chemical kinetics

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Chemical Kinetics Chemical Kinetics The Binary Collision Model The Binary Collision Model actually have a hydrogen molecule bump into a chlo actually have a hydrogen molecule bump into a chlo cule to have chemistry occur. Reaction during such cule to have chemistry occur. Reaction during such ision ision might might look like the following picture: look like the following picture:

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Chemical Kinetics. The Binary Collision Model. Must actually have a hydrogen molecule bump into a chlorine molecule to have chemistry occur. Reaction during such a collision might look like the following picture:. H. H. H. H. Cl. Cl. Cl. Cl. Cl 2. H 2. +. Collision Frequency. - PowerPoint PPT Presentation

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Page 1: Chemical Kinetics

Chemical KineticsChemical Kinetics

The Binary Collision ModelThe Binary Collision Model

Must actually have a hydrogen molecule bump into a chlorineMust actually have a hydrogen molecule bump into a chlorinemolecule to have chemistry occur. Reaction during such a molecule to have chemistry occur. Reaction during such a collision collision mightmight look like the following picture: look like the following picture:

Page 2: Chemical Kinetics

HH22 ClCl22

HH HH

ClClClCl

HH

ClCl

HH

ClCl

++

Page 3: Chemical Kinetics

Collision FrequencyCollision Frequency

Real gases consist of particles of finite size that bump Real gases consist of particles of finite size that bump into each other at some finite rate.into each other at some finite rate.

Assume first that the red molecule has a constant speedAssume first that the red molecule has a constant speedC and the green ones are standing still. C and the green ones are standing still.

Page 4: Chemical Kinetics

ABAB==A A + + BB

2 2 A A

BB

ABAB==A A + + BB

VVc c = = ((ABAB))2 2 CC

If a green molecule has some piece in this volumeIf a green molecule has some piece in this volumeCollision!Collision!

Page 5: Chemical Kinetics

AA is the radius of molecule A, is the radius of molecule A, BB the radius of B the radius of B

ABAB = = AA + + BB

Page 6: Chemical Kinetics

There is one subtlety. In deriving z, we assumed the redThere is one subtlety. In deriving z, we assumed the redmolecule flew through a cloud of motionless green ones at a speedmolecule flew through a cloud of motionless green ones at a speedof C.of C.

In reality, of course, all the molecules are moving.In reality, of course, all the molecules are moving.

Where Where =m=mAA m mBB/(m/(mAA+m+mBB) )

is called the is called the reduced massreduced mass and can be thought of as a kind of and can be thought of as a kind of (geometric) average of the masses of A,B.(geometric) average of the masses of A,B.

<u<urelrel>> is the mean speed of molecule A with respect to molecule B.is the mean speed of molecule A with respect to molecule B.

Page 7: Chemical Kinetics

Bonus * Bonus * Bonus * Bonus * Bonus * BonusBonus * Bonus * Bonus * Bonus * Bonus * Bonus

Page 8: Chemical Kinetics

zNzNAA= = ((ABAB))2 2 <u<urelrel>> (N(NBB/V)N/V)NAA

By convention, because we don’t want our results to depend on By convention, because we don’t want our results to depend on the size or volume V of our experimental apparatus, we define Zthe size or volume V of our experimental apparatus, we define ZABAB::

ZZABAB is the total number of collisions between is the total number of collisions between allall A and A and allall B B

Molecules Molecules perper liter (or per ml depending on units used for V). liter (or per ml depending on units used for V).

Note that ZNote that ZABAB depends on 4 things: depends on 4 things:

Page 9: Chemical Kinetics

A Subtlety that arises when A=BA Subtlety that arises when A=B

When we multiply z by NWhen we multiply z by NAA we count the collisions of all A we count the collisions of all A

molecules with all B molecules. When A=B (all collisions molecules with all B molecules. When A=B (all collisions are of A with other A’s) this turns out to count all collisionsare of A with other A’s) this turns out to count all collisionstwice!twice!

Page 10: Chemical Kinetics

Thus, <uThus, <urelrel>=(2)>=(2)1/21/2(8kT/(8kT/mmAA))1/21/2

This gives:This gives:

ZZAAAA = (1/2) (2) = (1/2) (2)1/21/2 ((AAAA))22 (8kT/(8kT/mmAA))1/21/2 (N (NAA/V)/V)22

(8kT/(8kT/mmAA))1/2 1/2 is the average speed of a molecule even asis the average speed of a molecule even as

(3kT/m(3kT/mAA))1/2 1/2 is the root mean square speed of a molecule is the root mean square speed of a molecule

Page 11: Chemical Kinetics

Bonus * Bonus * Bonus * Bonus * Bonus * BonusBonus * Bonus * Bonus * Bonus * Bonus * Bonus

Page 12: Chemical Kinetics

Reaction Energy BarriersReaction Energy Barriers

TransitionTransitionStateState

ReactantsReactants

EE

HH22 + Cl + Cl22

EEAA

E E ∆H ∆H

ClCl

HH HH

ClCl

2HCl2HCl

ProductsProducts

Page 13: Chemical Kinetics

As a result, we are not interested in the total collision rate ZAs a result, we are not interested in the total collision rate ZABAB, ,

but rather how much energy is available in the collisionbut rather how much energy is available in the collisionwhich in turn depends on the relative speed of A,B approach.which in turn depends on the relative speed of A,B approach.

Even knowing how Z depends on energy is not Even knowing how Z depends on energy is not sufficient. We must also know the probability ofsufficient. We must also know the probability ofreaction at a given energy. reaction at a given energy.

Page 14: Chemical Kinetics

A very simple model for PA very simple model for PRR is the “all or nothing” is the “all or nothing”

model where Pmodel where PRR(E)=0, E<E(E)=0, E<EAA and P and PRR(E)=1, E(E)=1, E>>EEAA..

By convention PBy convention PRR is associated with the collision is associated with the collision

““cross section” (cross section” (ABAB))22::

The reaction cross section, The reaction cross section, ((RR))22, is the , is the

product of the reaction probability, product of the reaction probability, PPRR, ,

at a given energy and the collision cross at a given energy and the collision cross

section, section, ((ABAB))22 ..

Page 15: Chemical Kinetics

PPRR(E) = 0 when E(E) = 0 when E<<EEAA

PPRR(E) = (1-E(E) = (1-EAA/E) when E>E/E) when E>EAA

ReactionReaction “Cross Section” “Cross Section” RR22

A + B A + B Products ProductsAll or Nothing ModelAll or Nothing Model

EEAA

EE00

11

PPRR

RR22 = P = PRRABAB

22

Page 16: Chemical Kinetics

RR

22 ==PPRR ABAB

22 PPRR=0=0 E≤EE≤EAA

Arrhenius ModelArrhenius Model

EEAA 2E2EAA 3E3EAA 10 E10 EAA

1/21/2

11PPRR

PPRR=(1-E=(1-EAA/E)/E) E>EE>EAA

EE

PPR R = 0.9, E=10E= 0.9, E=10EAA

PPR R = 1, E>>>E= 1, E>>>EAA