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Chapter 4 Systems of Linear Equations; Matrices Section 7 Leontief Input- Output Analysis

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Chapter 4 Systems of Linear Equations; Matrices. Section 7 Leontief Input-Output Analysis. Learning Objectives for Section 4.7 Leontief Input-Output Analysis. The student will be able to formulate and solve the two-industry model of input-output analysis. - PowerPoint PPT Presentation

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Page 1: Chapter 4 Systems of Linear Equations; Matrices

Chapter 4

Systems of Linear Equations; Matrices

Section 7Leontief Input-Output

Analysis

Page 2: Chapter 4 Systems of Linear Equations; Matrices

Barnett/Ziegler/Byleen Finite Mathematics 12e 2

Learning Objectives for Section 4.7 Leontief Input-Output Analysis

The student will be able to formulate and solve the two-industry model of input-output analysis.

The student will be able to formulate and solve the three-industry model of input-output analysis.

Page 3: Chapter 4 Systems of Linear Equations; Matrices

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Leontief Input-Output Analysis

In this section, we will study an important economic application of matrix inverses and matrix multiplication.

This branch of applied mathematics is called input-output analysis and was first proposed by Wassily Leontief, who won the Nobel Prize in economics in 1973 for his work in this area.

Page 4: Chapter 4 Systems of Linear Equations; Matrices

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Wassily Leontief1905-1999

Wassily Leontief was born August 5th, 1905 in St. Petersburg, the son of Wassily W. Leontief and his wife Eugenia. A brilliant student, he enrolled in the newly renamed University of Leningrad at only 15 years old. He got in trouble by expressing vehement opposition to the lack of intellectual and personal freedom under the country's Communist regime, which had taken power three years earlier. He was arrested several times.

Wassily Leontief in 1983

Page 5: Chapter 4 Systems of Linear Equations; Matrices

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Wassily Leontief(continued)

At Harvard, he developed his theories and methods of Input-Output analysis. This work earned him the Nobel prize in Economics in 1973 for his analysis of America's production machinery. His analytic methods, as the Nobel committee observed, became a permanent part of production planning and forecasting in scores of industrialized nations and in private corporations all over the world.Professor Leontief passed away on Friday February 6th, 1999. For more information on his life, visit http://www.iioa.org/leontief/Life.html

Page 6: Chapter 4 Systems of Linear Equations; Matrices

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Basic Input-Output Problem

The main problem of input-output analysis is the following:

Consider an economy with several industries. Each industry has a demand for products from other instrustries (internal demand). There are also external demands from the outside. Find a production level for the industries that will meet both internal and external demands.

Page 7: Chapter 4 Systems of Linear Equations; Matrices

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Two-Industry ModelExample

We start with an economy that has only two industries (agriculture and energy) to illustrate the method. Later, this method will generalized to three or more industries. These two industries depend upon each other. For example, each dollar’s worth of agriculture produced requires $0.40 of agriculture and $0.20 of energy. Each dollar’s worth of energy produced requires $0.20 of agriculture and $0.10 of energy.So, both industries have an internal demand for each others resources. Let us suppose there is an external demand of $12,000,000 of agriculture and $9,000,000 dollars of energy.

Page 8: Chapter 4 Systems of Linear Equations; Matrices

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Example:Matrix Equations

Let x represent the total output from agriculture and y represent the total output of energy (in millions of $)The expressions

0.4x + 0.2y 0.2x + 0.1y

can be used to represent the internal demands for agriculture and energy.

The external demands of 12 and 9 million must also be met, so the revised equations are :

x = 0.4x + 0.2y + 12 y = 0.2x + 0.1y + 9

These equations can be represented by the following matrix equation:

0.4 0.2 120.2 0.1 9

x xy y

⎡ ⎤ ⎡ ⎤⎡ ⎤ ⎡ ⎤= +⎢ ⎥ ⎢ ⎥⎢ ⎥ ⎢ ⎥⎣ ⎦ ⎣ ⎦⎣ ⎦ ⎣ ⎦

Page 9: Chapter 4 Systems of Linear Equations; Matrices

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Example:Technology Matrix (M )

$1$1

$1 $1

input from input fromagriculture agricultureto produce to produce

of agriculture of energy

input of energy input of energyto produce to produce ofof agriculture energy

⎛ ⎞ ⎛ ⎞⎜ ⎟ ⎜ ⎟⎜ ⎟ ⎜ ⎟⎜ ⎟ ⎜ ⎟⎜ ⎟ ⎜ ⎟⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠⎛ ⎞⎜ ⎟⎜ ⎟

⎛ ⎞⎜ ⎟⎜⎜ ⎟⎝ ⎜⎝ ⎠⎠

⎟⎟

⎡ ⎤⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎢ ⎥⎣ ⎦

0.4 0.20.2 0.1

⎡ ⎤=⎢ ⎥⎣ ⎦

A

A

E

Read left to right, E then up

= M

Page 10: Chapter 4 Systems of Linear Equations; Matrices

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Example:Solving the Matrix Equations

0.4 0.2 120.2 0.1 9

x xy y

⎡ ⎤ ⎡ ⎤⎡ ⎤ ⎡ ⎤= +⎢ ⎥ ⎢ ⎥⎢ ⎥ ⎢ ⎥⎣ ⎦ ⎣ ⎦⎣ ⎦ ⎣ ⎦

We can solve this matrix equation as follows: X = MX+D

X – MX = D

IX – MX = D

(I – M)X = D

if the inverse of (I – M) exists.

1( )X I M D−= −

Page 11: Chapter 4 Systems of Linear Equations; Matrices

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Example:Solution

We will now find 1( )X I M D−= −

1 0 0.4 0.2 0.6 0.20 1 0.2 0.1 0.2 0.9

−⎡ ⎤ ⎡ ⎤ ⎡ ⎤− =⎢ ⎥ ⎢ ⎥ ⎢ ⎥−⎣ ⎦ ⎣ ⎦ ⎣ ⎦

First, find (I – M):

1.8 .4.4 1.2

⎡ ⎤⎢ ⎥⎣ ⎦

The inverse of (I – M) is:

Page 12: Chapter 4 Systems of Linear Equations; Matrices

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Solution(continued)

After finding the inverse of (I – M), multiply that result by the external demand matrix D. The answer is:Produce a total of $25.2 million of agriculture and $15.6 million of energy to meet both the internal demands of each resource and the external demand.

1.8 .4.4 1.2

⎡ ⎤⎢ ⎥⎣ ⎦

129

⎡ ⎤⎢ ⎥⎣ ⎦

25.215.6

⎡ ⎤=⎢ ⎥⎣ ⎦

Page 13: Chapter 4 Systems of Linear Equations; Matrices

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Another Example

Suppose consumer demand changes from $12 million dollars of agriculture to $8 million dollars and energy consumption changes from $9 million to $5 million. Find the output for each sector that is needed to satisfy this final demand.

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Example(continued)

Suppose consumer demand changes from $12 million dollars of agriculture to $8 million dollars and energy consumption changes from $9 million to $5 million. Find the output for each sector that is needed to satisfy this final demand. Solution: Recall that our general solution of the problem is

The only change in the problem is the external demand matrix. (I – M) did not change. Therefore, our solution is to multiply the inverse of (I – M) by the new external demand matrix D.

1( )X I M D−= −

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ExampleSolution

1.8 .4.4 1.2

⎡ ⎤⎢ ⎥⎣ ⎦

8 16.45 9.2

⎡ ⎤ ⎡ ⎤=⎢ ⎥ ⎢ ⎥⎣ ⎦ ⎣ ⎦

1( )X I M D−= −

Page 16: Chapter 4 Systems of Linear Equations; Matrices

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Summary of Two Industry Solution

Given two industries, C1 and C2 , with

X =

x1

x2

⎡⎣⎢⎢

⎤⎦⎥⎥

D =d1

d2

⎡⎣⎢⎢

⎤⎦⎥⎥

C1 C2

M =C1

C2

a11 a12

a21 a22

⎡⎣⎢⎢

⎤⎦⎥⎥

where aij is the input required from Ci to produce a dollar’s worth of output for Cj, the solution to the input-output matrix equationis

assuming that I – M has an inverse. X =MX + D

X = I −M( )

−1D

Page 17: Chapter 4 Systems of Linear Equations; Matrices

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More Than Two Sectors of the Economy

This method can also be used if there are more than two sectors of the economy. If there are three sectors, say agriculture, building and energy, the technology matrix M will be a 3 3 matrix. The solution to the problem will still be

although in this case it is necessary to determine the inverse of a 3 3 matrix.

1( )X I M D−= −

Page 18: Chapter 4 Systems of Linear Equations; Matrices

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Example:Three-Industry Model

An economy is based on three sectors, agriculture (A), energy (E), and manufacturing (M). Production of a dollar’s worth of agriculture requires an input of $0.20 from the agriculture sector and $0.40 from the energy sector. Production of a dollar’s worth of energy requires an input of $0.20 from the energy sector and $0.40 from the manufacturing sector. Production of a dollar’s worth of manufacturing requires an input of $0.10 from the agriculture sector, $0.10 from the energy sector, and $0.30 from the manufacturing sector.

Find the output from each sector that is needed to satisfy a final demand of $20 billion for agriculture, $10 billion for energy, and $30 billion for manufacturing.

Page 19: Chapter 4 Systems of Linear Equations; Matrices

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Example(continued)

The technology matrix is as follows:

0.2 0 0.10.4 0.2 0.10 0.4 0.3

⎡ ⎤⎢ ⎥⎢ ⎥⎢ ⎥⎣ ⎦

Output

A E M

InputA

E

M

= M

0.8 0 0.10.4 0.8 0.10 0.4 0.7

I M−⎡ ⎤

⎢ ⎥− = − −⎢ ⎥⎢ ⎥−⎣ ⎦

1

1.3 0.1 0.2( ) 0.7 1.4 0.3

0.4 0.8 1.6I M −

⎡ ⎤⎢ ⎥− =⎢ ⎥⎢ ⎥⎣ ⎦

Page 20: Chapter 4 Systems of Linear Equations; Matrices

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Example(continued)

Thus, the output matrix X is given by:

1

2

3

1.3 0.1 0.2 20 330.7 1.4 0.3 10 370.4 0.8 1.6 30 64

xxx

⎡ ⎤ ⎡ ⎤⎡ ⎤ ⎡ ⎤⎢ ⎥ ⎢ ⎥⎢ ⎥ ⎢ ⎥= =⎢ ⎥ ⎢ ⎥⎢ ⎥ ⎢ ⎥⎢ ⎥ ⎢ ⎥⎢ ⎥ ⎢ ⎥⎣ ⎦ ⎣ ⎦⎣ ⎦ ⎣ ⎦

X (I - M)-1 D

An output of $33 billion for agriculture, $37 billion for energy, and $64 billion for manufacturing will meet the given final demands.