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    PHISICK TASK CHAPTER 3

    3.1 UNIFORM CIRCULAR

    MOTION

    3.2 CIRCULAR MOTIONTRANSVERING

    3.3 CIRCULAR MOTION

    WITH ACCELERATION

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    3.1 uniform circular

    motion Uniform circular Motion is a particle that

    moves circularly with radius R and constantspeed.

    Gerak Melingkar Beraturan adalah sebuahbenda yang bergerak melingkar denganjari-jari R dan kelajuan tetap

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    R

    B

    B

    A

    A

    B

    Notes

    A : Particle A ( benda A)

    B : Particle B ( Benda B)

    A : Linier Velocity A(kecepatan linier A)

    B : Linier velocity B (Kecepatan linier B

    : Angulairvelocity(kecepatan

    sudut)Sketch of circular motion

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    Period and Frequency (Periode dan Frekuensi)Period (Periode)

    Is the time elapses to reach 1 circular motion on a

    thing.Adalah waktu yang diperlukan untuk menempuh 1putaran pada sebuah benda.

    Formula :T: Period (Periode)..secondt : Time (Waktu)...secondn: The number of circular

    motion (jumlah putaran)n

    tT

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    Frequency (Frekuensi)

    Is a number of circular motion on athing in 1 second.Adalah jumlah putaran pada sebuahbenda dalam waktu 1 sekon.

    Formula:

    t

    nf

    f : frequency(frekuensi)..Hz

    n : The number of circular motion(jumlah putaran)

    t : time(waktu)..second

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    The Relation between Period andFrequency

    (Hubungan antara Periode dan Frekuensi)

    And

    So,

    And

    n

    tT

    t

    nf

    f

    1T

    T

    1

    f

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    Linier / Tangensial velocity (KecepatanLinier / Tangensial )

    Linier/Tangensial Velocity (Kecepatan Linier/ tangensial)Is the distant which covered per unit oftime.Adalah jarak yang ditempuh per satuanwaktu.

    To reach the distant of 1 circular motion

    (2R) needs 1 period (T).Untuk menempuh jarak 1 putaran (2R)

    memerlukan 1 periode (T).

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    So :

    linier velocity = distant / period

    or

    With radius R

    = 2Rf (m/s)

    T

    R2v

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    ngu a r e oc y ecepa ansudut)

    Angulair Velocity is angle which coveredper unit of time.Kecepatan sudut adalah sudut yang

    ditempuh per satuan waktu To reach 360O or 2 radian on 1 circular

    motion needs 1 period (T)

    Untuk menempuh 3600

    atau 2 radiandalam satu putaran memerlukan 1periode(T)

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    So:

    Angulair velocity =2 / T

    Or

    (read : Omega)1 circular / rotation = 2 radian

    )s/rad(T

    2

    )s/rad(f2

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    The Relation between Linier Velocity (V)

    and Angulair Velocity ().

    (Hubungan antara Kelajuan Linier (V)

    dan Kecepatan Sudut ().

    V : Linier Velocity(Kecepatan Linier)

    : Angulair velocity

    (kecepatan sudut)

    R : Radius (jari-jari)

    = . R

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    Centripetal Acceleration(Percepatan sentripetal)

    is The change of velocity per limit oftime

    Adalah perubahan kecepatan per satuanwaktu.Formula :

    oras= 2R (m/s2)

    Rva

    2

    s

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    Fs=m2

    .R

    Fs

    R

    A

    R

    mvFs

    2

    Fs = Centripetalforce

    (N,Dyne)m = mass (kg,gr)

    V = linier speed(m/s,cm/s)

    R = raius

    = Angulairvelocity(rad/s)

    Centripetal Force ( Gaya Sentripetal)

    A Body connected with rope than moves uniform circularly.Sebuah benda dihubungkan dengan tali kemudian bergerakmelingkar beraturan.

    Formula :

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    3.2 Circular motiontransvering

    (hubungan perputaran)

    DIRECT (Langsung)

    R1

    R2

    v1

    v2

    1 =

    2

    2

    2

    1

    1

    R

    v

    R

    v

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    INDIRECT ( Tidak langsung )

    V1 = v2

    1.R1 = 2.R2

    R1

    R2

    R1R2

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    If the pulleys connected with a gear, so :

    Jika roda terhubung dengan sebuahgir,maka :

    or

    nA&nB : amount of gear A and gear B

    (jumlah gir A & gir B)f: Frequency(frekuensi)T: Period (Periode)

    nA .fA = nB .fB

    TB

    nB

    TA

    nA

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    And

    mA & mB :amount of cyclus(jumlahputaran)

    RA & RB : radius A and B( jari-jari A danB)

    mA . RA = mB. RB

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    3.3 Circular motion withacceleration

    (gerak melingkar berubah

    beraturan) The Formula is similar with Linier

    Motion.

    Rumusnya sama dengan gerak lurus. They are: : Angulair acceleration

    /decelleration

    t: final angulair velocity( kecepatan sudut akhir)o: initial angulair velocity

    (kecepatan sudut awal)

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    Vt : Final linier velocity(kecepatan linier akhir)

    Vo : Initial linier velocity

    (kecepatan linier awal) :amount of rotation(jumlah

    putaran) read:teta

    t= o + .t

    t2=o2+2

    t = o - t

    2

    0t

    2

    1t

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    at : tangensial acceleration(percepatan tangensial)

    as : centripetal acceleration

    (percepatan sentripetal)

    atot: total acceleration

    (percepatan total)

    at = . R

    as = 2 . R

    22

    tot asata

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    EXERCISE 1

    UNIFORM CIRCUALR MOTION1. A particle moves circularly with constant

    velocity 300 cm/s and radius is 2,5 cmfind: a) Period and frequency

    b) Angulair velocity ( in rpm)c) Centripetal acceleration

    2. A particle moves circularly in 10 second covered5 circular. If radius is 4mfind : a) Period and frequency

    b) Angulair velocity ( in rpm)c) Centripetal acceleration

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    3. A dinamo has diameter 20 cm. Moves

    circularly in 150 rpmfind: a) Period and frequencyb) Linier velocity

    4. A particle moves circularly with radius = 4min 2 second. Happens angle displeacement(perpindahan sudut) 1 / 6 circularfind : a) Angle displeacement in radian

    b) Period and frequencyc) Angulair velocityd) Linier velocity

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    5. A thing has mass 50 gram connected with rope thathas long 1 meter. Moves circular and in 10 secondhappens 50 circular.

    Find : a) Linier velocity

    b) Centripetal acceleration

    c) Tension rope (centripetal force)

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    1. Four pulleys (wheel) with radius R1=5 cm, R2=15 cm,R3= 10 cm,R4= 25 cm as in the diagram bellow. Thefirst wheel moves with a frequency of 2 / Hz.Find : a) Angulair velocity of wheel 1b) Tangensial velocity of forth wheel

    EXERCISE 2CIRCULAR MOTION TRASVERING

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    2. A door trap bicycle with a front gear radius 12 cmand back gear radius 4 cm. The wheel radius is 18 cmeach. The front gear moves with a period of 3second .find : a) The time needed to reach the

    distance 18 km

    b) if the amount of the front gear 40,

    find the amount of the back gear

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    3. The machine use 2 wheel like diagram bellow. Smallerwheel has radius 5 cm and moves circularly on 120

    rad/sfind : a) Linier velocity both wheel

    b) If bigger wheel has radius 16cm, find the angulair velocity in rpm

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    4. Wheel A has radius 4cm and wheel B has radius 10cm. Wheel B connected with wheel C (radius = 3 Cm).

    If wheel A moves circularly by the same directionwith watch and angulair velocity 15 rad/s.

    find : linier velocity of wheel D has radius 16 cm.

    AB

    C

    D

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    5. An electric motorcycle rotate wheel A which has

    radius 10 cm. Wheel A connected with rope on otherwheel that has radius 50. If the motorcycle givesangulair 200 rad/s to wheel A

    find : Angulair velocity wheel B and centripetal

    acceleration of wheel B.

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    EXERCISE 3CIRCULAR MOTION WITH

    ACCELERATION1. A wheel rotates in 2 second the angulair changefrom 30 rpm to 20 rpm. The radius is 10 cmfind: a) Angulair deceleration

    b) The amount of rotation2. At first a wheel do nothing reach angulair

    velocity 64 rad/s on 16 second.find: a) Angulair acceleration

    b) Angle which covered

    c) If the radius of wheel 10 cm. Find thecentripetal acceleration

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    3. A disk with radius 15 cm at first rotate 25 rad/s and

    its brake till become 15 rad/s. During it, the disk hasrotate 40 radian.

    find : a) Angulair decceleration

    b) How long time needed to stop since the first

    brakec) Before brake find tangensial velocity,centripetal acceleration and total

    acceleration