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C x 4 8 A B C D 7x - 2 3x + 8 For each circle C, find the value of x. Assume that segments that appear to be tangent are. (4 pts each) 1. 2. 3. C 8 x 12 x K T

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K. 12. T. x. 8. x. C. Daily Check. For each circle C, find the value of x . Assume that segments that appear to be tangent are. (4 pts each) 1. 2.3. EOCT Practice #1. c. EOCT Practice #2. c. EOCT Practice #3. b. EOCT Practice. Question of the Day. - PowerPoint PPT Presentation

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Page 1: Daily Check

C

x4

8

A

B

C

D

7x - 2

3x + 8

For each circle C, find the value of x. Assume that segments that appear to be tangent are. (4 pts each)

1. 2. 3.

C8x

12

x

KT

Page 2: Daily Check

c

Page 3: Daily Check

c

Page 4: Daily Check

b

Page 6: Daily Check

Math IIDay 39 (10-6-10)

UNIT QUESTION: What special properties are found with the parts of a circle?Standard: MM2G1, MM2G2

Today’s Question:What effect does changing the radius have on S.A. and Volume of a sphere?Standard: MM2G4.a,b

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Page 8: Daily Check

r

Radius of a Sphere

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If you cut a sphere right down the middle you would create two congruent halves called HEMISPHERES.

You can think of the globe. The equator cuts the earth into the northern and southern

hemisphere.

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Look at the cross section formed when you cut a sphere in half.

What shape is it?A circle!!! This is called the GREAT CIRCLE of the sphere.

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Formulas for a Sphere2

3

443

SA r

V r

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8 in

Surface Area of a Sphere(round to the nearest hundredths)

SA4 r2

SA4 82

SA804.25 in2

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10 cm

Surface Area of a Sphere(round to the nearest hundredths)

SA4 r2

SA4 52

SA31416. cm2

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25 in

The circumference of a great circle of a sphere is 25 inches. Find the surface area of the sphere. (Round to the nearest tenths.) C 2 r

3.979r 24 (3.979)SA

25 2 r

2198.96SA in

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5 in

Surface Area of a SphereA spherical balloon has an initial radius of 5 in. When more air is added, the radius becomes 10 in. Explain how the S.A. changes as the radius changes.SA4 r2

2 2314.16 in .1,256.64 inSA vs

10 in

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Page 17: Daily Check

2 cm

Volume of a Sphere(round to the nearest hundredths) 34

3V r

V 3351. cm3

34 23

V

Page 18: Daily Check

10 cm

Volume of a Sphere

V 523 60. cm3

34 3

V r

34 53

V

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5 in

Volume of a SphereA spherical balloon has an initial radius of 5 in. When more air is added, the radius becomes 10 in. Explain how the volume changes as the radius changes.

2 2523.6 in . 4,118.8 inV vs

10 in

34 3

V r

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5 in

SA and Volume of a SphereA spherical balloon has a surface area of 16 in.2 Find the volume of the sphere.

26.02 inV

10 in

34 3

V rSA4 r2

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5 in

Volume of a SphereA sphere has an initial volume of 400 cm.3 The sphere is made bigger by making the radius 4 times as big. What is the new volume of the sphere?

225,600 inV

10 in

34 3

V r

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