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Chapter 5
The Second Law of
Thermodynamics
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Objectives of this chapter
Introduce 2nd law of
thermodynamics (SLT).
Corollaries of 2nd law are also
considered, including performance
limits for thermodynamic cycles.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
Consider the three systems pictured in Fig. 5.1.
Fig. 5.1a: In conformity with the conservation of energy principle, the decrease
in internal energy of body would appear as an increase in internal energy of
surroundings.
The inverse process would not take place spontaneously, even though energy
could be conserved: The internal energy of surroundings would not decrease
spontaneously while body warmed from T0 to its initial temperature.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
System b: Air held at a high pressure pi in a closed tank would flow spontaneously
to lower pressure surroundings at p0 if the interconnecting valve were opened.
Eventually fluid motions would cease and all of air would be at same pressure as
the surroundings.
The inverse process would not take place spontaneously, even though energy
could be conserved: Air would not flow spontaneously from surroundings at p0 into
the tank, returning pressure to its initial value.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
System c: A mass suspended by a cable at elevation zi would fall when released.
When it comes to rest, potential energy of mass in its initial condition would
appear as an increase in the internal energy of the mass and its surroundings, in
accordance with the conservation of energy principle.
Eventually, mass also would come to the temperature of its much larger
surroundings.
The inverse process would not take place spontaneously, even though energy
could be conserved: The mass would not return spontaneously to its initial
elevation while its internal energy or that of its surroundings decreased.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
Initial condition of a system can be restored, but not in
a spontaneous process.
Some auxiliary devices would be required.
By such auxiliary means:
object could be reheated to its initial temperature
air could be returned to tank and restored to its initial
pressure
mass could be lifted to its initial height
In each case, a fuel or electrical input normally would
be required for the auxiliary devices to function.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
Not every process consistent with the
principle of energy conservation can
occur.
Generally, an energy balance alone:
neither enables the preferred direction to be
predicted
nor permits processes that can occur to be
distinguished from those that cannot.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
When left to themselves, systems tend to undergo
spontaneous changes until a condition of equilibrium
is achieved, both internally and with their surroundings.
In some cases equilibrium is reached quickly
in others it is achieved slowly
Whether process is rapid or slow, it must of course
satisfy conservation of energy
However, that alone would be insufficient for
determining the final equilibrium state.
Another general principle is required. Second law.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
OPPORTUNITIES FOR DEVELOPING WORK
Fig. 5.1a: Instead of permitting the body to cool spontaneously
with no other result, energy could be delivered by heat transfer to
a system undergoing a power cycle that would develop a net
amount of work.
Fig. 5.1b: instead of permitting the air to expand aimlessly into the
lower-pressure surroundings, the stream could be passed through
a turbine and work could be developed.
Fig. 5.1c: instead of permitting the mass to fall in an uncontrolled
way, it could be lowered gradually while turning a wheel, lifting
another mass.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
OPPORTUNITIES FOR DEVELOPING WORK
When an imbalance exists between two systems, there is an opportunity
for developing work that would be irrevocably lost if the systems were
allowed to come into equilibrium in an uncontrolled way.
Recognizing this possibility for work, we can pose two questions:
1. What is the theoretical max value for work that could be obtained?
2. What are the factors that would preclude the realization of max value?
Devices would be subject to factors such as friction that would preclude
the attainment of the theoretical max work.
2nd law of thermodynamics provides means for determining theoretical
max and evaluating quantitatively factors that preclude attaining the max.
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5.1 Introducing the 2nd Law 5.1.1 Motivating the 2nd Law
SECOND LAW SUMMARY
2nd law & deductions are useful because they provide means for
1. predicting direction of processes.
2. establishing conditions for equilibrium.
3. determining best theoretical performance of cycles, engines, and
other devices.
4. evaluating quantitatively factors that preclude attainment of best
theoretical performance level.
5. defining a temperature scale independent of properties of any
thermometric substance.
6. developing means for evaluating properties such as u and h in terms
of properties that are more readily obtained experimentally.
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5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law
CLAUSIUS STATEMENT
It is impossible for any system to operate in such a way
that the sole result would be an energy transfer by
heat from a cooler to a hotter body.
It is impossible to construct a refrigeration cycle that operates
without an input of work.
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5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law
KELVIN–PLANCK STATEMENT
A thermal reservoir: a special kind of system that always remains at
constant temperature even though energy is added or removed by heat
transfer.
earth’s atmosphere
large bodies of water (lakes, oceans)
large block of copper
system consisting of two phases (although the ratio of the masses of the two
phases changes as the system is heated or cooled at constant pressure, the
temperature remains constant as long as both phases coexist).
Extensive properties of a thermal reservoir such as internal energy can
change in interactions with other systems even though the reservoir
temperature remains constant.
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5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law
KELVIN–PLANCK STATEMENT
A thermodynamic cycle: a sequence of processes that
begins and ends at the same state.
At the conclusion of a cycle all properties have the
same values they had at the beginning.
Over the cycle the system experiences no net change
of state.
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5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law
KELVIN–PLANCK STATEMENT
It is impossible for any system to operate
in a thermodynamic cycle and deliver a
net amount of energy by work to its
surroundings while receiving energy by
heat transfer from a single thermal
reservoir.
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5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law
KELVIN–PLANCK STATEMENT
1st and 2nd laws each impose constraints:
1st law: According to the cycle energy
balance
Although the cycle energy balance allows
the net work Wcycle to be positive or
negative, the 2nd law imposes a constraint
on its direction.
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5.1 Introducing the 2nd Law 5.1.2 Statements of the 2nd Law
KELVIN–PLANCK STATEMENT
A system undergoing a cycle while communicating
thermally with a single reservoir cannot deliver a net
amount of work to its surroundings. That is, the net
work of the cycle cannot be positive.
Analytical form of the Kelvin–Planck statement
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
An irreversible process: system and all
parts of its surroundings cannot be
exactly restored to their respective initial
states after the process has occurred.
A reversible process: both system and
surroundings can be returned to their
initial states.
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
A system that has undergone an irreversible process is not necessarily precluded from being restored to its initial state.
While the system restored to its initial state, it would not be possible also to return the surroundings to the state they were in initially.
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
From Clausius statement of 2nd law, any process involving a spontaneous heat transfer from a hotter body to a cooler body is irreversible.
Friction, electrical resistance, hysteresis, and inelastic deformation are examples of effects whose presence during a process renders it irreversible.
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
Irreversibilities can be divided into two
classes:
1. Internal irreversibilities: occur within the
system.
2. External irreversibilities: occur within the
surroundings.
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
Consider two bodies at different temperatures that are able to
communicate thermally.
With a finite temperature difference between them, a
spontaneous heat transfer would take place and, this would be a
source of irreversibility.
The importance of this irreversibility would diminish as the
temperature difference approaches zero.
The transfer of a finite amount of energy by heat between bodies
whose temperatures differ only slightly would require a
considerable amount of time, a larger heat transfer surface area,
or both.
To eliminate this source of irreversibility, therefore, would require
an infinite amount of time and/or an infinite surface area.
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
Irreversibility of the process can be demonstrated using
Kelvin–Planck statement of 2nd law and the following
procedure:
1. Assume there is a way to return the system and
surroundings to their respective initial states.
2. It would be possible to devise a cycle that produces
work while no effect occurs other than a heat transfer
from a single reservoir. Since the existence of such a
cycle is denied by Kelvin–Planck statement, initial
assumption must be in error and it follows that the
process is irreversible.
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5.2 Identifying irreversibility REVERSIBLE PROCESSES
A process of a system is reversible if
the system and all parts of its
surroundings can be exactly restored
to their respective initial states after
the process has taken place.
The passage of a gas through a
properly designed nozzle or diffuser
is an example.
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5.2 Identifying irreversibility IRREVERSIBLE PROCESSES
INTERNALLY REVERSIBLE PROCESSES
An internally reversible process: one in which there are no irreversibilities
within the system.
At every intermediate state of an internally reversible process of a closed
system, all intensive properties are uniform throughout each phase
present.
Temperature, pressure, specific volume, and other intensive properties do not
vary with position.
Internally reversible process consists of a series of equilibrium states: It
is a quasiequilibrium process.
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Applying 2nd Law to Thermodynamic Cycles 5.3.1 Interpreting the Kelvin–Planck Statement
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Applying 2nd Law to Thermodynamic Cycles 5.3.2 Power Cycles Interacting with Two Reservoirs
Thermal efficiency of cycle is
If value of QC were zero, the system would withdraw energy QH from hot reservoir and produce an equal amount of work, while undergoing a cycle. Thermal efficiency of such a cycle would be 100%.
This method of operation would violate Kelvin–Planck statement and thus is not allowed.
For any system executing a power cycle while operating between two reservoirs, only a portion of QH can be obtained as work, and the remainder, QC, must be discharged by heat transfer to the cold reservoir.
Thermal efficiency must be less than 100%.
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Applying 2nd Law to Thermodynamic Cycles 5.3.2 Power Cycles Interacting with Two Reservoirs
CARNOT COROLLARIES
1. Thermal efficiency of an irreversible power
cycle is always less than thermal efficiency
of a reversible power cycle when each
operates between same two thermal
reservoirs.
2. All reversible power cycles operating
between same two thermal reservoirs have
same thermal efficiency.
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Applying 2nd Law to Thermodynamic Cycles 5.3.3 Refrigeration and Heat Pump Cycles Interacting with Two Reservoirs
Coefficient of
performance of a
refrigeration cycle
Coefficient of
performance for a heat
pump cycle is
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Applying 2nd Law to Thermodynamic Cycles 5.3.3 Refrigeration and Heat Pump Cycles Interacting with Two Reservoirs
As Wcycle tends to zero, coefficients of
performance approach infinity.
If Wcycle were identically zero, system would
withdraw energy QC from the cold reservoir
and deliver energy QC to the hot reservoir,
while undergoing a cycle.
This method of operation would violate
Clausius statement of 2nd law and thus is not
allowed.
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Applying 2nd Law to Thermodynamic Cycles 5.3.3 Refrigeration and Heat Pump Cycles Interacting with Two Reservoirs
Corollaries for Refrigeration & Heat Pump Cycles
Coefficient of performance of an irreversible
refrigeration cycle is always less than
coefficient of performance of a reversible
refrigeration cycle when each operates
between same two thermal reservoirs.
All reversible refrigeration cycles operating
between same two thermal reservoirs have
same coefficient of performance.
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Maximum Performance Measures for Cycles
Operating Between Two Reservoirs 5.5.1 Power Cycles
Thermal efficiency of a system
undergoing a reversible power cycle
while operating between thermal
reservoirs at temperatures TH and TC.
Carnot efficiency increases as TH
increases and/or TC decreases.
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Maximum Performance Measures for Cycles
Operating Between Two Reservoirs 5.5.1 Power Cycles
Possibility of increasing thermal
efficiency by reducing TC below
that of the environment is not
practical,
For maintaining TC lower than
ambient temperature would
require a refrigerator that
would have to be supplied work
to operate.
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Maximum Performance Measures for Cycles
Operating Between Two Reservoirs 5.5.1 Power Cycles
Referring to segment a–b of the curve, where TH and h are relatively low,
h increases rapidly as TH increases, even a small increase in TH can have a large effect on efficiency.
Thermal efficiencies of actual cycles increase as average temperature at which energy is added by heat transfer increases and/or average temperature at which energy is discharged by heat transfer is reduced.
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Maximum Performance Measures for Cycles
Operating Between Two Reservoirs 5.5.2 Refrigeration and Heat Pump Cycles
Coefficient of performance of any system
undergoing a reversible refrigeration cycle while
operating between the two reservoirs
Coefficient of performance of any system
undergoing a reversible heat pump cycle while
operating between the two reservoirs
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EXAMPLE 5.1
Evaluating a Power Cycle Performance Claim
An inventor claims to have developed a power cycle capable of delivering a net work output of 410 kJ for an energy input by heat transfer of 1000 kJ. The system undergoing the cycle receives the heat transfer from hot gases at a temperature of 500 K and discharges energy by heat transfer to the atmosphere at 300 K. Evaluate this claim.
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EXAMPLE 5.2
Evaluating Refrigerator Performance
By steadily circulating a refrigerant at low temperature through passages in the walls of freezer compartment, a refrigerator maintains freezer compartment at -5°C when air surrounding refrigerator is at 22°C. The rate of heat transfer from freezer compartment to refrigerant is 8000 kJ/h and power input required to operate the refrigerator is 3200 kJ/h. Determine coefficient of performance of refrigerator and compare with coefficient of performance of a reversible refrigeration cycle operating between reservoirs at the same two temperatures.
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EXAMPLE 5.3 Evaluating Heat Pump Performance
A dwelling requires 5×105 kJ per day to maintain
its temperature at 22°C when the outside temperature is 10°C. If an electric heat pump is used to supply this energy, determine the
minimum theoretical work input for one day of
operation, in kJ.
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Carnot Cycle
a reversible power cycle
operating between two
thermal reservoirs.
The system is a gas in a
piston cylinder assembly.
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Carnot Cycle
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Carnot Cycle
Area under adiabatic process line 1–2 = work done per unit of mass to compress the gas.
Areas under process lines 2–3 and 3–4 = work done per unit of mass by the gas as it expands in these processes.
Area under process line 4–1 = work done per unit of mass to compress the gas.
The enclosed area on p–v diagram = net work developed by the cycle per unit of mass.
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Carnot Cycle
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Home Work Assignment H15-1
18, 23, 29, 33, 35, 42, 46
Due Saturday 28/4/2012
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