chapter 5 more triangles. mr. thompson more triangles. mr. thompson

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Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson.

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Page 1: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Chapter 5

More Triangles.

Mr. ThompsonMore Triangles.Mr. Thompson.

Page 2: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Midsegment Theorem

Page 3: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

A midsegment of a triangle is a segment that connects the midpoints of

two sides of

a triangle.

Page 4: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Midsegment TheoremThe segment connecting the

midpoints of 2 sides of a triangle is parallel to

the 3rd side

and is ½ as

long.

Page 5: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Perpendiculars and Bisectors

Page 6: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

In 1.5, you learned that a segment bisector intersects a segment at its midpoint.

10 10

midpoint

Segment bisector

Page 7: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

A segment, ray, line, or plane that is perpendicular to a segment at its midpoint is

called a perpendicular bisector.

12 12

d f

Page 8: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

A point is equidistant from two points if its distance from each point is the same.

x z

y

Y is equidistant from X and Z.

Page 9: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Perpendicular Bisector Theorem If a point is on the perpendicular

bisector of a segment,

8 8A B

then it is equidistant from the endpoints of the segment.

Page 10: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Converse of the Perpendicular Bisector Theorem

If a point is equidistant from the endpoints of a segment,

x z

y

Y is equidistant from X and Z.

Page 11: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Using Perpendicular Bisectors

T

Q

S

M N

12

12

What segment lengths in the diagram are equal?

NS=NT (given)

M is on the perpendicular bisector of ST, so…..

MS=MT (Theorem 5.1)

QS =QT=12 (given)

Page 12: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Using Perpendicular Bisectors

T

Q

12

12

Explain why Q is on MN.

S

MN

QS=QT, so Q is equidistant from S and T.

By Theorem 5.2, Q is on the perpendicular bisector of ST, which is MN.

Page 13: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

The distance from a point to a line….. defined as the length of the

perpendicular segment from the point to the line.

m

R

S

The distance from point R to line m is the length of RS.

Page 14: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Point that is equidistant from two lines…

When a point is the same distance from one line as it is from another line, the point is equidistant from the two lines(or rays or segments).

Page 15: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Angle Bisector TheoremIf a point is on the bisector of an angle,

then it is equidistant from the 2 sides of the angle.

If angle ABD = angle CBD,

then DC = AD.

Page 16: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Converse of the Angle Bisector TheoremIf a point is in the interior of an

angle and is equidistant from the sides of the angle, then it lies on the bisector of the angle.

If DC = AD, then angle ABD = angle CBD.

Page 17: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Bisectors of a Triangle…

Page 18: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

A perpendicular bisector of a triangle is a line (or ray or segment) that is perpendicular to a side of the triangle at the

midpoint of the

side.

Page 19: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Investigation…

…of the Perpendicular Bisector Theorem.

Page 20: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

When three or more lines (or rays or segments) intersect in the same point, they are called concurrent lines (or rays or segments). The point of

intersection of the

lines is called the

point of

concurrency.

Page 21: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

The three perpendicular bisectors of a triangle are concurrent. The point of concurrency can be inside the triangle, on the triangle, or outside the triangle.

Page 22: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

The point of concurrency of the perpendicular bisectors

of a triangle is

called the

circumcenter

of the triangle.

Page 23: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Concurrency of Perpendicular Bisectors of a Triangle

The perpendicular bisectors of a triangle intersect at a point

that is equidistant

from the vertices

of the triangle.

OA1 = OA2 = OA3

Page 24: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

An angle bisector of a triangle is a bisector of an angle of the triangle. The three angle bisectors are concurrent. The point of concurrency of the angle bisectors is called the

incenter of the triangle and is always inside the triangle.

Page 25: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Concurrency of Angle Bisectors of a TriangleThe angle bisectors of a triangle intersect at a point that is equidistant from the sides of the triangle. LMC = LMA = LMB

Page 26: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Classwork…

Page 246:6, 13, 31, 32, 35, 38

Page 252:28, 29, 33, 40, 46

Page 27: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Medians and Altitudes of a

Triangle

Page 28: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Medians and Altitudes

Page 29: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

A median of a triangle is a segment whose endpoints are a vertex of the

triangle and the

midpoint of the

opposite side.

Page 30: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

The three medians of a triangle are concurrent. The point of concurrency is called the centroid of the triangle. The centroid is always inside the triangle.

Page 31: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Concurrency of Medians of a Triangle

The medians of a triangle intersect at a point that is two thirds of the distance from each vertex to the midpoint of the opposite side.

Page 32: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

An altitude of a triangle is the perpendicular segment from a vertex to the opposite side or to the line that contains the opposite side. An altitude can lie inside, on or outside the triangle.

Page 33: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

If AR, CT, and BU are altitudes of triangle ABC, then AR, CT,

and BU intersect at some point P.

Page 34: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Example1) ABC [A(-3,10),

B(9,2), and C(9,15)]:

a) Determine the coordinates of point P on AB so that CP is a median of ABC.

b) Determine if CP is an altitude of ABC

Page 35: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Example2) SGB [S(4,7), G(6,2),

and B(12,-1)]:

a) Determine the coordinates of point J on GB so that SJ is a median of SGB

b) Point M(8,3). Is GM an altitude of SGB ?

Page 36: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Inequalities in One Triangle

Page 37: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

TheoremIf one side of a triangle is longer

than another side, then the angle opposite the longer side is larger than the angle

opposite the

shorter side.

Page 38: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

TheoremIf one angle of a triangle is larger than

another angle, then the side opposite the larger angle is longer than the side opposite the smaller

side.

Page 39: Chapter 5 More Triangles. Mr. Thompson More Triangles. Mr. Thompson

Triangle InequalityThe sum of the lengths of any two

sides of a triangle is greater than the length of the third side.

Would sides of length 4, 5 and 6 form a triangle....?

How about sides of length 4, 11, and 7 ?