design of dehydrator

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Dehydration design:  Gas production rate = 250 MMscfd = 7.078 Ms d Operating Pressure = 1000 psig = 1014.7 psia = 6997.93 Kpa Container maximum working pressure = 1500 psig = 1514.7 psia = 10344.82 Kpa Gas inlet temperature = 100 = 37.78 = 560°  = 310.78°  Given sample of gas is: S.no Compound Mole fraction Molecular Mass Kg/Kg-mol Of mixture 1 C1 89.470 16.043 14.35367 2 C2 6.0664 30.070 1.824166 3 C3 2.7386 44.097 1.20764 4 iC4 0.1000 58.124 0.058124 5 nC4 0.1200 58.124 0.069749 6 iC5 0.0769 72.150 0.055483 7 nC5 0.0081 72.150 0.005844 8 N2 0.0000 28.013 0 9 CO2 1.4200 44.010 0.624942 Total Total 100 18.19962 Hence   Now we need to calculate Z Calculations for Pseudo-critical Temperature and Pressure: By using the correlations we get:    Or       Or   

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Page 1: Design of Dehydrator

8/6/2019 Design of Dehydrator

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Dehydration design: 

Gas production rate = 250 MMscfd = 7.078 Msd

Operating Pressure = 1000 psig = 1014.7 psia = 6997.93 Kpa

Container maximum working pressure = 1500 psig = 1514.7 psia = 10344.82 Kpa

Gas inlet temperature = 100 = 37.78 = 560°  = 310.78°  

Given sample of gas is:

S.no Compound Mole fraction Molecular Mass Kg/Kg-mol

Of mixture

1 C1 89.470 16.043 14.35367

2 C2 6.0664 30.070 1.824166

3 C3 2.7386 44.097 1.20764

4 iC4 0.1000 58.124 0.0581245 nC4 0.1200 58.124 0.069749

6 iC5 0.0769 72.150 0.055483

7 nC5 0.0081 72.150 0.005844

8 N2 0.0000 28.013 0

9 CO2 1.4200 44.010 0.624942

Total Total 10018.19962

Hence

 

 Now we need to calculate Z

Calculations for Pseudo-critical Temperature and Pressure: By using the correlations we get:

 

 

Or 

 

 

 

Or 

 

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Pseudo-reduce Temperature and Pressures are calculated as:

 

 

 

 

 Now,

= 0.9790

From Standing & Katz chart we will calculate Z-factor as 0.88 

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Optimized required Dehydration rate = 95% (Based on economical aspects)

Glycol to water circulation rate = 5.5 gal TEG/ lb = 45.89 litres TEG/Kg  

Lean Glycol concentration = 99.5

Water content specification is 7 lb = 112.13 mg  

From figure 20-4 (GPSA) @ 6997.93 Kpa, dew point is -3, 970 mg  

 Now, Water removal efficiency is given as

= 88.44%

This value is less than our required Removal efficiency of 95%.

Hence we proceed as follows

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From figure 20-70, numbers of theoretical stages are calculated as

Given: 45.89 litres TEG/Kg & Lean Glycol concentration = 99.5%

This gives:

 

Required water removal efficiency is 95% which is greater than 94.5%, hence numbers of 

required stages are more than 1.5

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From figure 20-71 GPSA

This gives:

 

Required water removal efficiency is 95% which is lesser than 96.5%, hence numbers of 

required stages are 2.

2 trays = 8 bubble cap trays @ 0.6 m tray spacing or is equal to 3 m of structural packing.

(From table 20-75 GPSA)

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For size of contactor:

From table 20-75 GPSA

C = 176

For TEG = 1119.7 (From table 20-56 GPSA)

 

 Now,

    H

M=  

 Now, Area (A) = M/G =/31032.23 = 7.3138 

Hence we get diameter = 3.052 m

For structured packing:

From table 20-75 (GPSA)

C structured packing = 384 (Taking average value of 329 and 439)

D =   *(D bubble cap)

= *3.052 = 2.066 m.