chemistry 125: lecture 70 april 18, 2011 green chemistry mitsunobu reaction acids and acid...
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Chemistry 125: Lecture 70April 18, 2011
Green ChemistryMitsunobu Reaction
Acids and Acid Derivatives This
For copyright notice see final page of this file
Rest of the YearLecture 71 (4/20)
Acid Derivatives and Condensations (e.g. F&J Ch. 18-19)
Lecture 72-73 (4/22,25)Carbohydrates - Fischer's Glucose Proof (e.g. F&J Ch. 22)
Lecture 74 (4/27)Synthesis of an Unnatural Product (Review)
(Anti-Aromatic Cyclobutadiene in a Clamshell)
Lecture 75 (4/29)Synthesis of a Natural Product (Review)
(Woodward's Synthesis of Cortisone)
New Processes Desired
Aromatic cross-coupling (avoiding haloaromatics) 6
Aldehyde or ketone + NH3 & reduction to chiral amine 4
Asymmetric hydrogenation of olefins/enamines/imines 4
Greener fluorination methods 4
Nitrogen chemistry avoiding azides (N3), H2NNH2, etc. 3
Asymmetric hydramination 2
Greener electrophilic nitrogen (not ArSO2N3, NO+) 2
Votes
Asymmetric addition of HCN 2
+ NH3 + NADH
H
H+ glutamic acid
Like Nature
Current Processes That Need Improving
Amide formation avoiding poor atom-economy reagents 6
OH activation for nucleophilic substitution 5
Reduction of amides without hydride reagents 4
Oxidation/Epoxidation (without chlorinated solvents) 4
Safer and more environmental Mitsunobu reactions 3
Friedel-Crafts reaction on unactivated systems 2
Nitrations 2
Votes
Very general for acidic Nu-H
(pKa < 15)
e.g.
R-CO2-
(RO)2PO2-
(RCO)2N-
N3-
“active methylene compounds”
MitsunobuReaction
Nu-Ph3P O R
Ph3P O R Nugreat leaving group
Oyo Mitsunobu(1934-2003)
O. Mitsunobu Synthesis (1981)
H
MitsunobuReaction
61% yield>99% inversion
pKa = 13
“active methylene” compound
Oyo Mitsunobu(1934-2003)
O. Mitsunobu Synthesis (1981)
HO C epimers?
mild
painful
HO COOH
COOH
2
CO2
C
29
PhP:1
“DEAD”2
MitsunobuReaction Oyo Mitsunobu
(1934-2003)
HAcO
(R)
HHO
(R)-OH
OHH
(S)
Allows correcting a synthetic “mistake”!
O. Mitsunobu Synthesis (1981)
MitsunobuInversion
Ph3PDEAD
AcOH
MitsunobuMechanism
O. Mitsunobu Synthesis (1981)
Nu-Ph3P O R
Ph3P O R Nugreat leaving group
Ph3P H OR-3
-1
need an oxidizing agent
Diethylazodicarboxylate(DEAD)
(reduced DEAD)
Eliminating H2O (18 mol.wt.)
generates 450 mol.wt.of by-products.
“atom inefficient”
but complete separation requires chromatography!unless hooked to polymer beads
Three Nucleophiles“tuned” just right
OR2
H+H+HOR2
pKa < 15
if X- attacks P+, it comes off again
irreversible
but Ru-H won’tquite reach.
+
Reminiscent of closely balancedNAD+ NADH
GREEN
H
Milstein et al., J.A.C.S. 127, 10840 (2005)
H
H
HO-C-R
H
Catalytic Formation of Ester + H2
Another oxidation involving analogous removal of H2 from RCH(OH)2 plus
some kind of C-O coupling, completes
2 R-CH2-OH R-CO2-CH2R + 2 H2
with no other activation!
H
H
H
H
H
+
H O-C-RH
H
H H
H H
Milstein et al., J.A.C.S. 127, 10840 (2005)
Catalytic Formation of Ester + H2
Thermochemistry of2 EtOH AcOEt + 2 H2
Hf
HOEt -66.1±0.5
x 2 -132.2±1.0
AcOEt -114.8±0.2
H2 0
Hrxn 17.4endothermic!
but forming 3 molecules from 2 is favored
by entropyespecially at low pH2
Acidity of RCO2H (e.g. J&F p. 836)
pKa
4.8
4.5
4.1
2.8
4.8
2.9
1.3
0.7
-0.3
1.9
1.6
0.6
“Inductive Effect”
Additivity
Acidity of RCO2H (Rablen, JACS 2000)
Resonance
Resonance
Oind × 2
Oind
+ 34.1 = 3 Oind
Oind = 11.4Resonance = 4.8
Resonance Oind × 3
+39 (calc)
Resonance Oind × 2× 2
-13.2 (calc)
Resonance / InductiveNumerology
From this viewpoint only ~20% of the special acidity of the carboxylic acid
is due to resonance!
DpKa = 16 – 5 = 11
DHH2O = 4/3 * 11 = 15
localized chargemeans better solvation
End of Lecture 70April 18, 2011
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