crms calculus 2010 january 20, 2010

15
1 Derivative of the Inverse of a Function I can see clearly now. http://cs.armstrong.edu/greenlaw/climbing/vinson/Scan121.jpg

Upload: colorado-rocky-mountain-school

Post on 25-Jun-2015

382 views

Category:

Education


0 download

DESCRIPTION

Derivative of the inverse of a function property

TRANSCRIPT

Page 1: CRMS Calculus 2010 January 20, 2010

1

Derivative of the Inverse of a Function

I can see clearly now.

http://cs.armstrong.edu/greenlaw/climbing/vinson/Scan121.jpg

Page 2: CRMS Calculus 2010 January 20, 2010

2

Page 3: CRMS Calculus 2010 January 20, 2010

3

Page 4: CRMS Calculus 2010 January 20, 2010

4

Page 5: CRMS Calculus 2010 January 20, 2010

5

Page 6: CRMS Calculus 2010 January 20, 2010

6

Page 7: CRMS Calculus 2010 January 20, 2010

7

Page 8: CRMS Calculus 2010 January 20, 2010

8

Page 9: CRMS Calculus 2010 January 20, 2010

9

Page 10: CRMS Calculus 2010 January 20, 2010

10

Page 11: CRMS Calculus 2010 January 20, 2010

11

What is your conjecture?

Page 12: CRMS Calculus 2010 January 20, 2010

12

For any point (a, b) on an invertible function,the derivative of the inverse of the function evaluated at bis equal to the reciprocal of the derivative of the function evaluated at a.

If f (x) is an invertible function, then for any point (a, b) on f (x)

(f­1)'(b)    = 1f '(a)

Page 13: CRMS Calculus 2010 January 20, 2010

13

Page 14: CRMS Calculus 2010 January 20, 2010

14

* Note: Tangents intersecton y = x line

Page 15: CRMS Calculus 2010 January 20, 2010

15