Heat transfer
Rudolf Žitný, Ústav procesní a zpracovatelské techniky ČVUT FS 2010
HEAT PROCESSESHP4
Mechanisms of heat transfer. Conduction, convection (heat transfer coefficients), radiation (example: cooling cabinet). Fourier’s law of conduction, thermal resistance (composed wall, cylinder). Unsteady heat transfer, penetration depth (derivation, small experiment with gas lighter and copper wire). Biot number (example: boiling potatoes). Convective heat transfer, heat transfer coefficient and thickness of thermal boundary layer. Heat transfer in a circular pipe at laminar flow (derivation Leveque). Criteria: Nu, Re, Pr, Pe, Gz. Heat transfer in turbulent flow, Moody’s diagram. Effects of variable properties (Sieder Tate correction for temperature dependent viscosity, mixed and natural convection).
Mechanisms of heat transferHP4
There exist 3 basic mechanisms of heat transfer between different bodies (or inside a continuous body)
Conduction in solids or stagnant fluids
Convection inside moving fluids, but first of all we shall discuss heat transfer from flowing fluid to a solid wall
Radiation (electromagnetric waves) the only mechanism of energy transfer in an empty space
Aim of analysis is to find out relationships between heat flows (heat fluxes) and driving forces (temperature differences)
Heat flux and conductionHP4
Benton
( )
reaction and phase heat fluxchangesaccumulation this term is zero for
conductionof enthalpy incompressible liquid andreduces to Dp/Dt for ideal gas.
( ) ( ) Rp p
T v pc T T Q
t T t
enthalpies
and electric heat
General form of transport Fourier equation for temperature field T(t,x,y,z) in a solid or in a stagnant fluid taking into account internal heat sources and an adiabatic temperature increase during compression of gas.
Heat flux and conductionEnergy balance of a closed system dq = du + dw (heat delivered to system equals internal energy increase plus mechanical work done by system) tells nothing about intensity of heat transfer at the surface of system, neither about relationships between heat fluxes and driving forces (temperature gradients). This problem is a subject of irreversible thermodynamics.
Intenzity of heat transfer through element dA of boundary is characterized by vector of heat flux [W/m2]
n
dA q q
Direction and magnitude of heat flux is determined by gradient of temperature and thermal conductivity of media
Tq
Heat flow through boundary is projection of heat flux to the outer normal qn
Fourier’s law of heat conduction
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Thermal conductivity
Material [W/(m.K)] a [m2/s]
Aluminium Al 200 80E-6
Carbon steel 50 14E-6
Stainless steel 15 4E-6
Glas 0.8 0.35E-6
Water 0.6 0.14E-6
Polyethylen 0.4 0.16E-6
Air 0.025 20E-6
Thermal and electrical conductivities are similar: they are large for metals (electron conductivity) and small for organic materials. Temperature diffusivity a is closely related with the thermal conductivity
Memorize some typical values: pca
Thermal conductivity of nonmetals and gases increases with temperature (by about 10% at heating by 100K), at liquids and metals usually decreases.
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Distribution of temperatures and heat fluxes in a solid can be expressed in differential form, based upon enthalpy balancing of infinitesimal volume dv
Integrating this differential equation in a finite volume V the integral enthalpy balance can be expressed in the following form using Gauss theorem
Conduction – Fourier equation
hq
t
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V V S
hdv qdv n qds
t
n
dA q
yx zqq q
qx y z
Accumulation of enthalpy in unit control volume Divergence of heat fluxes (positive
if heat flows out from the control volume at the point x,y,z)
Accumulation of enthalpy in volume V
Heat transferred through the
whole surface S
Heat flux q as well as the enthalpy h can be expressed in terms of temperatures, giving partial differential equation – Fourier equation
Conduction – Fourier equation
( )
( ) ( ) ( )
g
p g
p g
hq Q
tT
c T QtT T T T
c Qt x x y y z z
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Thermal conductivity need not be a constant. It usually depends on temperature, and for anisotropic materials (e.g. wood) it depends also on directions x,y,z – in this case ij should be considered as
the second order tensor.
Internal heat source (e.g. enthalpy change of a chemical reaction or a volumetric heat produced by passing electric
current or absorbed microwaves)
Let us consider special case: Solid homogeneous body (constant thermal conductivity and without internal heat sources). Fourier equation for steady state reduces to the Laplace equation for T(x,y,z)
Boundary conditions: at each point of surface must be prescribed either temperature T or the heat flux (for example q=0 at an insulated surface).
Solution of T(x,y,z) can be found for simple geometries in an analytical form (see next slide) or numerically (using finite difference method, finite element,…) for more complicated geometry.
Conduction - stationary
2
2
2
2
2
220
z
T
y
T
x
TT
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2
2
22
10 ( )
10 ( )
T Tr
x r r rT
rr r r
The same equation written in cylindrical and spherical
coordinate system (assuming axial symmetry)
Calculate radial temperature profile in a cylinder and sphere (fixed temperatures T1 T2 at inner and outer surface)
Example temperature profile in a cylinder
2 1 1 2 2 11 1 2 1 2
2 1 2 1
2 1 1 2 2 2 1 11 2 1 2 1 2
2 1 2 1
ln ln, T=c ln c
ln / ln /
c, T=- c ( )
T T T R T RTr c r c c
r R R R R
R R T R T RTr c c T T c
r r R R R R
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Sphere (bubble)
cylinder
R1
R2
Knowing temperature field and thermal conductivity it is possible to calculate heat fluxes and total thermal power Q transferred between two surfaces with different (but constant) temperatures T1 a T2
Conduction – thermal resistance
TR
TTQ 21
L
RRRT 2
/ln 12)(1
2
2
1
1
hh
SRT
RT [K/W] thermal resistance
h1 h2
S
T1 T2
h
S1
S2
T1 T2
L
R1
R2
T1 T2
L
R1
T1
T2
h
Q
2211 SS
hRT
L
RhRT 2
/2ln
Serial Parallel Tube wall Pipe burried under surface
In this way it is possible to express thermal resistance of windows, walls,
heat transfer surfaces …
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Time development of temperature field T(t,x,y,z) in a homogeneous solid body without internal heat sources is described by Fourier equation
with the boundary conditions of the same kind as in the steady state case and with initial conditions (temperature distribution at time t=0).
This solution T(t,x,y,z) can be expressed for simple geometries in an analytical form (heating brick, plate, cylinder, sphere) or numerically.
Conduction - nonstacionary
)(2
2
2
2
2
2
z
T
y
T
x
Ta
t
T
The coefficient of temperature diffusivity a=/cp is the ratio of
temperature conductivity and thermal inertia
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Typical application: How long must be a can held in a sterilizer so that all microorganisms at the can center will be killed?
Simple answer: for infinitely long time. This is never possible to kill all of them, only some prescribed percents, e.g. the number of Clostridium Botulinum spores should be reduced by 12 orders according to regulation. Therefore only one of 1012 spores could survive the thermal treatment (not the viable form it would be much easier). Number of survived pathogens depends upon the whole temperature history at a given place (in this case in the center of can) and can be evaluated as an integral of temperature (see lecture aseptic processes).
Temperature field in a can is described by Fourier equation rewritten by using dimensionless temperature that is zero on the surface and 1 inside the can at time t=0
There are many ways how to solve the problem:
Numerically (finite differences seems to be an obvious choice)
Using integral transforms (e.g. Laplace transform to transform differential equation to an algebraic one)
Using Fourier’s method of separated variables, see next slide
Example Conduction - nonstationary
2
20
1( ), w
w
T Tr
x r r r T T
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=at, where a is temperature diffusivity
of meat in a can
Initial temperature wall temperature
Temperature field (=at,x,r) can be decomposed to the product X(,x)R(,r) of two functions that fulfill the following two simplified equations
It can be easily verified that the product (,x,r)= X(,x)R(,r) satisfies not only the original Fourier equation but also the prescribed boundary (=0) and initial (=1) conditions (this is the reason why it was necessary to introduce dimensionless temperature and
transformed time = a t ).
Resulting equations can be solved again by the separation of variables
Example Conduction - nonstationary
2
2
1( )
X X
xR R
rr r r
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X and R satisfy zero boundary condition (X=R=0
at surface) and initial condition (X=R=1)
iiii
iiii
rTrrR
xTxxX
)()(),(
)()(),(
Sometimes (for very long time ) it is sufficient to approximate the solution only by the first term in
these series
Axial temperature profile
Radial temperature profile
Resulting ORDINARY differential equations have the following solutions (the same exponential term describes time profile, the sin-function axial variation of temperature and the Bessel function J0 radial variation):
Eigenvalues i are determined from boundary conditions, e.q. sin(iL)=0.
Remark: It is possible to modify this solution for more complicated boundary conditions with finite thermal resistance on the surface of can, see Baehr S. Wärme und Stoff-übertragung, Springer, Berlin, 1994.
Coefficients xi,ri must be calculated so that the initial conditions (X=R=1) will be satisfied (using special properties of eigenfunctions sin,J0, called orthogonality).
Seems too complicated? For more details look at the mentioned book (Baehr), or wait to the next semester, where the same problem will be discussed in more details during the course Numerical analysis of processes.
Example Conduction - nonstationary
2
2
0
( )=e ( ) sin( )
( )=e ( ) ( )
i
i
i i i
i i i
T x x
T r J r
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L
Example Conduction - nonstationaryHP4
I wrote previous pages at home when I have only the Baehr’s book at hand. Today (at work) I can add reference to the famous book (first published at 1946!)
Carslaw H.S., Jaeger J.C.: Conduction of heat in solids, Clarendon Press, Oxford, 2004 (previous problem is solved on pages 328-329)
Previous example was probably too complicated. However, there exists much simpler and probably more important 1dimensional problem of heated halfspace, and the step wise change of surface temperature as a boundary condition.
Conduction - nonstacionary
t
Tw
T0
x
δ
2
2
2
0
2 0 2
21 exp( ) ( )
2
x d d
d d
xd erfc
at
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20
20
, w
T T
x T T
This equation is the same as previously and therefore the same method (separation of variables) can be used. The analyzed case of heat transfer in a plate was complicated by the boundary condition at x=L and now this requirement is shifted to infinity. Therefore the solution in the vicinity of surface will be controlled only by the boundary condition at x=0 (for short times) and a new kind of solution, based upon similarity transformation can be used. This transformation introduces suitable dimensionless combination of time and coordinate , for example =/x2, =x2/, =x/, recasting the partial differential equation (PDE) to an ordinary differential equation (ODE). The simplest form of the resulting ODE is obtained for =x/ (check other possibilities)
Erfc is complementary error function (available also in some pocket calculators)
Erfc function describes temperature response to a unit step at surface (jump from zero to a constant value 1). The case with prescribed time course of temperature at surface Tw(t) can be solved by using the superposition principle and the response can be expressed as a convolution integral.
Conduction - nonstacionaryHP4
x d
Tw()
T(t,x)
t
Time course Tw(t) can be substituted by short pulses Temperature at a distance x is the sum of responses to short pulses Tw()d
t
w dxtETxtT0
),()(),(
The function E(t,,x)=E(t-,x) is the impulse function (response at a distance x to a temperature pulse of infinitely short duration but unit area – Dirac delta function). The impulse response can be derived from derivative of the erfc function
)4
exp(2
),(2
2/3 at
x
ta
xxtE
Theory of penetration depth
Result is ODE for thickness as a function of time
4at
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Still too complicated? Your pocket calculator is not equipped with the erf-function? Use the acceptable approximation by linear temperature profile
Tw
T0
x
δ
t+tt
+Δ
0
0
0
|
( )2
x
w
w w
T Tdx a
t x
TTdx a
t
T Ta
t
Integrate Fourier equations (up to this step it
is accurate)
Approximate temperature profile by line
Using the exact temperature profile predicted by erf-function, the penetration
depth slightly differs =(at)
Theory of penetration depth=at penetration depth. Extremely simple and important result, it gives us prediction how far the temperature change penetrates at the time t. This estimate enables prediction of thermal and momentum boundary layers thickness etc. The same formula can be used for calculation of penetration depth in diffusion, replacing temperature diffusivity a by diffusion coefficient DA .
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Wire Cu
=0.11 m
=398 W/m/K
=8930 kg/m3
Cp=386 J/kg/K
Example Continuation the canHP4
Summary of previous results:
For very short times and small penetration depth the temperature profile can be always approximated by erf-function or linear function (even for cylinder as soon as the thickness <<R)
For very long times the temperature profile can be approximated only by the first term of Fourier’s expansion, in case of the can by
LR
2 2( )0e sin( ) ( )x r
x rc x J r
ConvectionHP4
Benton
( )
convection viscousconductionheatingthis term is zero for
incompressible liquid
( ) ( ) : Rp p
T v Dpc u T T q Q
t T Dt
General form of transport Fourier Kirchhoff equation
ConvectionCalculation of heat flux q from flowing fluid to a solid surface requires calculation of temperature profile in the vicinity of surface (see previous Fourier Kirchhoff equation but also for example temperature gradients in attached bubbles during boiling, all details of thermal boundary layer,…).
Engineering approach simplifies the problem by introducing the idea of stagnant homogeneous layer of fluid, having an equivalent thermal resistance (characterized by the heat transfer coefficient [W/(m2K)])
Tf is temperature of fluid far from surface (behind the boundary of thermal boundary layer), Tw is wall temperature. Thickness of stagnant boundary layer δ, f thermal conductivity of fluid.
Tq
)( wf TTq ( ) ( )ff w f f w
Tq T T T T
y
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n
dA
q
Boiling (bubbles)
Outer flow-thermal boundary layer
,yTf Tf
f
Example heating sphereHP4
Temperature distribution inside a solid sphere
22
( )s s sp
T Tc r
t r r r
It is correct only as soon as the heat flux q or the temperature is uniform on the sphere surface
Boundary condition (convection)
( )ss f s
TT T
r
Heat flux calculated from Fourier law inside the
sphere equals the flux in fluid
Fourier equation can be integrated at the volume of body (sphere in this case)
2sp s s
V V V
Tc dv T dv qdv
t
The integrals can be evaluated by the mean value and by Gauss theorem, assuming uniform flux at the surface
( )sp f s
S
TMc n qdS n qS T T S
t
Example heating sphereHP4
For the case that the temperature inside the sphere is uniform (as soon as the thermal conductivity s is very high) the mean temperature is identical with the surface temperature
/0
( )
( )
sf s
p
ts f f
p
dT ST T
dt c M
T T T T e
c M
S
This exponential solution works only for small values of Biot number
Thermal resistance of fluid >> thermal resistance of solid1.0s
DBi
Convection – Nu,Re,PrHeat transfer coefficient depends upon the flow velocity (u), thermodynamic parameters of fluid () and geometry (for example diameter of sphere or pipe D). Value is calculated from engineering correlation using dimensionless criteria
Nusselt number (dimensionless , reciprocal thickness of boundary layer)
Reynolds number (dimensionless velocity, ratio of intertial and viscous forces)
Prandl number (property of fluid, ratio of viscosity and temperature diffusivity)
uD
Re
D
Nu
a
Pr
Rem: is dynamic viscosity [Pa.s], kinematic viscosity [m2/s], =/
And others
Pe=Re.Pr Péclet numberGz=Pe.D/L Graetz number (D-diameter, L-length of pipe)
RayleighDe=Re√D/Dc Dean number (coiled tube, Dc diameter of curvature)
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Convection in a pipe
Liquid flows in a pipe with the constant wall temperature Tw that is different than the inlet temperature T0. Temperature profile depends upon distance from inlet and upon radius r (only thin temperature boundary layer of fluid is heated). Heat flux varies along the pipe even if the heat transfer coefficient is constant, because driving potential – temperature difference between wall and the bulk temperature Tm depends upon the distance x. Tm is the so called mean calorific temperature
A
m uTdAm
xT 1
)(
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Basic problem for heat transfer at internal flows: pipe (developed velocity profile) and a constant wall temperature
( ) ( )( ( ))w mq x x T T x
Heat flux from wall to bulk ( is related to the calorific
temperature as a characteristic fluid
temperature at internal flows)
Convection in a pipe
0 ( ( ) ( )) ( ( ))p m m w mmc T x T x dx T T x Ddx
0 ( ( ) ( )) ( ( ))w mm h x h x dx T T x Ddx
dxDTT
dTcm
mw
mp
x dx
DT0
Tw
Tm
Q
Axial temperature profile Tm(x) follows from the enthalpy balance of system, consisting of a short element of pipe dx :
0
( )ln w m
pw
T T xmc D x
T T
Solution Tm(x) by integration
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Convection in a pipePrevious integration is correct only if and the wall temperature are constant.
This doesn’t hold in laminar flow characterized by gradual development of thermal boundary layer (at entry this layer is thin and therefore =/ is high, decreases with increasing distance). Typical correlation for laminar flow is Leveque formula
is almost constant at turbulent flows characterized by fast development of thermal boundary layer. Typical correlation (Dittus Boelter)
More complicated are cases with mixed convection (effect of temperature dependent density and gravity), variable viscosity and first of all influence of phase changes (boiling/condensation).
0 0
outletT Lm
pw mT
dTmc D dx
T T
31.6 Re PrD D
NuL
0.8 1/30.023Re PrD
Nu
L
DT0
Tw
Toutlet
Q
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general formula for variable wall temperature and variable heat
transfer coefficient
Convection Laminar LevequeHP4
x
DT0
Tw
yumax
Leveque method is very important technique how to estimate thickness of thermal boundary layer and the heat transfer coefficient in many internal flows (not only in circular pipes). This theory is applicable only for “short” channels, in the region of developing temperature profile.
Convection Laminar Leveque
x
DT0
Tw
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8( )
uu y y ky
D
Linear approximation of temperature profile in thermal
boundary layer
Linear approximation of velocity profile in thermal
boundary layer
y
umax 2umax
xt
k
2 3 8
x axDat a
k u
Linearized velocity profile
Transit time of particle at the distance from wall
Thickness of boundary layer from penetration theory
2
333 3 38 8 8
Re Prx x
D D u D u Du D DNu D c c Gz
aDx ax a x x
Graetz number for distance x from inlet
Gz=Re.Pr.D/x
Convection Laminar LevequeHP4
Graetz number Gz=Re.Pr.D/L
Local Nux decreases with x. Mean value of Nu corresponding to the length of pipe L is obtained by integration, so that the outlet temperature Toutlet can be calculated from enthalpy balance
ln0 0
333ln
0 0
3ln
ln
1 3Re Pr Re Pr 1.6
2
1.6
Lw outlet
pw
L L
T Tmc D dx DL
T T
c D c Ddx dx Gz
L D L x D L D
DNu Gz
Heat transfer surface
Heat capacity of stream
Mean heat transfer coefficient related to the
mean logarithmic temperature difference
Remark: further on the index ln will be frequently omitted, and Nu, denotes mean values along the whole channel.
Convection Laminar LevequeHP4
1/3
0
,
0.8085
0.975
y
Tw const
q const
duD dy
Nu cDax
c
c
1/32(3 1)
0.8085D n D
Nu Pen x
x
DT0
Tw
Linear approximation of power law velocity profile in thermal
boundary layer
y
umax
13 1 2
11
nnn r
u un D
Previous result holds only for parabolic velocity profile, corresponding to the fully developed flow of a Newtonian liquid. For fluids with different velocity profiles (e.g. profiles corresponding to power law liquids) the whole derivation must be repeated – the idea of Leveque remains
The same procedure can be applied to the case with the constant wall
temperature and with a constant wall heat flux (only the constant c differs)
Velocity profile for power law liquid (n-flow index)
This example demonstrates that sometimes it is more important to know a derivation than the final result.
Convection Laminar HausenHP4
ln2/3
0.06683.66
1 0.04
D GzNu
Gz
Léveque solution is valid only at
Laminar flow (Re<2300) and fully developed velocity profile
In the region of thermal boundary layer development (“short” pipes, Gz>50)
For a pipe of arbitrary length the Graetz solution in form of series of eigenfunctions (see the Fourier method of separation of variables) can be used. At a very large distance from inlet the boundary layers merge, transverse temperature profiles become similar and the heat transfer coefficient approaches limiting value (Nu=3.66 for the case of constant wall temperature, Nu=4.36 for constant heat flux).
Hausen’s semiempirical correlation is a blend of Léveque solution and asymptotic values of Nu
Prove that the Hausen formula reduces to Leveque for Gz
Constant heat flux (therefore increasing wall
temperature). Typical for the counterflow heat
exchangers.
Constant wall temperature (maintained by boiling or
condensing steam)
Example Graetz number=50HP4
Water: kinematic viscosity 10-6 m2/s, Pr=6
4Re Pr Re Pr 0.05Re 1.36 Re50T hl ht
D DL L D L D
Gz
D [m] U [m/s] Re Lh [m] LT [m]
0.1 1 105 1.2 turbulent
0.05 1 50000 0.5 turbulent
0.01 1 10000 0.07 turbulent
0.01 0.1 1000 0.5 1.2
0.01 0.01 100 0.05 0.12
0.005 0.1 500 0.12 0.3
0.005 0.01 50 0.012 0.03
Maximum length for Leveque Stabilization velocity for laminar/turbulent flow
Rohsenow chapter 5.26
Thermal stabilization length Hydraulic stabilization length
Mixed convection, Sieder TateHP4
0,141/31/3 1/3 4/9
3
2
1,618 1 0,0111 ,
,
W
Nu Gz Gz Gr
g TDGr
Temperature dependendent properties of fluid are respected by correction coefficients applied to a basic formula (Leveque, Hausen, …similar corrections are applied in correlations for turbulent regime)
Temperature dependent viscosity results in changes of velocity profiles. In case of heating the wall temperature is greater than the bulk temperature, and viscosity of liquid at wall lowers. Velocity gradient at wall increases thus increasing heat transfer (look at the derivation of Leveque formula modified for nonnewtonian velocity profiles). Reversaly, in case of cooling (greater
viscosity at wall) heat transfer coefficient is reduced. This effect is usually modeled by Sieder Tate correction (ratio of viscosities at bulk and wall temperature).
Temperature dependent density combined with acceleration (gravity) generate buoyancy driven secondary flows. Resulting effect depends upon orientation (vertical or horizontal pipes should be distinguished). Intensity of natural convection (buoyancy) is characterized by Grashoff number Gr)
Leveque
Mixed convection (Grashoff)
Sieder Tate correction
Convection Turbulent flowHP4
Boccioni
Convection Turbulent flowHP4
Turbulent flow is characterised by the energy transport by turbulent eddies which is more intensive than the molecular transport in laminar flows. Heat transfer coefficient and the Nusselt number is greater in turbulent flows. Basic differences between laminar and turbulent flows are:
Nu is proportional to in laminar flow, and in turbulent flow.
Nu doesn’t depend upon the length of pipe in turbulent flows significantly (unlike the case of laminar flows characterized by rapid decrease of Nu with the length L)
Nu doesn’t depend upon the shape of cross section in the turbulent flow regime (it is possible to use the same correlations for eliptical, rectangular…cross sections using the concept of equivalent diameter – this cannot be done in laminar flows)
3 u 0.8u
The simplest correlation for hydraulically smooth pipe designed by Dittus Boelter is frequently used (and should be memorized)
0.80.023Re PrmNu m=0.4 for heating
m=0.3 for cooling
Similar result follows from the Colburn analogy 3/18.0 PrRe023.0Nu
Convection Turbulent flowHP4
,PrReL
D,Nu
,
W
,// 140
4204332
18010370
2300<Re<105 0,6<Pr<500
Nu
f
f W
n
Re Pr
. . Pr /8 56 35 92 12 3n=0,11 TW>T (heating)
n=0,25 TWT (cooling)
Dittus Boelter correlation assumes that Nu is independent of L. For very short pipes (L/D<60) Hausen’s correlation can be applied
Effect of wall roughness can be estimated from correlations based upon analogies between momentum and heat transfer (Reynolds analogy, Colburn analogy, Prandtl Taylor analogy). Results from hydraulics (pressure drop, friction factor f) are used for heat transfer prediction. Example is correlation Pětuchov (1970) recommended in VDI Warmeatlas
104Re5,106 0,5Pr2000 0,08W /40.
Friction factor
Pressure drop, friction factorHP4
21
2 f
Lp u
D
Friction factor f depends upon Re
and relative roughness
Pressure drop is calculated from Darcy Weissbach equation
Turbulent boundary layerHP4
Velocity profile
Laminar sublayer
e-roughness
Buffer layer
Thickness of laminar sublayer is at value y+=5
Rougness of wall has an effect upon the pressure drop and heat transfer only if the height of irregularities e (roughness) enters into the so called buffer layer of turbulent flow. Smaller roughness hidden inside the laminar (viscous) sublayer has no effect and the pipe can be considered as a perfectly smooth.
**, ,
4w
w
u y dp Dy u
dx
Friction velocity
Dimensionless distance from wall
y
Example smooth pipeHP4
Calculate maximum roughness at which the pipe D=0.1 m can be considered as smooth at flow velocity of water u=1 m/s.
Re 10000uD
4
0.3160.0316
Ref
211600
2 f
pu
L D
5 10 25L
e mD p
Blasius correlation for friction factor (smooth
pipes)
Thickness of laminar sublayer (y+=5)