6.1 – Ratios, Proportions, and the Geometric Mean
GeometryMs. Rinaldi
Ratio
• Ratio – a comparison of numbers• A ratio can be written 3 ways:
1. a:b
2.
3. a to b
Examples: 2 girls to 7 boys, length:width = 3:2
b
a
EXAMPLE 1 Simplify ratios
SOLUTION
64 m : 6 ma.
Then divide out the units and simplify.
b. 5 ft20 in.
b. To simplify a ratio with unlike units, multiply by a conversion factor.
a. Write 64 m : 6 m as 64 m6 m
.
= 323
= 32 : 3
5 ft20 in. = 60
20 = 31= 5 ft
20 in.12 in.1 ft
Simplify the ratio.
64 m6 m
EXAMPLE 2 Simplify Ratios
Simplify the ratio.
1. 24 yards to 3 yards
2. 150 cm : 6 m
EXAMPLE 3 Use a ratio to find a dimension
SOLUTION
Painting
You are planning to paint a mural on a rectangular wall. You know that the perimeter of the wall is 484 feet and that the ratio of its length to its width is 9 : 2. Find the area of the wall.
Write expressions for the length and width. Because the ratio of length to width is 9 : 2, you can represent the length by 9x and the width by 2x.
STEP 1
EXAMPLE 3 Use a ratio to find a dimension (continued)
STEP 2
Solve an equation to find x.
Formula for perimeter of rectangle
Substitute for l, w, and P.Multiply and combine like terms.
Divide each side by 22.
=2l + 2w P=2(9x) + 2(2x) 484= 48422x
Evaluate the expressions for the length and width. Substitute the value of x into each expression.
STEP 3
The wall is 198 feet long and 44 feet wide, so its area is198 ft 44 ft = 8712 ft .2
= 22x
Length = 9x = 9(22) = 198Width = 2x = 2(22) = 44
EXAMPLE 4 Use a ratio to find a dimension
The perimeter of a room is 48 feet and the ratio of its length to its width is 7:5. Find the length and width of the room.
EXAMPLE 5 Use extended ratios
Combine like terms.
SOLUTION
Triangle Sum Theorem
Divide each side by 6.= 30x=6x 180= 180
ox + 2x + 3x o oo
ALGEBRA The measures of the angles in CDE are in the extended ratio of 1 : 2 : 3. Find the measures of the angles.
Begin by sketching the triangle. Then use the extended ratio of 1 : 2 : 3 to label the measures as x° , 2x° , and 3x° .
The angle measures are 30 , 2(30 ) = 60 , and 3(30 ) = 90.o o o o o
ANSWER
EXAMPLE 6 Use Extended Ratios
A triangle’s angle measures are in the extended ratio of 1 : 3 : 5. Find the measures of the angles.
EXAMPLE 7 Solve proportions
SOLUTION
a. 510
x16=
Multiply.
Divide each side by 10.
a. 510
x16=
= 10 x5 16
= 10 x80
= x8
Write original proportion.
Cross Products Property
Solve the proportion.ALGEBRA
EXAMPLE 8 Solve proportions
Subtract 2y from each side.
1y + 1
23y
b. =
= 2 (y + 1)1 3y
= 2y + 23y
=y 2
Distributive Property
SOLUTION
b. 1y + 1 = 2
3y
Write original proportion.
Cross Products Property
EXAMPLE 9 Solve proportions
a. 2 x
5 8=
b. 1x – 3
43x=
c.
y – 3 7
y14=
Solve the proportion.
Geometric Mean
EXAMPLE 10 Find a geometric mean
Find the geometric mean of the two numbers.
a) 12 and 27
b) 24 and 48