correlation of pressure drop for two-phase, a thesis …

95
CORRELATION OF PRESSURE DROP FOR TWO-PHASE, CONCURRENT FLOW IN PACKED BEDS by HANG-YEN FANG, B.S. IN CH.E. A THESIS IN CHEMICAL ENGINEERING Submitted to the Graduate Faculty of Texas Tech University in Partial Fulfillment of the Requirements for the Degree of MASTER OF SCIENCE IN CHEMICAL ENGINEERING Approved Accepted December, 1981

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CORRELATION OF PRESSURE DROP FOR TWO-PHASE,

CONCURRENT FLOW IN PACKED BEDS

by

HANG-YEN FANG, B.S. IN CH.E.

A THESIS

IN

CHEMICAL ENGINEERING

Submitted to the Graduate Faculty of Texas Tech University in

Partial Fulfillment of the Requirements for

the Degree of

MASTER OF SCIENCE IN

CHEMICAL ENGINEERING

Approved

Accepted

December, 1981

ACKNOWLEDGMENTS

The author wishes to express his great appreciation

to the following people for their contributions to the

research which was the basis of this thesis:

Dr. L. D. Clements, Jr., chairman of the committee,

for his wise counsel, for his interest and enthusiasm, and

for his cooperation on every occasion.

Drs. S. R. Beck and S. Selim, committee members, for

their assistance and suggestions during the progress of

this work.

Mr. C. Y. Lee for his successful preparation.

My wife, Pi-Fei, first for her patient typing work,

but most of all, for her understanding and encouragement

during the course of this work.

ii

.- .. ··

TABLE OF CONTENTS

ACKNOitJLEDGMENT S . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . LIST OF TABLES

LIST OF FIGURES

NOMENCLATURE I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I

CHAPTER I INTRODUCTION ..... o o o o o o o o o o o •• o o o • o • o • o •

Objectives . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER II LITERATURE REVIEW

Liquid Holdup I I I I I I I I I I I I I I I I I I I I I I I I I

Pressure Drop in Single Phase Flow

page

ii

iv

v

Vll

l

5

6

7

in Packed Beds o • 0 ••• o • 0 o 0 0 o o 0 o o 0 o o 0 o • • 10

Two Phase Flow Pressure Drop a o • • • • • • 1 •

CHAPTER III THEORETICAL ANALYSIS I I I I I I I I I I I I I I I I I I

Energy Balance . . . . . . . . . . . . . . . . . . . . . . . ..__,

Model 0 I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I

CHAPTER IV CORRELATION AND DISCUSSIONS

Data Characteristic . . . . . . . . . . . . . . . . . . . Correlation of Experimental Data

Result of Correlation a • • • • • • • • • • • • • • • •

Discussions . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER V CONCLUSIONS AND SUGGESTIONS

Conclusions . . . . . . . . . . . . . . . . . . . . . . . . . . . Further Study Suggestions I I I I I I I I I I I I I

REFERENCES I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I

lll

18

39

39

41

52

52

56

67

70

81

81

81

83

LIST OF TABLES

page

Table I Comparison Between Countercurrent and Concurrent Operation II •• ~· Ill •••• II 2

Table II Holdup Correlations ~·· ....... I ••• I I •• I I 8

Table III Characteristics of Two-Phase Packed Bed Pressure Drop Data Used II .I ••••• Oil 53

Table IV Comparison of Correlations II. I ••• II •••• 71

iv

Figure

Figure

Figure

Figure

Figure

Figure

Figure

Figure

Figure

LIST OF FIGURES

page

1 Exponents for porosity function . . . . . . . . 12

2 Reynolds number vs. friction factor .... 13

3 fvvs. NRe/(1-E) ....................... 16

4 Comparison between Ergun's and Hick's equation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17

5 Larkins' correlation ................... 23

6 Control surface for the momentum

7

8

9

exchange model of Turpin and Huntington . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26

The capillary model .................... 35

The capillary flow model I I I I I I I I a I I I I D I

The capillary saparation flow model .... 42

48

Figure 10 Log ( oLGE3DpReL Pu (L2 (1-E )2 )) vs.

Log(Rei/(1-E)) , GPuLPG in the range

Figure 11

Figure 12

Figure 13

170 to 200 ............................. 58

Log(oLGE3DpReL Pu(L2 (1-E) 2 ) vs.

Log(Rei/(1-E)), GPL/LPG in the range: 90 to 100 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59

Log(oLGE3DpReLPU(L2 (1-E) 2 ) vs.

Log(Rei/(1-E)), G PuL.PG in the range:

40 to 50 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 60

Log(oLGE3DpReLPU(L2 (1-E) 2 ) vs.

Log(Rei/(1-E)), G PUL PG in the range: 7 . 5 t 0 12 . 5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . 61

v

Figure

Figure

Figure

Figure

Figure

Figure

Figure

14

15

16

17

18

19

20

Log(fTp/(Rei(l-E) 0 · 8 ) vs.

Spherical and cylindrical

Log(fTp/(Rei/l-E) 0•8 ) vs.

GPL Log (L p )

G packings

GPL Log (L p )

G

e I I I

page

63

Raschig ring packing .................. 64

fv vs. (G PL~G/LPG~L), @

Rei/ ( 1-E) less than 50 • • . . . . . . . . . . • . . • 66 @

Log((fTP-fv)/Fk) vs. Log(Rel/(1-E))

Spherical and cylindrical packings •... 68 @

Log((fTP-fv)/Fk) vs. Log(ReL/(1-E))

Raschig ring packing .................. 69

Distribution curve of error

Density distribution curves

vi

. . . . . . . . . . .

. . . . . . . . . . . 77

80

a v

Al'

Dp

D c

D e

* EuL

* EuG

fk

fv

fTP

G

* G

A2' A3

NOMENCLATURE

surface area per unit volume

coefficients of correlation groups

particle diameter

capillary diameter

equivalent diameter

- * 2 liquid Euler's number P atm'-L/(L )

gas Euler's number Patm ·~/(G*) 2

kinetic friction factor

viscous friction factor

friction factor for two phase flow 3 oLG .JL Dp ReL E

L2 (l-~)2

conversion factor, 32.17 poundals per pound

in English units

superficial gas flow rate in open column

(lb/ft 2 . hr)

average gas flowrate in packed bed (G/c)

liquid holdup

prediction holdup

true holdup

vii

1

* 1

n

F

F atm

* p

R

r c

s

t

u

dimensionless group * * * oF EuG.ReG

( ~ ) oZ 2

* * * oF Eu1 .Re1 ( ) *

dimensionless group oz 2

supercial liquid flow rate in open colu~n (lb/ft2 . hr)

average liquid flowrate in packed bed (1/E)

@ exponent of Re1/(l-E)

pressure

atmosphere pressure, 14.7 psi.

dimensionless group

radius

radius of capillary

F

Fatm

radius of the gas-liquid interface

DF G gas Reynolds number

gas Reynolds number at gas flowrate G/~

DF 1 liquid Reynolds number

u1

liquid Reynolds number at liquid flowrate 1/~

@ liquid Reynolds number at liquid velocity u

dimensionless interface radius, r 1/rc

the thickness of liquid along the wall of the

column

velocity viii

w

z

* z

Pm

E

velocity at the interface

velocity ( _b_ + p1

gas velocity

liquid velocity

* dimensionless gas velocity (uG/(G /PG)

* dimensionless liquid velocity (u1/(1 /P1 )

specific volume per unit mass

correlation group ( 1 PG ~1 )

G p1 UG

energy converted into heat by friction

shaft work done by the system

distance

dimensionless distance (Z/r ) c

gas density

liquid density

average two-phase density ( 1 + G --=--~~-) 1 + G

packing porosity p1 PG

gas viscosity

liquid viscosity

two phase energy loss per unit volume

liquid phase energy loss per unit volume in

open column

lX

X

gas phase energy loss per unit volume in open column

1

dimensionless group (o1/oG) 2

dimensionless radius (r/r ) c

X

CHAPTER I

INTRODUCTION

Two-phase flow of liquids and gases through catalyst

beds is becoming quite important to the chemical and

petroleum industry. In order to design the reaction

vessels, the ability to predict the pressure drops, heat

transfer, mass transfer, and reactor residence time is

required.

Commercial packed towers for gas-liquid contacting are

generally operated countercurrently with gas flowing

upwards and liquid flowing downwards. The capacity of

countercurrently flowing reactors is limited by flooding

when operated at very high gas and liquid flowrates. By

contrast, concurrent operations do not have hydrodynamic

capacity limits and are efficient when the chemical re­

action is fast and a short contacting time is needed. In

absorption and stripping operations, concurrent gas-liquid

vessels can operate with only one equilibrium stage.

Table I shows a comparison of both countercurrent and

concurrent operation.

Concurrent, gas-liquid flow is most often found in a

special type of reactor, called a trickle bed reactor.

This device is one in which a liquid phase flows at a low

rate and a gas phase flows at low to high rates concurrently

1

Tab

le

I

Co

mp

aris

on

Bet

wee

n C

ou

nte

rcu

rren

t an

d

Co

ncu

rren

t O

pera

tio

n

eq

uil

ibri

um

stag

es

flo

od

ing

co

nta

ct

tim

e

CON

CURR

ENT

on

e,

the

sam

e as

batc

h re

acto

r

no

flo

od

ing

sho

rt

COU

NTE

RCU

RREN

T

mu

ltip

le

stag

es,

dep

end

s o

n h

eig

ht

flo

od

ing

o

ccu

rs at

hig

her

gas

and

li

qu

id

flo

w ra

tes

lon

g

l\)

J

downward through a fixed bed. The liquid "trickles" over

the catalyst particles. Trickle bed reactors are used

extensively in the petroleum industry for hydrodesulfuri­

zation of heavy oil, hydrotreating and refining of lubricat­

ing oils and waxes, and cracking of high boiling point

hydrocarbons (10). Liquid-phase oxidation of organic

pollutants in water may be accomplished with the liquid and

gas flowing concurrently through a packed catalytic reactor

(31). Absorption of so2 in caustic solution, absorption of

NHJ in H2so4 and H3

Po4 , absorption of H2S in caustic

solution, and stripping of so2 at low liquid rates and high

gas rates can be operated in downward, two-phase concurrent

flow to prevent flooding (2J). Hydrogenation of glucose to

sorbitol or the hydrogenation of alkyl anthraquinone to the

hydroquinone to yield the quinone and hydrogen peroxide by

oxidation are also examples of the application of concurrent,

two-phase flow (1).

Pressure drop in liquid-gas two-phase flow has been

investigated by several researchers. Each investigator has

his own model and correlation to predict the pressure drop,

but unfortunately, few correlations can fit all the experi­

mental data readily available in the literature.

In this thesis, there are 1570 data points obtained by

Larkins(4), Weekman(25), Clements(27), and Halfacre(26).

Using these data a new model and correlation has been

developed. The pressure drop per unit length is assumed to

4

be the sum of the viscous pressure gradient plus the kinetic

pressure gradient. The viscous portion is obtained from a

capillary flow model and the kinetic portion is obtained

from a capillary separation flow model. The important

properties are the porosity of the packed bed, the viscosi­

ties of liquid and gas, the densities of liquid and gas, the

diameter of the packing materials, and the flow rates of

both fluids.

Chapter II is a review of the literature relating to

pressure drop modeling and correlation of both single and

two-phase flow in packed beds.

Chapter III is the theoretical analysis for the non­

foaming flow regime. In the viscous flow portion, a

capillary flow model is used to describe the packed bed flow

behavior. The liquid is assumed to flow along the walls of

the capillaries and gas flows in the center. In the kinetic

flow portion, a capillary separation flow model is presented.

For this model a small portion of the liquid flows along the

wall. In the center of the capillary, liquid and gas flow

separately. The mathematical models are presented to de­

scribe flow phenomena in two-phase flows in packed beds.

Chapter IV presents the final correlation of the

experimental data from the literature. The plots of calcu­

lated points against the parameters are presented, and the

coefficients of the pressure drop equations are obtained

from regression. The comparison between the experimental

5

data from the literature and the new pressure drop models

developed in this work is given in this chapter. The

comparison between this correlation and other investigator's

correlations is also presented. The assumptions used in

developing this correlation are discussed.

Chapter V concludes the correlation of two-phase flow

pressure drop through packed bed. The extension of the

correlation to two immiscible liquids is not recommended.

Objectives

1. Use flow models to describe the packed bed flow behavior.

2. Theoretical analysis of the models.

J. Correlation of the experimental data from the literature.

-4. Compare between present correlation and other corre­

lations.

CHAPTER II

LITERATURE REVIEW

There are three areas of interest related to two-phase

downflow in packed beds. The first area of interest de­

scribed is liquid holdup correlations for two phase flow

through packed beds. The amount of liquid held in the void

of the catalyst packed beds affects the space occupied by

each phase. The volume occupied by the fluid affects the

velocity of the fluid and influences the pressure drop.

The holdup prediction also affects the pressure drop pre­

diction of both Larkins' (1,4), and Turpin's (15) corre-

lations. In their correlations the actual two phase

pressure drop is 0LG(actual) = 0LG(experimental) + PLhL + PG(l-hL) ... (2- 1 )

in which hL is the liquid holdup.

The second area of interest is single phase pressure

drop through packed beds. Larkins (1,4), Sato (16), Midoux

(8), Sweeney (13), and Clements (27) use the calculated

single phase flow pressure drop to correlate the two-phase

flow pressure drop. The porosity and the friction factor

relate to single phase flow pressure drop and are expanded

to two-phase flow situations in the correlations. The

third area of interest is the modelling and correlation of

two phase flow through packed beds. Because of the variety

6

of approaches, comparison between each investigator's

modelling and correlation is made.

Liquid Holdup

Liquid holdup is defined as the ratio of volume of

freely drainable liquid to the void volume of the bed.

Knowledge of liquid holdup behavior leads to a better

understanding of the mechanisms of mass transfer and

heat transfer, and the prediction of pressure drop. The

amount of liquid held in the void of the catalyst beds

affects the chemical reaction rate and the average liquid

residence time. Higher liquid holdups will leave less

space for gas to flow and will cause a higher pressure

drop per unit length in the bed. In general, the liquid

holdup decreases when the gas flow rate increases and the

liquid holdup increases when the liquid flow rate ln­

creases. A decrease in the diameter of the packing

material will increase the specific area per unit volume

and cause higher liquid holdup. An increase in liquid

viscosity and surface tension also increases liquid

holdup.

A number of liquid holdup correlations have been

presented in the literature and are summarized in

Table II.

7

Eq

uati

on

s

Tab

le

II

Ho

ldu

p C

orr

ela

tio

ns

Lo

g h

L

2 =

-0

.36

3

+

0.1

68

L

og

X'

-0.0

43

(L

og x')

for

0.05

-.::

:::X

'<

100

x'

=

(

hL

= 0

.84

(

~PG L G

Pa

gc6

.Z

+

1

ReG

W

eG

ReL

hL

= 0

.40

a0

.33

~0.

22

1 )2

)-0

.03

4

x :

The

sa

me

as

Lark

ins

defi

ned

hL

= -

0.0

17

+

0

.13

2

(L/G

)0

·2 4 fo

r 1

.0 <

(L/G

)0

·2 4<

6.0

hL

= 0

.00

44

5

(Re

)0.7

6

L

Dev

elo

per

s &

Sy

stem

s

Ch

arp

en

tier

and

F

av

ier

(5)

3 mm

g

lass

sp

here

s,

1.8

x

6 an

d

1.4

x

5 mm

cy

lin

ders

air

, N

2,

co2

cycl

oh

exan

e,

gaso

lin

e,

petr

ole

um

eth

er

Cle

men

ts

(6)

3,

1.0

, 1

.6 m

m sp

here

air

-sil

ico

ne o

il

Sato

, H

iro

se,

Tak

ahas

hi

and

T

oda

(161

2

.6

to

24

.3

mm

gla

ss

sph

ere

s air

.... wate

r

Tu

rpin

an

d H

un

tin

gto

n

(15

) 8

.27

, 7

.64

mm

sph

ere

air

-wate

r

Hoc

hman

an

d E

ffro

n

(18

) 4

.8 m

m g

lass

sp

here

N

2,

met

han

ol

co

Tab

le II

(c

on

tin

ued

)

Eq

uati

on

s

hL

=

0.1

25

( Z

/'I' 1

• 1

) -0

• 31

2 ( a

v

Dp

/ E) 0

. 6

5

(Re

)1

.16

7

Z

-G

-

(Re

) 0

. 76

7 L

~ =

aw

( ~L

( Pw

)2

)1/3

aL

~w

PL

av

: p

ack

ing

geo

metr

ical

are

a

2 L

og 1

0

hL

=

-0.

774

+

0. 5

25

Log

10

X -

0.1

09

(Log

10

X )

for

0. 0

5 <

X

<

30

t.P

(t'!

Z)L

0.

5 t.P

)

(t.Z

)G

= (

Dev

elo

per

s &

Sy

stem

s

Sp

ecch

ia a

nd

D

ald

i (1

2)

6 mm

g

lass

sp

here

, 2

.7,

5.4

mm

gla

ss

cy

lin

der,

3

.2 m

m

cata

lyst

cy

lin

der

air

-wate

r an

d C

harp

en

tier

and

F

av

ier'

s

data

Lark

tns,

W

hit

e,

and

Je

ffre

y

(l)

3 mm

sp

here

s,

9.5

mm

sph

ere

s,

cy

lin

ders

an

d ra

sch

ig r

ing

s.

air

, w

ate

r,

eth

yle

ne

gly

co

l,

meth

ylc

ell

ulo

se

solu

tio

n

\()

Pressure Drop in Single Phase Flow

in Packed Beds

The Reynolds number and friction factor used to

describe flow through pipes have been modified to de-

scribe flow through a packed bed. Porosity of the bed

and diameter of packing materials are the prime factors

to describe the packing medium. Brownell and Katz (J),

Ergun (2), and Hicks (21) used Reynolds number, bed

porosity, and diameter of packing materials to correlate

the pressure drop for single phase flow through a packed

bed.

l. Brownell and Katz (1947) (J)

Brownell and Katz defined the modified Reynolds number

and modified friction factor as

Re =

f =

D u P

2g D f:lpEn c p

I I I I I I I I I I I 1 I I I I I I I I I I I I I I I I (2-2)

............................ (2-3)

in which D diameter of the particle for porous media p

u superficial velocity

E porosity of the beds, dimensionless

1 length over which f:lp is measured

) density

1.1. viscosity

10

11

A long series of trial-and-error calculations resulted

in n and m as a function of the ratio of particle sphe­

ricity to bed porosity (Fig. 1). The modified Reynolds

number (Eq. 2-2) and friction factor (Eq. 2-3) can be

calculated when n and m are known. The friction factor

had been plotted vs. Reynolds number with roughness (e/D)

as parameter (Fig. 2). Dis the diameter of the particle

and e is the average effective height of projection or

depression on the particle.

2. Ergun (1952) (2)

Ergun proposed that the factors which influence the

pressure drop in a packed bed are (a) rate of fluid flow,

(b) viscosity and density of the fluid, (c) closeness

and orientation of packing, and (d) size, shape, and

surface roughness of the particles. The first two

factors depend on the fluid, while the last two concern

the solid.

(a) Rate of fluid flow:

The pressure drop is proportional to the fluid

velocity at low rates, and approximately pro-

portional to the square of the velocity at

high rates.

~P/L = aU + bPU2 ....................... (2-4)

(b) Viscosity and density of fluid:

At low velocity the second term 1n equation (2-4)

~

..p

•rl

[/) 0 H

0 Pi

H

0 'i-t

..p s:: Q

) s:: 0 Pi ~

rLI

30

20

10

5 4 3 2 1 o.

0.

5 1

.0

1.5

2

.0

2.5

3.0

3

.5

Fig

1

Ex

po

nen

ts

for

po

rosit

y fu

ncti

on

(A

dap

ted

fr

om

R

ef.

J)

sp

heri

cit

y

po

rosit

y

4.0

1--'

1\)

S--1 0 .p

() ro

1.

't-i ~

0 •rl

.p

()

·rl S--1

li-t

.1

' ' ' ' '

' ' ' ' ' ' '

' ' '

--------1

.05

------------~.10

.00

01

.0

00

01

.01~----------~----------~------------L------------L----------~

10

1

02

10

3

10

4 1

05

1

06

Rey

no

lds

nu

mb

er

Fig

2

Rey

no

lds

nu

mb

er v

s.

fric

tio

n fa

cto

r (A

dap

ted

fr

om

R

ef.

3)

e D

1--'

\....J

14

is not important and the first term is important,

which is a condition for viscous flow. In

viscous flow, the pressure drop is proportional

to viscosity. The pressure drop equation can

be rewritten:

.........••••.•.• (2-5)

(c) Closeness and orientation of packing:

Leva, et al. (31) stated that the pressure drop

was proportional to (l-E) 2/E3 at low flow rates

and to (l~E)/E3 at higher flow rates. With this,

the pressure

t-P/L = a"

drop equation 2

(1-E) ~u + b" E3

becomes:

1-E 2 p u I I I (2-6)

(d) Size, shape, and surface of the particles:

Ergun and Orning (32) proposed that the pressure

drop is proportional to the square of the

specific surface, Sv, in viscous flow and to the

specific surface at higher flow rates. The

pressure drop equation now becomes

t:-Pg /L = 2a~S 2u (l-E) 2/E3 + c v m

(13/8)GU s (l-E)/E3 ......... I (2-7) m v The particle diameter D = 6/S is substituted

p v

into equation(2-7) and the equation becomes

~Pg (l-E) 2 ~U (1-E)GU -~c =kl 3 m2+k2. 3 m ... (2-8)

1 E D - E D p p

15

Ergun concluded that the energy loss through a pack­

ed bed can be separated into two parts, the viscous and

the kinetic energy loss. Viscous energy losses per unit

length are expressed by k1[ (1·-E )2/E3] [1-LU /D 2] and m p

kinetic energy losses are k2[(1-E)/E3] [GU /D ]. The m p friction factor f v' representing the ratio of pressure

drop to the viscous term takes the form

6-P D 2 E3 NRe f = p

kl + k2 (2-9) = v (l-E) 2 I I I I I I I

L 1-LU 1-E m Plot f vs. NRe/1-E from experimental data a solid line v

is obtained and the equation is

fv = 150 + 1.75 1-E ..................... (2-10)

Figure 3 is a logrithmic scale plot of the Ergun friction

factor.

3. Hicks (1970) (21)

Hicks proposed that the friction factor f of v

Ergun's equation is not a linear function of Reynolds

number. He suggested that in the range 300 < Re/(1-E) <

60, 000 the friction factor is ;,:ell represented by the

nonlinear relationship

f = 6.8 [Re/(l-E)]0 •8 v ' • • • • • • • • • • • • • • a • • • (2-11)

Parameters k1 and k2 of the linear Ergun equation

therefore vary with Reynolds number and are not truely

constant as is commonly accepted. Fig 4 is the compari-

son between Ergun's and Hicks' correlation.

16

..::t ...........

0 C\l 1""'1

' ct-; ~ (])

""' 0::: (]) \J)

.£ I s 1""'1 0

~ C"'1 ct-;

0 1""'1 '0

(])

~ Pi ro '0 <X:

...........

N (]) 0 0::: \J)

1""'1 ;;::: I 1""'1

rn :>

:> 0 ct-; 1""'1

C"'1

QD •r-i lit

1""'1 ..::t C"'1 N 0 0 0 1""'1 1""'1 1""'1

:> ct-;

N

"' .,-

.....

\1)

\1)

N

I P-

i rl

~

..........

. 0

;::::s

QD

:::t

P-i

<J

H

II :>

ct-i

50

00

00

10

00

0

50

00

10

00

~

A

Erg

un

's

Eq

uat

ion

,f'

/' "'

C!l

e•~

.. t·

'­~C!) ~

/

/

:,A/

/

" fl

" -

,e

" (-

]Hic

ks'

9G.4

E

qu

ati

on

C)

""\1

~,I(

J

~,

/

~

50

0

.. /-

+

10

0

.... 1

00

Fig

4

6

50

0

10

00

e W

entz

&

Tho

dos

(19

63

) e

Han

dle

y &

Heg

gs

(19

68

) •

Pec

k

& W

atk

ins

(19

56

) +

M

orco

m

(19

46

) Re

1-E

50

00

0

Co

mp

aris

on

b

etw

een

Erg

un

's

and

Hic

ks'

E

qu

ati

on

(A

dap

ted

fr

om

R

ef.

21

) f--

J --

...]

18

Two Phase Flow Pressure Drop

The manner of estimating pressure drop for two-phase

flow through packed bed can be separated into two major

approaches.

(a) Theoretical analysis but empirical correlation:

Larkins (1,4) considered each phase flow to be

through a section restricted by the presence of the

other phase. The two-phase flow pressure drop may

then be written in terms of the single-phase flow

pressure drop. Larkins used the parameter X defined

by Lockhart and Martinelli (29) to correlate the

pressure drop in two-phase flow through packed beds.

The solution is obtained by a theoretical analysis

but empirical means. Sato (16) and Midoux (8) used

the same parameter ;_ to correlate the two-phase flow

pressure drop.

Turpin and Huntington (15) used a momentum

exchange model (separated flow model) and assume that

each phase satisfied the conservation of momentum

separately and that the static pressures for each

phase are equal and constant at every cross section.

A "Z" group has been specificed as a function of

liquid Reynolds number and gas Reynolds number.

The friction factor is a cubic function of Ln (Z).

Hutton and Leung (7) presented a model in which

the two-phase flow pressure drop is a function of

19

gas flow rate in the restricted section of the bed,

and the liquid holdup is a function of liquid flow

rate and the pressure drop.

(b) Solving the modified flow model directly:

Sweeney (13) distinguished between the two

phases. He assumed that the liquid flows uniformly

over the packing surface, that both the liquid and

the gas phase are continuous, and that the pressure

drops through both phases are identical. The

fraction of void occupied by liquid is calculated by

trial and error and the two-phase flow pressure drop

is obtained by assuming single phase flow through

the void occupied by that phaseo

Clements (27) used a capillary model. The flow

in a packed bed is regarded as annular flow through

a bundle of capillary tubes. Surface tension is an

important factor in his model and the pressure drop

is a function of Weber number, liquid Reynolds

number, and gas Reynolds number.

1. Larkins (1959) (1,4)

Model:

During two-phase concurrent flow in a packed bed

each phase can be thought of as flowing in a bed

restricted by the other phase. The effective porosity

for one phase is reduced by the presence of the

20

second phase. The two-phase friction loss may then be

written in terms of the single-phase flow of liquid

in a restricted bed.

Assumptions:

1. The pressure drop for the gas is equal to that

of liquid phase and both pressure drops are

equal to the two-phase pressure drop.

2. hL is the liquid holdup, hGis the gas holdup,

E is the fraction void for the bed. Then

hL + hG = 1, and EhL and EhG are the effective

porosities for the liquid and gas respective-

ly.

The Reynolds number for the liquid may be defined as

••••••••••••••• 0 •• ( 2-12 )

The Fanning form of the friction factor is

J 2fL PL UL

(EhL)m D g p c

..................... (2-13)

The friction factor for the liquid may be expressed

in the general Blasius form as suggested for two phase

flow in pipes by Lockhart and Martinelli (29):

= [

Dll uL PL JJ ~L ( EhL)n

•.•..•...• (2-14)

21

Substitution of equation

~1 (Eh1)n = c 1 [____;;;;__-=--

Dp u1 p 1

2-14 for f 1 in 2-13 gives

3 2 PL u12 ] [---=--m~-] ..... ( 2-15)

( Eh1

) D g p c

~1 En 3 2 P1 u1

2

= c [ J [ J ns-m 1 Em D h1 •. (2-16) D u1 p1 p -p gc

The first two terms of equation 2-16 represent the

friction factor for the liquid flowing in the

unrestricted bed.

o - o h ns-m LG - 1 1 .................. (2-17)

The same procedure for the gas phase gives

oLG = oG (l-h1 )n's'-m' .................. (2-18)

Using equal exponents, that is, ns-m = n's'-m'

61 0.5

hG (s'n'-m')/2

h1 (m-sn)/2

X ( ) =[ J = = (sn-m)/2 -oG h1 (l-h1 )

............... (2-19)

The value of X can be calculated from an appropriate

single-phase correlation.

01G 1:. 2

Define ¢1 = ( o1

)

01G 1 2

and ¢G = ( oG

)

Further, it is observed that ¢1 , ¢G, and X are all

functions of the liquid saturation. Therefore, ¢1

and ¢G may be considered fQ~ctions of X alone.

22 1

0LG 2

.¢1 ( ) hL (sn-m)/2

Fl (X) .¢ G/x. . . ( 2 -2 0 ) = = = = 61 1

0LG 2

.¢G ( ) hG (s'n'-m')/2_F (X) - ¢ ..., .. (2-21) = = 6G - 2 - L'"

hL = F) (X) .............................. (2-22)

The value of .¢G becomes infinite as the gas rate goes

to zero and becomes unity as the liquid rate goes to

zero. In order to obtain a symmetric form for the

correlation, the definitions of .¢G and X may be

combined to obtain

= ........ (2-23)

Where F4 is a function which can be obtained from F1

or F2

So 6 LG is a function of X .

6 LG When log(o +6 )

1 G

is plotted against logX Fig. 5 results:

A curve fit gives the Larkins equation:

6LG Log 10 ( 6 +6 )

L G

Systems investigated:

0.416 = 2 ... (2-24)

[ (log10 X) + 0. 666]

Fluids used: water-air, methanol solution-air,

soap solution-air, ethylene glycol-

air, kerosene-natural gas, lube

oil-natural gas, lube oil-carbon

dioxide, hexane-carbon dioxide.

0 LG

oL+o

G

10

00

r-----

10

0

10

e A

ir-W

ater

a

Air

-Met

ho

cel

So

ln.

A A

ir-E

thy

len

e

Gly

col

oLG

0

.41

6

Log

lO(o

L+

oG)

(Lo

glO

X)2

+0

.66

6

h I

I ,,

l I

.AV

Y.,

1

I I ih

---

I 1 'o

X

Fig

5

Lark

ins'

co

rrela

tio

n

(Ad

apte

d

fro

m R

ef.

1,4

)

l\)

\.....

)

Packings used: J/8 in. Raschig rings, J/8 ln.

sphere, l/8 in. cylinders.

2. Sato (1973) (16)

The same model and assumptions as Larkins' corre-

24

lation have been proposed, but the symmetrical point is

%= 1.2 instead~= 1.0 as in Larkins' correlation. The

definition of 6LG is also different from what Larkins

used. Sato proposed that 6LG is the sum of static

pressure and the energy loss of elevation difference:

_.1_ + __Q_ + L + G

eeoo••••••••o•••(2-25)

·JL '2G

A curve fit glves the Sato's equation

System investigated:

Fluids used: air-water.

Packings used: 2.6 to 24 mm spheres.

J. Midoux, Favier and Charpentier (19?6) (8)

Correlations of pressure loss are proposed in terms

of the single-phase friction loss or frictional energy

for the liquid and the gas when each flows alone in the

bed. The parameters ¢Land z are defined as:

¢L = ( 6LG 6L

X ( 6L

= 6G

1 2

1 2

............................ (2-27)

) ............................ (2-28)

25 A curve fit glves .¢L as a function 0 f ~·~ .

.¢L = 1 + 1 + lol4 •••• 0 ••••••••••••••• (2-29) _, _, 0 0 54 I

/.

for 0.1 ~ X 80

The limiting cases are single phase flow of the liquid

phase and single phase flow of the gas phase,

G = 0, y_ = oo, .¢L = 1,

L = 0, " = 0, .¢L = 1/;','

Systems investigated:

Fluids used: water-air, cyclohexane-air, N2 ,

gasoline-N2 , He, co2 ,

petroleum ether-N2 , co2 ,

kerosene-air, N2 ,

desulfurized gas oil-C02 , air, He,

non-desulfurized gas oil-C02 , air, He.

Packings used: spherical catalyst 3 mm, glass sphere

3 mm, cylindrical catalyst 1.8 X 6 rnrn

and 1.4 X 5 mm.

4. Turpin and Huntington (1967) (15)

Model and assumption:

Momentum balances were written for each phase with

the assumption of a separated flow model. The total

pressure drop is expressed in terms of the sum of the

frictional pressure drop, the static pressure drop, and

the pressure drop due to acceleration of the fluids

(see figure 6).

gc(P+dP/2)dAL

DUE TO LIQUID PHASE AREA

CHANGE

/

g dF L C T

gc(P+dP/2)dAG

DUE TO GAS PHASE AREA CHANGE

--•• FORCE ----~-.~ MOMENTUM FLUX

Fig 6 Control surface for the momentum exchange model of Turpin and Huntington (Adapted from Ref. 15)

26

-(P - p ) = 2 1

For vertical flow e = 0, cos e = 1, and we can neglect

the acceleration term, so the equation becomes:

-(P2 - P1 ) = llPTPf + (1/A) (C 2AGL + PLALL + CJAGL2j2)

............ (2-31)

A area of flow

A the average area

Correlation:

The two-phase friction factor to be employed was

defined in the same manner as a single-phase friction

factor:

Where VGS is the velocity which the gas would have if it

were flowing in single-phase flow through the unpacked

conduit at the entering density PGl" D is the equiva­e

lent diameter which is four times the hydraulic radius

for the packed bed.

E

1-E ............... (2-.33)

28

For spherical particles: Vp/Sp = Dp/6, and

. . . . . . . . . . . . . . . . (2-34)

The results of a dimensional analysis of two-phase flow

with subsequent simplification shows the frictional

pressure gradient

~p

( 1 )TPf =

to be given

V2

GS PGl Ds gc

by:

•••••••oo(2-36)

Define z = N 1 · 167/N °·767 and use regresslon ReG ReC

methods to obtain

fTPf = 7.96 - 1.34 (Ln Z) - 0.0021 (Ln z) 2 +

0.0078 (Ln z) 3 . . . . . . . . . . . . . . . . (2-37)

0.2 ' 2 L 500

System investigated:

Fluids used air-water.

Packings used: 2,4, and 6 inches diameter columns

packed with tabular aluminum parti-

cles of 0.025 and 0.027 ft diameter.

5. Hutton and Leung (1974) (7)

Model and 2ssurnptions:

Assume both the liquid phase and the gas phase flow

29

continuously in the bed. Further assume that the liquid

holdup, h, in the column is dependent only on the liquid

rate, L, and the pressure gradient in the column,

(dP/dZ).

h = F1 (L, dP/dZ) ..................... (2-38)

The effects of gas flowrates on h are taken care of by

its effects on the pressure gradient. The pressure

gradient is assumed to be a function only of the gas

flowrate and holdup.

( dP ) dZ = F

2 (h,G) . . . . . . . . . . . . . ... (2-39)

The effect of liquid flowrate on ( dP ) is taken into dZ

consideration by its effect on holdup. The form of

equation (2-39) is taken as the same as the Ergun

equation for flow through packed beds using an effective

voidage available for gas flow defined as (1-c-h).

where c volume fraction occupied by solid

h liquid holdup per unit volume of column

Equation 2-39 can be written as

dP dZ = [

2 a GG v (

-G

~I a 0

·1

1 G v) J GG (l-c-h) 3

..•.•..•• (2-40)

Turpin and Huntington's experimental data were used in

developing this correlation.

6. Sweeney (196?) (13)

Model:

Assume two continuous phase are present 1n the bed.

JO The liquid phase flows uniformly over the packing surface

and both liquid and gas phase are continuous. The

pressure drops through both phases are identical.

Assumptions:

l. A pressure drop equation is available which

adequately predicts the frictional pressure drop

through the bed in terms of bed characteristics,

fluid properties, and fluid flow rates when

there is single phase flow in the system, that

lS, when the liquid or gas phase flows through

the bed in the absence of the other phase.

2. The pressure drop equation adequately predicts

the frictional pressure drop through the bed for

either phase when there is two-phase flow,

providing the presence of the other flowing

phase is taken into consideration.

Correlation:

From Ergun's equation for single phase flow:

4Pu2 6F = Ea + 4 a D~P J ............. (2-41)

gcD

The effective diameter and velocity are

D = 4 E (1-E) S

0 ' • • • • • • • • • • • • • • • • • • a • • • • (2-42)

-u = u

E . . . . . . . . . . . . . . . . . . . . . . . . (2-43)

Substitute (2-42) and (2-43) into (2-41) get

p~2 (l-E)S a~ (l-E)S0 oF= EJ 0 [~ + ] ••••• (2-44)

gc u )

Jl

Assume eL is the fraction of void volume occupied

by liquid, then

D = L

. . . . . . . . . . . . . . . . . . . . . .. (2-45)

. . . . . . . . . . . . . . . . . . . . . . . ( 2-46 )

Therefore, the frictional pressure drop through the

liquid phase is

PLuL2 (1-E)S 6' = 0 [~ +

LF eLJ EJgL

a.J.I.L(l-E)S --=---~0] • • • ( 2-47)

uL PL

Dividing by the value of oLF obtained for single­

phase liquid flow from equation (2-41), one gets

6 , LF

6 LF =

1

e J L

........................ ( 2-48 )

Assume also a gas volume factor eG, so

. . . . . . . . . . . . . . . . . . . . . . . .. (2-49)

In this case, the velocity of the gas phase relative

to that of the liquid phase is - -UG UL

UG = 8GE 9LE

-UG y

eG E .......... (2-50) =

Where

y = 1 eGuL - ....................... (2-51) eLuG

Since the liquid is assumed to flow uniformly over

the surface of the packing, the number of packing

particles is the same as in single phase flow, but

32 the effective packing volume and surface area have

changed because of the presence of the uniform

liquid film.

Now define

and

(1-E)S z2 0

z = (1 +

so that

1 3

. . . . . . . . . . . . . . . . . . . . . . ( 2-52 )

) ..................... (2-53)

2 O.!J.G(l-E)S Z 0 J

uG p G y •• ( 2-54 )

Dividing by the value of oGF obtained for single­

phase gas flow, one obtains

o'GF H =

6 eG 3

GF

Where $Y +

. . . . . . . . . . . . . . . . . . . . . . (2-55)

a.!J.G (1-E) s 0z2

H = yz2 [ uG PG J ... (2-56)

~ +

The total pressure drop through the liquid phase

is given by the combinations of friction loss and

fluid head terms for the liquid 0LF 6 'LT = 6 'LF- PL = 8G3

and, for the gas phase

phase:

. . . . . . . . . (2-57)

.33

6GFH 3

- p e G

G

. . . . . . . . .. (2-58)

It is assumed that the total pressure drop through

each phase is the same,

6 'LGT =

Since eL + eG = 1, therefore 1 1

0LF 3 6GFH 3 ( 6 1 LGT PL

) + ( 6 1 LGT ) = 1 .... (2-60) + + PG

To calculate the two-phase pressure drop, the following

procedure can be used:

1. Assume a value of eL

2. Calculate eG and H

J. Calculate a new value of eL from the relation

1 PL- PG 3

6 )]+1} ... (2-61) GF

4. Repeat steps 2 and 3 until a constant value of

eL is obtained.

5. Use equation (2-59) to calculate two-phase

pressure drop.

The modified form of equation (2-61) is assumed H = 1,

this form is to be preferred because of its simplicity. 1 1

3 + PL) J +

6GF [(6' + p )

LGT G J

3 = 1 •. ( 2-62)

34 System investigated:

Fluids used: N2co3 solution-air, CaC12

solution-air

and fluids used by Larkins et al.

Packings used: Berl saddles 1 in., lt in., tin.,

Intalox saddles 1 in., lt., tin.,

packings used by Larkins et alo

7. Clements (1980) (27,28)

Model:

Assume the packed bed may be treated as a bundle of

capillaries, each containing equal fractions of the

overall gas and liquid flows. The capillary dimensions

are function of the particle size, the bed void fraction,

and the particle shape; (Fig. 7)

Assumptions:

lo The frictional pressure drop contributions of

the liquid to the overall pressure drop are

negligible.

2. Neglect gravity effects in the liquid phase.

J. The overall pressure drop across the region of

interest is low enough that gas phase properties

may be taken as averages of entry and exit

values.

4. No slip at the gas-liquid interface.

5. At any point, Z, there is axial symmetry.

With these assumptions the liquid equation of motion is

35

...-... CX)

'0 C\l .,..; ::s t::r

.,..;

.

.....:l

('-

-r

r-1 C\l

H

Q)

~

'0 •

t 0 Ii-i s ~ ~ s

(/)

~ 0

ro

ro ~

eJ

r-1'+-i r-1 .,..; '0

()

P..Q)

~

ro~ () p..

'0

a> ro ..c:'O 8.::s .,..;

_L ::s t::r

.,..; .....:l

C'-

QD .,..; li-t

36

o UzL PL uzL ( o z ) =

-IJ.L o auZL r [ o r (r a r ) J · · · · · (2-63)

Let 3 = Z/L

-rr = r/R

uL= uzL/m/n(R2- ri2) PL

to get the dimensionless expression

l l o o UL R~ L [ ( -17- a.;) ( '7 o. -ry ) J . . . . ( 2- 64 )

Where 2 2 2 = ~ /[ nL(R - r 1 ) IlL]

For the gas phase

=

Therefore,

v1here

- (

aP

az

. . . . . . . . . . . . . . . . .. (2-66)

If we require that a equilibrium exist at every point 1n

the capillary between the pressure exerted by the gas

phase and the restoring surface force exerted by the

liquid phase.

P (Z)gas = [a/rr(Z)] liquid . . . . . . . . . . . .... (2-68)

Taking derivatives of this equation

aP =

- o o r 1 -~2 ( ) ····················· (2-69)

r 1 o 3

37

Substitution of equation (2-69) into (2-67)

a 1 1 a UG a ri a uG UG ( a l'j ) = -A a ! - ReG

-( ~1') a 1': ) •• (2-70) 'I] I

where

The liquid holdup is

Ho = (R2- ri2)/R2 .......................... (2-71)

So, a ri R2 a H a ~ - - 2r I ( a ~ 0

) . . . . . . . . . . . . . . . . . . (2-72)

And equation (2-70) becomes

1

we G

It is assumed that

ReGWeG

a H 0

a n J

1 1

p~G -Y!-o a uG

[ a1J (11 a Yl ) J ......... (2-73)

H = f ( 0 ReL ) . . . . . . . . . . . . . . . . . . . . . . . (2-74)

From the assumptions, the two-phase flow pressure drop

must equal to both gas and liquid single phase pressure

drop, therefore

- ( ~p 6P ~p I

~L )TP = - ( ~L )G = - ( ~L )L = (Wf P)TP ......... (2-75)

From the Blasius form of the friction factor

and from the Brownell and Katz friction factor

n/ 2 fG = 2~PG DPEG ~LuG . . . . . . . . . . . . . . . . . . . .. (2-77)

Eliminate fG

(Wf P)TP

from equation (2-76) and (2-77)

= CG [

= c [ G

IJ.G(EHG)m s pGuG

2

J [ J Dp PG 2(EHG)nDPgc

II -cffi S 2 ~G ~ J [ _PG;;;._.u...;;;.G __

DPPG 2EnDPgc

(ms-n) J HoG

38

= WfG (HoG)-x . . . . . . . . . . . . . . . . . . . . (2-78)

There ( 6P )LG/( 6L

From the silicone-air two phase flow experimental data

Clements and Schmidt (27) obtained the expression

( 6p ) /( ~p )G = 190 D ( 6L LG 6L UL P

. . . . . ... (2-80)

System investigated:

Fluids used : air-silicone oil.

Packings used: Sphere 1.6 mm, 3 mm.

Extrudate 0.8 mm.

CHAPTER III

THEORETICAL ANALYSIS

Energy Balance

The general energy balance in a flow system is

2 J VdP + ~u + ~z· + wf + w = o ......... (3-1)

gc s

where v is the specific volume per unit weight, u is the ~u

2 velocity, 2g lS the kinetic energy difference due to

c changes ln velocity, z is the vertical distance and ~z

indicates the potential energy difference, wf is the

energy converted into heat by friction, and W is shaft s

work done on the surrounding by the system. W lS zero s

for two-phase downward flow. The velocity difference is

usually small over the column.

( velocity = volume flow rate/cross section area,

volume flow rate = liquid mass flow rate

liquid density

+ gas mass flow rate

gas density

In the flow system liquid mass flow rate and gas mass

flow rate are constant either on the top or bottom

section. The density of liquid is constant, but the

gas density varies with pressure. So, if the column

is short, the pressure difference is small, and we may

gas density varies only slightly.

term is very small.)

39

Hence the

Equation (3-1) can be written as

J VdP + ~z· + wf = 0 . . . . . . . . . . . . . . . . . . . . . . Using specific volume V as the inverse of specific

density

1 v = Pm

Equation (3-2) becomes

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

40

(3-2)

(3-3)

~ __ dP + ~z' + w f = o . . . . . . . . . . . . . . . . . . . . . . . . ( 3-4) m

Assume p is constant and integrate the first term, m

~P + ~z· + wf = o m

. . . . . . . . . . . . . . . . . . . . . . . . . . . . Divide by ~Z and rearrange

• 0 • • • • • • • • • • • • • • • • • • • • • • • • ••

Let ~Z'= -~Z (change sign because we want downward

direction to be positive)

. . . . . . . . . . . . . . . . . . . . . . ..

(3-5)

(3-6)

(3-7)

is the measured pressure drop per unit length over

the column.

~p + p - ~z m ••••••••••••••••••toot {3-8)

oLG is the total energy required to overcome friction

per unit length downward through the packed column.

Larkins ( l, 4), and Turpin ( 15) regard Pm as h P1 + ( 1-h) PG,

where h is the liquid holdup. Sato(l6) regards p as m

(L+G )/ (1/ P1 + G/ PG). In this correlation pm is equal to

41

(L+G )/(L/ .-·1 + G/ ... G), because the specific volume per unit

weight is

V = (~ + ~)/(L +G) __,L ~""G

and ~m is the inverse of V (Eq. 3-3).

Model

In this development, two models are considered. The

first one is the capillary flow model describing viscous

flow and the second one is a capillary seperation flow

model describing kinetic flow.

1. Viscous flow

Capillary flow model: (Fig 8)

Treat the packed column as a bundle of capillary

tubes. The liquid flows laminarly along the wall of the

capillary and the gas also flows laminarly through it in

the center.

The diameter (D ) of the capillary is assumed to be c

equal to the effective diameter, De' of the packing.

D = D = effective diameter c e = 4 wetting volume/ wetting area

= 4 E/(6(1-E)/Dp) 2 E

= 3 Dp ( 1-~ )

The equation of motion for both liquid phase and gas

phase is

~L (--a--(r a uzL)) r or a r

a P az .•..• (3-9)

/ 42

D c ' ' ~I '

Liquid Gas Liquid " " L G L

wall wall

' " ' " ' '

~ I v I

I

I

I v I

I

I

" I v I v ' ~ .. ...... w,... v

velocity profile

Fig 8 The capillary flow model

Assume the vertical velocity gradients are zero, although

gas density is different for the top and bottom section

and the velocity is also slightly different. The

equations become

~1 a a ---r- (-ar (r a

a P az

~G ( a (r a uzG)) = r ar a r

a P a---z

B. c. 1 r=r uz1=o c

B. c . 2 r=r I Uz1=uzG

B. c . J r=r I -r1=-rG

B. c. 4 r=O -r -o G-

............... (J-11)

··············· (J-12)

To solve equations (3-11) and (J-12)

define ~ r = r c

* * u - uzG/(G /PG) G-

* * u = uzrl (1 I P1) 1

* Z/rc z =

* G = mass flow rate of 2 gas lb/ft .hr

* of liquid lb/ft2 .hr 1 = mass flow rate ~~ ..

P/Patmosphere p =

The dimensionless forms of Equations (J-11) and (J-12)

are * aP ~ az

·············· (J-13)

44 * aP ~ az

............. (3-14)

B. C. 1 3=1

B. C. 2 * L i .. G UL = UG

PG PL ·n· *

B. C. 3 IlL L auL PLaT

= !lG G auG PG aT

B. C. 4 3=0

* * 2 EuL is the Euler's number of liquid, P atm PL/ (L )

* * 2 EuG is the Euler's number of gas, p atm PG/(G )

* * ReL is the Reynolds number of liquid, L De/IlL

* * ReG is the Reynolds number of gas, G Dc/!lG

* * * EuL ReL Define KL=

ap ---:'i' 2 az

* * * EuG ReG and K =

ap G * 2 az

Substitute KL and KG into Equations (3-13) and (3-14),

and integrate twice to get

* 1 32 UL = 4 KL + cl Ln 3 + c2 ............. (3-15)

and

* 32 3 u - 1 KG + C3 Ln + c4 G - 4 ............. (3-16)

Apply B. c. 4 to get c =0 3

Apply B. c. 3 to get c =0 1 Apply B. c • 1 to get C2=-iKL

45

Substitute c1 , c2 , c3 , and c4 into Equations (J-15) and

(J-16) to get

The

gas

U ~ = i K1 ( ~ 2

-1 ) . . . . . . . . . . . . . . . . . . . . . . . . . . ( J -1 7 )

conservation of mass equations for both liquid and

are . . * r

Liquid: 1 2 =! c u12'1"JT dr I I 1 1 1 1 I I I 1 I I I I I (J-19) - nr P1 c ri

Substitute UL into (J-19) and the equation becomes

t = ..................... {J-20)

Substitute (J-17) into (J-20) to get 1

t = J s i K1 ( ~ 2 -1 ) ~ d ~ . . . . . . . . . . . • ( J-21 )

Integrate (J-21) to get

2 KL

= -i

Solve (J-22) to get

2 -8 )t s = 1 - (~-KL

................. (J-22)

................... (3-23)

K1 is negative by previous definition, and S is

always less than 1.

* G 2 Gas: -- nr PG c

ri = !0

uG 2nr dr ................ (J-24)

46

Substitute uG into (J-24) and the equation becomes

* s 2 2 2 L PG t= /

0 [iKG~ -iKGS +iKL(S -1) * ]~ d~ ... (J-25)

G PL Integrate (J-25) to get

* 1 l 4 l 4 l L PG 2 2 2 =f6KG S - 8KG S + 8KL ( -lt- ) S ( S -1 ) ...... , ( J- 2 6 )

G PL

From the definitions of KL and KG the following

expression can be obtained

* f.l.G G PL

* ...................... ( 3-2 7)

f.l.L L PG

Substitute (J-27) into (J-26) to get

f.J.L is usually much greater than f.J.G' neglect the

smaller term to get

! = s4(- ftKG ) - ~KGS2 ~~ ............. (J-29)

Substitute s2 (J-2J) into (J-29), and neglect the

smaller term to get

1 KG l l ( - 8 ) t t = 2 K - IbKG + 8KG K

L L ............ (J-JO)

Define w=KG/KL and substitute into (J-JO) to get

t = ............. g.(J-31)

Solve (J-Jl) to get l.

-KL = 8 + 8/w + l6/w2 .•...........••.•.• (J-32)

47

From the preVlOUS definitions

* i}

* Eu1 Re

1 D iJ -KL=

aP ap c L i~

~ = - Re1 ooooo(3-33)

az 2 az (L~l-)2

so,

•o•••••••••••••••••(J-J4)

Substitute

* Re 1 = Rer/(1-E)

De=Dc= ~ DpE/(1-~)

* L = L/E

...... (3-35)

From this mathematical model, the two phase concurrent

flow pressure drop equation has the following form,

0 ...... (3-36)

1n the viscous flow portion. The coefficients A1 , A2 ,

and A3

are constants.

2. Kinetic flow

Capillary separation flow model: (Fig. 9)

In the turbulent flow region, the fluids are

considered to flow in a separation flow model, that 1s,

the liquid phase and the gas phase flow separately. In

the center of the capill~y tubes, the liquid and gas

flow at the same velocity u1 . Near the wall of the

A. Partial capillary separation flow D

velocity profile

~

L

J

*

R

~

c

Liquid

G*

1r Gas t Liquid

Gas I r1-~t

'

B. Total capillary separation flow

velocity profile

u II

Liquid

Gas

Liquid

Gas

, ,

L~ t * ~ G "

L ~

,

¥

u

ull=

II

Fig 9 The capillary separation flow model

48

49

capillary tubes, the liquid flows along the wall with

velocity u2 , and the thickness is t. When both the gas

and the liquid flowrates are too low, the amount of liquid

in the center is very small and this is the capillary flow

model. When both the liquid and the gas flowrates are

high enough, u2 is very small compared to u1 , and the

thickness near the wall is very small too. Under this

assumption, the liquid and the gas will flow at the same

velocity u".

Lerou, Glasser, and Luss(22) used this model to

describe the pulsing flow. Originally this model was

used to study the effect of axial dispersion. Here, the

pressure drop effect is of interest in this model.

For the partial separation model, assume the liquid

flows laminarly near the wall. The velocity profile

in a tube for laminar flow is

oF R2 1-( r )2] uz = - az 4u

1 [ R ........... (3-37)

at r=r 1 * *

u" _1_+ G uz = ul ~ =

PG PL so,

2 (u ) = - oF .JL [l-(Rr)2] ~ u" ....... (3-38)

z 1 az t.ru1

rearrange and multiply by L2P1 /L2P1

aF az =

u" 4u1

R2[1-(r1/R) 2J

2 ~ QLU" 2 =(4L _1 L )/[1-(rl/R) J

PLR RL

= 72(1-E) 2L2

E2

PLDpReL

50

1 ... (3-39)

G PL . LP ls much greater than 1 and r 1 is nearly equal to R,

G

so Equation (3-39) can be rewritten as

The thickness of the liquid, t, increases when the liquid

volumetric flowrate increases or the gas volumetric flow-

rate decreases. From this we can say that t is a

function of G 9r/L ~h.

Equation (3-40) becomes

Define

ap az

The Reynolds number of

D u"P " ReL = e L ~L

=

............ (3-41)

................ (J-42)

the liquid at the center is @

2 ReL

3 1-E ................. (J-43)

The pressure drop caused by gas friction lS small

51

compared to the pressure drop caused by liquid friction.

So, the gas term has been neglected. The pressure drop

ln a turbulent flow is proportional to the n-th power

of the Reynolds number, based on

Re@ _ oP ot:.R "nat..( L )n az eL 1-E

Combine (3-41) and (3-44) get

Taking

oP az =

boundary layer theory.

............... (J-44)

GPL LP ) ••••• ( 3-4 5)

G

= ( !::.ZP) . + ( ~zp) k. t. . .... ( 3-46) !::. VlSCOUS u lne lC

At laminar flow (6P) is very small compared t::.Z kinetic

to (~~)viscous and Equation (3-36) is equal to (~~)TP'

At turbulent flow,

t::.P to (AZ)k. t· and

u lne lC

(~2P) . is very small compared u VlSCOUS

Equation (3-45) is equal to (~~)TP"

In the transition zone, both (~~)viscous and (~~)kinetic

are important.

Combine (3-8), (3-36), and (3-45) get

The constants A1 , A2 , A3

and the function F will be

determined in Chapter IV.

CHAPTER IV

CORRELATION AND DISCUSSIONS

Data Characteristic

Experimental data from four investigators have been

used in developing this correlation. Larkins(4) collected

his data in 1959 for his Ph.D. dissertation and 555 data

points have been used from his data set. Clements(27) col­

lected silicone oil-air data in 1975 for Chevron Research

Company and 279 data points are used from his report.

Halfacre(26) collected his data in 1978 for his Master's

thesis and there are 531 data points listed in his thesis.

Weekman(25) collected his data in 1963 for his Ph.D. dis­

sertation and there are 183 data points used. Turpin(30)

collected some data in 1965 for his Ph.D. dissertation.

His data were not included because the calculated single

phase pressure drop from Ergun's equation is higher than

experimental two phase pressure drop.

In all, there are 1570 nonfoaming data points which

have been used in developing this correlation. Table III

shows the characteristic parameters of these data.

52

Tab

le

III

Ch

ara

cte

rist

ics

of

Tw

o-P

hase

P

ack

ed

Bed

P

ress

ure

D

rop

Dat

a U

sed

Dat

a S

ou

rce

Sy

stem

P

ack

ing

D

iam

eter

Vo

id

Am

ount

L

iqu

id

Liq

uid

S

et

ft

Fra

cti

on

o

f D

ata

Vis

co

sity

D

en

sity

cp

lb

/ft3

1 C

lem

ents

S

ilic

on

e-A

ir

Sp

her

e 0

.00

52

0

.38

8

42

1.3

9

53

.5

2 C

lem

ents

S

ilic

on

e-A

ir

Spfi~re: · ~

-0

.00

52

0

.38

8

45

4

.62

5

7.6

3 C

lem

ents

S

ilic

on

e-A

ir

Spflere~·

0. 0

096

0.3

18

8

7

4.6

2

57

.6

4 C

lem

ents

S

ilic

on

e-A

ir

Ex

tru

date

0

.00

34

0

.36

1

36

1.3

9

53

.5

5 C

lem

ents

S

ilic

on

e-A

ir

Ex

tru

date

0

.00

34

0

.36

1

69

4

.63

5

3.5

6 H

alf

acre

W

ater

-Air

S

ph

ere

0.0

2

0.3

7

93

0.8

9

62

.l2

7 H

alf

acre

W

ater

.IP

A(3

%)

Sp

her

e 0

.02

0

.37

Z

4 1

.0

61

.5

-Air

8 H

alf

acre

W

ater

.IP

A(4

%)

Sp

her

e 0

.02

0

.37

54

1

.05

6

1.4

-A

ir

9 H

alf

acre

W

ater

.IP

A(9

.5%

) S

ph

ere

0.0

2

0.3

7

39

1

.34

6

0.8

-A

ir

10

H

alf

acre

W

ater

.IP

A(l

l.5

%)

Sp

her

e 0

.02

0

.37

42

1

.46

6

0.8

-A

ir

11

H

alf

acre

W

ater

.IP

A(2

0%

) S

ph

ere

0.0

2

0.3

7

33

1.9

5

59

.9

-Air

\...

1\

\..U

Tab

le

III

(co

nti

nu

ed

)

Dat

a S

ou

rce

Sy

stem

P

ack

ing

D

iam

eter

Voi

d A

mou

nt

Liq

uid

L

iqu

id

Set

ft

Fra

cti

on

o

f D

ata

Vis

co

sity

Den

sity

cp

lb

/ft3

12

Half

acre

W

ater

.IP

A(4

8%

) S

ph

ere

0.0

2

0.3

7

42

2. 9

8 5

6.1

-A

ir

13

H

alf

acre

W

ater

.IP

A(4

%)

Sp

her

e 0

.01

0

.34

1

5

1.0

5

61

.4

-Air

14

H

alf

acre

W

ater

.IP

A(9

%)

Sp

her

e 0

.01

0

.34

27

1

.34

6

0.9

-A

ir

15

H

alf

acre

W

ater

.IP

A(l

9.5

%)

Sp

her

e 0

.01

0

.34

42

1

.94

6

1.4

-A

ir

16

H

alf

acre

W

ater

-Air

S

ph

ere

0.0

1

0.3

4

54

0.8

9

62

.12

17

H

alf

acre

W

ater

.IP

A(4

8%

) S

ph

ere

0.0

1

0.3

4

54

2. 9

8 5

6.1

-A

ir

18

H

alf

acre

W

ater

.IP

A(1

.5%

) S

ph

ere

0.01

1 0

.34

1

2

0.9

1

61

.7

-Air

19

W

eekm

an

Wat

er-A

ir

Sp

her

e 0

.02

12

0

.43

62

0

.9-1

.0

62

.4

20

Wee

kman

W

ate

r-A

ir

Sp

her

e 0

.01

55

0

.39

56

0

.9-1

.0

62

.4

21

Wee

kman

lr

J2.t

er-A

ir

Sp

her

e 0

.01

24

0

.37

8

65

0.9

-1.0

6

2.4

22

Lark

ins

Wat

er-A

ir

Ras

chig

0

.01

94

5

0.5

2

272

1.0

6

2.4

R

ing

\..

J\

+=-

Tab

le

Data

S

ou

rce

Sy

stem

P

ack

ing

S

et

23

L

ark

ins

Meth

ocel

So

lu-

Rasc

hig

ti

on

-

Air

R

ing

24

L

ark

ins

Eth

yle

ne

Gly

co

l R

asc

hig

-A

ir

Rin

g

25

L

ark

ins

Eth

yle

ne

Gly

co

l S

ph

ere

-A

ir

26

L

ark

ins

Wate

r-A

ir

Sp

here

27

L

ark

ins

Wate

r-A

ir

Cy

lin

der

28

L

ark

ins

Meth

ocel

So

luti

on

Cy

lin

der

-Air

29

L

ark

ins

So

ap S

olu

tio

n

Cy

lin

der

-Air

IPA

:

Iso

pro

py

l A

lco

ho

l

III

(co

nti

nu

ed

)

Dia

mete

r V

oid

A

mo

un

t L

iqu

id

Liq

uid

ft

Fra

cti

on

o

f D

ata

V

isco

sit

y D

en

sity

cp

lb

/ft3

0.0

19

45

0

.52

5

4

12

.0-1

4.0

6

2.4

0.0

19

45

0

.52

6

5

12

.0-1

7.0

6

9.5

0.0

31

25

0

.36

2

62

1

2.0

-17

.0

69

.5

0.0

31

25

0

.36

2

. 4

4

0.8

-1.0

6

2.4

0.0

10

4

0.3

57

3

4

0.8

-1.0

6

2.4

0.0

10

4

0.3

57

1

2

2.0

-2.9

6

2.4

0.0

10

4

0.3

57

1

2

0.8

-1.0

6

2.4

\..n

\.

.n

56 Correlation of Experimental Data

It is the objective of this section to find out what

coefficients(A1 , A2 , A3

) are and what function F is in

equation(J-47). To achieve this, assumptions and preliminary

calculations must be made.

1. Assumption

1. No mass transfer between the liquid and gas phase,

so that the liquid flow rates and gas flow rates

remain constant.

2. No heat transfer from the surroundings and no heat

transfer between the two phases, so that throughout

the column the temperature is constant and liquid

temperature is the same as gas temperatureo

J. The gas density is assumed to be constant in the

column. The density is calculated at the average

pressure between two measured points.

4. The velocity along the column is constant for both

liquid and gas phases.

2. Preliminary calculation

lo Calculate the experimental average pressure

pav = (Ptop + pbottom)/2

2. Calculate the average gas density

:·hav = p avM/RT

J. Calculate the true pressure drop

0LG =-( ~~)observed+ (L+G)/(L/~L + GjpG)

57 3. Correlation

Equation(3-47) is the basic form of two phase flow

pressure drop. Define friction factor fTP as

fTP=6LGt:3 r-L DPReL/ (L 2 ( 1-E) 2) .............. ( 4-l)

combine (3-47) and (4-l) get 1 GP1 fTP=A1 + A2/w + A3/w2 + F(Re1@/(l-E), JGL) .. (4-2)

fTP= fv + fk ............................. (4-3)

fv: Viscous friction factor 1

= A1 + A2/w + A3/w~ fk: Kinetic friction factor

G~ = F (Re1@/(l-E), , ~)

:"G Kinetic portion:

In turbulent region fv is very small compared to fk.

fk is a function of Re1@ and G?1/JGL and we will empirically

determine what this function is in this section.

From equation (3-~)

- :~ e£ (Re1@/(l-~) )n .................. (3-43)

So, in turbulent flow region

fTP=fv + fk ~ fk o-: (Re1@/(l-~) )n .......• (4-4)

Fig. 10,11,12,13 are plots of the calculated results from

the data. The calculated values of Log(fTP) are shown

plotted against Log(Re1@/(l-~)) at constant volume ratio

( GP1/ PGL).

For higher values of Re1@/(l-E) the graph is linear and

the slope is 0.8. In fig. 10,11,12,13 the volu~e ratio is

different but the slope is the same. So, in turbulent flow

.........

.........

N ,....

.., \J

) I rl

....,.

C\J t--=

1 ....

,. "'-

-.. t--=1

0..

t--=1

Q)

~

~P-t

C'\

\J

) CJ H

<0

....

,. QO

0 t--=1

12

10

Tra

nsi

tio

n

zon

e 8

" "'

/

/ ;

; ,

/

·'

, 6

/

/

4 4

6

Fig

10

G

PL

/L P

G in

th

e

ran

ge

• •

A

n/

o

0

8

17

0

to

200

Tu

rbu

len

t re

gio

n

A

slo

pe=

0.8

A

Lark

ins

' d

ata

0

Half

acre

's

data

Wee

kman

' s

data

X

C

lem

en

ts'

data

·10

6

Log

ReL

@/(

1-E

)

\..n

(X)

,-..

. ,-

...

N ,-

...

\J) I

r1

....._..

N H

.._

_. "'-

.. H

0..

H

Q) ~

C'\

\J

) 0 H

c.O

.._

_. QD

0 H

12~----------------------------------

10

8

4

Tra

nsit

ion

zo

ne /

/

/ /

/

/

A o o~-·

0 ty

0

'/..

/,.,

,..

0 0

/ 0

Fig

ll

G P

L/L

Pa

in th

e

ran

ge

0 ll

0 0

90

to

11

0

Tu

rbu

len

t

slo

pe=

0.8

A

Lark

ins'

data

o

Half

acre

's

data

Wee

km

an's

d

ata

X

C

lem

en

ts'

data

Lo

g R

eL@

/(1

-E)

\.n

\.

()

,--.

.. ,-

-...

N ,.-

....

w I r-1

.........

N .....

:! .....

.... ~

a... .....

:! Q

) p:

; ~P-i

(Y

"'\ w 0 .....

:! cO

.....

.... b.O

0 .....:!

12~----------------------------------

Tu

rbu

len

t re

gio

n

10

0

• A

bP

A

o

. 0

__

,-0

Tra

nsi

tio

n

zon

e •

81-

~,

~ A

,,

p

d

" t

'I. ~

0 ~"

0 /

" /

/

/ /

6~

/ /

, /

A

Lark

ins'

d

ata

0

Half

acre

's

data

Wee

kman

's

data

t

Cle

men

ts'

data

I

4 4 6

8 10

@

L

og R

eL

/(1

-E)

Fig

1

2

G P

L/L

Pa

in th

e

ran

ge

. 40

to

50

~

. 0

,........

.,........

N

.,........

\1

) I rl

......_..

..

N ....

:! .....

._....

12

r---------------------------------------------

Tu

rbu

len

t

~

10

dA

A

A

Q ....

:! Q

)

p:::;P

-t j:

:l

(Y\ \1

) 0 ....:!

<0

.....

._....

till

0 ....:!

Tra

nsit

ion

zo

ne

8 4

l ~ A

A o

-- 9 .b

V4

/ 0

,. ..

/

6 /

/

/ ,

, /

/

A

A

AA

4

4 L

ark

ins'

data

o

Half

acre

's

data

Wee

km

an' s

d

ata

X

C

lem

en

ts'

data

4 I

4 6

Fig

1

3

G(J

L/ P

aL

in

the

ran

ge

8

?.5

to 1

2.5

10

L

og

ReL

@/(

1-E

) 0'.

f-

J

62 region the friction factor fk is a linear function of

(Re1@/(l-E)) 0 · 8 • This correlation matches with Hick's(21)

correlation for single phase pressure drop through a

spherical packed bed, the power of Re/(1-E) is also 0.8 for

turbulent flow. It is easy to see that for turbulent flow

Re1 @

0.8 GP1 f - ( ) Fk( (fL ) •• I I • e e e e I e • I I I I ( 4-5) k- 1-E 0

G

In Fig. 10,11,12,13 the transition point is at @ h @

Log(Re1 /(1-E)) about equal to 7, that is, Re1 /1-E ~ 1100.

The liquid flow is turbulent when Re1@ / (1-E) > 1100. When

Re1@/(l-E) ~1100 the flow is in transition zone or laminar

flow. To distinguish between the laminar flow and the @

transition zone is very difficult, because for Re1 /(1-E)

< 1100 two conditions can exist: (1) the liquid flow is

la~inar and the gas flow is turbulent (2) both the liquid

flow and the gas flow are laminar. In the first condition,

the flow is in the transition zone. In the second condition,

the flow is described by the capillary flow_model. an~ w~is

the important variable. It is very difficult to say at what @

value of Re1 /(1-E) the capillary flow will truly fit the

flow.

Fig. 14 and 15 are plots of Log(fk/(Re1@/(l-E)) 0 ' 8 ) vs.

Log(Gp1/pGL). Fig. 14 is a plot for both spherical and

cylindrical packings. Fig. 15 is a plot for Raschig ring

packings. Both curves are hyperbolic curves. For Raschig

ring packed beds, the geometry of the particle is less

smooth and it causes higher pressure drops. Accordi!}:g-to

5 .,

-...

I I<D .

0 .,

-...

.,-

...

\J.J

P,l I

4 8

8

G-i

"'- @ t--=

1 <

I)

IX:

1-- -- t:U

J 3

0 t--=1

2 1

'I. •

){

:>e ......._

. 0

0 0

• 0

0

0 0

o o

o o

• )(

oo

oo

o

• 0

0

0 1

2 3

Fig

1

4

Sp

heri

cal

and

cy

lin

dri

cal

pac

kin

gs

4

!J L

ark

ins'

d

ata

o

Half

acre

's

data

Wee

kman

's

data

t

Cle

men

ts'

data

0 0

0 0

0 0

• 0.

• oo

/

0 ;:.

..---

0

41 0 5

0

6

Lo

g

r('G

pL/L

PG)

~

I.....V

ct1 ~

+'I ct1 '0

00 ~

•rl ~

S-.1 ct1 H

( e·o< (3-T)/©'IaH)

dili~ ) ~0'1

'1.1\

C\l

0 ~

64

.,-.... ~

a.

~ o..H ~ ...........

QD 0 H

Larkins' (4) correlation, the friction factor is different

for different packing shapes when calculating the single

phase pressure drop. After regression, the best fits for

the curves in Fig. 14 and 15 are:

For spherical and cylindrical packings:

65

GPL 2 Log Fk= 1.60+0.109(Log(p L)-2.9) ................ (4-6)

G

Substitute into Re @

(4-5)

f = ( L )0.8 k 1-E

GPL 2 . Exp(l.60+0.109(Log(p L)-2.9) ) ... (4-7)

G

For Raschig ring packing:

GPL 2 Log Fk= 2.10+0.109(Log(p::y;)-2.9) ................ (4-8)

G

Substitute into R @

(4-5)

f = ( eL )0.8 k 1-E

GPL 2 • Exp(2.10+0.109(Log( p L)-2.9) ) ... (4-9)

G

Viscous portion

For the laminar flow region, w is the most important

group which influences the pressure drop. w is defined as _.1..

(LPGuL)/(PLGuG). Fig. 16 is a plot of fv vs. w 2 for

ReL@/(1-E) less than 50. Since there are no Raschig ring

packing low Reynolds number data, the viscous portion cannot

be correlated.

For spherical packings:

fv = fTP - fk ••................................. (4-10)

fTP is calculated from equation (4-1)

fk is calculated from equation (4-7)

The curve in Fig. 16 is hyperbolic. After regression, the

following equation was obtained.

f v

Th

is co

rrela

tio

n

10

00

L

-----

Th

eo

reti

cal

valu

e

'I.

500

30

0

--, __

_

0 0

o.s

Fig

16

@

R

eL /(

1-E

) le

ss

than

50

1.0

y.

,;

, ~

,.

,. ,

.... .,. - t C

lem

ents

' d

ata

1.5

1

( G P

Lf! c

/L p

Gil

L)

2

~

~

1 fv = 300 + 240/w + l20/(w2) It I 1 1 1 I I I I I I I I I It (4-11)

The theoretical value of fv for capillary model (3-35) is 1

fv(theoretical) = 72 + 72/w + l44/(w2) 00 0. ooo (4-12)

The theoretical value is smaller than the experimental

value, because in a packed bed there is no capillary tube

67

at all. The flowing path of fluids in a packed bed can not

be straight. In this case, the fact that the experimental

value of fv is higher than the theoretical value is not

surprising.

Result of Correlation

Fig. 17 and 18 are plots of Log((fTP-fv)/Fk) vs. @

Log(Re1 /(1-E)) for all data. fTP is defined in (4-l),

fv is calculated from (4-ll), and Fk is calculated from

(4-6) or (4-8). From Fig.l7 and 18, the pressure drop for

two phase flow in packed bed will be:

For spherical and cylindrical packings:

oLG= 12

(l-E)2

[(300 + 240/w + 120/(w!) + E3PLDPRe1

ReL@ 0 8 Gi 2 ( l-E) .. Exp(l.60+0.109(Log(;GL)-2.9) )J ... (4-13)

For Raschig ring packing:

L2 (l-E) 2 0LG= 3 [(fv(Raschig ring)

E p1 DpRe1

+

@ ReL 0.8 G? 2

( l-E ) . Exp(2.10+0ol09(Log(?G~)-2.9) )] ... (4-14)

f (R h" . ) cannot be determined in this correlation v asc 1g r1ng

for lack of experimental data. If we assume that

,.........

~

~

........

.... :>

't-t I P-1

E-

1 't-

t .....

.....

..........

QD

0 .....

:!

10

------------------------------------------------------------------~

8 6 4 2

)(

2

• o

t•••

o

•• •

••

A

Lo

g(

(fT

P-f

)/

Fk

)=0

.8

Lo

g( (R

eL@/

(1-f

:)~

~ 00•\•

iAo

4 °

v 0

••• o

. 0

00

. 0

0

"

• • ••

•o•

o!

•o

o,\

\o

o 0

·~

oflr

l' I•

•o

• o

o o

o.

• •

•o

A

.J~f"lo

laA

AA

10C

1l )(

lC •

.A4

AA

A o

0 11

"' K

x

'( •

• o

o A

!'.a

o o

". .

'.

-J(

J0C

¥W

cJO

C

• 1

lA4

66

0 .1

( 1t

lC

JtX

)Clt

'IC

lt)(

JC

)(O

A4

° A

)(

tx

--~t~A

lo

o .4

o A

'1.

)(

JCoJ

I A

A

A

• JC

JC

o

••l1

•4

""

~ 0

K

l(JC

.k

'l&y

.~ll

• •

-~,.,...,..,.

"""~-"

"' 'I.

.,. .,...

,. 'I..

4 6

8

!J. L

ark

ins'

data

o

Half

acre

's

data

Wee

krna

n' s

d

ata

X

Cle

men

ts'

data

10

L

og

(R

eL@

/(1

-E))

Fig

1

7

Sp

heri

cal

an

d C

yli

nd

rical

Pack

ing

s 0

'\

(X)

ctl .p ............ ctl 0 -"d ,.., IJ.)

I ,.., CJ) ......... ~ " •r-i @J

.X: .....:l ~ Q)

ctl 0:: .....:l .........

<l QD 0

.....:l

co

.............

............. \.L' '<I~

I ,.., .........

" @) .....:l

Q)

0:: ......... QD ~

QD ·r-i 0 .X:

.....:l 0 ctl

co P-!

0 II

QD ~

............. •r-i .X: 0::

li-4

" .............

QD •r-i

:> G-t

..c: 0

I P-i 8

CJ)

ctl 0:::

G-t ......... ......... co ,..,

QD 0

.....:l QD •r-i

C\l li-4

co

70

f (R h" . ) is equal to f ( ) the error l·s v asc lg rlng v sphere very

small for turbulent flow, because fv is very small compared @

to fk. When ReL /(1-E) > 500 the assumption is valid.

Equation (4-13) and (4-14) are valid for 2 < G,\/;GL- 600.

Discussions

l. Accuracy of this correlation

In this correlation the average error and absolute

error have been calculated.

l N average error = - ~

N l predicted value - experimental value

experimental value

absolute error= 1 ~, predicted value -experimental value N 1 I experimental value

For the data without Larkins' spherical packing data, the

average error is -0.837%, the absolute error is 21.67%.

The prediction value of Larkins' spherical packing data was

much higher than the experimental value. This will be

discussed later. If all the data were included, the average

error is 2.1% and the absolute error is 23.6%. The standard

deviation is 25.3%.

2. Comparison with correlations ln literature

The models and correlations in literature have been

described in Chapter II. Table IV is the comparison of all

correlations. We can see clearly from the table that the

new correlation developed here is generally better than the

other correlations. Fig. 19 is the error distribution

curve. 53% of the data are within 10% error, 69% of the

data are within 20% error, 82% of the data are within 30%

71

Table IV

Comparison of Correlations

A. Error (%)

~!~a(Table III) 1 2 3 4 5 6 Amount 42 45 87 36 69 of Data 93 This -12.50 -21.90 correlation -3.81 -7.80 10.50 17.90

Larkins -9.64 -4.64 14.46 19.69 33.30 -32 I 90

Sweeney -20.61 -15.11 -1.87 3. 90 22.90 -63.90

Clements -82.27 -73.89 -7L;,,6o -77.95 -78.10 -46.40

Turpin -11.46 -79.88 -80.40 -41.65 -85.10 47.90

Charpentier '?.28 12.06 54.54 34.80 56.50 -18.91

Hutton -51.72 -59.49 -22.78 36.60 -59.10 -56 I 96

Sa to 11.26 17.24 60.84 41.42 69.50 -13.32

Midoux -29.18 -24.58 1.17 -10.80 9.40 -46.16

B. Absolute Error (%)

This 12.50 21.90 15.10 11.20 13.30 19.10 correlation

Larkins 12.20 13.37 25.09 21.84 36.00 32.90

Sweeney 21.05 17.64 26.50 14.63 27.55 63.90

Clements 82a27 73.89 74.60 77.95 78.10 46a40

Turpin 11.46 79.88 80.40 44.19 85.10 52.60

Charpentier 13.27 17.62 54.54 41.49 57.50 20.16

Hutton 51.72 59,49 33.02 41.69 59.10 56.96

Sa to 13 I 92 18.06 60.84 44.87 69.50 16.72

!VIidoux 29.18 24.77 14.65 18.57 14.65 46.16

Table IV (continued) 72

A. Error (%)

Data(T bl Set a e III). 7 8 9 10 11 12 Amount 24 54 39 42 33 42 of Data This -28.80 -26.50 -11.80 -5.30 41.50 correlation -7.90

Larkins -49.70 52.60 -40.64 -40.85 -39.25 -8.35

Sweeney -67.60 -68.70 -62.79 -62.81 -60.84 -42.35

Clements -60 .10· -63.20 -54.22 -55.91 -50.78 -28.35

Turpin -22.0 -27.60 -27.?6 -31.90 -51.73 -52.03

Charpentier -37.83 -41.50 -27.47 -28.26 -25.72 9.89

Hutton -56.43 -60.10 -55.86 -59.90 -56.07 -49.17

Sa to -32.30 -36.50 -21.88 -23.66 -20.18 16.62

Midoux -59.09 -61.40 -52.10 -52.74 -51.08 -26.81

B. Absolute Error (%)

This 33.40 37.80 24.60 24.40 36.10 46.30 correlation Larkins 50.38 54.75 41.56 40.85 40.45 21.07

Sweeney 67.60 68.70 62.79 62.81 60.84 42.35

Clements 60.10 63.20 55.27 55.91 51.21 30.49

Turpin 26.47 34.65 28.41 31.90 51.73 52.03

Charpentier 41.42 43.30 32 I 99 30.12 38.98 29.47

Hutton 56.43 60.10 57.77 59.90 59.12 51.87

Sa to 41.13 43.10 34-.29 30.62 41.38 31.17

Midoux 59.09 61.40 52.10 52.74 51.08 27.04

Table IV (continued) 73

A, Error (%) .... - . - - .

Data Set (Table_ III) 13 14 - 15 16 17 18 Amount 15 27 42 54 54 12 of Data This -9.10 -18.80 4.80 5.60 26.30 14.70 correlation Larkins -35.85 -31.57 -12.34 -20.46 8.50 -14.49

Sweeney -49.70 -46.27 -29.87 -38.73 -9.63 41.67

Clements -79.53 -78.90 -75.78 -76.51 -71.40 -69.90

Turpin -3 9.12 -44.73 -48 . .55 29.10 -62.29 -14.74

Charpentier -20.43 -16.44 4.67 -4.09 28.82 4.44

Hutton -42.45 -48.60 -50.20 -49.07 -48.04 -34.94

Sa to -13.38 -11.07 9.50 1.64 36.59 11.61

Midoux -47.84 -45.36 -30.84 -36.62 -10.09 -31.48

B. Absolute Error (%)

This 31.80 30.50 16.00 20.00 26.60 44.40 correlation Larkins 39.53 34.22 15.91 22.65 16.32 29.02

Sweeney 49.70 46.27 29.87 38.87 12.55 41.67

Clements 79.52 78.90 75.78 76.51 71.40 69.90

Turpin 46.14 45.12 48.55 42.14 62.29 38.29

Charpentier 30.63 26.84 20.79 12.19 32.44 33.92

Hutton 44.33 49.81 50.74 49.07 48.04 34.94

Sa to 29.46 26.56 21.80 11.48 37.27 37.94

Midoux 47.84 45.36 30.84 36.62 13.88 33.07

74 Table IV (continued)

A. Error (%)

Data( Set Table. III.) 19. 20 21 22 23 24 Amount 62 56 65 272 54 65 of Data This -8.00 -20.20 -5.50 4.90 -1.20 6.40 correlation Larkins -70.)9. ,...64.91 ,.-57.10 -20.40 -20.55 ,...11.40

Sweeney ,...86.81 -81.32 ,...79.10 -28.40 -29.00 -23.16

Clements -53.27 -70.83 -70.54 -31.70 231.90 270.90

Turpin 29.50 5.73 22.53 -3.50 -83.10 -84.27

Charpentier -64.42 -57.40 -48.30 -6.34 -5.20 5.10

Hutton -76.59 -63.40 -62.60 -86.10 -78.50 -78.87

Sa to -60.46 -53.78 -43.60 8.01 4.94 16.87

Midoux -75.36 -71.46 -64.90 -31.20 -34.10 -26.10

B. Absolute Error (%)

This 13.90 22.10 15.30 18.30 17.60 29.50 correlation Larkins 70.39 64.91 57.10 21.20 26.80 18.08

Sweeney 86.61 81.32 79.10 28.60 33.77 26.06

Clements 53.27 70.83 70.54 49.60 231.90 270.90

Turpin 30.60 20.93 35.34 31.20 83.10 84.27

Charpentier 64.42 57.40 48.30 16.80 24.41 20.57

Hutton 76.59 63.40 62.60 86.10 78.50 78.87

Sa to 60.46 53.78 43.60 19.40 23.59 27.54

Midoux 75.36 71.46 64.90 31.20 35.10 26.30

Table IV (continued) ?5

A. Error(%)

Data(T bl Set a e III) 25 26 27 28 29 Amount 62 44 34 12 12 of Data This 54.10 26.50 -17.40 -40.40 -20.70 correlation Larkins 21.75 38.34 -13.24 -48.77 -35.55

Sweeney 7.76 27.80 -17.73 -54.94 -40.58

Clements 23.48 -70,36 -87.90 -86.70 -92.26

Turpin -83.02 -7.88 -33.08 -80.35 -38.13

Charpentier 44.83 64.20 5.20 -39.74 -23.73

Hutton -56.17 -46.16 -49.20 -79.16 -79.37

Sa to 59.88 81.20 13.87 -36.90 -15.16

Midoux 0.84 14.60 -29.58 -59.45 -46.23

B. Absolute Error (%)

This 64.10 30.80 23.20 40.90 48.90 correlation Larkins 40.00 44.46 18.11 48.77 41.96

Sweeney 40.10 39.90 20.90 54.94 44.67

Clements 47.70 70.36 87.90 86.70 92.26

Turpin 83.02 16.44 33.08 80.35 48.47

Charpentier 57.47 68.47 19.10 39.92 36.50

Hutton 64.70 61.06 49.30 79.37 79.37

Sa to 70.30 84.38 23.64 39.70 37.57

Midoux 27.45 26.13 29.90 59.45 49.37

Table IV (continued) 76

A, Error (%)

Data III) Total Set (Table without 25 1 26 total

Amount 1464 1570 of Data This

-0.837 2.10 correlation Larkins -17.15 -14.05

Sweeney -36.96 -33.38

Clements -36.84 -35.10

Turpin -25.90 -27.60

Charpentier 0.46 -3.10

Hutton -57.50 -57.20

Sa to 1.17 5. 73

Midoux -36.80 -33.90

B. Absolute Error (%)

This 21.67 23.60 correlation Larkins 31.20 31.97

Sweeney 42.89 42.70

Clements 77.90 76.50

Turpin 46.70 47.30

Charpentier 31.10 33.23

Hutton 61.20 61.40

s·ato 31.20 34.30

Midoux 37.20 36.80

PI

82%

o

f U

w

ith

in

~

69%

o

f ~within

153

%

of

wit

hin

the

data

±

30

% err

or

the

data

±

20

% err

or

the

data

±

10

% err

or

-30

Fig

1

9 D

istr

ibu

tio

n cu

rve

of

err

or

= x

% o

f th

e

data

w

ith

in ±y

%

err

or

are

a

betw

een

±

y

tota

l are

a Err

or

%

--..J

--..J

78

error for the new expression.

J. Discussion of friction factor in single phase

Larkins (4) suggested that the friction factor of

single phase flow through packed beds is 118.2/Re + 1.0.

Ergun (2) correlated the friction factor to be 150/Re+ 1.75.

If Ergun is correct then Larkins' sphere packing experiment­

al data are too low. The two forms of friction factors will

be compared by using Larkins' equation to predict the two

phase flow pressure drop. For Cle~ents, Halfacre and

Weekman's data, Larkins' equation has -16% average error

and 35% absolute error when f = 150/Re + 1.75. While f =

118.2/Re + 1.0, the average error is -47.4% and the absolute

error is 47o9%. This indicates that f = 150/Re + 1.75 is

better.

4. Holdup

The holdup term is important in Larkins' (1,4) and

Turpin's (15) correlation. This section we will see how

the holdup prediction influences their correlations. Let

E be the error for the holdup equation chosen. Equation r

4-15 shows how errors in the holdup can cause errors in the

pressure drop calculation.

where

'(~ )pr ( ap ) + h az az exp pr =

(~ az )tr ( ap ) + az exp htr

h is the predicted holup pr

htr is the true holdup

PL + (1-h ) PG pr .... (4-15)'

J + ( l-htr) _;G 'L

79

Substitute hpr= htr(l + Er) and neglect the gas term to get

( ap ) az- pr

( ap ) az tr

= l + ( ap) + h o

--a2 exp tr' L I 0 0 I I I o o o I I I (4-16)

From equation (4-16), it is easy to understand that at

higher values of ( ap az )exp the holdup error has less effect

in the calculation. If ( ~~ ) = 0 the error is + Er. exp and PL = 62.4 lb/ftJ If (

ap )exp 0.1 psi., htr 0.4, = = az

~ ~ ) = l psi . the exp then the error is + o.6J E • If ( - r error is + 0.14 E • - r

For Clements and Larkins' data the experimental

pressure drop is more than l psi., this indicate that holdup

prediction has little effect on the correlation. For

Halfacre and Weekman's data, many pressure drop data are in

the range of 0.01 to l psi.a The accuracy of the prediction

of holdup influences Larkins and Turpin's correlation

significantly.

5. Gas density

In this correlation, the gas· density is assumed constant

throughout the column. It is almost true when the column is

short or the pressure drop is low. Fig 20 is the distribu-PG in

tion curve of ,JG av

of the data within 25%.

84% of the data within 10% and 99%

From this curve it is easy to

accept the assumption that gas density is constant.

f(x)

1.0

1

.1

Fig

f(x)=

-=

--::

......

l...!

;"--

L

1.2

P. 1

n

Pav

1.0

F(x

)

.84 1

.0

20

D

en

sity

dis

trib

uti

on

cu

rves

F(x

) am

ount

o

f P

in/P

av le

ss

than

x to

tal

data

1.1

1

.2

Pin

Pav

CX>

0

CHAPTER V

CONCLUSIONS AND SUGGESTIONS

Conclusions

1. The capillary flow model may be used as the basis for

correlation of viscous flow energy loss behavior. The

capillary separation flow model may be used as the basis

for correlation of kinetic flow energy loss behavior.

2. Correlation of the frictional pressure loss for downward

nonfoaming flow can be separated into viscous and

kinetic flow portion.

J. For viscous flow the friction factor is a function of G:--LuG

LPGuL function

For kinetic flow the friction factor is a @

of modified liquid Reynolds number ReL/1-E

and the volumetric flow ratio.

4. The density change from top to bottom which causes the

velocity of fluid at the top to be different from the

bottom may be neglected for operating pressures below

50 psia.

5. The pressure loss is independent of the two phase flow

pattern for nonfoaming flow.

6. This correlation is good for 2 < ..-_ 600.

Further Study Suggestions

1. For the capillary model when the liquid flowrate is high

and the gas flow rate is low, the surface tension is

81

82

important. For higher surface tensions the flow is still

laminar, while for lower surface tensions the flow will

change to turbulent flow. It is required to study how

the surface tension influence the pressure drop in the

high liquid volumetric flow rate region.

2. For Raschig ring packings, the laminar flow region

experimental data is lacking. To collect the experiment­

al data in this region is necessary.

J. Correlation for foaming flow is necessary.

REFERENCES

(1) Larkins, R. P., and White, R. R., and Jeffrey, D. W., "Two-Phase Concurrent Flow in Packed Beds," AIChE J., z, 231-239 (1961).

(2) Ergun, S.: "Fluid Flow Through Packed Columns," Chern. Engr. Frog. 48, 89-94, (1952)

(3) Brownell, L. E., and Katz, D. L.: "Flow of Fluids Through Porous Media," Chern. Engr. Frog. ~' 537-601, ( 1947) .

(4) Larkins, R. P.: "Two-Phase Cocurrent Flow in Packed Beds," Ph. D. Thesis, University of Michigan, Ann Arbor, Michigan, (1959).

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