data communication lecture-17. recap of lecture 16 analog-to-digital conversion pulse code...
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DATA DATA COMMUNICATIONCOMMUNICATION
Lecture-17
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Recap of Lecture 16Analog-To-Digital ConversionPulse Code Modulation (PCM)
–Pulse Amplitude Modulation (PAM)–Quantization–Binary Encoding–Digital-to-Digital Conversion
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Overview of Lecture 17
Digital-to Analog ConversionBit Rate and Baud RateCarrier SignalsAmplitude Shift Keying (ASK)Frequency Shift Keying (FSK)Phase Shift Keying (PSK)Quadrature Amplitude Modulation (QAM)
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Digital To Analog Conversion
Process of changing one of the characteristics of an analog signal based on the info in a digital signal
Digital data must be modulated on an analog signal that has been manipulated to look like two distinct values corresponding to binary 1 to binary 0
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Digital To Analog Conversion
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Variation in Characteristics of Sine Wave
A sine wave is defined by 3 characteristics:• Amplitude• Frequency• Phase
By changing one aspect of a simple electrical signal back & forth,we can use it to represent digital data
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Mechanisms for Modulating Digital Data to Analog Signals
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Bit Rate & Baud Rate
Bit rate:no. of bits transmitted during one second
Baud rate:no. of signal units per second that are required to represent that bit
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Analogy for Bit rate &Baud Rate
In transportation–a Baud is analogous to a Car–a Bit is analogous to a Passenger
If1000 cars can go from one point to another carrying only one passenger(only driver),than 1000 passengers are transported
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Analogy for Bit rate &Baud Rate
However, if each car carries four passengers, then 4000 passengers are transported
Note that the Number of Cars (Bauds), not the Numbers of Passengers (Bits) determines the traffic and therefore the need for wider highways
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Example 5.6
An analog signal carries 4 bits in each signal element.If 1000 signal elements are sent per second, find the Baud Rate and Bit Rate?
Solution:– Baud Rate= Number of Signal Elements – Baud Rate =1000 bauds/second– Bit Rate=Baud Rate * Number of bits per signal
element Bit Rate= 1000 * 4 = 4000 bps
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Carrier Signals
The sending device produces a high frequency signal, that acts as a basis for the information
signal. This base signal is called the Carrier Signal or Carrier
Frequency
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Amplitude Shift Keying (ASK)
The amplitude of the Carrier signal is varied to represent binary 1 or 0
Both frequency and phase remain constant, while the amplitude changes
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Amplitude Shift Keying (ASK)
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Effect Of Noise on ASK
Highly susceptible to noise interference
ASK relies solely on Amplitude for recognition
Noise usually affects the amplitude
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On-Off- Keying (OOK)
A popular ASK Technique
In OOK, one of the bit values is represented by no voltage
The advantage is the reduction in the amount of energy required to transmit Information
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Bandwidth for ASK (Figure)
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Bandwidth for ASK (Figure)
Bandwidth requirements for ASK are calculated using the formula
BW = (1+d)*Nbaud
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Example 5.8Find minimum bandwidth required for an
ASK signal TX at 2000 bps. TX. Mode is half duplex
Solution:– In ASK, Baud Rate= Bit Rate Therefore, Baud Rate = 2000– Also ASK requires a minimum bandwidth
equal to its Baud Rate Therefore Minimum BW = 2000 Hz
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Summary
Digital-to Analog ConversionBit Rate and Baud RateCarrier SignalsAmplitude Shift Keying (ASK)
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Suggested Reading
Section 5.3, “Data Communications and Networking” 2nd Edition by Behrouz A. Forouzan