chapter 5 copyright © 2015, 2011, 2007 pearson education, inc. chapter 5-1 factoring
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3 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-3 Factoring Trinomials of the Form ax 2 + bx + c, a = 1TRANSCRIPT
Chapter 5
Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-1
Factoring
2 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-2
5.1 – Factoring a Monomial from a Polynomial
5.2 – Factoring by Grouping5.3 – Factoring Trinomials of the Form
ax2 + bx + c, a = 15.4 – Factoring Trinomials of the Form
ax2 + bx + c, a ≠ 15.5 – Special Factoring Formulas and a
General Review of Factoring5.6 – Solving Quadratic Equations Using
Factoring5.7 – Applications of Quadratic Equations
Chapter Sections
3 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-3
Factoring Trinomials of
the Formax2 + bx + c, a =
1
4 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-4
Factoring TrinomialsRecall that factoring is the reverse process of multiplication. Using the FOIL method, we can show that
((xx + 3)( + 3)(xx + 4) = + 4) = xx22 + 7 + 7xx + 12. + 12.
Therefore xx22 + 7 + 7xx + 12 + 12 = = ((xx + 3)( + 3)(xx + 4) + 4) Note that this trinomial results in the product of two binomials whose first term is x and second term is a number (including its sign).
5 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-5
Factoring TrinomialsFactoring any polynomial of the form Factoring any polynomial of the form xx22 + b + bxx + c + cwill result in a pair of binomials:will result in a pair of binomials:
Numbers go here.Numbers go here.
x2 + bx + c = (x +?)(x +?)
O
( x + 3 )( x + 4 )
F
I
L
= x2 + 4x + 3x + 12
= x2 + 7x + 12
F O I L
6 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-6
Factoring Trinomials1. Find two numbers whose product
equals the constant, c, and whose sum equals the coefficient of the x-term, b.
2. Use the two numbers found in step 1, including their signs, to write the trinomial in factored form. The trinomial in factored form will be
(x + first number) (x + second number)
7 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-7
Examplesa.) Factor x2 - 11x - 60.
x2 - 11x - 60 = (x + ?) (x + ?)Replace the ?s with two numbers that are the product of -60 and the sum of -11.x2 + 8x + 15 = (x -15) (x + 4)
b.) Factor x2 + 5x + 12.This is a prime polynomial
because it cannot be factored.
8 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-8
Examples Continuedc.) Factor x2 + 3xy + 2y2.
We must find two numbers whose product is 2 (from 2y2) and whose sum is 3 (from 3xy). The two numbers and 1 and 2. Thus,x2 + 3xy + 2y2 = (x + 1y)(x + 2y) =
(x + y)(x + 2y)