describing an objects position and motion using calculus concepts application of some higher order...

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Describing an objects position and motion using calculus concepts Application of some higher order derivatives. Analyzing the straight line motion of an object in front of a motion detector.

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Page 1: Describing an objects position and motion using calculus concepts Application of some higher order derivatives. Analyzing the straight line motion of an

Describing an objects position and motion

using calculus concepts

Application of some higher order derivatives.

Analyzing the straight line motion of an object in front of a motion detector.

Page 2: Describing an objects position and motion using calculus concepts Application of some higher order derivatives. Analyzing the straight line motion of an

differentiatedifferentiate

Differentiate twice

Undo the derivative (integration, anti-derivative). Data point needed to determine the constant.

Undo the derivative (integration, anti-derivative). Data point needed to determine the constant.

¿𝑑𝑠(𝑑)𝑑𝑑

¿𝑑𝑣 (𝑑)𝑑𝑑

or  π‘‘2𝑠 (𝑑)𝑑2 𝑑

   β€œs(t)” β€œv(t)” β€œa(t)”

Position at time β€œt” velocity at time β€œt” acceleration at time β€œt”changing position over time. Changing velocity over time.

Page 3: Describing an objects position and motion using calculus concepts Application of some higher order derivatives. Analyzing the straight line motion of an

Position relative to the motion detector

meters

Analyzing the motion of 5 objects in front of a motion detector

Time, β€œt” seconds

Object β€œA”

Object β€œB”

Object β€œC”

Object β€œD”

Obj

ect β€œ

E”

Position is unchanged,Velocity is zero

s(t)= 5 m or v(t)=0 m/s

𝑠 (𝑑 )=0.5 𝑑+5 Straight line, constant velocity

m/s 𝑑𝑣 (𝑑)𝑑𝑑

π‘œπ‘Ÿ π‘Ž (𝑑 )=0π‘š /𝑠2then

𝑠 (𝑑 )=2.5 𝑑+5

𝑠 (𝑑 )=7 𝑑2+7

s (t )=βˆ’1 t+5

stee

per s

o m

ovin

g at a

faste

r con

stant

spee

d th

an o

bjec

ts A

, B an

d D

constant speed

π‘Ž (𝑑 )=0π‘š/ 𝑠2

m/s π‘Ž (𝑑 )=0π‘š/ 𝑠2Constant slope, Constant velocity, no acceleration

Object β€œE” has positive changing tangent slopes, speed is changing m/s π‘Ž (𝑑 )=14π‘š/ 𝑠2

Constant velocityNo acceleration

𝑑𝑣 (𝑑 )𝑑𝑑

π‘œπ‘Ÿ π‘Ž (𝑑 )=0π‘š/ 𝑠2

Page 4: Describing an objects position and motion using calculus concepts Application of some higher order derivatives. Analyzing the straight line motion of an

If the acceleration is positive, does that mean the object is speeding up? Not always.β€’ Plot , 0≀t ≀7β€’ Analyze the motion of the object. β€’ Superimpose the velocity and acceleration graphs, β€’ by first predicting their predictionβ€’ then by taking derivatives and accurately plotting their position

β€’ Using the equations analyze the motion of the object at 4 seconds and then verify with the graphed data.β€’ Determine the algebraic characteristics of an object that β€’ is speeding up * Slowing downβ€’ Moving towards the detector * Moving away from the detector