chapter 9 chemical bonding. section 9.1: why does bonding occur in the first place? bonding lowers...
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Chapter 9Chemical Bonding
Section 9.1: Why does bonding occur in the first place?
Bonding lowers the potential energy between positive and negative particles (p341).
What is potential energy?
1 type of Potential Energy: Gravitational P.E.
Ball On Top of a Hill
P.E. = mgh
h
m
Energy changes forms: P.E. Kinetic Energy (K.E.)
Section 9.1: Why does bonding occur in the first place?
Bonding lowers the potential energy between positive and negative particles (p341).
Energy changes forms
MechanicalEnergy
ElectricalEnergy
ChemicalEnergy
Light (Radiant)Energy
Heat (Thermal)Energy
Friction
EnginesGenerator
Motor
BatteryCharger
Battery
Photosynthesis
Chemiluminescence
SolarHeaterFIre
Section 9.1: Why does bonding occur in the first place?
Bonding lowers the potential energy between positive and negative particles (p341).
When chemical bonds form: Chemical P.E. changes to Heat Energy & Light Energy
MechanicalEnergy
ElectricalEnergy
ChemicalEnergy
Light (Radiant)Energy
Heat (Thermal)Energy
Section 9.1: Why does bonding occur in the first place?
http://chemsite.lsrhs.net/chemKinetics/PotentialEnergy.html
Bonding lowers the potential energy between positive and negative particles (p341).
Energy changes forms: Chemical P.E. Heat & Light Energy
Section 9.1: Three Type of Bonds
http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch10/non.php
Ionic bonding: Metal + Nonmetal (Valence e- transferred)Covalent bonding: Nonmetal + Nonmetal (Valence e- shared)Metallic bonding: Metal + Metal (“Sea” of e-)
Review: Valence Electrons – e- involved in forming compounds (Ch 8, p315)
Boron (B) Magnesium (Mg) Hydrogen (H)
How many valence e-?
How many needed for full outer shell?
Total valance e-:
Concept Check
Section 9.1: Two Bond Types With Localized Electrons
Ionic & Covalent Bonding
Representative Elements
Transition Elements
For REPRESENTATIVE elements:• period (row) = shell # (n = 1, 2, 3, 4….n)• group (column) = # of e- in outer shell
Group # # of valence e-
IA 1
IIA 2IIIA 3
IVA 4
VA 5
VIA 6
VIIA 7
VIIA 8
Shellsof anatom
Section 9.1: Two Bond Types With Localized Electrons
Ionic & Covalent Bonding: Why do ionic bonds form instead of covalent bonds, and vice versa?
Covalent Bonds Ionic Bonds
“Bonding Continuum”
nonmetals + nonmetal metal + nonmetal
Polar Covalent BondNonpolar Covalent Bond Ionic Bond
Electrons are shared unequally. Electrons are transferred.
Extent of electron sharing in Covalent Bonds
e-’s shared between atomsof the same element:
Equal Sharing
e-’s shared between atomsof different elements:
Unequal Sharing
Unequal sharing – occurs because one of the atoms in a bond has a stronger attraction for the pair of e-’s than does the other atom
Why does one atom have a stronger attraction for e-?
Definition: electronegativity (E.N) – the ability of an atom to attract the shared electrons
Increasing E.N.D
ecre
asin
g E
.N.
Electronegativity
Rule for Bond FormationThe atom with the greater E.N. pulls the shared electrons closer to its nucleus resulting in (1) – charge on high E.N. atom (2) + charge on low E.N. atom
More later: Section 9.5
Covalent Bonds Ionic Bonds
“Bonding Continuum”
e- sharing2 nonmetals
e- transfermetal + nonmetal
E.N. difference > 1.70.4 < E.N. < 1.7 1.70.4 < E.N. Polar ColvalentNonpolar Colvalent
Why do ionic bonds form instead of covalent bonds, and vice versa?
Example: Oxygen (O) bonds withMagnesium (Mg): MgO
E.N. of O = 3.5E.N. of Mg = 1.2
E.N. difference = 2.3
Answer: Electronegativity Differences
Section 9.1: “The Other” Bond Type With Delocalized Electrons
Metallic Bonding
A messy “sea” of electrons
Metallic Bonding - Delocalized Covalent Bonding, Ionic Bonding - Delocalized
Electrons fit neatly into shells.
Section 9.1: “The Other” Bond Type With Delocalized Electrons
Metallic Bonding
A messy “sea” of electrons
Metallic Bonding - Delocalized
Outer e-
Inner e-
Lewis Electron-Dot Symbols
(1) Element symbol – nucleus + inner electronsEx: The element lithium has an element symbol Li
(2) Surrounding dots – valence electrons (outer most shell)
Two parts:
Li
Different elements can have the same number of dots
Be
Mg
Same Group(Column)
Review: Ions
Ion – charged particles that form when an atom gains or loses one or more electrons(Ch2, p60)
Mg
Cl Cl-
Mg2+
Element Ion Ion Type
Cation
Anion
Review: Electron Configuration and Orbital Diagrams (Ch8, p304-317)
MgExample:
Concept Check
• End of Chapter Problems in-class (for now):
9.7, 9.9, 9.13, 9.15
Write the ion for the following elements: K, Br, Sr, Ar, O
For example, the ion for Mg is Mg2+.
• Suggested Optional Practice Problems (for outside of class):
9.6, 9.8, 9.10, 9.12, 9.14 (Answers in back of book or online)
Section 9.2: Ionic Bonding
Central idea: Electrons are transferred from metal atoms to nonmetal atoms to form ions that come together in a solid ionic compound.
HH
O O OC
Examples: Water (H2O) Carbon Dioxide (CO2)
Sodium chloride (NaCl)
Contrast with molecules formed during covalent bonding (more later).
Na – metal
Cl - nonmetal
Solid Ionic compound
Rule: The total number of e- lost by the metal atom equals the total number gained by the nonmetal atom.
Section 9.2: Ionic Bonding
Cl-Na+
lost gained
Why is the melting point of MgO higher than the melting point of KCl?
Behavior of Ionic Compounds
Lattice Energy(∆Hº
lattice)
Section 9.2: Lattice Energy
Definition – The enthalphy change that occurs when 1 mol of ionic solid separates into gaseous ions.
For Review of Enthalpy: Ch6, p243
Lattice Energy denoted as: ∆Hºlattice
∆Hºlattice cannot be measured directly, BUT it can be calculate using the:
Born-Haber cycle
Section 9.2: Born-Haber Cycle
Uses Hess’s Law: Total enthalpy of an overall reaction is the sum of the enthalpy changes of individual reactions. (∆Htotal = ∆Hrxn1 + ∆Hrxn2 +……….)
*Not actual steps.
Section 9.2: Trends in Lattice Energy
Coulomb’s Law (Ch2)
Section 9.2: Trends in Lattice Energy
So, why is the melting point of MgO higher than the melting point of KCl?
Behavior of Ionic Compounds
Concept Check
• End of Chapter Problems in-class (for now):
9.27, 9.30
• Suggested Optional Practice Problems (for outside of class):
9.26, 9.28 (Answers in back of book)
Problem 9.30
Section 9.3: Covalent Bonding
HH
O O OC
Examples: Water (H2O) Carbon Dioxide (CO2) Organic Compounds
Contrast with ionic solids formed during ionic bonding (discussed previously).
Sodium chloride (NaCl)
Na – metal
Cl - nonmetal
Nonmetal + Nonmetal
C C C H
H
HH
H
H
H
H
e- sharing – primary way that atoms interact
Section 9.3: Covalent Bonding
Why do covalent bonds form?
Lower P.E. = More stable
Section 9.3: Covalent Bonding
How are the electrons distributed?
ElectronDensity
• Bonding Pairs & Lone Pairs
• Bond Type – double, single, triple
In order for each atom to have a full outer shell (2 e- for H, He; 8 e- for others), the electrons arrange themselves in certain configurations:
Section 9.3: Covalent Bonding
Bond Energy (B.E.) – aka Bond Enthalpy or Bond Strength
Covalent Bond Strength – depends on strength of attraction between nuclei and shared electrons
Bond Energy – energy needed to overcome attraction and
break the bond
Section 9.3: Covalent Bonding
Bond Energy (B.E.)
Bond formation is exothermic: ∆Hº always +
Bond breakage is endothermic: ∆Hº always -
Absolute value of B.E. – Each bond has its own unique B.E. due to variations in:(1) e- density(2) charge(3) atomic radii
Section 9.3: Covalent Bonding
Strength of Bond different than E required to pull atoms apart (B.E.)
Weaker Bonds =Higher Energy
“Shallow Energy Well”
Stronger Bonds =Lower Energy
“Deeper Energy Well”
Less E needed to break.
Lower B.E.
More E needed to break.
Higher B.E.
Section 9.3: Covalent Bonding
Bond Energy (B.E.) and Bond Length
Bond Length – sum of the radii of the bonded atoms (analogous to distance in Coloumb’s Law)
At minimum E point.
R2 = 0.3155
0
50
100
150
200
250
300
150 250 350 450 550
Bond Energy
Bo
nd
Le
ng
th
Section 9.3: Covalent Bonding
Bond Energy (B.E.) and Bond Length
This relationshipholds, in general,ONLY for single
bonds.
Section 9.3: Covalent Bonding
Bond Type (Single, Double, Triple) also matters
Nuclei more attracted to 2 shared pairs of e- than one shared pair of e-.
Higher bond order = Shorter bond length = Higher Bond Energy
Same twoelements,
different B.E.
Section 9.3: Covalent Bonding
Periodic Table Trends Without Detailed Bond Lengths
The closer theatoms, the
stronger the bond.
Bond Energy:C—F > C—Cl > C—Br
Section 9.3: Covalent Bonding
Covalent Bonds are stronger than Ionic Bonds
So why, then, do covalent compounds have lower melting pointsthan ionic compounds?
Example: CCl4 m.p. = -23 ºC NaCl m.p. = 800 ºC
solid liquid gas
Strong covalent bonding forcesHold atoms together
Weak intermolecular forcesHold molecules together
(More in Chapter 12)
Chemical Reaction Phase Change
HH
O
-
++
Section 9.4: Bond Energy and Chemical Change
http://chemsite.lsrhs.net/chemKinetics/PotentialEnergy.html
Where does the heat that is released come from?
Section 9.4: Bond Energy and Chemical Change
Total energy of a chemical system = K.E. + P.E.
Example of a chemical system
A container filled with molecules.
Kinetic Energy (K.E.)
Three types:(1) Vibrational(2) Rotational(3) Translational
• Does not change during chemical reaction (depends on T). Changes during a Phase Change (Chapter 12).
solid liquid gashttp://www.landfood.ubc.ca/courses/fnh/301/water/motion.gif
Section 9.4: Bond Energy and Chemical Change
This leaves us with changes in P.E. during chemical reactions.
P.E. contributions can from electrostatic forces between:Separate Vibrating Atoms Nucleus & Electrons in AtomsProtons & Neutrons in NucleusNuclei and Shared Electron Pair in Each Bond = Bond Energy
Where does the heat that is released come from?
The energy released or absorbed during a chemical change is due to thedifferences between the reactant bond energies and the product bond energies.
B.E.reactants - B.E.products = Heat
Section 9.4: Bond Energy and Chemical Change
∆Hºrxn = ∆Hºreactant bonds broken + ∆Hºproduct bonds formed
Heat of reaction, ∆Hºrxn
(∆Hºtotal = ∆Hºrxn1 + ∆Hºrxn2 +……+ ∆Hºlattice)
Lattice Energy, ∆Hºlattice Born-Haber cycle
Analogous to ionic compound formation:
Exothermic reaction: - ∆Hºrxn
Endothermic reaction: + ∆Hºrxn
∆Hºrxn = ∆BEreactant bonds broken – ∆BEproduct bonds formed
Section 9.4: Bond Energy and Chemical Change
Example: H2 + F2 2 HF
Weaker BondsLess Stable, More Reactive
H2 and F2
Stronger BondMore Stable, Less Reactive
HF
Section 9.4: Bond Energy and Chemical Change
Another way to looks at this reaction: H2 + F2 2 HF
∆Hºrxn = ∆Hºreactant bonds broken + ∆Hºproduct bonds formed
Heat of reaction, ∆Hºrxn
H2 + F2
2 H + 2 F
HF
Section 9.4: Bond Energy and Chemical Change
Use bond energies to calculate ∆Hºrxn (Table 9.2)
H2 + F2 2 HF 9.39, 9.47, 9.49
Optional Homework Problems: 9.38, 9.46, 9.48, 9.50
Section 9.4: Bond Energy and Chemical Change
Application: Energy Released From Combustion of Fuel
∆Hºrxn = ∆BEreactant bonds broken – ∆BEproduct bonds formed
Energy Released = B.E.(fuel + O2) – B.E.(CO2 + H2O)
Fuels with more weak bonds yield more energy than fuels with fewer weak bonds.
Food fuels the body:
Fats:MoreC-HC-C
Carbs:MoreO-HC-O
Section 9.5: Between the Extremes
Scientific models are idealized descriptions of reality.
Electronegativity – the relative ability of a bonded atom to attract the shared e-
Covalent Bonds Ionic Bonds
“Bonding Continuum”
e- sharing2 nonmetals
e- transfermetal + nonmetal
E.N. difference > 1.70.4 < E.N. < 1.7 1.70.4 < E.N. Polar ColvalentNonpolar Colvalent
Electronegativity – inversely related to atomic size (radius) WHY?
Section 9.5: Between the Extremes
atomic size E.N.
Section 9.5: Between the Extremes
Nonmetals are more electronegative than metals.
Section 9.5: Between the Extremes
Electronegativity and Oxidation Number (O.N.) (Review of O.N.: Section 4.5)
Oxidation-reduction (redox) reactions: The net movement of electrons from onereactant to the other.
Oxidation – the loss of e- (LEO), Reduction – the gain of e- (GER) “LEO the lions says GER!”
Oxidizing agent – becomes reduced; Reducing agent – becomes oxidized
Which element is oxidized? Reduced? Which is the oxidizing agent? Reducing agent?
Oxidation Number and Electronegativity
When dead organisms (such as plankton) fall to the bottom of the sea, theirdead bodies are eaten (respiration) by bacteria living in the ocean sediments:
CH2O + O2 CO2 + H2O
What might be a problem for bacteria trying to eat CH2O deep in sediments?
In addition to O2: SO42- and NO3
2- are present in the sediments.
Which might they use?
Section 9.5: Between the Extremes
Electronegativity and Oxidation Number (O.N.)
E.N. is used to determine an atom’s O.N. in a given bond.
(1)The more E.N. atom in a bond is assigned ALL the SHARED e-; The lessE.N. atoms is assigned NONE
Example: HCl Cl: 8 H: 0
(2) O.N. = # valence e- - # shared e-
Example: O.N.Cl = 7 – 8 = -1 O.N.H = 1 – 0 = +1
Section 9.5: Between the Extremes
Polar Covalent Bonds
Covalent Bonds Ionic Bonds
“Bonding Continuum”
e- sharing2 nonmetals
e- transfermetal + nonmetal
E.N. difference > 1.70.4 < E.N. < 1.7 1.70.4 < E.N. Polar ColvalentNonpolar Colvalent
This bond type is indicated by:
(1)polar arrow ( ) pointing toward negative pole H–F
(2)delta symbol ()
HH
O
-
++
Covalent Bonds Ionic Bonds
“Bonding Continuum”
e- sharing2 nonmetals
e- transfermetal + nonmetal
E.N. difference > 1.70.4 < E.N. < 1.7 1.70.4 < E.N. Polar ColvalentNonpolar Colvalent
Section 9.5: Between the Extremes
Polar Covalent vs. Nonpolar Covalent
Section 9.5: Between the Extremes
Partial Ionic Character – related directly to the electronegativity difference (∆EN)
Why?
A greater ∆EN results in larger partial charges () and a higher partial ionic character.
Example: HCl, LiCl, Cl2
Arrange these compounds in order of least to most partial ionic character.
Section 9.5: Between the Extremes
Two approaches for getting a sense of a compound’s ionic character:
#1: Arbitrary cutoffs used in bonding continuum.
Covalent Bonds Ionic Bonds
“Bonding Continuum”
e- sharing2 nonmetals
e- transfermetal + nonmetal
E.N. difference > 1.70.4 < E.N. < 1.7 1.70.4 < E.N. Polar ColvalentNonpolar Colvalent
Section 9.5: Between the Extremes
Two approaches for getting a sense of a compound’s ionic character:
#2: Calculate the percent ionic character (increases with ∆EN)
Compare actual behavior of a polar molecule in an electric field with thebehavior it would show if the e- were completely transferred (pure ionic).
50 % is dividing line.
Notice: Cl2 is 0% ionic, but no molecule has 100 % ionic character (e- sharingoccurs to some extent in every bond.
Section 9.5: Between the Extremes
Notice, now: Why metal that bond with nonmetals form ionic bonds. Why nonmetals that bond with other nonmetals form covalent bonds.
Section 9.5: Between the Extremes
Properties of substances are indicative of their ionic or covalent character.
Section 9.6: Metallic Bonding (More in Chap 12)
Electron Sea Model
In reactions with nonmetals, metals (Na) transfer their outer e- to form ionic solids (NaCl).
What holds together bonded metals (Na)? All metal atoms contribute their valence e-,which are shared among all the atoms in a sample.
A messy “sea” of electrons
Metallic Bonding - Delocalized Covalent Bonding, Ionic Bonding - Localized
Electrons fit neatly into shells.
Alloys - more than one metal element involved in a metallic “sea”
Properties of metal substances are explained by the electron sea model.
Most metals are solids.
High m.p. = attractions b/w cations and anions need not be broken
Much higher b.p. = attractions b/w cations and anions broken
m.p. depends on # of valence e-:
Section 9.6: Metallic Bonding (More in Chap 12)
Problems for today
9.62, 9.64, 9.66
What would you expect the B.E. of a H–F bond to be given that:H–H = 432 kJ/molF–F = 159 kJ/mol ?