chemical kinetics ch 13
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Chemical Kinetics Ch 13. We have learned that enthalpy is the sum of the internal energy plus the energy associated with the work done by the system (PV) on the atmosphere In addition, entropy and Gibb’s Free Energy predict whether a reaction will occur or not - PowerPoint PPT PresentationTRANSCRIPT
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Chemical Kinetics Ch 13
• We have learned that enthalpy is the sum of the internal energy plus the energy associated with the work done by the system (PV) on the atmosphere
• In addition, entropy and Gibb’s Free Energy predict whether a reaction will occur or not
• Now we will examine the rate at which a reaction will proceed
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Chemical Kinetics
Thermodynamics – does a reaction take place?
Kinetics – how fast does a reaction proceed?
Reaction rate is the change in the concentration of a reactant or a product with time (M/s).
A B
rate = -[A]t
rate = [B]t
[A] = change in concentration of A over time period t
[B] = change in concentration of B over time period t
Because [A] decreases with time, [A] is negative.
13.1
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A B
13.1
rate = -[A]t
rate = [B]t
time
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Br2 (aq) + HCOOH (aq) 2Br- (aq) + 2H+ (aq) + CO2 (g)
time
393 nmlight
Detector
[Br2] Absorption3
93 n
m
Br2 (aq)
13.1
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Br2 (aq) + HCOOH (aq) 2Br- (aq) + 2H+ (aq) + CO2 (g)
average rate = -[Br2]t
= -[Br2]final – [Br2]initial
tfinal - tinitial
slope oftangent
slope oftangent slope of
tangent
instantaneous rate = rate for specific instance in time13.1
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rate [Br2]
rate = k [Br2]
k = rate[Br2]
13.1
= rate constant
= 3.50 x 10-3 s-1
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2H2O2 (aq) 2H2O (l) + O2 (g)
PV = nRT
P = RT = [O2]RTnV
[O2] = PRT1
rate = [O2]t RT
1 Pt=
measure P over time
13.1
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2H2O2 (aq) 2H2O (l) + O2 (g)
13.1
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Reaction Rates and Stoichiometry
13.1
2A B
Two moles of A disappear for each mole of B that is formed.
rate = [B]t
rate = -[A]t
12
aA + bB cC + dD
rate = -[A]t
1a
= -[B]t
1b
=[C]t
1c
=[D]t
1d
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Write the rate expression for the following reaction:
CH4 (g) + 2O2 (g) CO2 (g) + 2H2O (g)
rate = -[CH4]
t= -
[O2]t
12
=[H2O]
t12
=[CO2]
t
13.1
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The Rate Law
13.2
The rate law expresses the relationship of the rate of a reaction to the rate constant and the concentrations of the reactants raised to some powers.
aA + bB cC + dD
Rate = k [A]x[B]y
reaction is xth order in A
reaction is yth order in B
reaction is (x +y)th order overall
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F2 (g) + 2ClO2 (g) 2FClO2 (g)
rate = k [F2]x[ClO2]y
Double [F2] with [ClO2] constant
Rate doubles
x = 1
Quadruple [ClO2] with [F2] constant
Rate quadruples
y = 1
rate = k [F2][ClO2]
13.2
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F2 (g) + 2ClO2 (g) 2FClO2 (g)
rate = k [F2][ClO2]
Rate Laws
• Rate laws are always determined experimentally.
• Reaction order is always defined in terms of reactant (not product) concentrations.
• The order of a reactant is not related to the stoichiometric coefficient of the reactant in the balanced chemical equation.
1
13.2
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Determine the rate law and calculate the rate constant for the following reaction from the following data:S2O8
2- (aq) + 3I- (aq) 2SO42- (aq) + I3
- (aq)
Experiment [S2O82-] [I-]
Initial Rate (M/s)
1 0.08 0.034 2.2 x 10-4
2 0.08 0.017 1.1 x 10-4
3 0.16 0.017 2.2 x 10-4
rate = k [S2O82-]x[I-]y
Double [I-], rate doubles (experiment 1 & 2)
y = 1
Double [S2O82-], rate doubles (experiment 2 & 3)
x = 1
k = rate
[S2O82-][I-]
=2.2 x 10-4 M/s
(0.08 M)(0.034 M)= 0.08/M•s
13.2
rate = k [S2O82-][I-]
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Definitions: 1st Order Reaction
• First Order Reaction: The reaction that occurs first, not always the one desired. For example, the formation of brown gunk in an organic prep.
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First-Order Reactions
13.3
A product rate = -[A]t
rate = k [A]
k = rate[A]
= 1/s or s-1M/sM
=[A]t
= k [A]-
[A] is the concentration of A at any time t
[A]0 is the concentration of A at time t=0
[A] = [A]0exp(-kt) ln[A] = ln[A]0 - kt
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Definitions: Physical Chemistry
• The pitiful attempt to apply y=mx+b to everything in the universe.
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Decomposition of N2O5
13.3
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Learn this equation & how to use
0[ ]ln
[ ]t
Nkt
N
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An Example
• A reaction is 25% complete in 42 seconds. Calculate the half life.
0[ ]ln
[ ]t
Nkt
N
Ln 1/.75=-.287, Div by 42 and k=6.84x10-3
T1/2 =0.693/k=101 s
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The reaction 2A B is first order in A with a rate constant of 2.8 x 10-2 s-1 at 800C. How long will it take for A to decrease from 0.88 M to 0.14 M ?
ln[A] = ln[A]0 - kt
kt = ln[A]0 – ln[A]
t =ln[A]0 – ln[A]
k= 66 s
[A]0 = 0.88 M
[A] = 0.14 M
ln[A]0
[A]
k=
ln0.88 M
0.14 M
2.8 x 10-2 s-1=
13.3
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First-Order Reactions
13.3
The half-life, t½, is the time required for the concentration of a reactant to decrease to half of its initial concentration.
t½ = t when [A] = [A]0/2
ln[A]0
[A]0/2
k=t½
ln2k
=0.693
k=
What is the half-life of N2O5 if it decomposes with a rate constant of 5.7 x 10-4 s-1?
t½ln2k
=0.693
5.7 x 10-4 s-1= = 1200 s = 20 minutes
How do you know decomposition is first order?
units of k (s-1)
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A product
First-order reaction
# of half-lives [A] = [A]0/n
1
2
3
4
2
4
8
16
13.3
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13.3
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Second-Order Reactions- ignore
13.3
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Summary of the Kinetics of Zero-Order, First-Orderand Second-Order Reactions
Order Rate LawConcentration-Time
Equation Half-Life
0
1
2
rate = k
rate = k [A]
rate = k [A]2
ln[A] = ln[A]0 - kt
1[A]
=1
[A]0
+ kt
[A] = [A]0 - kt
t½ln2k
=
t½ =[A]0
2k
t½ =1
k[A]0
13.3
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A + B C + D
Exothermic Reaction Endothermic Reaction
The activation energy (Ea) is the minimum amount of energy required to initiate a chemical reaction.
13.4
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Temperature Dependence of the Rate Constant also known as the Arrhenius equation
k = A • exp( -Ea/RT )
Ea is the activation energy (J/mol)
R is the gas constant (8.314 J/K•mol)
T is the absolute temperature
A is the frequency factor
lnk = -Ea
R1T
+ lnA
(Arrhenius equation)
13.4
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Activation Energy
• The useful quantity of energy available in one cup of coffee
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Zero-Order Reactions
13.3
A product rate = -[A]t
rate = k [A]0 = k
k = rate[A]0
= M/s[A]t
= k-
[A] is the concentration of A at any time t
[A]0 is the concentration of A at time t=0
t½ = t when [A] = [A]0/2
t½ =[A]0
2k
[A] = [A]0 - kt
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13.4
lnk = -Ea
R1T
+ lnA
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13.4
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A catalyst is a substance that increases the rate of a chemical reaction without itself being consumed.
k = A • exp( -Ea/RT ) Ea k
uncatalyzed catalyzed
ratecatalyzed > rateuncatalyzed
Ea < Ea‘ 13.6
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In heterogeneous catalysis, the reactants and the catalysts are in different phases.
In homogeneous catalysis, the reactants and the catalysts are dispersed in a single phase, usually liquid.
• Haber synthesis of ammonia
• Ostwald process for the production of nitric acid
• Catalytic converters
• Acid catalysis
• Base catalysis
13.6
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N2 (g) + 3H2 (g) 2NH3 (g)Fe/Al2O3/K2O
catalyst
Haber Process
13.6
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Ostwald Process
Hot Pt wire over NH3 solutionPt-Rh catalysts used
in Ostwald process
4NH3 (g) + 5O2 (g) 4NO (g) + 6H2O (g)Pt catalyst
2NO (g) + O2 (g) 2NO2 (g)
2NO2 (g) + H2O (l) HNO2 (aq) + HNO3 (aq)
13.6
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Catalytic Converters
13.6
CO + Unburned Hydrocarbons + O2 CO2 + H2Ocatalytic
converter
2NO + 2NO2 2N2 + 3O2
catalyticconverter
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Enzyme Catalysis
13.6
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uncatalyzedenzyme
catalyzed
13.6
rate = [P]t
rate = k [ES]