dalton’s atomic theory (1808)

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V.Montgomery & R.Smith 1 Dalton’s Atomic Theory (1808) 1. All matter is made of tiny indivisible particles called atoms. 2. Atoms of the same element are identical. The atoms of any one element are different from those of any other element. 3. Atoms of different elements can combine with one another in simple whole number ratios to form compounds. 4. Chemical reactions occur when atoms are separated, joined, or rearranged;however, atoms of one element are not changed into atoms of another by a chemical reaction.

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Dalton’s Atomic Theory (1808). All matter is made of tiny indivisible particles called atoms. Atoms of the same element are identical. The atoms of any one element are different from those of any other element. - PowerPoint PPT Presentation

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Page 1: Dalton’s Atomic Theory (1808)

V.Montgomery & R.Smith 1

Dalton’s Atomic Theory (1808)1. All matter is made of tiny indivisible particles

called atoms. 2. Atoms of the same element are identical. The

atoms of any one element are different from those of any other element.

3. Atoms of different elements can combine with one another in simple whole number ratios to form compounds.

4. Chemical reactions occur when atoms are separated, joined, or rearranged;however, atoms of one element are not changed into atoms of another by a chemical reaction.

Page 2: Dalton’s Atomic Theory (1808)

Summary of the Atom• atoms are the smallest particles that can be

uniquely associated with an element• each element has unique atoms • atoms are composed of e-, p and n• atoms are electrically neutral (# of e- = # of p)• for a single element, isotopes differ only in

number of n (neutrons)• atoms have characteristic masses (atomic

weights)• atoms combine with one another in definite,

whole number proportions to make compounds

Page 3: Dalton’s Atomic Theory (1808)

~ 10-10 m

nucleusMass 9 x 10Mass 9 x 10-31-31 kg kg Mass > 10Mass > 10-26-26 kg kg

electron

Page 4: Dalton’s Atomic Theory (1808)

~ 1 – 7 x 10-15 m (1 – 7 fermi)

Page 5: Dalton’s Atomic Theory (1808)
Page 6: Dalton’s Atomic Theory (1808)

atoms are dominantly empty space:

If an oxygen atom had a total radius of 100 km, the nucleus

would be a ~1 m diameter sphere in

the middle.

electron orbits

The Spacious Atom

Page 7: Dalton’s Atomic Theory (1808)

In a simplistic model, electrons float around the nucleus in energy levels called shells.

As the number of

electrons increases,

they start to fill shells

farther out from the

nucleus.

In most cases,

electrons are lost or

gained only from the

outermost shell.

electron orbits

Electrons in Orbit

Page 8: Dalton’s Atomic Theory (1808)

AtomAtom

NucleusNucleus

Page 9: Dalton’s Atomic Theory (1808)

The Nuclear Modelof the atom

Page 10: Dalton’s Atomic Theory (1808)

• Mass of an electron is approximately 1/1840th of a

proton or neutron.

• Mass of a neutron is very close to the mass of a proton.

• 1 atomic mass unit (amu or u)=

1.66054x10-24g

• 1 g= 6.022 x1023amu• 1amu is defined as 1/12th the mass of an atom of

carbon-12 .

Page 11: Dalton’s Atomic Theory (1808)

Subatomic Particles

Particle Symbol Charge RelativeMass

Electron e- 1- 0

Proton p+ 1+ 1

Neutron n 0 1

Page 12: Dalton’s Atomic Theory (1808)

Atomic Number(nuclear charge)

11

Na

Atomic Number

Symbol

Page 13: Dalton’s Atomic Theory (1808)

All atoms of an element have the same number of protons

11

Na

11 protons

Sodium

Page 14: Dalton’s Atomic Theory (1808)

Number of Electrons

If an atom is neutral ;The net charge is zeroNumber of protons = Number of electronsAtomic number = Number of electrons in a

neutral atom

Page 15: Dalton’s Atomic Theory (1808)

Ions• Have a net electrical charge since the total

number of electrons isn’t equal to the number of protons.

• Can be anions (e->p+ ;formed as a result of gaining electrons; negatively charged), cations (p+>e-;formed as a result of losing electrons; positively charged).

• e- + q(charge of the ion) = proton number

Page 16: Dalton’s Atomic Theory (1808)

• In chemical rxns, atom never gain or lose protons. It’s the interaction of electrons.

Page 17: Dalton’s Atomic Theory (1808)

Mass Number(nucleon number)

Counts the number

of

protons and neutrons

in an atom

A= p+ + n0

Page 18: Dalton’s Atomic Theory (1808)

Atomic Symbols

Show the mass number and atomic number

Give the symbol of the element

23Na

11

(Z)atomic number

(A)mass number

sodium-23

Page 19: Dalton’s Atomic Theory (1808)

Notation for Atoms

12C13C C

only one isotope of carbon

all isotopes of carbon

only one isotope of carbon

Page 20: Dalton’s Atomic Theory (1808)

Basic Definitions• “atomic number” = number of protons in the

nucleus;

• “mass number” = sum of protons + neutrons in the nucleus

• “isotopic mass” = mass of a single isotope

Page 21: Dalton’s Atomic Theory (1808)

More Atomic Symbols

16 31 65

O P Zn

8 15 30

8 p+ 15 p+ 30 p+

8 n 16 n 35 n8 e- 15 e- 30 e-

Page 22: Dalton’s Atomic Theory (1808)

Isotopes

Atoms with the same number of protons,

but different numbers of neutrons.

Atoms of the same element (same atomic

number) with different mass numbers

Isotopes of chlorine

35Cl 37Cl17 17

chlorine - 35 chlorine - 37

Page 23: Dalton’s Atomic Theory (1808)

• Since both isotopes have the same number of protons and electrons, they have identical chemical properties.

• Since physical properties depend on the mass of particles as well, isotopes will often have slightly different physical properties such as density, mass, rate of diffusion etc.

Page 24: Dalton’s Atomic Theory (1808)

Natural abundances of isotopes

Natural chlorine contains :

75 % 35Cl and 25 % 37Cl . 17 17

• These percentages are known as the natural abundances of the isotopes and determined by “mass spectrometry.”

Page 25: Dalton’s Atomic Theory (1808)

Relative atomic mass

• is weighted mean.

5.35100

)37x25()35x75(

Relative atomic mass has no unit since the atomic mass unit, amu is cancelled out in calculation w/ respect to C-12.

Page 26: Dalton’s Atomic Theory (1808)

Exercise 1

• The molar mass of iridium is 192.2 g / mol. What are the naturally occurring percentages of the two isotopes of Ir-191 and Ir-193?

Page 27: Dalton’s Atomic Theory (1808)

solution

40x

2.192100

)x100(193)x(191

Iridium is a mixture of 40% 191Ir and 60 % 193Ir.

Page 28: Dalton’s Atomic Theory (1808)

Isotopes of Hydrogen element

H

H

H

11

21

31

has the biggest abundance in nature.

Page 29: Dalton’s Atomic Theory (1808)

Radioactive isotopes

• Are produced by exposing the natural element to a flux(flow) of neutrons in a nuclear reactor. The nucleus of an atom captures an additional neutron and form radioisotope.

Page 30: Dalton’s Atomic Theory (1808)

Usages of radioisotopes1. The rate of radioactive decay is used to date

objects (C-14). Naturally occurring C has a fixed proportion of

C-14 due to exchange w/ C in the atmosphere. When the plant is dead, the exchange stops & the proportion of C-14 starts to decrease in the plant due to radioactive decay. This decayed amount is used to date the plant. After about 5,700 yrs, the proportion of C-14 falls to about half its initial value.

Page 31: Dalton’s Atomic Theory (1808)

2. as tracers.Radioactive isotope reacts chemically &

biologically. For example the activity of thyroid gland can be measured w/ monitoring the increase in radioactivity of the gland after taking a drink including iodine radioisotopes (I-125 and I-131) since the thyroid gland absorbs the radioactive iodine when it works.

Usages of radioisotopes

Page 32: Dalton’s Atomic Theory (1808)

3. Source of gamma rays and therefore, source intense radioactivity.

Cobalt-60 is an example of such a radioactivity source. It’s used in radiation treatment for cancer and industrially as well

Usages of radioisotopes

Page 33: Dalton’s Atomic Theory (1808)

• A mass spectrometer is an instrument which separates particles according to their masses , records the relative proportions of these, and determine natural abundances of the isotopes of an element. Therefore, it also allows us to calculate the atomic mass of an element.

• The most accurate way for determining atomic and molecular weights is provided by mass spectrometer.

Mass spectrometry

Page 34: Dalton’s Atomic Theory (1808)

• mass spectrometer, invented by the English physicist Francis William Aston (1877-1945) when he was working in Cambridge with J. J. Thomson. It was in his use of this instrument that the existence of isotopes of elements was discovered.

• Aston eventually discovered many of the naturally occurring isotopes of non-radioactive elements.

• He was awarded the Nobel Prize for Chemistry in 1922.

Mass spectrometry

Page 35: Dalton’s Atomic Theory (1808)

Mass spectrometry

A B

C

DE

accelerating

F

Page 36: Dalton’s Atomic Theory (1808)

A: a gaseous sample is very slowly

introduced to the mass spectrometer.

B: atoms/molecules are bombarded by a stream of high energy electrons to produce positive ions, mostly w/ a 1+ charge. These electrons collide w/ electrons in the particle knocking them out and leaving a positive ion.

C: positively charged ions are accelerated high enough to make the particles pass through the slits and magnetic field by high electrical voltage on the negatively charged grid. With the slits, the ions were made a beam of ions.

Page 37: Dalton’s Atomic Theory (1808)

D: Fast moving ions enter a magnetic field

produced by an electromagnet. Ions are deflected by a magnetic field into a curved path. The deflection of the ions depends on “charge to mass ratio(q/m). ”The more massive the ion, the less the deflection. The ions w/ equal mass and charge will deflect the same.

E: By changing the strength of the magnetic field or the accelerating voltage on the negatively charged grid, ions of varying masses can be made to enter the detector at the end of the instrument.

Page 38: Dalton’s Atomic Theory (1808)

• On the detector, ions are collected on a

metal plate and the current flows through the metal plate to neutralise the ions and this current is recorded.

• In this way, the relative abundances of ions of different masses in the sample can be determined and put into a graph called “mass spectrum.”

Page 39: Dalton’s Atomic Theory (1808)

F: The mass spectrometer must be at a high vacuum for its correct operation and its correct operation depends on particles being able to pass through it w/o colliding with any other particles.

Page 40: Dalton’s Atomic Theory (1808)

• A: vapourised sample introduced

• B: ionization by electron bombardment

• C: Positive ions accelerated by electrical field

• D: ions deflected by a magnetic field

• E: detector records ions of a particular mass

• F: vacuum prevents molecules colliding

Page 41: Dalton’s Atomic Theory (1808)

• Mass spectrometer is used to identify the molecular structure of a compound or analyze mixtures of substances.

• When a molecule loses an electron, it falls apart, forming fragments. Mass spectrometer measures the mass of these fragments, producing a chemical “fingerprint” of the molecule and providing clues about how the atoms were connected together in the molecule.

Page 42: Dalton’s Atomic Theory (1808)

Atomic weight measurements How was the atomic weight measured?• By mass spectrometry

– This also measures

% natural abundance

for a given isotope- The graph is called as

“mass spectrum.”

Page 43: Dalton’s Atomic Theory (1808)

• P.53check out the graph.

Page 44: Dalton’s Atomic Theory (1808)

Atomic weight calculation There are three naturally occuring isotopes

of neon (Ne):

20Ne isotopic mass = 19.99244018 amu21Ne isotopic mass = 20.9938467 amu22Ne isotopic mass = 21.9913855 amu

the atomic weight is reported in text as:20.1797 amu

Page 45: Dalton’s Atomic Theory (1808)

Learning Check 1

Naturally occurring carbon consists of three isotopes, 12C, 13C, and 14C. State the number of protons, neutrons, and electrons in each of these carbon atoms.

12C 13C 14C 6 6 6

#P _______ _______ _______

#N _______ _______ _______

#E _______ _______ _______

Page 46: Dalton’s Atomic Theory (1808)

Solution

12C 13C 14C 6 6 6

#P __6___ _ 6___ ___6___

#N __6___ _ _7___ ___8___

#E __6___ _ 6___ ___6___

Page 47: Dalton’s Atomic Theory (1808)

Learning Check 2

An atom of zinc has a mass number of 65.

A. Number of protons in the zinc atom

1) 30 2) 35 3) 65

B. Number of neutrons in the zinc atom

1) 30 2) 35 3) 65

C. What is the mass number of a zinc isotope

with 37 neutrons?

1) 37 2) 65 3) 67

Page 48: Dalton’s Atomic Theory (1808)

Solution

An atom of zinc has a mass number of 65.

A. Number of protons in the zinc atom

1) 30

B. Number of neutrons in the zinc atom

2) 35

C. What is the mass number of a zinc isotope

with 37 neutrons?

3) 67

Page 49: Dalton’s Atomic Theory (1808)

Learning Check 3

Write the atomic symbols for atoms with the following:

A. 8 p+, 8 n, 8 e- ___________

B. 17p+, 20n, 17e- ___________

C. 47p+, 60 n, 47 e- ___________

Page 50: Dalton’s Atomic Theory (1808)

Solution

16OA. 8 p+, 8 n, 8 e- 8

B. 17p+, 20n, 17e- 37Cl 17

C. 47p+, 60 n, 47 e- 107Ag 47

Page 51: Dalton’s Atomic Theory (1808)

Learning Check 4

An atom has 14 protons and 20 neutrons.A. Its atomic number is

1) 14 2) 16 3) 34

B. Its mass number is1) 14 2) 16 3) 34

C. The element is1) Si 2) Ca 3) Se

D. Another isotope of this element is

1) 34X 2) 34X 3) 36X 16 14 14

Page 52: Dalton’s Atomic Theory (1808)

Solution

An atom has 14 protons and 20 neutrons.A. It has atomic number

1) 14

B. It has a mass number of3) 34

C. The element is1) Si

D. Another isotope of this element would be

3) 36X 14

Page 53: Dalton’s Atomic Theory (1808)

Masses of Atoms

A scale designed for atoms gives their small

atomic masses in atomic mass units (amu)

An atom of 12C was assigned an exact mass of

12.00 amu

Relative masses of all other atoms was

determined by comparing each to the mass of 12C

An atom twice as heavy has a mass of 24.00

amu. An atom half as heavy is 6.00 amu.

Page 54: Dalton’s Atomic Theory (1808)

Average atomic mass(atomic weight)

• “atomic weight or mass” = average mass of an atom calculated from the masses and natural abundances of all isotopes

(use atomic weights to calculate the molecular weights of compounds from their constituent elements!)

Page 55: Dalton’s Atomic Theory (1808)

Atomic Mass

Average atomic mass is based on all the

isotopes and their abundance %

Atomic mass is not a whole number

Na22.99

Page 56: Dalton’s Atomic Theory (1808)

Calculating Atomic Weight or Mass

Percent(%) abundance of isotopes

Mass of each isotope of that element

Weighted average =

mass isotope1(%) + mass isotope2(%) + …

100 100

Page 57: Dalton’s Atomic Theory (1808)

• Naturally occurring C is composed of 98.93

% 12C and 1.07 % 13C. The masses of these nuclides are 12 amu (exactly) and 13.00335 amu, respectively.

amu01.12100

)amu00335.13x07.1()amu12x93.98(

Average atomic mass(atomic mass) or atomic weight

Page 58: Dalton’s Atomic Theory (1808)

Atomic Mass of Magnesium

Isotopes Mass of Isotope Abundance 24Mg = 24.0 amu 78.70%

25Mg = 25.0 amu 10.13%

26Mg = 26.0 amu 11.17%

Atomic mass (average mass) Mg = 24.3 amu

Mg24.3

Page 59: Dalton’s Atomic Theory (1808)

Atomic mass calculation

How was the atomic mass calculated?

• multiply each isotopic mass by the reported natural abundance for the isotope, then:

• add these individual contributions for each isotope to get the average atomic mass for the element

Page 60: Dalton’s Atomic Theory (1808)

Atomic mass calculation

There are three naturally occuring isotopes of neon (Ne):20Ne mass # = 19.99244018 amu (90.51%)21Ne mass # = 20.9938467 amu (0.27%)22Ne mass # = 21.9913855 amu (9.22%)

the atomic mass is reported in text as:

20.1797 amu

18.10 + 0.057 + 2.03 = 20.19 amu

Page 61: Dalton’s Atomic Theory (1808)

Learning Check 5

Gallium is a metallic element found in

small lasers used in compact disc players.

In a sample of gallium, there is 60.2% of

gallium-69 (68.9 amu) atoms and 39.8% of

gallium-71 (70.9 amu) atoms. What is the

atomic mass of gallium?

Page 62: Dalton’s Atomic Theory (1808)

Solution

Ga-69

68.9 amu x 60.2 = 41.5 amu for 69Ga

100

Ga-71 (%/100)

70.9 amu x 39.8 = 28.2 amu for 71Ga

100

Atomic mass Ga = 69.7 amu

Page 63: Dalton’s Atomic Theory (1808)

Finding An Isotopic Mass

A sample of boron consists of 10B (mass 10.0 amu) and 11B (mass 11.0 amu). If the average atomic mass of B is 10.8 amu, what is the % abundance of each boron isotope?

Page 64: Dalton’s Atomic Theory (1808)

Assign X and Y values:X = % 10B Y = % 11B

Determine Y in terms of XX + Y = 100Y = 100 - X

Solve for X:X (10.0) + (100 - X )(11.0) = 10.8

100 100

Multiply through by 10010.0 X + 1100 - 11.0X = 1080

Page 65: Dalton’s Atomic Theory (1808)

Collect X terms

10.0 X - 11.0 X = 1080 - 1100

- 1.0 X = -20

X = -20 = 20 % 10B

- 1.0

Y = 100 - X

% 11B = 100 - 20% = 80% 11B

Page 66: Dalton’s Atomic Theory (1808)

Learning Check 6

Copper has two isotopes 63Cu (62.9 amu) and 65Cu (64.9 amu). What is the % abundance of each isotope? (Hint: Check Zumdahl or any other chemistry text for atomic mass)

1) 30% 2) 70% 3) 100%

Page 67: Dalton’s Atomic Theory (1808)

Solution

2) 70%

Solution

62.9X + 6490 = 64.9X = 6350

-2.0 X = -140

X = 70%

Page 68: Dalton’s Atomic Theory (1808)

Atomic Masses

13C12C

13.00335 amu (1.11%)

12.0000 amu (98.89%)

atomic weight of C = 12.01115 amu WHY?

Page 69: Dalton’s Atomic Theory (1808)

Calculating masses of atoms relative to 12C

(mass of 12C atom) * 1.58320 = mass of F atom

= 18.99840

reported atomic weight of F = 18.9984

Page 70: Dalton’s Atomic Theory (1808)

Charged Atoms: Ions

Left to their own devices, atoms are electrically neutral.

That means that they have an equal number of

protons and electrons.

During the course of most natural events,

protons are not gained or lost, but electrons may be.

Atoms with more or fewer electrons than protons are

electrically charged. They are called ions:

an atom that loses electrons takes on a positive charge

(cation);

an atom that gains electrons takes on a negative charge

(anion).

Complex cations and anions can also occur: (NH4)+1, (SO4)-2

Page 71: Dalton’s Atomic Theory (1808)

An ISOTOPE is one of a set of nuclides with the same Z and consequently different A. (ie isotopes are the same chemical element but different masses). e.g.

  C126 C136 C146

An ISOBAR is one of a set of nuclides with the same A but different N and Z.

e.g C146 O148N147

An ISOTONE is one of a set of nuclides with the same N and consequently different A. e.g.

21412021

401921

3918 A,K,A

Page 72: Dalton’s Atomic Theory (1808)

• More on atomic notation, which is based on the nuclear structure:– Isotope: same Z, different A and N– Isobar: same A, different Z and N– Isotone: same N, different Z and A

Example: From the following list of atoms, which are isotopes, isobars, and isotones?

Component

Atom

A Z N

Xe

I

Cs

I

Xe13154 I130

53 Cs13255 I131

53