composite functions: application the price per unit, p, for the product is p = 2000 – 10t, where t...

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Composite Functions: Application The price per unit, p, for the product is p = 2000 10t, where t is the number of months past January 2010. Example 1: The monthly demand, D, for a product, is 5,000,000 D p p is the price per unit of the product. the monthly demand, D, as a function of t.

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Page 1: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010.

Example 1:

The monthly demand, D, for a product, is

5,000,000D

p

where p is the price per unit of the product.

Write the monthly demand, D, as a function of t.

Page 2: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

Compute (D p)(t) = D(p(t)).

Note, D is a function of p, D(p)D

pand p is a function of t.

tp(t)

5,000,000D

p 2000 10p t

(2000 10 )D t 5000000

2000 10t

Page 3: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

(D p)(t) =t102000

000,000,5

This is now a function of demand with respect to t, so can be relabeled,

5,000,000( )

2000 10D t

t

Page 4: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

When will the monthly demand reach 6,250 units?

5,000,000( )

2000 10D t

t

5,000,0006250

2000 10t

Page 5: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

6250(2000 – 10t) = 5000000

12500000 – 62500t = 5000000

- 62500t = - 7500000

t = 120 months

The monthly demand will reach 6,250 units in January 2005.

5,000,0006250

2000 10t

Page 6: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

Example 2: An observer on the ground is 300 feet away from the launching point of a balloon. The balloon is rising is rising at a rate of 10 feet per second.

Let d = the distance (in feet) between the balloon and the observer.

Let t = the time elapsed (in seconds) since the balloon was launched.

Let x = the balloon's altitude (in feet).

300 feet

xd

Page 7: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

(a) Express d as a function of x.

Hint: Use the Pythagorean Theorem.

300 feet

xd

22300 xxd

2 2 2300d x

2 2300d x

Page 8: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

300 feet

xd

(b) Express x as a function of t.

x(t) = 10t

The balloon is rising is rising at a rate of 10 feet per second.

x = the balloon's altitude (in feet).

Page 9: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

300 feet

xd

(c) Express d as a function of t.

( )d x t d x t

x(t) = 10t

22300 xxd

2 2300 (10 )t

Page 10: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application

300 feet

xd

(d) Use the result found in (c) to determine how long it takes from launching for the balloon to be 500 feet from the observer.

It takes 40 seconds.

2 2( ) 300 (10 )d t t

2 2 2500 300 100t

2 22500 300

100t

40t

Page 11: Composite Functions: Application The price per unit, p, for the product is p = 2000 – 10t, where t is the number of months past January 2010. Example 1:

Composite Functions: Application