correlation & regression dk 2015
TRANSCRIPT
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8/19/2019 Correlation & Regression DK 2015
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12/3/20
CELAI
D K, D
ALA K DIJAAB HAI II
1. B
?
2. B ?
3. K ?
ALA K DIJAAB HAI II
4. B
?
5. F
?
6. B
?
CH EALA KAJIA
• A () ?
• A () ()?
• A () () ?
KELAI
• K
• K
• K ()
/ D
• CAEL
2
( ).
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CAE F CELAI
,
.
&
CAE DIAGAM
• D ,
()
(
) .
I M( )
= 0.81
L:
.
L E E
= 0.14
L
BEA CACE MALI AD
HIE
= 0.75
L
CAIACE
• C:
• D :
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CAIACE
• K ,
•
BEA CACE AD HIE
= 0.75
EKALI KELAI EA
• N ,
1
EGIAAID M
M
1 5 2
2 3 1
3 9 3
4 4 2
5 9 5
6 5 2
7 7 4
8 2 1
EELEAIA & FAC AG MEMEGAHI
EKALI KELAI
•
•
H
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MEGHADKA JLA HEEGEE AMLE
EMEHAIA
• H
A
N 6.47 4.03
6.13 3.76
NE 6.19 3.77
E M 4.89 3.34
M 5.63 3.47
E A 4.52 2.92
5.89 3.2
4.79 2.71
5.27 3.53
6.08 4.51
N I 4.02 4.56
EMEHAIA
= 0.224;
=0.509
CELAI & CAAI
• H
.
•
.
• H
• M
.
JIA IGIFIKA KELAI
• , .
• C:
– 25 – 25
– D = 0.278
– = N 2, N =
– J
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5 LAGKAH JIA HIEI
1. H
2. ()3. B
4. D
5. B K
JIA IGIFIKA KELAI
• H0: ρ = 0
• H1: ρ ǂ 0
• = 0.05
• Buat Pengiraan; dapat df
• Dapatkan nilai kritikal (daripada
jadual)
• Buat Keputusan
K
CH AKHI
• () .
• N = 50
• = 0.30
• A ?
CAA ELIA DAAA KELAI
• () . , 50 KM, ( 5 ) (A=4;B=3) .
• ,
. K
= 0.30 ,
, ((48) = 0.30,
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LAIHA
• A
?
• A ?
• .
H
56 87
56 91
65 85
65 91
50 75
25 28
87 122
44 66
35 58
EGEI LIEA MDAH
• A ?
• A ?
• B ?
• ?
• B ?
• B ?
BEAA EGEI DEGA KELAI?
• A , : – A ?
– A ?
• A / , .
IILAH BA
• : () .
• :
• K D K (2): K . I: 2 0.56, 56% .
CH EBICAGA
ID M M
1 5 2
2 3 1
3 9 3
4 4 2
5 9 5
6 5 2
7 7 4
8 2 1
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MAA LAGKAI & MAKAH
= 0.887
GAIA EGEI
• = N
• = K
• = ( = 0)
• =
GAIA BE FI
• A F?
.
• K MEI ,
0, .
•
G
I M( )
= 0.81
= . = . = .
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EKALI EGEI
• (EKALI EGEI):
, .
CH EBICAGA
ID M
M
1 5 2
2 3 1
3 9 3
4 4 2
5 9 5
6 5 2
7 7 4
8 2 1
Y = 33.988 + 2.239X1
E & MM CH LEA
EIG
EGEI HAA BEMAKA JIKA KELAI
AAA DA EMBLEHBAH EEBADALAH IGIFIKA!!!!
ENGJIAN HIOEI??
• K
()
,
.
• K ,
.
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ELAA EGEI
•
. 13 . ; ((11) = 0.86,
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LEBIH DAIADA 1 EAMAL?
• = N
• = K
• = ( = 0)
• =
•
• I K: ( )
– 1= 1, 2
– = . .
k k 221i1X bX bX ba Ŷ ++++= K
N
A K
CH EGEI BEGADA
• C: A
5?
• = M
• 1 = M
• 2 = M
EGEI BEGADA
0
Y
X1X2
Kerana kita adatiga
pembolehubah, plot kita
juga mempunyai tiga
dimensi...
•
1
2
GAF MDEL DA FAK/EMBLEHBAH
2211X bX bŶ ++= aKita cuba lukiskan
satu satah yang
mempunyai “error”yang paling kecil…
EGEI BEGADA
•
.
• (
),
.
– J :
– J :
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C 1
• A
() . D
:
No: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
BilAnak(Y): 2 5 1 9 6 3 0 3 7 7 2 5 1 9 6 3 0 3 7 14 2 5 1 9 6
Pendidikan (X1) 12 16 20 12 9 1 16 14 9 12 12 10 20 11 9 18 16 14 9 8 12 10 20 11 9
Pendapatan (‘000, X2): 3 4 9 5 4 12 10 1 4 3 10 4 9 4 4 12 10 6 4 1 10 3 9 2 4
• O
:
B A
51.9% variasi dalam
bilangan anak boleh
dijelaskan oleh tahun
pendidikan dan
pendapatan.
Y = 10.06 - 0.31X1 – 0.33X2
Σ ( )2∧
• . ( , )
• H:
– H0: β = 0 ( )
– H1: β ≠ 0 ( )
• I .
AA
• ANOA
. I
()
• H:
– H0: β1 = β2 = = β = 0 ( )
– H1: β ≠ 0
• I ANOA
ANOA
.
ELAA EGEI BEGADA
•
. J
() () .
A
.
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ELAA
• A
(F(2,22)=11.88, 2 =0.519). F (=0.31, =2.23,=0.036) (=0.33, =2.19,=0.039) . : () ()
ELAMA MAJ JAA