chemistry - key skills
TRANSCRIPT
8/6/2019 Chemistry - Key Skills
http://slidepdf.com/reader/full/chemistry-key-skills 1/3
Chemistry: Key Skills
Chemical Reaction Types
Decomposition is
the reve rse o fcombination. That is, a single reactant is broken
down into two or more products either elements
or compounds.
EXAMPLE
AB→ A + B2HgO(s) → 2Hg(l) + O2(g)
Decomposition
A reaction between
a n a c i d i c
compound and a basic compound to form a
onic salt and water.
EXAMPLE
Acid + Base→ Salt + WaterHCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
Neutralisation
C o m b u s t i o n
reactions generally
apply when an organic compound is burned in
air - reacting with the oxygen - producing
carbon dioxide and water.
EXAMPLE
Organic + O2 → CO2 + H2OCH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
Combustion
A d isp lacement
reaction involves
a n e l e m e n treacting with a
compound displacing another element from the
compound.
EXAMPLE
A + BC→ AB + C
Zn(s) + 2HCl(aq) → ZnCl2(s) + H2(g)
Single
Displacement
A d o u b l e
d i s p l a c e m e n t
reaction involves
two compounds
reacting by swapping ions so that each ion hasa new partner.
EXAMPLE
AB + CD→ AC + BD
AgNO3(aq) + NaCl(aq) →
! ! ! ! AgCl(s) + NaNO3(aq)
Double
Displacement
Any reaction in
which two or more
substances combine to form a single product is
a combination reaction.
EXAMPLE
A + B→ AB2Na(s) + Cl2(g) → 2NaCl(s)
Combination
8/6/2019 Chemistry - Key Skills
http://slidepdf.com/reader/full/chemistry-key-skills 2/3
Chemical Equations
The law of conservation of mass
states that matter can neither be
created nor destroyed, so a
chemical equation must have the
same amounts of each particle on
each side of the equation.
States of matter (solid, liquid, gas
and aqueous) must be included for
every reactant and product.
Numbers in subscript after an
element or ion are a part of the
molecule or compound and cannot
be changed.
Coefficients placed in front of a molecule apply to
he whole molecule and must be used to indicate
a balanced ratio of reactants and products.
A balanced equation must show the coefficients
used in the simplest possible whole number ratio.
Rules for wri t ing
chemical e uations
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
Same amounts of reactants and products.
States of matter shown for each chemical.
Think of the elements and ions in an equation as units . Polyatomic ions that remain
unchanged on both sides of the equation can be counted as a single unit.
Start with an element or ion that is in only one chemical on both sides of the equation.
Work with one element or ion at a time going back and forth between reactants and
products (or vice versa). Once you have balanced an element or ion both sides, balance
any other(s) in the same compound or molecule.
Keep a tally for each unitʼs amount on both sides can make life easier when balancing more
complex chemical equations.
Save balancing any single elements, water molecules, or molecules with only one element
or last.
B a l a n c i n g
chemical equations
8/6/2019 Chemistry - Key Skills
http://slidepdf.com/reader/full/chemistry-key-skills 3/3
Pick a product Al2(SO4)3(aq) + NaOH(aq) → Al(OH)3(aq) + Na2SO4(aq)
Write a balanced half
equation 2Al2(aq) + 6OH(aq) →
2Al(OH)3(aq)
Balance the overallequation. 2Al2(SO4)3(aq) + 6NaOH(aq) → 2Al(OH)3(aq) + 3Na2SO4(aq)
Chemical EquationsThe following two methods are for equations that are too difficult to balance on inspection.
The “odd one out” method is best used to balance composition, decomposition and to a
lesser extent, neutralisation reactions.
The “half and half” method is bettersuited to ionic equations, in particular
double displacement reactions.
The “Odd one out”Method
The “Half and half”
Method
Give the odd one out acoefficient of 2 Ca(OH)2(aq) + H3PO4(aq) → 2Ca3(PO4)2(aq) + H2O(aq)
Balance as necessary 6Ca(OH)2(aq) + 4H3PO4(aq) → 2Ca3(PO4)2(aq) + 12H2O(aq)
Write coefficients insimplest whole number
ratio.
3Ca(OH)2(aq) + 2H3PO4(aq) → Ca3(PO4)2(aq) + 6H2O(aq)
Step 1.! Identify the largest reactant or product with an odd number (except 1) of an
! unbalanced element (it is the odd one out) or ion and give it a coefficient of 2.
Step 2. ! Add coefficients to the !chemicals on the opposite side of the equation to be in
! balance with the !odd one out.
Step 3. ! Balance any remaining unbalanced reactants or products.Step 4. ! If needed, alter the coefficients to be in the simplest whole number ratio.
Step 1.! Pick one of the products of the equation and identify the ions that form it
! from !chemicals on the reactants side.
Step 2. ! Write a half equation using the product you selected and the ions from the
!reactants side including the correct amounts of each.
Step 3. ! Balance the half equation by adding coefficients to the ions and product.
Step 4. ! Transfer the balanced coefficients !from the half equation to the respective
! chemicals in the full equation.
Step 4.! Write a second half equation for the other product and repeat the steps.