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1. Lima puluh ribu lapan belas P12. 12 P1
3. 7.031 P14. P1
5. 5 P16. 4600
+ 4850K1
9450 N17. 9812
X 7K1
68684 N18. 3.100
- 0.405K1
2.695 N19. 18.720
- 2.554K1
16.166 N110. X 1000 K1
300 N111. 3.60 ÷ 3 K1
1.20 N112. RM264 ÷ 2 K1
RM132 N113. X 1200 K1
480 ml N114. 20 + 8 + 8 + 9 + 9 + 9 + (20-9) K1
74 m N115. 35 ÷ 5 K1
7 m N116. Tahun 4 : 35x3 = 105
Tahun 5 : 25x4 = 100Tahun 6 : 38x2 = 76
K1
105- 76
K1
29 N117. X 250 K1
X 175 K1
RM 105atau
N1
250 – ( x 250 ) K1
175 – ( x 175 ) K1
RM105 N1
18. 30 bulan K1X 30 K1
6 bulanatau
N1
30 bulan K130 – ( x 30) K1
6 bulan N119. 3150 K1
3150 ÷ 3 K11050 ml N1
20. 49 + ( X 49) K1
56+ 49
K1
105 kg N1* Terima apa jua jalan kerja murid yang logik
KERTAS 1
1. B 11. D 21. B 31. D2. D 12. C 22. B 32. B3. D 13. B 23. C 33. A4. C 14. B 24. D 34. A5. D 15. C 25. A 35. C6. B 16. D 26. D 36. B7. D 17. A 27. B 37. D8. D 18. A 28. B 38. A9. A 19. D 29. A 39. D
10. B 20. C 30. B 40. DA = 8 B = 12 C = 6 D=14
Catatan:
Skema ini diubahsuai dan dimurnikan daripada skemaasal yang diterima oleh sekolah-sekolah. Terdapat 3ralat jawapan K1 yang telah dibetulkan.
Disediakan oleh
Cikgu Faizhttp://rphonline.teknologihijau.net
SKEMA JAWAPAN MATEMATIKPERCUBAAN UPSR NEGERI PERAK 2013
KERTAS 2
1. Lima puluh ribu lapan belas P12. 12 P1
3. 7.031 P14. P1
5. 5 P16. 4600
+ 4850K1
9450 N17. 9812
X 7K1
68684 N18. 3.100
- 0.405K1
2.695 N19. 18.720
- 2.554K1
16.166 N110. X 1000 K1
300 N111. 3.60 ÷ 3 K1
1.20 N112. RM264 ÷ 2 K1
RM132 N113. X 1200 K1
480 ml N114. 20 + 8 + 8 + 9 + 9 + 9 + (20-9) K1
74 m N115. 35 ÷ 5 K1
7 m N116. Tahun 4 : 35x3 = 105
Tahun 5 : 25x4 = 100Tahun 6 : 38x2 = 76
K1
105- 76
K1
29 N117. X 250 K1
X 175 K1
RM 105atau
N1
250 – ( x 250 ) K1
175 – ( x 175 ) K1
RM105 N1
18. 30 bulan K1X 30 K1
6 bulanatau
N1
30 bulan K130 – ( x 30) K1
6 bulan N119. 3150 K1
3150 ÷ 3 K11050 ml N1
20. 49 + ( X 49) K1
56+ 49
K1
105 kg N1* Terima apa jua jalan kerja murid yang logik
KERTAS 1
1. B 11. D 21. B 31. D2. D 12. C 22. B 32. B3. D 13. B 23. C 33. A4. C 14. B 24. D 34. A5. D 15. C 25. A 35. C6. B 16. D 26. D 36. B7. D 17. A 27. B 37. D8. D 18. A 28. B 38. A9. A 19. D 29. A 39. D
10. B 20. C 30. B 40. DA = 8 B = 12 C = 6 D=14
Catatan:
Skema ini diubahsuai dan dimurnikan daripada skemaasal yang diterima oleh sekolah-sekolah. Terdapat 3ralat jawapan K1 yang telah dibetulkan.
Disediakan oleh
Cikgu Faizhttp://rphonline.teknologihijau.net
SKEMA JAWAPAN MATEMATIKPERCUBAAN UPSR NEGERI PERAK 2013
KERTAS 2
1. Lima puluh ribu lapan belas P12. 12 P1
3. 7.031 P14. P1
5. 5 P16. 4600
+ 4850K1
9450 N17. 9812
X 7K1
68684 N18. 3.100
- 0.405K1
2.695 N19. 18.720
- 2.554K1
16.166 N110. X 1000 K1
300 N111. 3.60 ÷ 3 K1
1.20 N112. RM264 ÷ 2 K1
RM132 N113. X 1200 K1
480 ml N114. 20 + 8 + 8 + 9 + 9 + 9 + (20-9) K1
74 m N115. 35 ÷ 5 K1
7 m N116. Tahun 4 : 35x3 = 105
Tahun 5 : 25x4 = 100Tahun 6 : 38x2 = 76
K1
105- 76
K1
29 N117. X 250 K1
X 175 K1
RM 105atau
N1
250 – ( x 250 ) K1
175 – ( x 175 ) K1
RM105 N1
18. 30 bulan K1X 30 K1
6 bulanatau
N1
30 bulan K130 – ( x 30) K1
6 bulan N119. 3150 K1
3150 ÷ 3 K11050 ml N1
20. 49 + ( X 49) K1
56+ 49
K1
105 kg N1* Terima apa jua jalan kerja murid yang logik
KERTAS 1
1. B 11. D 21. B 31. D2. D 12. C 22. B 32. B3. D 13. B 23. C 33. A4. C 14. B 24. D 34. A5. D 15. C 25. A 35. C6. B 16. D 26. D 36. B7. D 17. A 27. B 37. D8. D 18. A 28. B 38. A9. A 19. D 29. A 39. D
10. B 20. C 30. B 40. DA = 8 B = 12 C = 6 D=14
Catatan:
Skema ini diubahsuai dan dimurnikan daripada skemaasal yang diterima oleh sekolah-sekolah. Terdapat 3ralat jawapan K1 yang telah dibetulkan.
Disediakan oleh
Cikgu Faizhttp://rphonline.teknologihijau.net
SKEMA JAWAPAN MATEMATIKPERCUBAAN UPSR NEGERI PERAK 2013
KERTAS 2
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