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Chapter 5 The Second Law of Thermodynamics 5/7/2012 8:46 AM Dr. Mohammad Abuhaiba, PE 1

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  • Chapter 5

    The Second Law of

    Thermodynamics

    5/7/2012 8:46 AM

    Dr. Mohammad Abuhaiba, PE 1

  • Objectives of this chapter

    Introduce 2nd law of

    thermodynamics (SLT).

    Corollaries of 2nd law are also

    considered, including performance

    limits for thermodynamic cycles.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    Consider the three systems pictured in Fig. 5.1.

    Fig. 5.1a: In conformity with the conservation of energy principle, the decrease

    in internal energy of body would appear as an increase in internal energy of

    surroundings.

    The inverse process would not take place spontaneously, even though energy

    could be conserved: The internal energy of surroundings would not decrease

    spontaneously while body warmed from T0 to its initial temperature.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    System b: Air held at a high pressure pi in a closed tank would flow spontaneously

    to lower pressure surroundings at p0 if the interconnecting valve were opened.

    Eventually fluid motions would cease and all of air would be at same pressure as

    the surroundings.

    The inverse process would not take place spontaneously, even though energy

    could be conserved: Air would not flow spontaneously from surroundings at p0 into

    the tank, returning pressure to its initial value.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    System c: A mass suspended by a cable at elevation zi would fall when released.

    When it comes to rest, potential energy of mass in its initial condition would

    appear as an increase in the internal energy of the mass and its surroundings, in

    accordance with the conservation of energy principle.

    Eventually, mass also would come to the temperature of its much larger

    surroundings.

    The inverse process would not take place spontaneously, even though energy

    could be conserved: The mass would not return spontaneously to its initial

    elevation while its internal energy or that of its surroundings decreased.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    Initial condition of a system can be restored, but not in

    a spontaneous process.

    Some auxiliary devices would be required.

    By such auxiliary means:

    object could be reheated to its initial temperature

    air could be returned to tank and restored to its initial

    pressure

    mass could be lifted to its initial height

    In each case, a fuel or electrical input normally would

    be required for the auxiliary devices to function.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    Not every process consistent with the

    principle of energy conservation can

    occur.

    Generally, an energy balance alone:

    neither enables the preferred direction to be

    predicted

    nor permits processes that can occur to be

    distinguished from those that cannot.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    When left to themselves, systems tend to undergo

    spontaneous changes until a condition of equilibrium

    is achieved, both internally and with their surroundings.

    In some cases equilibrium is reached quickly

    in others it is achieved slowly

    Whether process is rapid or slow, it must of course

    satisfy conservation of energy

    However, that alone would be insufficient for

    determining the final equilibrium state.

    Another general principle is required. Second law.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    OPPORTUNITIES FOR DEVELOPING WORK

    Fig. 5.1a: Instead of permitting the body to cool spontaneously

    with no other result, energy could be delivered by heat transfer to

    a system undergoing a power cycle that would develop a net

    amount of work.

    Fig. 5.1b: instead of permitting the air to expand aimlessly into the

    lower-pressure surroundings, the stream could be passed through

    a turbine and work could be developed.

    Fig. 5.1c: instead of permitting the mass to fall in an uncontrolled

    way, it could be lowered gradually while turning a wheel, lifting

    another mass.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    OPPORTUNITIES FOR DEVELOPING WORK

    When an imbalance exists between two systems, there is an opportunity

    for developing work that would be irrevocably lost if the systems were

    allowed to come into equilibrium in an uncontrolled way.

    Recognizing this possibility for work, we can pose two questions:

    1. What is the theoretical max value for work that could be obtained?

    2. What are the factors that would preclude the realization of max value?

    Devices would be subject to factors such as friction that would preclude

    the attainment of the theoretical max work.

    2nd law of thermodynamics provides means for determining theoretical

    max and evaluating quantitatively factors that preclude attaining the max.

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  • 5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law

    SECOND LAW SUMMARY

    2nd law & deductions are useful because they provide means for

    1. predicting direction of processes.

    2. establishing conditions for equilibrium.

    3. determining best theoretical performance of cycles, engines, and

    other devices.

    4. evaluating quantitatively factors that preclude attainment of best

    theoretical performance level.

    5. defining a temperature scale independent of properties of any

    thermometric substance.

    6. developing means for evaluating properties such as u and h in terms

    of properties that are more readily obtained experimentally.

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  • 5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law

    CLAUSIUS STATEMENT

    It is impossible for any system to operate in such a way

    that the sole result would be an energy transfer by

    heat from a cooler to a hotter body.

    It is impossible to construct a refrigeration cycle that operates

    without an input of work.

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  • 5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law

    KELVIN–PLANCK STATEMENT

    A thermal reservoir: a special kind of system that always remains at

    constant temperature even though energy is added or removed by heat

    transfer.

    earth’s atmosphere

    large bodies of water (lakes, oceans)

    large block of copper

    system consisting of two phases (although the ratio of the masses of the two

    phases changes as the system is heated or cooled at constant pressure, the

    temperature remains constant as long as both phases coexist).

    Extensive properties of a thermal reservoir such as internal energy can

    change in interactions with other systems even though the reservoir

    temperature remains constant.

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  • 5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law

    KELVIN–PLANCK STATEMENT

    A thermodynamic cycle: a sequence of processes that

    begins and ends at the same state.

    At the conclusion of a cycle all properties have the

    same values they had at the beginning.

    Over the cycle the system experiences no net change

    of state.

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  • 5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law

    KELVIN–PLANCK STATEMENT

    It is impossible for any system to operate

    in a thermodynamic cycle and deliver a

    net amount of energy by work to its

    surroundings while receiving energy by

    heat transfer from a single thermal

    reservoir.

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  • 5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law

    KELVIN–PLANCK STATEMENT

    1st and 2nd laws each impose constraints:

    1st law: According to the cycle energy

    balance

    Although the cycle energy balance allows

    the net work Wcycle to be positive or

    negative, the 2nd law imposes a constraint

    on its direction.

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  • 5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law

    KELVIN–PLANCK STATEMENT

    A system undergoing a cycle while communicating

    thermally with a single reservoir cannot deliver a net

    amount of work to its surroundings. That is, the net

    work of the cycle cannot be positive.

    Analytical form of the Kelvin–Planck statement

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    An irreversible process: system and all

    parts of its surroundings cannot be

    exactly restored to their respective initial

    states after the process has occurred.

    A reversible process: both system and

    surroundings can be returned to their

    initial states.

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    A system that has undergone an irreversible process is not necessarily precluded from being restored to its initial state.

    While the system restored to its initial state, it would not be possible also to return the surroundings to the state they were in initially.

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    From Clausius statement of 2nd law, any process involving a spontaneous heat transfer from a hotter body to a cooler body is irreversible.

    Friction, electrical resistance, hysteresis, and inelastic deformation are examples of effects whose presence during a process renders it irreversible.

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    Irreversibilities can be divided into two

    classes:

    1. Internal irreversibilities: occur within the

    system.

    2. External irreversibilities: occur within the

    surroundings.

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    Consider two bodies at different temperatures that are able to

    communicate thermally.

    With a finite temperature difference between them, a

    spontaneous heat transfer would take place and, this would be a

    source of irreversibility.

    The importance of this irreversibility would diminish as the

    temperature difference approaches zero.

    The transfer of a finite amount of energy by heat between bodies

    whose temperatures differ only slightly would require a

    considerable amount of time, a larger heat transfer surface area,

    or both.

    To eliminate this source of irreversibility, therefore, would require

    an infinite amount of time and/or an infinite surface area.

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    Irreversibility of the process can be demonstrated using

    Kelvin–Planck statement of 2nd law and the following

    procedure:

    1. Assume there is a way to return the system and

    surroundings to their respective initial states.

    2. It would be possible to devise a cycle that produces

    work while no effect occurs other than a heat transfer

    from a single reservoir. Since the existence of such a

    cycle is denied by Kelvin–Planck statement, initial

    assumption must be in error and it follows that the

    process is irreversible.

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  • 5.2 Identifying irreversibility REVERSIBLE PROCESSES

    A process of a system is reversible if

    the system and all parts of its

    surroundings can be exactly restored

    to their respective initial states after

    the process has taken place.

    The passage of a gas through a

    properly designed nozzle or diffuser

    is an example.

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  • 5.2 Identifying irreversibility IRREVERSIBLE PROCESSES

    INTERNALLY REVERSIBLE PROCESSES

    An internally reversible process: one in which there are no irreversibilities

    within the system.

    At every intermediate state of an internally reversible process of a closed

    system, all intensive properties are uniform throughout each phase

    present.

    Temperature, pressure, specific volume, and other intensive properties do not

    vary with position.

    Internally reversible process consists of a series of equilibrium states: It

    is a quasiequilibrium process.

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  • Applying 2nd Law to Thermodynamic Cycles 5.3.1 Interpreting the Kelvin–Planck Statement

  • Applying 2nd Law to Thermodynamic Cycles 5.3.2 Power Cycles Interacting with Two Reservoirs

    Thermal efficiency of cycle is

    If value of QC were zero, the system would withdraw energy QH from hot reservoir and produce an equal amount of work, while undergoing a cycle. Thermal efficiency of such a cycle would be 100%.

    This method of operation would violate Kelvin–Planck statement and thus is not allowed.

    For any system executing a power cycle while operating between two reservoirs, only a portion of QH can be obtained as work, and the remainder, QC, must be discharged by heat transfer to the cold reservoir.

    Thermal efficiency must be less than 100%.

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  • Applying 2nd Law to Thermodynamic Cycles 5.3.2 Power Cycles Interacting with Two Reservoirs

    CARNOT COROLLARIES

    1. Thermal efficiency of an irreversible power

    cycle is always less than thermal efficiency

    of a reversible power cycle when each

    operates between same two thermal

    reservoirs.

    2. All reversible power cycles operating

    between same two thermal reservoirs have

    same thermal efficiency.

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  • Applying 2nd Law to Thermodynamic Cycles 5.3.3 Refrigeration and Heat Pump Cycles Interacting with Two Reservoirs

    Coefficient of

    performance of a

    refrigeration cycle

    Coefficient of

    performance for a heat

    pump cycle is

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  • Applying 2nd Law to Thermodynamic Cycles 5.3.3 Refrigeration and Heat Pump Cycles Interacting with Two Reservoirs

    As Wcycle tends to zero, coefficients of

    performance approach infinity.

    If Wcycle were identically zero, system would

    withdraw energy QC from the cold reservoir

    and deliver energy QC to the hot reservoir,

    while undergoing a cycle.

    This method of operation would violate

    Clausius statement of 2nd law and thus is not

    allowed.

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  • Applying 2nd Law to Thermodynamic Cycles 5.3.3 Refrigeration and Heat Pump Cycles Interacting with Two Reservoirs

    Corollaries for Refrigeration & Heat Pump Cycles

    Coefficient of performance of an irreversible

    refrigeration cycle is always less than

    coefficient of performance of a reversible

    refrigeration cycle when each operates

    between same two thermal reservoirs.

    All reversible refrigeration cycles operating

    between same two thermal reservoirs have

    same coefficient of performance.

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  • Maximum Performance Measures for Cycles

    Operating Between Two Reservoirs 5.5.1 Power Cycles

    Thermal efficiency of a system

    undergoing a reversible power cycle

    while operating between thermal

    reservoirs at temperatures TH and TC.

    Carnot efficiency increases as TH

    increases and/or TC decreases.

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  • Maximum Performance Measures for Cycles

    Operating Between Two Reservoirs 5.5.1 Power Cycles

    Possibility of increasing thermal

    efficiency by reducing TC below

    that of the environment is not

    practical,

    For maintaining TC lower than

    ambient temperature would

    require a refrigerator that

    would have to be supplied work

    to operate.

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  • Maximum Performance Measures for Cycles

    Operating Between Two Reservoirs 5.5.1 Power Cycles

    Referring to segment a–b of the curve, where TH and h are relatively low,

    h increases rapidly as TH increases, even a small increase in TH can have a large effect on efficiency.

    Thermal efficiencies of actual cycles increase as average temperature at which energy is added by heat transfer increases and/or average temperature at which energy is discharged by heat transfer is reduced.

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  • Maximum Performance Measures for Cycles

    Operating Between Two Reservoirs 5.5.2 Refrigeration and Heat Pump Cycles

    Coefficient of performance of any system

    undergoing a reversible refrigeration cycle while

    operating between the two reservoirs

    Coefficient of performance of any system

    undergoing a reversible heat pump cycle while

    operating between the two reservoirs

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  • EXAMPLE 5.1

    Evaluating a Power Cycle Performance Claim

    An inventor claims to have developed a power cycle capable of delivering a net work output of 410 kJ for an energy input by heat transfer of 1000 kJ. The system undergoing the cycle receives the heat transfer from hot gases at a temperature of 500 K and discharges energy by heat transfer to the atmosphere at 300 K. Evaluate this claim.

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  • EXAMPLE 5.2

    Evaluating Refrigerator Performance

    By steadily circulating a refrigerant at low temperature through passages in the walls of freezer compartment, a refrigerator maintains freezer compartment at -5°C when air surrounding refrigerator is at 22°C. The rate of heat transfer from freezer compartment to refrigerant is 8000 kJ/h and power input required to operate the refrigerator is 3200 kJ/h. Determine coefficient of performance of refrigerator and compare with coefficient of performance of a reversible refrigeration cycle operating between reservoirs at the same two temperatures.

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  • EXAMPLE 5.3 Evaluating Heat Pump Performance

    A dwelling requires 5×105 kJ per day to maintain

    its temperature at 22°C when the outside temperature is 10°C. If an electric heat pump is used to supply this energy, determine the

    minimum theoretical work input for one day of

    operation, in kJ.

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  • Carnot Cycle

    a reversible power cycle

    operating between two

    thermal reservoirs.

    The system is a gas in a

    piston cylinder assembly.

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  • Carnot Cycle

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  • Carnot Cycle

    Area under adiabatic process line 1–2 = work done per unit of mass to compress the gas.

    Areas under process lines 2–3 and 3–4 = work done per unit of mass by the gas as it expands in these processes.

    Area under process line 4–1 = work done per unit of mass to compress the gas.

    The enclosed area on p–v diagram = net work developed by the cycle per unit of mass.

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  • Carnot Cycle

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  • Home Work Assignment H15-1

    18, 23, 29, 33, 35, 42, 46

    Due Saturday 28/4/2012

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