current mirrors and biasing prof. ali m. niknejad prof...
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Department of EECS University of California, Berkeley
EECS 105 Spring 2017, Module 4
Prof. Ali M. Niknejad Prof. Rikky Muller
Current Mirrors and Biasing
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Announcements
l HW9 due on Friday
University of California, Berkeley
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Load Impedance
Courtesy M.H. Perrott
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Issue: Headroom Limitations
Courtesy M.H. Perrott
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Achieving High Gain
Courtesy M.H. Perrott
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Diode Connected Device
l How do we build current sources? l Let’s start with a “diode connected” device l A MOS device with gate and drain shorted operates
like a diode (but not exponential) University of California, Berkeley
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Diode Connected -- SS Model
l We can derive the small-signal model by shorting out the hybrid-pi model
l Note that a Gm generator with it’s controlling terminals connected to the Gm is more simply a …?
University of California, Berkeley
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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The Integrated “Current Mirror” l M1 and M2 have the same
VGS l If we neglect CLM (λ=0),
then the drain currents are equal
l Since λ is small, the currents will nearly mirror one another even if Vout is not equal to VGS1
l We say that the current IREF is mirrored into iOUT
l Notice that the mirror works for small and large signals!
University of California, Berkeley
High Res
Low Resis
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Multiplication Ratio
University of California, Berkeley
VGS1 =VGS 2
IOUT = kW2
L2(VGS 2 −VT )
22 = IINW2 / L2W1 / L1
= NIIN
IIN = kW1L1(VGS1 −VT )
2 IOUT = kW2
L2(VGS 2 −VT )
2
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Current Mirror as Current Source
l The output current of M2 is only weakly dependent on vOUT due to high output resistance of FET
l M2 acts like a current source to the rest of the circuit l For good current source behavior, what is the minimum vOUT?
University of California, Berkeley
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Small-Signal Resistance of I-Source
University of California, Berkeley
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Improved Current Sources
University of California, Berkeley
Goal: increase Ro(ut) Approach: look at amplifier output resistance results … to see topologies that boost resistance
Looks like the output impedance of a common-source amplifier with source degeneration
out oR r>>
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Effect of Source Degeneration
l Equivalent resistance loading gate is dominated by the diode resistance … assume this is a small impedance
l Output impedance is boosted by factor University of California, Berkeley
( )St t m gs o Rv i g v r v= − +
1eq
m
Rg
≈
Sgs Rv v≈ −
SR t Sv i R=
( )t t m S t o t Sv i g R i r i R= + +
( )1to m S o
t
vR g R ri
= ≈ +
( )1 m Sg R+
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Improved Current Sources
University of California, Berkeley
How would you scale the output current?
IIN = kW1L1(VG −VS −VT )
2
VS = IIN RS
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Cascode (or Stacked) Current Source
University of California, Berkeley
Insight: VGS2 = constant AND VDS2 = constant
Small-Signal Resistance Ro:
( )1o m S oR g R r≈ +
( )1o m o oR g r r≈ +
20o m oR g r r≈ >>
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Drawback of Cascode I-Source
University of California, Berkeley
What is the minimum output voltage to keep all transistors in saturation?
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Drawback of Cascode I-Source
University of California, Berkeley
Minimum output voltage to keep both transistors in saturation:
, 4, 2,OUT MIN DS MIN DS MINV V V= +
vOUT
iOUT
2, 2 0 2DS MIN GS T DSATV V V V> − =
4 2 4 2 4 0D DSAT GS GS GS TV V V V V V> + = + −
, 2 4 0OUT MIN GS GS TV V V V= + −
In EE140 we will learn circuit tricks to overcome this problem!
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Current Sinks and Sources
University of California, Berkeley
Sink: output current goes to ground
Source: output current comes from voltage supply
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Current Mirrors
University of California, Berkeley
Idea: we only need one reference current to set up all the current sources and sinks needed for a multistage amplifier.
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Example: Common-Drain Amplifier
University of California, Berkeley
21 ( )2DS ox GS T
WI C V VL
µ= −
vin
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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Common Drain AC Schematic
University of California, Berkeley
vin
How does a REAL current source fit in to the small-signal model?
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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CD Voltage Gain With Real I-Source
University of California, Berkeley
RL
Ideal I-Source voutRL || ro
= gmvgs
voutRL || ro
= gm vin − vout( )
vin
Real I-Source
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EE 105 Spring 2017 Prof. A. M. Niknejad Prof. Rikky Muller
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CD Voltage Gain (Cont.)
University of California, Berkeley
KCL at source node:
Voltage gain:
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