chemistry answer key

1. A balanced equation has equal numbers of each type of atom on each side of the equation. 2. Chemical equations do not come already balanced. 3. You cannot change a subscript. 4. You cannot place a coefficient in the middle of a formula. 5. Make sure that your final set of coefficients are all whole numbers with no common factors other than one. 6. When sodium metal (Na) and a chlorine gas (CL 2 ) react, the product is the ionic compound NaCl. 7. Sometimes, in balancing equations, fractional coefficient seems necessary. 8. Synthesis reactions occur between two or more different elements. 9. The products of chemical reaction are identified by doing experiments. 10. Substances other than hydrocarbons will burn in oxygen. Chemical formula Methane Acetylene Octane Decomposition Synthesis Burning Heat Light Combustion Reactant Product A+B AB AB A+B Hydrocarbon Balancing chemical equations is a basic skill in chemistry. Chemical reactions have the same number of atoms before the reaction as after the reaction. This collection of ten chemistry test questions deals with balancing chemical reactions. Answers 1. 1 SnO 2 + 2 H 2 → 1 Sn + 2 H 2 O 2. 3 KOH + 1 H 3 PO 4 → 1 K 3 PO 4 + 3 H 2 O 3. 2 KNO 3 + 1 H 2 CO 3 → 1 K 2 CO 3 + 2 HNO 3 4. 1 Na 3 PO 4 + 3 HCl → 3 NaCl + 1 H 3 PO 4 5. 1 TiCl 4 + 2 H 2 O + 1 TiO 2 + 4 HCl 6. 1 C 2 H 6 O + 3 O 2 → 2 CO 2 + 3 H 2 O 7. 2 Fe + 6 HC 2 H 3 O 2 → 2 Fe(C 2 H 3 O 2 ) 3 + 3 H 2 8. 4 NH 3 + 5 O 2 → 4 NO + 6 H 2 O 9. 1 B 2 Br 6 + 6 HNO 3 → 2 B(NO 3 ) 3 + 6 HBr 10. 4 NH 4 OH + 1 Kal(SO 4 ) 2 ·12H 2 O → 1 Al(OH) 3 + 2 (NH 4 ) 2 SO 4 + 1 KOH + 12 H 2 O 1. 2 AgI + 1 Na 2 S → 1 A g 2 S + 2 NaI 2. 1 Ba 3 N 2 + 6 H 2 O → 3 Ba(OH ) 2 + 2 NH 3 3. 3 CaCl 2 + 2 Na 3 PO 4 → 1 C a 3 (PO 4 ) 2 + 6 NaCl 4. 4 FeS + 7 O 2 → 2 F e 2 O 3 + 4 SO 2 5. 1 PCl 5 + 4 H 2 O → 1 H 3 PO 4 + 5 HCl 6. 2 As + 6 NaOH → 2 N a 3 AsO 3 + 3 H 2 7. 3 Hg(OH) 2 + 2 H 3 PO 4 → 1 H g 3 (PO 4 ) 2 + 6 H 2 O 8. 12 HClO 4 + 1 P 4 O 10 → 4 H 3 PO 4 + 6 Cl 2 O 7 9. 8 CO + 17 H 2 → 1 C 8 H 18 + 8 H 2 O 10. 10 KClO 3 + 3 P 4 → 3 P 4 O 10 + 10 KCl 1. __ SnO 2 + __ H 2 → __ Sn + __ H 2 O 2. __ KOH + __ H 3 PO 4 → __ K 3 PO 4 + __ H 2 O 3. __ KNO 3 + __ H 2 CO 3 → __ K 2 CO 3 + __ HNO 3 4. __ Na 3 PO 4 + __ HCl → __ NaCl + __ H 3 PO 4 5. __ TiCl 4 + __ H 2 O → __ TiO 2 + __ HCl 6. __ C 2 H 6 O + __ O 2 → __ CO 2 + __ H 2 O 7. __ NH 3 + __ O 2 → __ NO + __ H 2 O 8. __ AgI + __ Na 2 S → __ A g 2 S + __ NaI 9. __ FeS + __ O 2 → __ F e 2 O 3 + __ SO 2 10. __ PCl 5 + __ H 2 O → __ H 3 PO 4 + __ HCl

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1. A balanced equation has equal numbers of each type of atom on each side of the equation.

2. Chemical equations do not come already balanced.

3. You cannot change a subscript.4. You cannot place a coefficient in the middle of

a formula.5. Make sure that your final set of coefficients

are all whole numbers with no common factors other than one.

6. When sodium metal (Na) and a chlorine gas (CL2) react, the product is the ionic compound NaCl.

7. Sometimes, in balancing equations, fractional coefficient seems necessary.

8. Synthesis reactions occur between two or more different elements.

9. The products of chemical reaction are identified by doing experiments.

10. Substances other than hydrocarbons will burn in oxygen.

Chemical formulaMethaneAcetyleneOctaneDecompositionSynthesisBurningHeatLightCombustionReactantProductA+B ABAB A+BHydrocarbon

Balancing chemical equations is a basic skill in chemistry. Chemical reactions have the same number of atoms before the reaction as after the reaction. This collection of ten chemistry test questions deals with balancing chemical reactions.

Answers1. 1 SnO2 + 2 H2 → 1 Sn + 2 H2O2. 3 KOH + 1 H3PO4 → 1 K3PO4 + 3 H2O3. 2 KNO3 + 1 H2CO3 → 1 K2CO3 + 2 HNO3

4. 1 Na3PO4 + 3 HCl → 3 NaCl + 1 H3PO4

5. 1 TiCl4 + 2 H2O + 1 TiO2 + 4 HCl6. 1 C2H6O + 3 O2 → 2 CO2 + 3 H2O7. 2 Fe + 6 HC2H3O2 → 2 Fe(C2H3O2)3 + 3 H2

8. 4 NH3 + 5 O2 → 4 NO + 6 H2O9. 1 B2Br6 + 6 HNO3 → 2 B(NO3)3 + 6 HBr

10. 4 NH4OH + 1 Kal(SO4)2·12H2O → 1 Al(OH)3 + 2 (NH4)2SO4 + 1 KOH + 12 H2O

1. 2 AgI + 1 Na2S → 1 Ag2S + 2 NaI 2. 1 Ba3N2 + 6 H2O → 3 Ba(OH)2 + 2 NH3

3. 3 CaCl2 + 2 Na3PO4 → 1 Ca3(PO4)2 + 6 NaCl4. 4 FeS + 7 O2 → 2 Fe2O3 + 4 SO2

5. 1 PCl5 + 4 H2O → 1 H3PO4 + 5 HCl6. 2 As + 6 NaOH → 2 Na3AsO3 + 3 H2

7. 3 Hg(OH)2 + 2 H3PO4 → 1 Hg3(PO4)2 + 6 H2O8. 12 HClO4 + 1 P4O10 → 4 H3PO4 + 6 Cl2O7

9. 8 CO + 17 H2 → 1 C8H18 + 8 H2O10. 10 KClO3 + 3 P4 → 3 P4O10 + 10 KCl

1. __ SnO2 + __ H2 → __ Sn + __ H2O2. __ KOH + __ H3PO4 → __ K3PO4 + __ H2O3. __ KNO3 + __ H2CO3 → __ K2CO3 + __ HNO3

4. __ Na3PO4 + __ HCl → __ NaCl + __ H3PO4

5. __ TiCl4 + __ H2O → __ TiO2 + __ HCl6. __ C2H6O + __ O2 → __ CO2 + __ H2O7. __ NH3 + __ O2 → __ NO + __ H2O8. __ AgI + __ Na2S → __ Ag2S + __ NaI9. __ FeS + __ O2 → __ Fe2O3 + __ SO2

10. __ PCl5 + __ H2O → __ H3PO4 + __ HCl

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