d-10 solving log equations using properties notes filed-10 solving log equations using properties...

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D-10 Solving Log Equations Using Properties Notes β†’ Equations in the form of () = () Examples: Solve the equation for x. Round answers to 3 decimal places. a. 13 (2) = 13 ( 2 βˆ’ + 2) b. 3 ( 2 + 3) = 3 (52) c. ln (x + 2) + ln (3x – 2) = 2 ln (2x) d. 3 (7 + 3) βˆ’ 3 ( + 1) = 3 (2) e. log (x) + log (x – 3) = log (28) f. ln (x - 5) + ln 4 = ln x - ln 2

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D-10 Solving Log Equations Using Properties Notes

β†’ Equations in the form of π‘™π‘œπ‘”π‘(π‘₯) = π‘™π‘œπ‘”π‘(𝑦)

Examples: Solve the equation for x. Round answers to 3 decimal places. a. π‘™π‘œπ‘”13(2π‘₯) = π‘™π‘œπ‘”13(π‘₯2 βˆ’ π‘₯ + 2) b. π‘™π‘œπ‘”3(π‘₯2 + 3) = π‘™π‘œπ‘”3(52)

c. ln (x + 2) + ln (3x – 2) = 2 ln (2x) d. π‘™π‘œπ‘”3(7π‘₯ + 3) βˆ’ π‘™π‘œπ‘”3(π‘₯ + 1) = π‘™π‘œπ‘”3(2π‘₯) e. log (x) + log (x – 3) = log (28) f. ln (x - 5) + ln 4 = ln x - ln 2

β†’ Solving log equations in the form π‘™π‘œπ‘”π‘(π‘₯) = 𝑐

a. 3 + π‘™π‘œπ‘”9(4π‘₯) = 5 b. 2 = βˆ’3 + ln (π‘₯ + 2)

β†’ Solving log equations in the form π‘™π‘œπ‘”π‘(π‘₯) + π‘™π‘œπ‘”π‘(𝑦) = 𝑐 or π‘™π‘œπ‘”π‘(π‘₯) βˆ’ π‘™π‘œπ‘”π‘(𝑦) = 𝑐

Examples: Solve each equation for x. Round to the nearest hundredth. a. π‘™π‘œπ‘”12(12π‘₯) + π‘™π‘œπ‘”12(π‘₯ βˆ’ 1) = 2 b. log (x – 12 ) – log (x – 2 ) = 2

c. log (50x ) = 2 + log( 2x - 3 ) d. π‘™π‘œπ‘”1/4 (1

4π‘₯) = βˆ’

5

2 βˆ’ π‘™π‘œπ‘”1/4(π‘₯ + 8)

d. e. π‘™π‘œπ‘”2(π‘₯) + π‘™π‘œπ‘”2(π‘₯ βˆ’ 2) = 3