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Do Now:. Write the standard form of an equation of a line passing through (-4,3) with a slope of -2. Write the equation in standard form with integer coefficients y = -1/3x - 4. Do Now:. Worksheet – Match the correct bottle with its graph. Factoring Using the Distributive Property. - PowerPoint PPT PresentationTRANSCRIPT
Do Now:
Write the standard form of an equation of a line passing through (-4,3) with a slope of -2.
Write the equation in standard form with integer coefficientsy = -1/3x - 4
Do Now:
Worksheet – Match the correct bottle with its graph
Factoring Using the Distributive Property
GCF and Factor by Grouping
1) Factor GCF of 12a2 + 16a
12a2 = 16a =
2 2 3 a a
2 2 2 2
2 2 a = 4a212 16a a 4a (3 )a 4a (4)
Use distributive
property
4a (3 4)a
a
PRIME POLYNOMIALSA POLYNOMIAL IS PRIME IF IT IS NOT THE PRODUCT OF POLYNOMIALS HAVING INTEGER COEFFICIENTS.
TO FACTOR A PLYNOMIAL COMPLETLEY, WRITE IT AS THE PRODUCT OF •MONOMIALS• PRIME FACTORS WITH AT LEAST TWO TERMS
2X2 + 8 = 2(X2 + 4)
YES, BECAUSE X2 + 4 CANNOT BE FACTORED USING INTEGER COEFFICIENTS
2X2 – 8 = 2(X2 – 4)
NO, BECAUSE X2 – 4 CAN BE FACTORED AS (X+2)(X-2)
TELL WHETHER THE POLYNOMIAL IS FACTORED COMPLETELY
Using GCF and Grouping to Factor a Polynomial
First, use parentheses to group terms with common factors.
Next, factor the GCF from each grouping. Now, Distributive Property…. Group both GCF’s.
and bring down one of the other ( ) since they’re both the same.
2) Factor 4 8 3 6ab b a ( ) ( )4b ( 2)a 3 ( 2)a
(4 3)b ( 2)a
Using GCF and Grouping to Factor a Polynomial
First, use parentheses to group terms with common factors.
Next, factor the GCF from each grouping. Now, Distributive Property…. Group both GCF’s.
and bring down one of the other ( ) since they’re both the same.
23) Factor 6 15 8 20x x x ( ) ( )3x (2 5)x 4 (2 5)x
(3 4)x (2 5)x
Using GCF and Grouping to Factor a Polynomial
First, use parentheses to group terms with common factors.Next, factor the GCF from each grouping.Now, Distributive Property…. Group both GCF’s. and bring down one of the other ( ) since they’re both the same.
24) Factor 2 6 3 9a a a ( ) ( )2a ( 3)a 3 ( 3)a
(2 3)a ( 3)a
Using the Additive Inverse Property to Factor Polynomials.
When factor by grouping, it is often helpful to be able to recognize binomials that are additive inverses. 7 – y is
y – 7 By rewriting 7 – y as -1(y – 7)
8 – x is x – 8 By rewriting 8 – x as -1(x – 8)
5) Factor 35 5 3 21x xy y ( )( )5x (7 )y 3 ( 7)y
( 5 3)x ( 7)y
Factor using the Additive Inverse Property.
5x( 1) ( 7)y 3 ( 7)y
5x ( 7)y 3 ( 7)y
6) Factor 2 8 4c cd d ( ) ( )c (1 2 )d 4 (2 1)d
( 4)c (2 1)d
Factor using the Additive Inverse Property.
c ( 1) (2 1)d 4 (2 1)d
c (2 1)d 4 (2 1)d
27) Factor 10 14 15 21x xy x y
There needs to be a + here so change the minus to a
+(-15x)
210 14 ( 15 ) 21x xy x y •Now group your common terms.
•Factor out each sets GCF.
•Since the first term is negative, factor out a negative number.
•Now, fix your double sign and put your answer together.
( ) ( )2x(5 7 )x y 3( ) (5 7 )x y
(2 3)x (5 7 )x y
8) Factor 8 6 12 9ax x a
There needs to be a + here so change the minus to a
+(-12a)
8 6 ( 12 ) 9ax x a •Now group your common terms.
•Factor out each sets GCF.
•Since the first term is negative, factor out a negative number.
•Now, fix your double sign and put your answer together.
( ) ( )2x (4 3)a 3( ) (4 3)a
(2 3)x (4 3)a
Summary
A polynomial can be factored by grouping if ALL of the following situations exist. There are four or more terms. Terms with common factors can be
grouped together. The two common binomial factors
are identical or are additive inverses of each other.