digital & analog communication systems (8th edition) – answer and script solutions manual

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Chapter 1 \ 1-1 \ =\{iCIDO) +V'llaOO} §4.ILfJt1',f'(J" [ 1-2 J U.rin, (1-/), d. d,= f;J;; = i :l,(r ODD) oil- (2.. E.\"f I., . '). PCIl>OO) i- -::. S51tt,/es h 1 =(56 - .r- ::: S 2. H+ '1. 1.. ." ( htr e ) = d t t"e :J h7., p .hre = d"'J- 1, re 5"2.BDM,7es Ld· J..::: cnde-"4 At'-ltkf l:r fe.l) atvl d ti, ";,{(S. J2. 2,,1, -= or .d = Vff: 2. d =- :; 0 =. 2 {2h =; t[- (1 It): (& ())2.. I-.-=- (3o)YB =. 112. 1 1 - 5 la :::th =12 = N.I'!", ,(2.." :J. 4 ... h ['1-) :: 1.83 I Tt1i'al t>f t'.97IHj 1 es 1 1 - 6 11M;}-=: f-i.o,(10)I,D,lf.o1 i.::/} '1-; P':fi:O.lj - -J" (O.l) _ 2 31" 7:;"';J, -I .... (o.J) -/7'17':4.- -;r - J 2.. _. I- (r ) -'4.L.Jf- I L -." ·/u . fl Pj Ij = 2. +{o. j}I. '73?] :; I .. C??/6;h J-. \1-7 II (1-) :9' 1 I .X /"?-IP{lI)::. I Ip<jJl} "9 1= =- (K) 1 INSTRUCTOR SOLUTIONS MANUAL (United States Edition) Digital & Analog Comm. Systems 8th Edition, L. W. Couch, II

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Page 1: Digital & Analog Communication Systems (8th Edition) – Answer and Script Solutions Manual

Chapter 1

\ 1-1 \ cl,+d~ =\{iCIDO) +V'llaOO} ~ §4.ILfJt1',f'(J"

[ 1-2 J U.rin, (1-/), d. ~ d,=f;J;; =i :l,(rODD) ~ oil-~ (2.. ~"1. E.\"f I., ~ . ~ ').

d,+~'1.-= SS~·"e.s ~ PCIl>OO) i- V'J,.~~ -::. S51tt,/es

~ h1 =(56 - .r- ('l»b»~ ::: S2. H+

'1. 1.. ." ( htre ) =d t t"e

:J h7.,p .hre = d"'J- kJ~~'{' 1, ~<. re ~d~2ht'~ ~hd re.:t('J~DIli,k;): 5"2.BDM,7es

Ld· J..::: cnde-"4 At'-ltkf l:r fe.l) atvl d ti, ";,{(S.

~ J2. (lIIlles)~ 2,,1, ~;;~ (.s-ll3()N~/e.r) ~cr- -= 1.~ or .d =Vff:

2. d=- :;0 ni.J~ =. 2{2h =; t[- (1It): (&())2.. ~ I-.-=- (3o)YB =. 112.

--=-~o:::oo!.oIl_

11-5 la :::th =12 ~DO) =N.I'!", ,(2.." :J. 4 ... h ['1-) :: 1.83 "'I'/~ I Tt1i'al t'C4.d/~ t>f cove"4g.~:::J,+~,,='I¥-'It/.+,..93:: t'.97IHj 1es

1 1 -6 11M;}-=: f-i.o,(10)I,D,lf.o1 i.::/} '1-; P':fi:O.lj 1j.=flf~o.1 ~ :t~.I - -J" (O.l) _ 2 31" L~ 7:;"';J, -I.... (o.J) -/7'17':4.­-;r • ~ - J 2.. _. I- • (r ) -'4.L.Jf- I L -." ·/u

~ . ~.

fl ::..~ Pj Ij =2. ~.l}(l.1u} +{o. j}I. '73?] :; I .. C??/6;h J-.

\1-7 II~ /~l. (1-) :9' 1I .X i~JlJj /"?-IP{lI)::. 1~/l>(;')

~ I Ip<jJl} ~ JD~('f} "9 1= :~:r.f =- ID~1. (K)

1

INSTRUCTOR SOLUTIONS MANUAL (United States Edition)

Digital & Analog Comm. Systems 8th Edition, L. W. Couch, II

Page 2: Digital & Analog Communication Systems (8th Edition) – Answer and Script Solutions Manual

LET p--The probability for sending a binary 1, then the probability for sending a binary 0 is (l-p). From the entropy formula for H(p), we can draw the figure of R(p) ,and from this figure , we can find the maximum entropy and the p.

R(p)=(p*ln(P)+(1-p)*ln(1-p»j(-ln(2»

k := 0 •• 50 P k

:= k -50

HMAX := 1

h k

-1 :=-­

In(2)

2

h ,HMAX I------+-----:=--+----=====--+------i k

o o P 1

k From the .above figure, we know the maximum entropy is 1 where the probability for sending 1 or 0 is 0.5.

INSTRUCTOR SOLUTIONS MANUAL (United States Edition)

Digital & Analog Comm. Systems 8th Edition, L. W. Couch, II

Page 3: Digital & Analog Communication Systems (8th Edition) – Answer and Script Solutions Manual

P I

::- o.L5 . ~l..:: ~~ ~ 0,15 .·\1-10 ) )

f 'f = ~ 5 "- P~ :.?) "Pg =- PC[ = D, 0 /

o. L 5" + 2 (O./S-) -I- cD (a. 0)) = 0 •cr I :. ~ :::. t).os ~;""te 2.

/0

p. == ',0'0 ~j ~ I

~ to

H = 2 p. ~~ ~ (t\ ~ [~J 2 p, ~ f· '-, J .)) 11 J j j- ..t:Ao'L ";'::'1

=[i-I"L] [. L5 .Lv. ,?. <; + Ll ) , ,,,. fr- ,/S­

+(<0) ,oi t.,.. ,Of + .o~ Jr. ,o"l, ]

H ::: S, 0 g 4- b,'+~

I1-11 ~ ,) ?, = 0, ~ • P?:: 0 , '7

D,3bo.s +O,(~O,I

_~ L

o. gg I bl'ts

(h,) f! IIW>.x (oJ- P; = ~ = ~ = 0 S .i ~ I, 1M

II oM'" j. =- - L ( 6.5) J,.,.. 6," " 1 b,,'f "fI""c.'f-b"L

1 1-12 I M ~ /0 ~, :: -L '=:.. l lo

) 10 .) t

H = - I() (. J) ~ . I =- ~ . ~ (2.. h ;ts )ML

T~ li- :: S,5LL ~;+~ :; /,11 Sft, ::.T f!... 3 lA.; +~ 1st. c.

3

H =

INSTRUCTOR SOLUTIONS MANUAL (United States Edition)

Digital & Analog Comm. Systems 8th Edition, L. W. Couch, II

Page 4: Digital & Analog Communication Systems (8th Edition) – Answer and Script Solutions Manual

11 13 - I,~ LI~;r .,(11;-& /w...I 1>1=2.'1- ) ~ =~);r ~ ~ i e,,~fl j=tJt

U.. ~ 1J I,,~ -/'71..

=- f2"[ Ii} I] /11 (1)'1 -/- 3(t/'jyl 3(1)/1] - 1¥1l...

C~ecJ;. t'P: ~ l'l[U/~ J{i.F~ =9 J-J::. 1/. BII> Ms oJ"l i '=- 2. U ( ti(tJ'~:: /. 0

1 14 1 - I B -" 3~o U-z t~ )"8 "3tlJ B

c= ~ Jp~l.[l-l~)] ~ /;1. /11 [if ~j *~)J8/b I.,j-fr) (sIAlMB 3

-q- iJ:: ID J~ :::. (D':: II> Db

c.. =I:I>~ l~ [lDllQ - 1. 'l'1~ Ii)~ ;

1-15 1

(a) chars := 110 Number of characters available

log (chars) ]b := ceil Number of bits required to represent a character[ log(2)

====> b = 7 bits

(b) B:= 3200 Hz Channel bandwidth SNRdB := 20 dB Signal to noise ratio

SNRdB

10 SNR :;:;:: 10 ==;~===> SNR = 100 (Absolute power ratio)

C := B. [log (1 + SNR)] 4

==> C = 2.131·10 Channel capacity (bits/sec) log(2)

C 3 C :::::: ­ ===> C = 3.044 10 Channel capacity (chars/sec)

b

(c) Assuming equally likely characters, information content of each character is:

1 P := ----- Probability of each character

chars

log[~] 1;=-­ =========> I = 6.781 bits

109(2)

4

INSTRUCTOR SOLUTIONS MANUAL (United States Edition)

Digital & Analog Comm. Systems 8th Edition, L. W. Couch, II

Page 5: Digital & Analog Communication Systems (8th Edition) – Answer and Script Solutions Manual

1 1-16 I R (S ) [()~ 1-' (I + J D~o/I~ ) :. EI~ I t i1 ::. 'B J,,~ /. t1.) :: 'B ~ Jt,'l4q)

(a) ~ J:Lt)O-3DlY~ crbD ~ R'::.(qOQ) (t4l/i/f) :: 13.1-5 k~/fJ"fr

(6] B::. 31t)~ -U;on-='/7oo:1 R:::.V7tJ~(j~91-q) '= 7-5~ 'H kl;cfs!r

(c) :B-=- 32. DO'" jDe>=' 2'tbTJ ~ ~~ (;l9~ (I'f. 9'f-Jl)=-~3. 35~ki!J.!r

[i -17=-J ~ t; ~ sL;ff. re1lsto­- Ur\c.oJ~J Jt4+o. 1~

l!ti,ff' ,~ 1 b~-h ~t

(S~/ff ()lfi-

"-h~) .......,.--L..-,~-r--.L,--J.;,--L.-r-l

COd~J :l~t~ o~t

. . ~ ~',Is 4t (,. 1i;"e.)]r, f sf,,(j Y(3,rrey1-18

x .- 1 x .- 0 x .- 1 x .- 1 x .- 1 Input vector 0 1 2 3 4

ga .- 1 ga .- 0 ga .- 0 ga .- 1 Gain vector, mod2 adder 0 1 2 3

gb .- 1 gb .- 1 gb .- 1 gb .- 1 Gain vector, mod2 adder 0 1 2 3

k := 0 .. length(ga) - 2 v : = 0 k: = 0 .. length (x) - 1 v : = X

k k+length(ga)-l k k := length (x) + length (ga) - 1 .. length{x) + 2 length (ga) - 3

v := 0 i : = 0 .. length (v) - length (ga) k j := 0 .. length (ga) - 1

sa i

sb v:= V [9b ]i ~ length(gb)-j-l j+i

j

s := sa s := sb 2 i i 2 i+1 i

sb i

i := 0 .. 2 length (x) - 1

out : = S i i

For ====>

x T = (I 0 outT = (1

1 1

1 0

1) 1 1 0 0 Ill)

5

INSTRUCTOR SOLUTIONS MANUAL (United States Edition)

Digital & Analog Comm. Systems 8th Edition, L. W. Couch, II