chapter 4 other force diagrams
DESCRIPTION
Chapter 4 Other Force Diagrams. W ||. W . 28 °. F f. Find F f :. Find F NET :. Find F A :. F N. F A. =.675(51.9) = 6(3.5) F A – 27.6 – 35 = 21 = 35.0 N= 21.0 N 83.6 N. But first one RAMP PROBLEM for review………. - PowerPoint PPT PresentationTRANSCRIPT
But first one RAMP PROBLEM for review……….
With what force must you push to accelerate a 6.00 kg block 3.50 m/s2 UP a 28° ramp with = .675?
28°
W
W||
FN FA
Ff
m =
W =
W=
W||=
m =
W =
W=
W||=
6
58.8
51.9
27.6
FN = W
FA – W|| - Ff = FNET
Find FA :
FA – W|| - Ff = FNET
Find FNET :
FNET = ma
Find Ff :
Ff = FN
=.675(51.9) = 6(3.5) FA – 27.6 – 35 = 21
= 35.0 N = 21.0 N 83.6 N
What is the acceleration of a 20.0 kg object when pulled with a rope that makes an angle of 22° with the horizontal? The applied force on the rope is 250 N and = .333.
F
F||
FA
FN
W
Ff
m =
W=
FA=
F=
F||=
m =
W=
FA=
F=
F||=
250
FN + F = W
F|| - Ff = FNET
20
250
196250
F||
F
93.7
232
sin =
cos =
F
250
F||
250
What is the acceleration of a 20.0 kg object when pulled with a rope that makes an angle of 22° with the horizontal? The applied force on the rope is 250 N and = .333.
F
F||
FA
FN
W
Ff
m =
W=
FA=
F=
F||=
m =
W=
FA=
F=
F||=
250
FN + F = W
F|| - Ff = FNET
20
196
250
93.7
232
Find a:Find FNET:Find Ff :Find FN:
FNET = maF|| - Ff = FNETFf = FNFN + F = W
FN+ 93.7 = 196 =.333(102) 232 – 34 = FNET 198 = 20 a
102 N 34.0 N 198 N 9.90 m/s2
What is the coefficient of friction if pulling with 55.0 N on a handle that makes an angle of 35° with the ground gives a 60.0 N object an acceleration of 3.00 m/s2?
F
F||
FN
W
Ff
55
FN + F = W
F|| - Ff = FNET
m =
W=
FA=
F=
F||=
m =
W=
FA=
F=
F||=
6.12
60.0
55
31.5
45.1
Ff = FNF|| - Ff = FNET FN + F = WFNET = ma
Find FNet: Find FN:Find Ff : Find :
= 6.12(3) 45.1 – Ff = 18.4 FN + 31.5 = 60 26.7= (28.5)
18.4 N 26.7 N 28.5 N .937