d08540000120114004session 4_inventory control systems

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    Session 03

    Inventory Control SystemsEconomic Order Quantity and its variation.

    D 0 8 5 4Supply Chain : Manufacturing and Warehousing

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    Bina Nusantara University

    2

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    INVENTORY CONTROL SYSTEMS

    The fundamental inventory problem can be succinctlydescribed by two questions :1. When should an order be placed ?

    2. How much should be ordered ?

    The complexity of the resulting model depends upon theassumptions one makes about the various parametersof the system.

    The major distinction is between

    a. Inventory Control Subject to Known Demand

    b. Inventory Control Subject to Unknown Demand

    Bina Nusantara University

    3Source : Production and Operations Analysis 4th

    Edition, Steven NahmiasMcGraw Hill International Edition

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    Econom ic Order Quant i ty and i ts var iat ion

    The EOQ Model ( Economic Order Quantity Model )

    is the simplest and most fundamental of all inventorymodels.

    It describes the most important trade-off between

    Fixed Order Costs and Holding Costs.

    And is the basis for the analysis of more complex systems.

    Bina Nusantara University

    4Source : Production and Operations Analysis 4th

    Edition, Steven NahmiasMcGraw Hill International Edition

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    Order Quantity

    Annual Cost

    Order (Setup) Cost Curve

    Optimal

    Order Quantity (Q*)Bina Nusantara University

    5

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    Notation

    D= Demand rate (in units per year).

    c= Unit production cost, not counting setup or inventory

    costs (in dollars per unit). A = Constant setup (ordering) cost to produce

    (purchase) a lot (in dollars).

    h= Holding cost

    Q= Lot size (in units); this is the decision variable

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    The model

    Inventory versus time in the EOQ model

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    The model

    Average inventory level:

    The holding cost per unit:

    The setup costper unit:

    The production cost per unit:

    2

    Q

    D

    hQ

    D

    hQ

    2

    2

    Q

    A

    c

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    Economic order quantity

    )(2

    02

    )(2

    quantityordereconomichADQ

    conditionorderf irstQ

    A

    D

    h

    dQ

    QdY

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    What-if

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    What-if

    EOQ EOQ

    Annual demand 12,000 12,000

    Cost per unit $6.75 $6.75Interest rate to hold 20% 20%

    Ordering cost $28.00 $28.00

    Quantity each order 461 =INT(C5/C10)

    Number of orders 26 26

    Unit holding cost $1.35 =C6*C7

    Annual holding cost $311 =C9*C11/2Annual ordering cost $728 =C10*C8

    Combined cost $1,039 =C12+C13

    Annual purchase cost $81,000 =C5*C6

    Total cost $82,039 =C14+C15

    What-If AnalysisThe minimum costobtained by using theeconomic orderquantity is $952.50, soincreasing the orderquantity by 10% leadsa total cost increase ofonly $4.30. Changingthe order quantity by a

    small amount has verylittle effect on the cost,because EOQ formulagives robust solutions.

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    Bina Nusantara University

    Inventory Systems

    Single-Period Inventory Model

    One time purchasing decision (Example: vendor sellingt-shirts at a football game)

    Seeks to balance the costs of inventory overstock andunder stock

    Multi-Period Inventory Models

    Fixed-Order Quantity Models

    Event triggered (Example: running out of stock) Fixed-Time Period Models

    Time triggered (Example: Monthly sales call by salesrepresentative)

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    Bina Nusantara University

    Single-Period Inventory Model

    uo

    u

    CC

    CP

    soldbeunit willy that theProbabilit

    estimatedunderdemandofunitperCostC

    estimatedoverdemandofunitperCostC

    :Where

    u

    o

    P

    This model states that we should

    continue to increase the size of the

    inventory so long as the probability

    of selling the last unit added is

    equal to or greater than the ratio

    of: Cu/Co+Cu

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    Single Period Model Example

    Our college basketball team is playing in a tournamentgame this weekend. Based on our past experience wesell on average 2,400 shirts with a standard deviation of

    350. We make $10 on every shirt we sell at the game,but lose $5 on every shirt not sold. How many shirtsshould we make for the game?

    Cu=$10 and Co= $5; P $10 / ($10 + $5) = .667

    Z.667 = .432 (use NORMSDIST(.667)

    therefore we need 2,400 + .432(350) = 2,551 shirts

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    Multi-Period Models:Fixed-Order Quantity Model Model Assumptions (Part 1)

    Demand for the product is constant and uniformthroughout the period

    Lead time (time from ordering to receipt) is

    constant

    Price per unit of product is constant

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    Bina Nusantara University

    Multi-Period Models:Fixed-Order Quantity Model Model Assumptions (Part 2)

    Inventory holding cost is based on average inventory

    Ordering or setup costs are constant

    All demands for the product will be satisfied (No backorders are allowed)

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    Basic Fixed-Order Quantity Model and Reorder Point Behavior

    R = Reorder pointQ = Economic order quantity

    L = Lead time

    L L

    Q QQ

    R

    Time

    Numberof unitson hand

    1. You receive an order quantity Q.

    2. Your start using

    them up over time. 3. When you reach down to

    a level of inventory of R,

    you place your next Q

    sized order.

    4. The cycle then repeats.

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    Bina Nusantara University

    Basic Fixed-Order Quantity (EOQ) Model Formula

    H2

    Q+SQ

    D+DC=TC

    TotalAnnual =Cost

    AnnualPurchase

    Cost

    AnnualOrdering

    Cost

    AnnualHolding

    Cost+ +

    TC=Total annual

    cost

    D =Demand

    C =Cost per unit

    Q =Order quantityS =Cost of placing

    an order or setup

    cost

    R =Reorder point

    L =Lead time

    H=Annual holding

    and storage cost

    per unit of inventory

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    Deriving the EOQ

    Using calculus, we take the first derivative of the total cost function withrespect to Q, and set the derivative (slope) equal to zero, solving for theoptimized (cost minimized) value of Qopt

    Q =2DS

    H=

    2(Annual Demand)(Order or Setup Cost)

    Annual Holding CostOPT

    R eorder point, R = d L_

    d = average daily demand (constant)

    L = Lead time (constant)

    _

    We also need areorder point to tell uswhen to place anorder

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    Bina Nusantara University

    EOQ Example (1) Problem Data

    Annual Demand = 1,000 unitsDays per year considered in average

    daily demand = 365

    Cost to place an order = $10Holding cost per unit per year = $2.50Lead time = 7 daysCost per unit = $15

    Given the information below, what are the EOQ andreorder point?

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    Bina Nusantara University

    EOQ Example (1) Solution

    Q =2D S

    H=

    2(1,000 )(10)

    2.50= 89.443 units or OPT 90 u nits

    d =1,000 units / year

    365 days / year= 2.74 units / day

    R eo rder p oin t, R = d L = 2 .7 4u nits / d ay (7d ays) = 1 9.1 8 or _

    20 un its

    In summary, you place an optimal order of 90 units. In thecourse of using the units to meet demand, when you only have20 units left, place the next order of 90 units.

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    EOQ Example (2) Solution

    Q =2D S

    H=

    2(10,000 ) (10)

    1.50= 3 6 5 .1 4 8 un its , o r O P T 366 u ni ts

    d =10,000 units / year

    365 days / year= 27.397 units / day

    R = d L = 27.397 units / day (10 days) = 273.97 or

    _

    274 u nits

    Place an order for 366 units. When in the course of using theinventory you are left with only 274 units, place the next order of 366units.

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    Bina Nusantara University

    Multi-Period Models: Fixed-Time Period Model:Determining the Value ofT+L

    T+L di 1

    T+L

    d

    T+L d

    2

    =

    Since each day is independent and is constant,

    = (T + L)

    i

    2

    The standard deviation of a sequence of randomevents equals the square root of the sum of thevariances

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    Bina Nusantara University

    Example of the Fixed-Time Period Model

    Average daily demand for a product is 20

    units. The review period is 30 days, and lead

    time is 10 days. Management has set a policy

    of satisfying 96 percent of demand from items

    in stock. At the beginning of the review period

    there are 200 units in inventory. The daily

    demand standard deviation is 4 units.

    Given the information below, how many units should be

    ordered?

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    Bina Nusantara University

    Example of the Fixed-Time Period Model: Solution (Part 1)

    T+ L d2 2= (T + L) = 30 + 10 4 = 25.298

    The value for z is found by using the Excel NORMSINV

    function, or as we will do here, using Appendix D. Byadding 0.5 to all the values in Appendix D and finding the

    value in the table that comes closest to the service

    probability, the z value can be read by adding the column

    heading label to the row label.So, by adding 0.5 to the value from Appendix D of 0.4599,

    we have a probability of 0.9599, which is given by a z = 1.75

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    Bina Nusantara University

    Example of the Fixed-Time Period Model: Solution (Part 2)

    or644.272,=200-44.272800=q

    200-298)(1.75)(25.+10)+20(30=q

    I-Z+L)+(Td=q L+T

    units645

    So, to satisfy 96 percent of the demand, you should

    place an order of 645 units at this review period

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    Bina Nusantara University

    Price-Break Model Formula

    CostHoldingAnnual

    Cost)SetuporderDemand)(Or2(Annual

    =iC

    2DS

    =QOPT

    Based on the same assumptions as the EOQ model, the price-break model has a similar Qopt formula:

    i = percentage of unit cost attributed to carrying inventoryC = cost per unit

    Since C changes for each price-break, the formula above willhave to be used with each price-break cost value

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    Bina Nusantara University

    Price-Break Example Problem Data(Part 1)

    A company has a chance to reduce their inventory ordering costs by placing

    larger quantity orders using the price-break order quantity schedule below.What should their optimal order quantity be if this company purchases this

    single inventory item with an e-mail ordering cost of $4, a carrying cost rate

    of 2% of the inventory cost of the item, and an annual demand of 10,000

    units?

    Order Quantity(units) Price/unit($)0 to 2,499 $1.202,500 to 3,999 1.00

    4,000 or more .98

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    Price-Break Example Solution (Part 2)

    units1,826=0.02(1.20)

    4)2(10,000)(=

    iC

    2DS=QOPT

    Annual Demand (D)= 10,000 unitsCost to place an order (S)= $4

    First, plug data into formula for each price-break value of C

    units2,000=0.02(1.00)

    4)2(10,000)(=iC

    2DS=QOP T

    units2,020=0.02(0.98)

    4)2(10,000)(=

    iC

    2DS=QOP T

    Carrying cost % of total cost (i)= 2%Cost per unit (C) = $1.20, $1.00, $0.98

    Interval from 0 to 2499, theQopt value is feasible

    Interval from 2500-3999, theQopt value is not feasible

    Interval from 4000 & more, theQopt value is not feasible

    Next, determine if the computed Qopt

    values are feasible or not

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    Bina Nusantara University

    Price-Break Example Solution (Part 3)

    Since the feasible solution occurred in the first price-break, itmeans that all the other true Qopt values occur at the beginnings ofeach price-break interval. Why?

    0 1826 2500 4000 Order Quantity

    Totalannualcosts So the candidates

    for the price-

    breaks are 1826,2500, and 4000units

    Because the total annual cost function isa u shaped function

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    Bina Nusantara University

    Maximum Inventory Level, M

    Miscellaneous Systems:

    Optional Replenishment System

    MActual Inventory Level, I

    q = M - I

    I

    Q = minimum acceptable order quantity

    If q > Q, order q, otherwise do not order any.

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    Miscellaneous Systems:

    Bin SystemsTwo-Bin System

    Full Empty

    Order One Bin of

    Inventory

    One-Bin System

    Periodic Check

    Order Enough toRefill Bin

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    ABC Classification System Items kept in inventory are not of equal importance in

    terms of:

    dollars invested

    profit potential

    sales or usage volume

    stock-out penalties

    0

    30

    60

    30

    60

    A BC

    % of$ Value

    % ofUse

    So, identify inventory items based on percentage of total dollar value,where A items are roughly top 15 %, B items as next 35 %, and

    the lower 65% are the C items

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    Inventory Accuracy and Cycle Counting

    Inventory accuracy refers to how well theinventory records agree with physical count

    Cycle Counting is a physical inventory-takingtechnique in which inventory is counted on afrequent basis rather than once or twice a year