cs 1031 the c++ language c evolves into c++ object oriented programming –classes and objects...
TRANSCRIPT
CS 103 1
The C++ Language
• C Evolves into C++
• Object Oriented Programming– Classes and Objects – Operator Overloading– Inheritance– Polymorphism– Template classes
CS 103 2
C Evolves into C++
CS 103 3
C is Alive in C++
C++ is a superset of C. Any correct C program is also a correct C+
+ program, except for some loopholes in C that are not allowed in C++.
CS 103 4
What is still the same
The syntax of statements if-else, switch, the “?:” conditional for/while/do-while loops assignments arithmetic/logic/relational/ bitwise expressionsdeclarations, struct/union/enum types, typedefpointers, arrays, casting
Same preprocessor commands in C &C++.
CS 103 5
C++: A Better C • Convenient syntax for inline comments: // …• Declaration anywhere• Function overloading • Default arguments• Simplified IO: cin >>, cout<<, and more• A new Boolean data type: bool• Easier dynamic memory allocation: new & delete• References (automatically dereferenced pointers)• Function templates: data types as parameters• Tag names as new data types • Better type system: tighter use of void *
CS 103 6
Convenient Syntax for Inline Comments
• Anything from // to the end of line is considered a comment and thus ignored by the compiler.
• The C-syntax for comments, /* … */, can still be used for multi-tine comments.
int i; // i is an integer that will index the next arraydouble x[10]; // an array that will store user input // and will then be sorted.
CS 103 7
Declaration Anywhere
• Declarations need no longer be at the head of blocks.
• Variables and functions can be declared any time, anywhere in a program, preferably as close to where a variable is used the first time.
• For example: note i is declared within for for (int i=0;i<n;i++)
CS 103 8
Function Overloading
• Two or more functions can have the same name but different parameters
• Example:int max(int a, int b) {
if (a>= b)return a;
elsereturn b;
}
float max(float a, float b) {if (a>= b)
return a;else
return b;}
CS 103 9
Default Arguments
• A default argument is a value given in the function declaration that the compiler automatically inserts if the caller does not provide a value for that argument in the function call.
• Syntax:
return_type f(…, type x = default_value,…);
CS 103 10
Default Arguments (Examples)
• The default value of the 2nd argument is 2.
• This means that if the programmer calls pow(x), the compiler will replace that call with pow(x,2), returning x2
double pow(double x, int n=2)// computes and returns xn
CS 103 11
Default Arguments (Rules)
• Once an argument has a default value, all the arguments after it must have default values.
• Once an argument is defaulted in a function call, all the remaining arguments must be defaulted.
int f(int x, int y=0, int n)// illegal
int f(int x, int y=0, int n=1)// legal
CS 103 12
Examples of Legal/Illegal Defaulting in Function Calls
• Let substring be a function whose prototype is:
• Assume • Which call to substring is OK and which is not
OK? If OK, what is it equivalent to?– substring(p)
– substring(p,10)
– substring( )
char * substring (char *p, int length=10, int pos=0)
char *p=“hello”;
CS 103 13
Default Arguments and Function Overloading
• Default arguments and function overloading can give rise to an ambiguity
• Consider an overloaded function f where one declaration has default arguments that, if removed, makes the function look identical to a second declaration, as in
1. int f(int x, int y=0); returns xy
2. int f(int x); // returns 2x
If we call f(2), is it to fin (1) or (2)? The 1st returns 1. The 2nd returns 4.
CS 103 14
Default Arguments and Function Overloading (Contd.)
• If overloaded declarations of a function with default arguments cause ambiguity, the compiler gives an error message.
• It is the responsibility of the programmer not to cause such ambiguities.
CS 103 15
Example of Function Overloading and Default Args
// Precondition: x[] is a double array of length n.// n is a positive integer. If missing, it defaults to 10// Postcondition: the output is the maximum in x[]double max(double x[], int n=10){
double M = x[0]; // M is the maximum so farfor (int i=1;i<n;i++)
if (x[i]>M) M=x[i];
return M; }
CS 103 16
Overloading & Defaulting Example (Contd.)
// Precondition: x[] is an int array of length n.// n is a positive integer. If missing, it defaults to 10// Postcondition: the output is the maximum in x[]int max(int x[], int n=10){
int M = x[0]; // M is the maximum so farfor (int i=1;i<n;i++)
if (x[i]>M) M=x[i];
return M; }
CS 103 17
Simplified IO
• Instead of the complicated syntax of printf and scanf, and the many variations of print and scan, C++ offers a much simpler syntax
• For standard output, use cout • For standard input, use cin • File IO is also simpler, and will be discussed later• Note: one can still use the IO syntax of C in C++
CS 103 18
Cout
• For printing output, use this syntax:
This prints out the string or the value of the extpression.
• For output chaining, use this syntax
Each Si is a string or an expression. The effect is to print out the value of S1 followed by the value of S2, followed by the value of S3.
cout << a string or an expression;
cout << S1 <<S2<<S3<<endl;
CS 103 19
Cout (Contd.)
• The reserved word, endl, ensures that the next cout command prints its stuff on a new line.
• New lines can also be added using “\n”.
CS 103 20
Cout (Examples)
Statements Outputint x=3; double y =4.5;
cout <<“the value of x=“<<x;
cout<<“; y=“<<y<<endl;
cout <<“x+y”<<x+y;
the value of x=3; y=4.5
x+y=7.5
int x=3; double y =4.5;
cout <<“x = “<<x<<“\n”;
cout<<“y=“<<y;
cout <<“\nx+y”<<x+y;
x = 3
y=4.5
x+y=7.5
CS 103 21
Cin
• For reading input values into variables:
• This reads the input from the standard input (say the screen for now), puts the first read value in variableName1, the second read value in variableName2, and the third read value in variableName3.
cin >> variableName1 >> variableName2 >> variableName3;
CS 103 22
Cin (Examples)
• Suppose you want to read an int value and a double value into variables n and x.
• This code will do it (see next slide):
int n; double x;
cout<<“enter an int, a space, and a double: “;cin>>n>>x; // use of cin
cout<<“You entered int n=“<<n;
cout<<“, and double x=“<<x<<endl;
CS 103 23
• If you run that code, you first get:
• Let’s say, you enter: -3 9.8
• The code next will store –3 in n, and 9.8 in x, and print out to you:
Enter an int, a space, and a double:
Enter an int, a space, and a double: -3 9.8
You entered int n=-3, and double y=9.8
CS 103 24
A new Boolean data type: bool
• A bool variable is a variable that can have only two values: true or false.
• C does not have Boolean values or variables
• Instead, any non-zero was considered the equivalent of true , and 0 the equivalent of false.
CS 103 25
Example of bool // Precondition: x[] is an integer array of length n.// n is a positive integer.// Postcondition: The output is true if the elements // of the input array are all positive,. Else, false. bool isAllPositive(int x[], int n){
for(int i=0;i<n;i++)if (x[i] <= 0)
return false; return true;
}
CS 103 26
A Comprehensive Example#include <cstdlib>#include <iostream>using namespace std;// codes for isAllPositive( ), and for overloaded// function max( ) should be inserted hereint main(int argc, char *argv[]){ cout << " enter five integers :"; int x[5]; int n=5; for (int i=0;i<n;i++) // read the input to x[] cin>>x[i];
CS 103 27
cout << "You entered: "; for (int i=0;i<n;i++) cout << x[i]<<" "; if (isAllPositive(x,n)) cout << “\nYour data is all positive\n"; else cout << “\n Your data is not all positive\n"; int M = max(x,n); cout<<“Your maximum value is: "<<M<<endl;} // end of main( )
CS 103 28
Easier Dynamic Memory Allocation: new & delete
• new corresponds to malloc/calloc in C• delete corresponds to free in C• The syntax of new has forms:
• The semantics of this syntax is explained next
–type *pointer = new type; // type is a built-in // or user-defined data type.
–type *pointer = new type[n]; // type as above
CS 103 29
Semantics of new
• For type *pointer = new type; :– The system allocates dynamically (during
execution) a chunk of memory large enough to hold data of the specified type, and returns a pointer pointing to the address of that chunk. This pointer is stored in the user-provided pointer-variable pointer.
CS 103 30
Semantics of new [n]
• For type *pointer = new type[n]; :– The system allocates dynamically an array of n
memory chunks, each large enough to hold data of the specified type, and returns a pointer pointing to the address of that chunk.
– The difference between this type of arrays (called dynamic arrays) and conventional arrays is that the size of the latter is constant while the size of the former can vary.
CS 103 31
Example of new
// Precondition: n is a positive integer// Postcondition: computes and prints out the first n // elements of the Fibonacci sequence void fibonacci(int n){ int *x = new int [n]; // creation of a dynamic array x[0]=1; x[1]=1; for (int i=2;i<n;i++)
x[i]=x[i-1]+x[i-2]; cout<<"The Fibonacci sequence of "<<n<<" values are:\n"; for (int i=0;i<n;i++)
cout<<"x["<<i<<"]="<<x[i]<<endl; }
CS 103 32
Syntax and Semantics of delete
• The syntax of delete has two forms:
• The first releases the memory of the single memory chunk pointed to by pointer
• The second releases the memory allocated to the array pointed to by pointer.
– delete pointer ;
– delete [] pointer ;
CS 103 33
References
• A reference is an autmatically dereferenced pointer
• Syntax of reference declaration:
• Semantics: refname becomes another name (or alias) for variable. Any change to the value of variable causes the same change to refname, and vice versa.
Type& refname = variable;
CS 103 34
Illustration of ReferencesStatements Outcome
int x=17;int& xref = x;cout<<“x=“<<x<<endl;cout<<“xref=“<<xref<<endl;
x=17
xref=17
x=x+5;cout<<“x=“<<x<<endl;cout<<“xref=“<<xref<<endl;
x=22
xref=22
xref = xref-10;cout<<“x=“<<x<<endl;cout<<“xref=“<<xref<<endl;
x=12
xref=12
CS 103 35
References and Function Call by Reference
void swap(int x, int y){
int tmp=x; x=y; y=tmp;
}
int x=5; int y=10;
swap(x,y);
cout<<x<<“, “<<y;
void swap(int& x, int& y){
int tmp=x; x=y; y=tmp;
}
int x=5; int y=10;
swap(x,y);
cout<<x<<“, “<<y;
Outcome:
5, 10 // no swap
Outcome:
10, 5 // it did swap
CS 103 36
Templates of Functions(Motivation)
• Functions are a great construct because they all the programmer to specify fairly generic parameters (variable arguments), and later call a function multiple times with different argument values, thus saving on programming effort
• It will be equally convenient and effort-saving if one can specify generic types that can be substituted with any actual type whenever a function is called
CS 103 37
Templates of Functions(Purpose and Syntax)
• Templates provide that great convenience
• They make the data type/types of function arguments and of the return value to be “programmable”
• Syntax for declaring template function:template<class type> function_declaration;
-Or-template<typename type> function_declaration;
CS 103 38
Templates of Functions (Example)// Precondition: x[] is an array of length n, of // a generic type. n is a positive integer. // Postcondition: the output is the minimum in x[]template<typename T> T min(T x[], int n){ T m = x[0]; // M is the minimum so far
for (int i=1;i<n;i++)if (x[i]<m) m=x[i];
return m;}
CS 103 39
How to Call a Function Template
• The syntax of calling a function template:
• Example:
functionName<an-actual-type>(parameter-list);
int x[]={11, 13, 5, 7, 4, 10};double y[]={4.5, 7.13, 3, 17};int minx = min<int>(x,6);double miny=min<double>(y,4);cout<<“the minimum of array x is: “<<minx<<endl;cout<<“the minimum of array y is: “<<miny<<endl;
CS 103 40
Templates with More than One Generic Type
• Templates can have several generic types
• Syntax for their declaration:
• class can be replaced by typename.
template<class type1,class type2> funct_decl;