulfate--CuSO4
159.6
Sulfur--S 32.1Iron--Fe 55.8Water—H2O 18.0
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MOLAR MASS OF ELEMENTS—SAME AS ATOMIC MASS Ex: Titanium 47.867 = 47.9 g/mole
(this sample contains Avogadro’s number of atoms)
Ex: oxygen 15.999 = 16.0 g/mole(this sample contains Avogadro’s number
of atoms)
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MOLAR MASS OF COMPOUNDS—MUST WRITE CHEMICAL FORMULA CORRECTLY Multiply the # of atoms for each element
by the atomic mass from periodic table
Ex:Magnesium hydroxideMg (OH)2
Mg 1(24.3) = 24.3O 2(16.0) = 32.0H 2(1.0) = 2.0
58.3 g/mole (this mass also contains Avogadro’s number of molecules)
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Find the molar mass of aluminum sulfate
Al 2 (SO4)3
Al 2(27.0) = 54.0S 3 (32.1)= 96.3O 12(16.0) = 192.0
342.3 g/mole (this mass also contains Avogadro’s number of molecules)
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Calculate the molar mass of diarsenic trioxide.
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MOLAR MASS PRACTICE-- Stannic carbonate
Diarsenic pentasulfide
Hydrofluoric acid
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ACTIVATOR: CALCULATE THE MOLAR MASS Sucrose
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% COMPOSITION Shows the % of each element that makes up a
compound Must be calculate molar mass first.Ex: magnesium hydroxide Mg (OH)2
Mg 1 x 24.3 =24.3 24.3/58.3 x 100 = 41.7%
O 2 x 16= 32.0 32.0/58.3 x 100 = 54.9%
H 2x1.0 = 2.0 58. 3 g/mole 2.0/58.3 x 100 = 3.4%
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ACTIVATOR: Calculate the % composition of sulfurous
acid
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LAB—BITE THE BUBBLE SAVE YOUR WRAPPER FOR ENTIRE
LAB!!
DO NOT START CHEWING UNTIL YOU SIT DOWN BACK AT YOUR DESK.
CHECK BALANCE TO MAKE SURE IT’S OK BEFORE YOU START!!
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READ PROBLEM:
MAKE A HYOTHESIS:
PROCEDURE 1—4
DATA TABLE 1—5
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After chewing: (KEEP YOUR SAME BALANCE)
Procedure 5—8
Data table 6—8
Conclusion
Questions 1—2
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Calculate the % composition for a sugar substitute called SUCRALOSE
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C 12( 12.0) = 144.0 H 19 (1.0) = 19.0 Cl 3 (35.5) = 106.5 O 8 (16.0) = 128.0
397. 5 g/mole% C= 144.0 / 397.5 x 100 = 36.2%% H= 19.0 / 397.5 x 100 = 4.8%% Cl= 106.5 / 397.5 x 100 = 26.8%% O= 128.0/ 397.5 x 100 = 32.2%
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TICKET OUT 1. Calculate the % composition of
carbonic acid.
2. Calculate the % composition of diantimony trioxide.
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1. H2CO3
H-2 (1.0) = 2.0 3.2%C- 1 (12.0) = 12.0 19.4%O – 3(16.0) = 48.0 77.4%
62.0 g/mole
2. Sb2O3
Sb- 2(121.8) =243.6 83.5%O – 3(16.0) = 48.0 16.5%
291.6 g/mole
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ACTIVATOR Calculate the molar mass AND %
composition of:
1. C12H22O11
2. Cupric sulfate
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C: 12 (12.0) = 144.0 H: 22 (1.0) = 22.0 O: 11(16.0) = 176.0
CuSO4
Cu: 1(63.5)= 63.5S: 1 (32.1) = 32.1O: 4(16.0) = 64.0
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CONVERTING GRAMS TO MOLESWill need to use unit
conversion(cancellation) and molar mass will be used for the conversion factor.
Ex: 2.50 grams of hydrochloric acid = ____moles
H Cl
2.50 grams x 1 mole = 0.0685 moles(3sigfigs)
36.5 grams
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CONVERTING MOLES TO GRAMSEx: 2.50 moles of HCl = __________grams
2.5 moles x 36.5 grams = 91 grams 1 mole (2 sig figs)
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CONVERTING PARTICLES TO MOLES Particles, atoms, molecules (synonyms)
Will have to use Avogadro’s number as a conversion factor
Ex: 5.25 x 1025 atoms of Mg = _____moles
5. 25 x 1025 atoms x 1 mole = 87.2 moles
6.02 x 1023 (3 sig figs)
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CONVERTING MOLES TO PARTICLES2.50 moles MgO = _________molecules
2.50 moles x 6.02 x 1023 molecules 1 mole
= 1.50 x 1024 molecules (3 sig figs)
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CONVERTING GRAMS TO PARTICLES Will need to use both molar mass AND Avogadro’s
number as conversion factors Will be 2 steps instead of 1 step unit cancellation
Ex: 4.5 grams nitrous acid = __________molecules
HNO2
4.5 g x 1 mole x 6.02 x 1023 molecules = 47 g 1 mole
5.8 x 1022 molecules (2 sig figs)
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CONVERTING PARTICLES TO GRAMS Ex: 9.35 x 1021 particles of carbon
tetrabromide = _____grams
C Br4
9.35 x 1021 p x 1 mole x 154 grams = 6.02x1023 p 1 mole
2.39 grams (3 sig figs)
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ANSWERS TO HOMEWORK: MUST SHOW WORK TO RECEIVE CREDIT1. 0.14 mole (gram to moles)2. 150 g (moles to grams)3. 1.1 x 1023 molecules (g to molecules)4 5.30 x 1025 molecules (moles to
molecules)5. 0.074 mole( gram to moles)6. 0.619 g (particles to grams)7. 0.49 mole (grams to moles)8. 0.00083 mole (particles to moles)
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TAB 3 “EVEN MORE MOLE PROBLEMS”—SHOW WORK TO RECEIVE CREDIT1. 22 g2. 1.53 x 1024 molecules3. 0.014 g4. 7.2 x 1021 molecules5. 7.2 x 1023 molecules6. 2.08 x 106 g7. 56 g8. 2.5 g9. 31 g10. 0.0029 mole11. 167 gBONUS: 3.37 x 1026 atoms
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ACTIVATORIf grams are converted to moles,use _______________ to convert.If moles are converted tomolecules, then use______________to convert.
****Have calculator, periodic table, and best friend chart****
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MOLE GAMEAll members of your group must show
their work on separate sheet of paper.
When you calculate the answer, flip the card over to find a word.
All of your words will make a sentence.
First group to show all work and finish first, wins bonus!
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MOLE PROBLEM DIAGRAM
Grams-----moles-----particles(atoms or molecules)
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EXTRA PRACTICE-MOLE PROBLEMS1. 55.33 grams of sodium oxide =
____moles
2. 5.00 x 1022 particles of sodium= _______moles
3. 2.49 x 1026 atoms of acetic acid = _______________grams
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HOMEWORK:Video sheet Problems #1—3, 5, 6
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ACTIVATOR:Fill in the blanks with multiply/divide
OR molar mass/Avogadro’s number:
***When going from moles to grams, _______________ by _____________.
***When going from moles to particles, ____________by _________________.
I AM CHECKING 5 HOMEWORK PROBLEMS!!!!
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TICKET OUT
Briefly describe the steps for calculating an empirical formula AND molecular formula.
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ACTIVATOR
Define empirical formula
***both labs due today***
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MOLE REVIEW PROBLEMS1. Convert 5.03 x 1024 molecules
of phosphoric acid to grams.
2. Convert 35.75 grams of dinitrogen monoxide to moles.
3. Convert 5.0 moles of water to molecules.
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ANSWERS1. 819 grams of H3PO4
2. 0.8125 moles of N20
3. 3.0 x 1024 molecules of water
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TICKET OUTTell how to solve for each:1. G to moles2. Moles to G3. Particles to moles4. Moles to particles5. G to particles6. Particles to G
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GUM LAB—SHOW WORK TO RECEIVE CREDIT
HYPOTHESIS, DATA 1—8, CONCLUSION, QUESTIONS 1—4
3. MASS OF SUGAR (in grams—data #8)--------MOLES(SUGAR = C12 H22 O11) 4. MOLES----------PARTICLES
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LAB-USING THE MOLE Data Table: mass of empty vial AND
substances mass (make sure you’ve subtracted empty vial each time!!)
SHOW WORK TO GET CREDIT
CONVERT GRAMS----------MOLES CONVERT MOLES---------PARTICLES ANSWER QUESTIONS 1---5, 6 (BONUS)
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ACTIVATOR:
Convert 25.0 moles of water to grams.
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ACTIVATORA molecular formula is a whole number____________of the empirical formula.
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EMPIRICAL FORMULAS Shows the SIMPLEST, WHOLE NUMBER
ratio of elements in a compound
Will give you % composition of compound and ask you to find the formulas
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STEPS FOR CALCULATING:1. Change % sign to grams (some problems
may already give you grams instead of %)
2. Convert grams to moles (using molar mass)**round to 4 decimals***
3. Simplify the mole ratio by dividing each one by the smallest
4. Round to the nearest whole number and assign these numbers to the appropriate element
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EXAMPLE:A compound is 78.1% Boron and 21.9% H.
Calculate the empirical formula.78.1 grams B x 1 mole = 7.2315 moles B
10.8 g21.9 grams H x 1mole =21.9 moles H
1.0 g7.2315 : 21.97.2315 7.2315
1: 3 = BH3
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MOLECULAR FORMULAS:Is a WHOLE NUMBER MULTIPLE of the
empirical formula
You must then first know the empirical formula
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STEPS FOR CALCULATING:1. You must first have empirical formula (if not,
you will have to calculate it first!!)
2. Find the molar mass of the empirical formula.
3. Take the molar mass of the molecular formula that is given in the problem divided by the empirical formula’s molar mass. Round this to a whole number.
4. Distribute this number to the numbers within the empirical formula to get the new molecular formula.
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EXAMPLE: 1Given the empirical formula of BH3 and
the molecular formula’s molar mass of 27.67 g/mole, find the molecular formula.
Molar mass of BH3 is 13.8 g/mole
27.67 divided by 13.8 = 2
So molecular formula is B2H6
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EXAMPLE: 2A compound is 4.04 grams of nitrogen and 11.46
grams of oxygen. The molecular molar mass is 108.0 g/mole. Find the molecular formula.
4.04 g N x 1 mole= 0.2886 mole N14.0 g
11.46 g O x 1 mole =0.7163 mole O16.0 g
0.2886 : 0.71630.2886 0.28861: 2 = NO2 empirical molar mass = 46.0 g/mole108.0 divided by 46.0 = 2Molecular formula = N2O4