dc motor control janet klinkhachorn jeannine meyers cheri settell december 6, 2002
TRANSCRIPT
DC Motor ControlDC Motor ControlJanet KlinkhachornJanet Klinkhachorn
Jeannine MeyersJeannine Meyers
Cheri SettellCheri Settell
December 6, 2002
OverviewOverviewIntroductionIntroductionTheoryTheoryDesign ApproachDesign ApproachProcedureProcedureResultsResultsAnalysisAnalysisConclusionConclusion
December 6, 2002Janet KlinkhachornJanet Klinkhachorn
IntroductionIntroductionTaskTaskDC MotorsDC Motors
Electrical power into Electrical power into mechanical powermechanical power
Used for heavy duty Used for heavy duty applicationsapplications
DC Motor ComponentsDC Motor ComponentsStatorStatorRotorRotor
December 6, 2002Janet KlinkhachornJanet Klinkhachorn
http://www.prestoliteasia
TheoryTheoryVVff = R = RffIIff + L + LffdIdIff/dt/dt
VVtt = I = IaaRRaa + E + Eaa + +
LLaadIdIaa/dt/dt
Jdω / dt = TJdω / dt = Tee - T - TLL
EEaa = K = Kee * I * Iff *ω *ω
http://murry.newcastle.edu.au
December 6, 2002Janet KlinkhachornJanet Klinkhachorn
OverviewOverviewIntroductionIntroductionTheoryTheoryDesign ApproachDesign ApproachProcedureProcedureResultsResultsAnalysisAnalysisConclusionConclusion
December 6, 2002
Design ApproachDesign ApproachInitial ConditionsInitial Conditions
Ke=0.33Ke=0.33Vf=150 VDC Vf=150 VDC Vt=100 VDCVt=100 VDCRa= 0.9 ΩRa= 0.9 Ω La= 0.01 HLa= 0.01 HRf= 75 ΩRf= 75 Ω Lf= 50 HLf= 50 HJ= 0.2 kgJ= 0.2 kgm2m2TL= 5 NTL= 5 Nmm
http://murry.newcastle.edu.au
December 6, 2002Jeannine Meyers
Design ApproachDesign ApproachMeasure If, Ia, E, Measure If, Ia, E, ωωChange Rf and LfChange Rf and Lf
Rf= 100 ΩRf= 100 ΩLf= 75 HLf= 75 HBoth Rf and LfBoth Rf and LfRf= 50 ΩRf= 50 ΩLf= 25 HLf= 25 HBoth Rf and LfBoth Rf and Lf
http://murry.newcastle.edu.au
December 6, 2002Jeannine Meyers
ProcedureProcedureDefinition of integralDefinition of integral
[i(t + Δt) – i(t)] / Δt[i(t + Δt) – i(t)] / ΔtCT to DTCT to DT
VVff = R = RffIIff + L + LffdIdIff/dt/dt VVtt = I = IaaRRaa + E + Eaa + L + LaadIdIaa/dt/dtJdω / dt = TJdω / dt = Tee - T - TLL EEaa = K = Kee * I * Iff *ω *ω
December 6, 2002Jeannine Meyers
ProcedureProcedureExampleExample
VVtt = I = IaaRRaa + E + Eaa + L + LaadIdIaa/dt/dt
dIdIa a / dt = [(V/ dt = [(Vtt – I – IaaRRaa – E – Eaa) / L) / Laa]]
[I[Iaa(t + Δt) – i(t + Δt) – iaa(t)] / Δt] = [(V(t)] / Δt] = [(Vtt – I – IaaRRaa – E – Eaa) / L) / Laa]]
IIaa(t + Δt) = i(t + Δt) = iaa(t) + Δt * [(V(t) + Δt * [(Vtt – I – IaaRRaa – E – Eaa) / L) / Laa]]
MatLab CodeMatLab CodeIa = I1 + dt*(Vt – (Ra*I1) – ea) / La Ia = I1 + dt*(Vt – (Ra*I1) – ea) / La
December 6, 2002Jeannine Meyers
OverviewOverview
IntroductionIntroductionTheoryTheoryDesign ApproachDesign ApproachProcedureProcedureResultsResultsAnalysisAnalysisConclusionConclusion
December 6, 2002Cheri Settell
ResultsResultsChange the value of field resistance Change the value of field resistance
and inductance by 25and inductance by 25Increase Rf Increase Rf Increase LfIncrease LfIncrease both Rf and LfIncrease both Rf and LfDecrease RfDecrease RfDecrease LfDecrease LfDecrease both Rf and LfDecrease both Rf and Lf
Cheri Settell December 6, 2002
Analysis of RfAnalysis of RfTime IC Rf inc Rf dec
Back emf 2.5 3.75 1.25
Field Current 3.75 2.5 5
Armature Current 2.5 3.75 2.5
Speed 1.9 3.75 1.25
Back emf 92 92 95
Field Current 2 1.5 3
Armature Current 115 115 115
Speed 140 180 99
Cheri Settell December 6, 2002
Analysis of LfAnalysis of LfTime IC Lf inc Lf dec
Back emf 2.5 2.5 1.9
Field Current 3.75 5 1.9
Armature Current 2.5 2.5 1.9
Speed 1.9 1.9 1.9
Back emf 92 95 95
Field Current 2 2 2
Armature Current 115 115 115
Speed 140 140 140
Cheri Settell December 6, 2002
Analysis of BothAnalysis of BothTime IC B inc B dec
Back emf 2.5 3.75 1.25
Field Current 3.75 3.75 2.5
Armature Current 2.5 3.75 1.26
Speed 1.9 3.75 1.25
Back emf 92 90 95
Field Current 2 1.5 3
Armature Current 115 115 115
Speed 140 185 98
Cheri Settell December 6, 2002
ConclusionConclusionSolutionsSolutions
Increase Rf to 100 ohmsIncrease Rf to 100 ohmsDecrease Lf to 25 ohmsDecrease Lf to 25 ohms
Team’s DecisionTeam’s DecisionLf = 25 ohms and Rf = 75 ohmsLf = 25 ohms and Rf = 75 ohms
Cheri Settell December 6, 2002