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Chemical Systems & Equilibrium Unit 4

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Chemical Systems & Equilibrium. Unit 4. Calculating the Equilibrium Constant. The equilbrium constant, Keq , is the ratio of equilibrium concentrations at a particular temp Kc for solution-phase systems or Kp for gas-phase systems K eq = [C] c [D] d for the eqn - PowerPoint PPT Presentation

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Page 1: Chemical Systems & Equilibrium

Chemical Systems & Equilibrium

Unit 4

Page 2: Chemical Systems & Equilibrium

Calculating the Equilibrium Constant The equilbrium constant, Keq, is the ratio of

equilibrium concentrations at a particular temp Kc for solution-phase systems or Kp for gas-

phase systems

Keq = [C]c[D]d for the eqn[A]a[B]b aA+bB cC+dD

Note: The equilibrium constant depends ONLY on the concentration of gases (not liquids/solids)

Page 3: Chemical Systems & Equilibrium

Questions: Equilibrium Law Expression1. Write the equilibrium law expression for the following:a) 2NO2(g) ↔ N2O4(g)

b) 2HI(g) ↔ H2(g) + I2(g)

2. A reaction vessel contains NH3, N2 and H2 gas at equilibrium at a certain temperature. The equilibrium concentrations are [NH3] = 0.25mol/L, [N2] = 0.11mol/L and [H2] = 1.91 mol/L. Calculate the equilibrium constant for the decomposition of ammonia.

K = [N2O4(g)]

[NO2(g) ]2

K = [H2(g)] [I2(g) ]

[HI(g) ]2

K = [N2(g)] [H2(g) ]3

[NH3(g) ]2K =

[0.11] [1.91 ]3

[0.25 ]2

K = 12.3

2NH3(g) ↔ N2(g) + 3H2(g)

Page 4: Chemical Systems & Equilibrium

Questions: Equilibrium Law Expression3. Nitryl chloride gas, NO2Cl, is in equilibrium at a certain temperature in a closed container with NO2 and Cl2 gases. At equilibrium, [NO2Cl] = 0.00106mol/L and [NO2] = 0.0108mol/L. If K = 0.558, what is the equilibrium concentration of Cl2?

4. Write a balanced equation for the reaction with the following equilibrium law expression:

K = [NO2(g)]2

[NO (g) ]2 [O2 (g) ]

Page 5: Chemical Systems & Equilibrium

Heterogeneous Equilibria homogeneous equilibria = equilibria in

which all entities are in the same phase Reactants and products are all gas or all

aqueous

heterogeneous equilibria = equilibria in which reactants and products are in more than one phase Reactants and products are in different

phases

Page 6: Chemical Systems & Equilibrium

Homogenous equilibrium applies to reactions in which all reacting species are in the same phase.

N2O4 (g) 2NO2 (g)

Kc = [NO2]2

[N2O4]Kp = NO2

P2

N2O4P

Page 7: Chemical Systems & Equilibrium

Heterogenous equilibrium applies to reactions in which reactants and products are in different phases.CaCO3 (s) CaO (s) + CO2 (g)

Kc =[CaO(s) ][CO2(g)]

[CaCO3(s)][CaCO3(s)] = constant[CaO(s) ] = constant

Kc = [CO2(g)]

The concentration of solids and pure liquids are considered to be constant and are not included in the expression for the

equilibrium constant.

Kc [CaO(s)]

[CaCO3(s)] = [CO2(g)]

Page 8: Chemical Systems & Equilibrium

PCO2 = Kp

CaCO3 (s) CaO (s) + CO2 (g)

PCO2does not depend on the amount of CaCO3 or CaO

Page 9: Chemical Systems & Equilibrium

N2O4 (g) 2NO2 (g)

Start with NO2 Start with N2O4 Start with NO2 & N2O4

equilibrium

equilibrium

equilibrium

Equilibrium favors the reactant side

Page 10: Chemical Systems & Equilibrium

CHECKPOINTThe reaction at 200C between ethanol and ethanoic acid produces ___________________ and __________________.

1. Write the equation for this reaction

2. Determine the equilibrium constant expression for the reaction

Page 11: Chemical Systems & Equilibrium

Sample Problem:When ammonia is heated it decomposes:

2NH3(g)↔ N2(g) + 3H2(g)

When 4.0 mol of ammonia is introduced in a 2.0L container and heated. Theequilibrium amount of ammonia is 2 0 mol. Determine the equilibrium concentrations of the other two entities.

STEP 1: Determine the concentration (initial and equilibrium) for known valuesSTEP 2: Setup an ICE TableSTEP 3: Determine the value of XSTEP 4: Use x value to determine the other quantities

Calculating Equilibrium Concentrations (when given one concentration)

Page 12: Chemical Systems & Equilibrium

Setup ICE Table

Determine the concentrations[NH3]initial = 4.0mol/2.0L = 2.0mol/L

[NH3]equilibrium = 2.0mol/2.0L = 1.0mol/L

Page 13: Chemical Systems & Equilibrium

Determine the value of X[NH3](g)equil = 2 0mol / L - 2x

[NH3](g)equil = 1.0mol/L (from calculations in Step 1)

2.0mol/L – 2x = 1.0mol/L-2x = - 1.0mol/Lx = 0.5mol/L

Use X to determine other quantities

Page 14: Chemical Systems & Equilibrium

constant

Page 15: Chemical Systems & Equilibrium

Reversible Reactions

For a given overall system composition, the same equilibrium concentrations are reached whether equilibrium is approached in the forward or the reverse direction

What about Keq will it be the same in fwd/rev?